Answer: The correct answer is No solution.
Explanation:
We are given:
Given mass of thiophene for the experiment = 90.00 g
12.3% w/w solution of thiophene
This means that 12.3 g of thiophene is present in 100 g of solution
Applying unitary method:
If 12.3 g of thiophene is present in 100 g of solution
So, 90.00 g of thiophene will be present in [tex]\frac{100g}{12.3g}\times 90.00g=731.7g [/tex] of solution
Converting it into kilograms:
1 kg = 1000 g
So, 731.7 g = 0.7317 kg
As the given amount of solution is 0.50 kg which is less than the required amount.
Thus, there is not enough solution the student should use.
How many ions are in 1
mole of potassium sulfate?
Answer:
We will need two potassium ions to balance the charge on the sulfate ion, so the proper chemical formula is K 2SO 4.
Explanation:
hope this helps
Question 2 of 10
What is the purpose of the flame that is lit below a hot air balloon?
A. To increase enthalpy
B. To increase reduction
C. To decrease enthalpy
O D. To decrease specific impulse
Answer:
A is correct answer for your question. A
Explanation:
A P E X
The purpose of the flame that is lit below a hot air balloon is to Increase Enthalpy. Hence, Option (A) is Correct.
What is Enthalpy ?
A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.
A hot air balloon uses a burner to heat up the air inside the balloon. The burner is usually fueled by liquid propane. The burner mixes the fuel with air and ignites the mixture, which creates a flame directly underneath the bottom opening of the hot air balloon.
Once the air inside the balloon begins to get warm, the balloon will rise. The pilot controls the balloon’s altitude by releasing hot air from a vent at the top of the balloon, releasing the warmer air causes the balloon to descend.
Therefore, The purpose of the flame that is lit below a hot air balloon is to Increase Enthalpy. Hence, Option (A) is Correct.
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sodium is an inactive metal why
Answer:
Inactive metals are inert metals that doesn’t react with most of the chemicals.They are highly resistant to oxidation and corrosion when exposed to moisture.
Explanation:
A solution is prepared by dissolving solid ammonium nitrate, NH4NO3, in water. The initial temperature of the water was 25oC, but after the solid had dissolved, the temperature had fallen to 20oC. What conclusion may be made about delta H and delta S
Answer:
ΔH is positive, ΔS is positive
Explanation:
The enthalpy of reaction (ΔH) is positive in an endothermic reaction. An endothermic reaction leads to a decrease in temperature. Hence the fact that the temperature was decreased from 25oC to 20oC shows that the reaction is endothermic therefore ΔH is positive.
Also, the equation of the dissolution is;
NH4NO3(s) -----> NH4^+(aq) + NO3^-(aq)
This means that the number of particles in solution were increased. The entropy increases with increase in number of particles hence ΔS is positive.
A 2.5 M solution of a weak acid is prepared. Using a pH meter, the pH is measured to be 5.1. Calculate the acid ionization constant, [tex]K_{a}[/tex] , of this weak acid.
Show your work
Molarity of acid=2.5M
pH=5.1.
ka=?
Now
We need to write an eqn to show the dissociation of the acid
HA + H2O === H3O+ + A-
Writing The Equilibrium(Or Acid dissociation constant) of this reaction
Ka =[H3O+] {A-]/ {HA].
The concept behind this is
concentration of Products divided by those of reactants. Water is not written because its a pure liquid and does not affect the Equilibrium constant.
Now If you have any Idea on ICE tables..
You'd know that the concentration of acid will decrease by 2.5-x
Whilst the products...will increase by x each
Note: This is when the ratio of their Moles are in 1:1
ka= x.x/2.5-x
Since the Moles of A- and H3O+ are in 1:1... Their concentrations at equilibrium will be the same
so
Ka= x²/2.5-x
Now what is x??
x is the Hydrozonium ion concentration.
we can get it from the pH formula
pH= -log (H3O+)
Making H3O+ subject by applying Logarithm Rules
H3O+ = 10^-ph
x=10^-5.1
=7.94x10^-6.
Now back to Ka
Ka= x²/2.5-x
Ka= (7.94x10^-6)²/2.5-(7.94x10^-6)
Ka= (7.94x10^-6)²/2.4999
Ka= 2.52x10^-11.
Was a Fun One
The ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex]. The values can be substituted in dissociation formula.
What information do we have?
Molarity of acid=2.5M
pH=5.1
To find:
ka=?
Calculation of ionization constant:[tex]HA + H_2O < === > H_3O^+ + A^-[/tex]
The value of dissociation constant will be:
[tex]Ka =[H_3O^+] [A^-]/ {HA][/tex]
The Moles of A- and H3O+ are in 1:1.Their concentrations at equilibrium will be the same.
[tex]Ka= x.x/2.5-x\\\\Ka= x^2/2.5-x\\\\pH= -log (H_3O^+)\\\\H_3O^+ = 10^{-pH}\\\\x=10^{-5.1}\\\\x=7.94*10^{-6}[/tex]
[tex]Ka= x^2/2.5-x\\\\Ka= (7.94*10^{-6})^2/2.5-(7.94*10^{-6})\\\\Ka= (7.94*10^{-6})^2/2.4999\\\\Ka= 2.52*10^{-11}\\\\[/tex]
Thus, ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex].
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How many moles (of molecules or formula units) are in each sample?
0.2346 g C8H18
Express your answer to four significant figures.
nC8H18 =
How to do 3 and 4 questions
Answer:
3) Q = -836.8 J.
4) Q = 950J.
Explanation:
Hello there!
In this case, for those calorimetry problems, we use the general equation:
[tex]Q=mC\Delta T[/tex]
Thus, we proceed as follows:
3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(4.184\frac{J}{g\°C} )(40\°C-80\°C)\\\\Q=-836.8J[/tex]
4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(1.90\frac{J}{g\°C} )(200\°C-100\°C)\\\\Q=950J[/tex]
Regards!
NEED HELP ASAP
Question 7 (5 points)
(05.05 MC)
A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams of
methanol are produced when 7.0 grams of carbon monoxide reacts with excess hydrogen gas? (5 points)
20 grams
7.0 grams
8.0 grams
6.1 grams
Explanation:
Write the balance equation for the reaction taking place:
CO(g) + 2H2(g) ==> CH3OH ... balanced equation
Find the limiting reactant:
moles CO present = 14 g x 1 mol CO / 28 g = 0.5 moles COmoles H2 present = 1.5 g x 2 mol H2 / 2 g = 0.75 moles H2OBecause according to the balanced equation it takes 2 moles H2 for every 1 mole CO, there isn't enough H2, so it is limiting and will dictate how much CH3OH can be made.
Mass of CH3OH produced = 0.75 moles H2 x 1 mol CH3OH / 2 mol H2 x 32 g CH3OH / mol = 12 g CH3OH
What happens when an electron moves to a higher energy level?
A. It releases energy of a specific frequency
B. It gains energy in a quantized amount.
C. It loses energy in the form of light.
D. It absorbs photons of many energies
ANSWER: B. It gains energy in a quantized amount.
Answer:
B. It gains energy in a quantized amount.
Will give brainliest
If it is 9 am in San Francisco, is it also 9 am in New York? Why or why not?
Answer:
no
Explanation:
Becasue time zones, San Fransico is in the west while New York is in the north New York is 3 hours ahead of California
Which term below describes the study of how energy is transferred to
different locations and forms?
A. Thermodynamics
O B. Entropy
C. Enthalpy
D. Chemical reactions
You ran a mile on Monday. Then you ran another mile on Tuesday and your speed was faster. How would your time be different on Tuesday?
Answer:
your mile-time for tuesday would be shorter compared to your mile-time for monday
Explanation:
Answer: Your time on Tuesday would be different because your body has improved from a simple exercise on Monday, allowing your speed to increase; meaning your time will be much faster.
Explanation:
How many neutrons are in an atom of argon–40?
Answer:
22 neutrons
Explanation:
If so please sorry
A substance in a specific state of matter with volume of 6 liters was transferred to a 12 liter container. The substance took up the
A. It is highly compressible.
B. It also has a definite shape.
C.Its particles slide past one another
D. Its intermolecular forces are of high strength.
[tex]\huge\color{yellow}\boxed{Answer:}[/tex]
My answer is C.Its particles slide past one another
[tex]\huge\color{yellow}\boxed{toshiro hitsugaya}[/tex]
When the 6 liters volume of the substance takes up 12 liter container, we conclude that the substace is highly compressible.
What is compressibility?
Compressibility is the measure of the relative volume change of a solid or a fluid with respect to pressure change.
Gases are the most compressible susbtance because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.
Therefore, when the 6 liters volume of the substance takes up the entire volume of 12 liter container, we can conclude that the substace is highly compressible.
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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Which of the following statements is true?
Some plants cannot reproduce.
Pollen contains male sperm cells.
Mitosis results in two non-identical cells.
Flowering plants reproduce using spores.
Answer:
errccvbnnbb
Explanation:
jjuxxxsyy
Answer:
i think it the third one
Explanation:
sorry if im wrong are u in biology?
Name the following alkene:
CH3CH = CHCH2CH3
A. 3-pentane
B. 2-pentene
C. 2-pentane
D. 3-pentene
Answer:
2-pentene
Explanation:
The name of the alkene is 2 pentene. The correct option is B, 2-pentene.
What is 2-pentene?Alkenes with the chemical formula [tex]C_5H_10[/tex] are known as pentene. Within its molecular structure, each has one double bond.
The given alkene [tex]CH_3CH = CHCH_2CH_3[/tex] is 2-pentene because the double bond is present in the second carbon and it's pentene because there are five carbons present.
Thus, the correct option is B. 2-pentene.
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Identify the conjugate base in the equation below
CH3COOH + H2O - H30* + CH3COO-
O a. CH3COO
O b. H20
O c. H30+
O d. CH3COOH
Answer:
a. CH3COO⁻.
Explanation:
Hello there!
In this case, according to the given ionization reaction of acetic acid:
CH₃COOH + H₂O --> H₃O⁺ + CH₃COO⁻
Whereas we can evidence how the CH₃COOH is the acid whereas H₂O the base, as the former donates H ions to the latter, which accepts them; we can infer that H₃O⁺ is the conjugate acid, resulting from the base and the a. CH3COO⁻ is the conjugate base, resulting from the acid.
Best regards!
What piece of apparatus could be used to measure the volume of gas produced in a reaction
1)beaker
2)gas syringe
3) top pan balance
Answer: 2)gas syringe
Explanation:
the volume of a gas is usually measured with a gas syringe (or sometimes with an upside-down measuring cylinder)
Answer:
top pan balance
Explanation:
is a glow stick Endothermic or exothermic ?
Answer:
exothermic
Explanation:
Ionic bonds result from elements ____.
A. that share electrons
B. with high electronegativity differences
C. That form polar bonds
D. That are only nonmetals
Hey duckers
Pp poopoo everyday
Answer:
So when a cat puts up its middle finger its usually trying to scare you off.
Explanation:
it's gonna kill you.
how many cats are in the word
Answer: more than 70,00 and most of that population is living on the streets
The compound AlP (aluminum phosphide) is a compound semiconductor having mixed ionic and covalent bonding. Calculate the fraction of bonding that is ionic.
Answer:
0.086
Explanation:
The formula for calculating the fraction of a covalent bond can be expressed as:
= exp (-0.25ΔE²)
[tex]= exp[-0.25(E_{Al}-E_{p})^2]---(1)[/tex]
from the equation above;
[tex]E_{Al}[/tex] = the electronegativity of aluminum
[tex]E_P[/tex] = electronegativity of phosphorus
Using the data from periodic table figures;
[tex]E_{Al}[/tex] = 1.5
[tex]E_P[/tex] = 2.1
∴
fraction of the covalent = exp[-0.25(1.5 - 2.1)²]
fraction of the covalent = exp(-0.09)
fraction of the covalent = 0.914
Now, the fraction of ionic bond will be = 1 - the fraction of covalent bond
= 1 - 0.914
∴
the fraction of bond that is ionic = 0.086
12 points
Methyl methacrylate has a molar mass of 100 g/mole When a sample of methyl methacrylate weighing 3.14 g was completely combusted, the only products formed
were 6.91 g of CO2 and 2.26 g of water. What is methyl methacrylate's molecular formula?
O A C5H8O2
OBC6H120
OCC7H16
OD. None of the above
O E C4H403
Answer:
C₅H₈O₂
Explanation:
methyl methacrylate = 100 amu
6.91g CO₂ = 0.157 moles
2.26g H₂O = 0.125 moles
0.157 ÷ 0.125 = 1.256
{(CO₂)₁.₂₅₆ + (H₂O)₁} × 4 = (CO₂)₅ + (H₂O)₄
C₅H₈O?
C₅ = 60.05 amu H₈ = 8.064 amu
60.05 + 8.064 = 68.114 amu
100 amu - 68.114 amu = 31.886 amu
O = 16 amu
O = 2
The molecular formula of methyl methacrylate is C₅H₈O₂. The correct option is A, C₅H₈O₂.
What is methyl methacrylate?
Methyl methacrylate (MMA) is a colorless liquid monomer with a distinctive fruity odor. It is an organic compound that belongs to the family of acrylic esters.
We have to determine the empirical formula of methyl methacrylate first and then multiply it by the integer n to determine the molecular formula. Empirical formula:
CO₂ and H₂O are the combustion products of methyl methacrylate.
C₅H₈O₂ + (9n / 2)
O₂ → 5CO₂ + (n)H₂O
There are 5 C atoms and (8 + 2n), H atoms in the left and 5 C atoms, and n H atoms in the right.
5C = 5C, and 8 + 2n = nH.
n = 6
Molecular formula calculation is dividing the molecular weight by the empirical formula weight to determine the multiplication factor.
C₅HₙO₂ (empirical formula) has a weight of:
(5 x 12.011) + (8 x 1.008) + (2 x 15.999) = 100.12 g/mol
The actual molecular weight of methyl methacrylate is 100 g/mol.
Therefore, the molecular formula is (C₅H₈O₂) x 1, which is C₅H₈O₂, option A.
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When the ocean absorbs CO2, the pH of the ocean water drops. What's the
effect of this process?
A. The hydrogen ion concentration increases.
B. The amount of water in the ocean increases.
C. The hydroxide ion concentration increases.
O D. The balance of H+ and OH ions is the same.
SUBMIT
Answer:
the amount of water
in the ocean increases
Answer:
A. The hydrogen ion concentration increases.
Pbo.....
= 2Pb +......
Answer:
It's
Explanation:
Pbo + c
= pb + co2
While balancing it becomes
2pbo + c = 2pb + co2
(I was also doing same qn)
please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas will there be in a room after 1 hour of time has passed?
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -Assuming STP-. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
Volume Methane:
3600s * (0.25L / s) = 900L Methane
Moles methane:
PV = nRT; PV / RT = n
Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
Mass methane:
40.18 moles * (16g/mol) =
643g of methane will there be in the roomdescribes the oil-free paint manufacturing process
Answer:
which account for over 60% of total resin use in the USA. The main pigment was titanium dioxide and the major solvents aliphatic hydrocarbons
Explanation:
In the calculations it was assumed that:
a. Before any acetic acid was added, essentially all the indicator was in the In-form.
b. After the HCl was added, essentially all the indicator was in the HIn form.
Required:
Justify these assumptions using the measured pH of these solutions and your experimental value for pKHIn to determine:
1. The fraction of the indicator in the HIn form in solution B before any of solution A was added.
2. The fraction of the indicator in the In- form after the HCl was added.
Answer:
Following are the responses to the given points:
Explanation:
Form the above-given question, it indicates that the bromate ion green ionizes in water to form a green-blue solution, therefore the before adding the HCL it indicator was in anionic from hence it is written as In^{-} therefore the HCL is mixed which the anion is protonated to give HIN
which best describes the type of titration for the graph below? O strong acid titrated with a strong base
O strong base titrated with a strong acid
O weak acid titrated with a strong base
O weak base titrated with a strong acid
Answer:
B. strong base titration with a strong acid