Answer: azada calva
Explanation:
To prepare 250mL of calcium chloride solution with a molar concentration of 1.20mol/L, what mass of calcium chloride would be required?
Answer:
33.30 grams of CaCl2 will be required
Explanation:
Given,
Volume of solution, V= 250 ml
Molarity of solution, M= 1.20 mol/L
Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111
We know,
Required mass, W= SVM/1000
Now,
W = (111 X 250 X 1.20)/1000
= 33300/1000
= 33.30
Therefore, 33.30 grams of Calcium Chloride will be required.
is there a gravitation attraction between you and your computer
If g of chlorine gas occupies a volume of mL at a particular temperature and pressure, what volume will g of chlorine gas occupy under the same conditions
The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?
Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
Explanation:
Given: [tex]Mass_1[/tex] = 1.04 g, [tex]V_{1}[/tex] = 872 mL
[tex]Mass_2[/tex] = 2.08 g, [tex]V_{2}[/tex] = ?
As molar mass of chlorine is 35.5 g/mol.
Number of moles is the mass of a substance divided by its molar mass.
Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]
Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.
[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]
Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]
Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
Answer:
[tex]V_2=600mL[/tex]
Explanation:
Hello there!
In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:
[tex]V_2M_2=V_1M_1[/tex]
Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:
[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]
Regards!
Which of these is a major drawback of using fuel cells in a car?
a lack of hydrogen filling stations
a drop in reliance on petroleum products
an increase in water vapor into the atmosphere
an increase in the use of rechargeable batteries
A major drawback of using fuel cells in a car is a lack of hydrogen filling stations.
What is fuel cell?A fuel cell is an electrochemical device that converts the energy stored in a fuel, typically hydrogen, directly into electrical energy.
One significant disadvantage of using fuel cells in a car is the scarcity of hydrogen filling stations.
While fuel cell technology has several advantages, including increased efficiency and lower emissions, the infrastructure for producing, transporting, and storing hydrogen is currently limited, making it difficult to refuel fuel cell vehicles on the road.
Because of this limitation, fuel cell vehicles are less suitable for long-distance travel and have a limited market penetration.
Thus, the answer is "a lack of hydrogen filling stations".
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Answer:
its A trust!!!!!
Explanation:
Write an equation for sodium chloride and sodium oxide
Answer:
Explanation:
The Chemical Equation for each one of these compounds would be the following
Sodium Chloride: NaCl
This compound contains 1 Sodium atom and 1 Chlorine atom
Sodium Oxide: Na₂O
This compound contains 2 Sodium atoms and 1 Oxygen atom.
A balance was tested against a standard calibration mass with a certified value of 200.002 g and produced the following readings in grams: 195.587, 195.586, 195.588, 195.587, 195.589. The performance of this balance is best described as:
Answer:
Precise but not accurate.
Explanation:
We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.
However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).
A gas system has volume, moles and temperature of 1.52 L, 0.52 moles and 203K, respectively. What is the pressure in atm?
Answer:
P = 5.70 atm
Explanation:
Use PV = nRT
In this case, R = 0.0821 L·atm/mol·K (because we are finding the pressure in atm)P(1.52 L) = (0.52 moles)(0.0821)(203 K)
P = 5.701628947 atm
what's the most lightest element known?
Answer:
Hydrogen
Explanation:
Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).
Answer:
Hydrogen
Explanation:
Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).
As the temperature increases from 0°C to 25°C the amount of NH3 that can be dissolved in 100 grams of water.
A) decreases by 10 grams
B) decreases by 40 grams
C) increases by 10 grams
D) increases by 40 grams
Answer:
decreases by 10 gram
Explanation:
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to its final temperature is 200 J/K. What is the final temperature of the gas
Answer:
668.9K is the final temperature
Explanation:
The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:
ΔS = n*Cv*ln (T2/T1)
Where ΔS is change in entropy = 200J/K
n are moles = 20.0mol
Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)
T2 is final Temperature and T1 initial temperature = 300K
Replacing:
ΔS = n*Cv*ln (T2/T1)
200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)
0.80186 = ln (T2/300K)
2.23 = T2 / 300K
668.9K is the final temperatureCalculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.
Answer:
The total energy absorbed is 32.171 kilojoules.
Explanation:
The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:
[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)
Where:
[tex]m[/tex] - Mass of the ice, in kilograms.
[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.
[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.
[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.
[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.
[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.
[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.
[tex]Q[/tex] - Total energy absorbed, in kilojoules.
If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:
[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]
The total energy absorbed is 32.171 kilojoules.
1. (8pt) Using dimensional analysis convert 600.0 calories into kilojoules
2. (8pts) how much heat and kilojoules is needed to raise the temperature of 236 g of silver from 8.5°C to 34.9°C? (Cag = 0.24 J/g°C)
Answer:
1. 2.510kJ
2. Q = 1.5 kJ
Explanation:
Hello there!
In this case, according to the given information for this calorimetry problem, we can proceed as follows:
1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:
[tex]1cal=4.184J\\\\1kJ=1000J[/tex]
Then, we perform the conversion as follows:
[tex]600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ[/tex]
2. Here, we use the general heat equation:
[tex]Q=mC(T_2-T_1)[/tex]
And we plug in the given mass, specific heat and initial and final temperature to obtain:
[tex]Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ[/tex]
Regards!
What human development period 2 years and 12 years called
Answer:
In these lessons, students become familiar with the four key periods of growth and human development: infancy (birth to 2 years old), early childhood (3 to 8 years old), middle childhood (9 to 11 years old), and adolescence (12 to 18 years old).
In the lab, a 156 g sample of unknown compound KClOx was completely decomposed to produce 50.4 L of O2 (g) at STP and an unknown amount of KCl. What is the value of X
Answer:
2
Explanation:
Step 1: Write the generic decomposition reaction
KClOₓ ⇒ KCl + O₂
Step 2: Calculate the moles of O₂
At STP, 1 mole of an ideal gas occupies 22.4 L.
50.4 L × 1 mol/22.4 L = 2.25 mol
Step 3: Calculate the mass corresponding to 2.25 moles of O₂
The molar mass of O₂ is 32.00 g/mol.
2.25 mol × 32.00 g/mol = 72 g
Step 4: Determine the value of x
Every 156 g of KClOₓ there are 72 g of oxygen. The mass percent of O is:
%O: 72 g/156 g × 100% = 46.2%
In KClO, the mass percent of O is: 32.00 g/90.5 g × 100% = 35.4%
In KClO₂, the mass percent of O is: 64.00 g/138.5 g × 100% = 46.2%
Then, x = 2
Write the Ksp expression for the sparingly soluble compound cobalt(II) sulfide, CoS. If either the numerator or denominator is 1, please enter 1.
Answer:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write the chemical equation for this reaction as shown below:
[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]
Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Regards!
b. Calculate the empirical formula of a formula unit with the following percent compositions: 59.7%
lithium (Li) and 40.3% nitrogen (N). Complete the table to help with the calculations. (5 points)
Given
Li - 59.7 %
N - 40.3 %
Solution,
First get the molar mass of each Atom,
Li- 6.941
N- 14.00
Second find the moles of both atom,
moles of Li = 59.7/6.941 = 8.60
Moles of N = 40.3/14 = 2.87
Third devide both the moles with smaller mole,
first- 8.6÷2.87 = 2.99 ~ 3
second 2.87÷2.87 = 1
Ratio of Li to N is 3:1
The compound is Li3N.
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) reduced, and the oxidation number changes from +1 to 0.
b)reduces and the oxidation number changes from +2 to 0.
c)oxidized and the oxidation number changes from 0 to +1.
d) oxidized, and the oxidation number changes from +1 to 0.
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) Reduced, and the oxidation number changes from +1 to 0.
b) Reduces and the oxidation number changes from +2 to 0.
c) Oxidized and the oxidation number changes from 0 to +1.
d) Oxidized, and the oxidation number changes from +1 to 0.
____________________Solution :-Given Information :-Reaction ➢ Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag To Find :-Whether Ag⁺ is:-a) Reduced, and the oxidation number changes from +1 to 0.b) Reduces and the oxidation number changes from +2 to 0.c) Oxidized and the oxidation number changes from 0 to +1.d) Oxidized, and the oxidation number changes from +1 to 0.Answer :-Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-
Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.In this reaction, Ag⁺ gains an electron to get reduced to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.
Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.
____________________Final Answer :-Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.____________________Name and describe the type of bond found in a water molecule.
Answer:
covalent bonds
Explanation:
covalent bonds hold together the hydrogen and oxygen atoms of individual H2O molecules. Covalent bonds occur when two atoms share electrons with each other.
Question 1
3 pts
TI
Which part(s) of the following ground state electron configuration holds the valence
electrons?
At
o
1s22s22p63523p4
ОЗр
03s
O2s
O 35 and 3p
Answer:
3s and 3p
Explanation:
From the question given above, the following data were obtained:
Electronic configuration =>
1s² 2s²2p⁶ 3s²3p⁴
Location of valence electron =?
From the electronic configuration given above, we can see clearly that the atom has three (3) shells.
Valence electron(s) are located at the outer most shell of an atom.
The outer most shell of the atom above is 3s and 3p.
Therefore, 3s and 3p will contain the valence electron(s)
determine the mass fraction of iron in its compounds:
Please!
Answer:
Fe(NO₃)₃ = 0.23; FeCl₃ = 0.34
Explanation:
Mass fraction is defined as the ratio between the mass of iron in 1 mol of the compound and the mass of the complete compound.
In Fe(NO₃)₃ there is just 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 241.86g/mol. Thus, mass fraction is:
55.845g/mol / 241.86g/mol =
Fe(NO₃)₃ = 0.23In FeCl₃ there is 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 162.2g/mol. Thus, mass fraction is:
55.845g/mol / 162.2g/mol =
FeCl₃ = 0.34What are anti-oxidants? Why are they added to fat and oil containing food?
Answer:
A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.
help please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?
A 201kpa
B 200kpa
C 400kpa
D 78kpa
Answer:
A. 201 kPa
Explanation:
We can solve this problem by using Boyle's law, which states:
P₁T₂ = P₂T₁Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:
P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 KWe input the data:
125 kPa * 487 K = P₂ * 303 KAnd solve for P₂:
P₂ = 201 kPaWhat is the coldest temperature ever achieved?
Answer:
The lowest natural temperature ever directly recorded at ground level on Earth is −89.2 °C
-273.144 degrees celsius. This is close to 'absolute zero', which is equal to -273.15 degrees celsius
Explanation:
Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.
Answer:
HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER
Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for CaY2- is 5.0 x 1010 and the fraction of unprotonated EDTA (Y4-) is 0.35 at pH10. Calculate the concentration of free Ca2 in this solution.
Answer:
the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
Explanation:
Given the data in the question;
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
Formation constant Kf
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰
Now,
[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35
so the equilibrium is;
[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄ [tex]CaY^{2-[/tex] + 4H⁺
Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] { 1 mol [tex]Ca^{2+[/tex] reacts with 1 mol [tex]H_4Y[/tex] }
so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x
∴
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
x + x 0.010-x
since Kf is high, them x will be small so, 0.010-x is approximately 0.010
so;
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ 0.010 / ( [x][ 0.35 × x] ) = 5.0 × 10¹⁰
⇒ 0.010 / 0.35x² = 5.0 × 10¹⁰
⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 5.7142857 × 10⁻¹³
⇒ x = √(5.7142857 × 10⁻¹³)
⇒ x = 7.559 × 10⁻⁷
Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
1. What do you understand about equivalent weight for lime requirement?
2. What is the relationship between normality and equivalence?
Answer:
Explanation:
What do you understand about equivalent weight for lime requirement?
If field data are not available, lime requirements can be determined with the solution is added to a given weight or volume of soil and the pH is measured. Each milligram per liter of sodium bicarbonate is equal to 0.56 mg/L of alkalinity. A winter wheat crop grown on a light sand soil in a low rainfall area will mean an
True or False
Low temperatures lead to faster dissolution rates compared to high temperatures
Answer:
false
Explanation:
this is because , high temperature speeds up the the random motion of particles which leads to high dissolution
Identify the specific element that corresponds to each of the following electron configuration 1s2, 2s2, 2p6,3s2, 3p6
Explanation:
It's argon
As argon has atomic number 18 so it's configuration is
1s2, 2s2, 2p6,3s2, 3p6
Hope it will help :)❤
The given electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
Each number and letter in the electron configuration corresponds to a specific electron orbital and the number of electrons present in that orbital.
In this case, the electron configuration indicates that:
The first shell (n=1) has 2 electrons in the 1s orbital.
The second shell (n=2) has 2 electrons in the 2s orbital and 6 electrons in the 2p orbital.
The third shell (n=3) has 2 electrons in the 3s orbital and 6 electrons in the 3p orbital.
By adding up the total number of electrons (2 + 2 + 6 + 2 + 6), we find that the configuration represents 18 electrons. The element that has 18 electrons is argon, which has an atomic number of 18.
Therefore, the electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
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Using what you know about the structures of the amino acid side chains and the mechanisms presented in this chapter, which of the following amino acid side chain may play the following roles in an enzymatic mechanism: a. participate in proton transfer, b. act as a nucleophile
Answer:
a. participate in proton transfer - His
b. acts as a nucleophile - Ser
Explanation:
Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.