what is the mass of of 3.20 X 10^23 particles of Co2?​

Answers

Answer 1

Answer:

Mass = 23.36 g

Explanation:

Given data:

Number of particles of CO₂ = 3.20 ×10²³

Mass of  CO₂ = ?

Solution:

1 mole contain 6.022×`10²³ particles,

3.20 ×10²³ particles  × 1 mol / 6.022×`10²³ particles

0.531 mol

Mass of CO₂:

Mass = number of moles × molar mass

Molar mass = 44 g/mol

Mass =  0.531 mol× 44 g/mol

Mass = 23.36 g


Related Questions

a student finishes an experiment and is left with three empty beakers that held liquids during the experiment .the best lab practice is to

Answers

Answer:

Rinse With distilled water

Which of the following statements best describes how metamorphic rock was formed?
A. Low temperature and low pressure may transform an igneous rock into a metamorphic rock with banded layers.

B. High temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.

C. Low temperature intense pressure may transform a sedimentary rock into a metamorphic rock with banded layers.

Answers

Answer:

High temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.  

Explanation:

A metamorphic rock is formed under high temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.

An igneous rock is often formed when molten magma erupts from the earth's crust. The molten magma is usually very hot but cools off with time to form a solid mass.

This rock that was first formed eventually gets transformed in the course of time as it is acted upon by high temperature and intense pressure which gradually transforms the igneous rock into a metamorphic rock with banded layers.

Learn more: https://brainly.com/question/19930528

Dry ice changes from a solid to a gas in a process known as A. Melting B. Freezing C.sublimation

Answers

Answer:

c

Explanation:

solid to gas directly

What is the molarity of a solution
made by dissolving 18.9 g of
ammonium nitrate (NH4NO3) in
enough water to make 855 mL of
solution?
Molar Mass N: 14.01 g/mol
Molar Mass H: 1.008 g/mol
Molar Mass O: 16.00 g/mol

Answers

Answer:

Molarity = 0.28 M

Explanation:

Given data:

Mass of NH₄NO₃ = 18.9 g

Volume of solution = 855 mL (855mL × 1 L/1000 mL = 0.855 L)

Molarity of solution = ?

Solution:

Number of moles of NH₄NO₃:

Number of moles = mass/molar mass

Number of moles = 18.9 g/ 80.043 g/mol

Number of moles = 0.24 mol

Molarity:

Molarity = number of moles of solute  / volume in L

Molarity = 0.24 mol /0.855 L

Molarity = 0.28 M

Answer:

0.28

Explanation:

:D

Once we use up all the nonrenewable Energy sources they cannot be replenished.
O True
O False

Answers

Answer:

true

Explanation:

it says none renewable so you can't reuse it

Answer:

false

Explanation:

becuase nonrenewable means it can not be replenished

Neeeeeeeedddddd hellllllllllppppppp

Answers

The answer is letter A

Calculate the maximum mass of aluminium which can be extracted from 10 kg of
aluminium oxide

2AlO3+ 3C ----->4Al + 3CO2

Answers

Answer:

Hrishikesh. bshjsjbd. jwjjja

BRAINLIEST!! PLZ HELP

Answers

Answer:

1.0 is Answer

Explanation:

May be this is helpful!

Please help: A 0.200 M NaOH solution was used to titrate a 18.25 mL HF
solution. The endpoint was reached after 31.20 mL of titrant
were added. Find the molar concentration of the original HF
solution.

Answers

The molar concentration of the original HF  solution : 0.342 M

Further explanation

Given

31.2 ml of 0.200 M NaOH

18.2 ml of HF

Required

The molar concentration of HF

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)

Titrant = NaOH(1)

Titrate = HF(2)

Input the value :

[tex]\tt 0.2\times 31.2\times 1=M_2\times 18.25\times 1\\\\M_2=0.342[/tex]

which term refers to the condition that exists when no over all change in concentration results from diffusion?

a. concentration
b. osmosis
c. equilibrium
d. randomness​

Answers

Answer:

a.cocentration es la respuesta

Balance the following equations

Al + Cl2 AlCl3
Ag2O + Be Ag + BeO
K + O2 K2O
CoP + NaBr CoBr3 + Na3P
Si + Hg2S SiS2 + Hg
Li + Ni3N2 Li3N + Ni
Ca + K3N --> Ca3N2 + K
SnS2 + F2 --> SnF4 + S

Answers

Answer:

Explanation:

2Al + 3Cl2 --> 2AlCl3

Ag2O + Be -----> 2Ag + BeO

4K + O2 ---> 2K2O

CoP  + 3NaBr ---> CoBr3 + Na3P

Si +  Hg2S ---> SiS2 + Hg

6Li + Ni3N2 --- > 2Li3N + 3Ni

3Ca + 2K3N  --> Ca3N2 + 6K

SnS2 + 2F2 --> SnF4 + 2S

PLEASE ANSWER QUICK! 50 POINTS!!!!
How does the structure of amino acids allow them to form a polypeptide?

Options:
A. Each amino acid has an amino group and a carboxyl group.
B. Each amino acid has a hydrogen atom and a carboxyl group.
C. Each amino acid has a carboxyl group and an R group.
D. Each amino acid has an R group and a hydrogen atom.

Answers

Answer:

A. Each amino acid has an amino group and a carboxyl group.

Answer:a

Explanation:

When can I use ideal gas law?

Answers

Answer:

The ideal gas law can be used in stoichiometry problems in which chemical reactions involve gases. Standard temperature and pressure (STP) are a useful set of benchmark conditions to compare other properties of gases. At STP, gases have a volume of 22.4 L per mole.

If a concentrated solution of acetic acid is 99.5 % HC 2 H 3 O 2 and has a density of 1.05 g/mL, what is the concentration of this acid in moles per litre?

Answers

The concentration of this acid in moles per litre : 17.41

Further explanation

Given

99.5% acetic acid

density=ρ=1.05 g/ml

Required

the concentration (mol/L)

Solution

99.5% dan density 1.05 g/ml (MW acetic acid = 60 g/mol)

[tex]\tt 99.5\%\times 1.05\dfrac{g}{ml}\times \dfrac{1000~ml}{L}=1044.75~g/L\\\\\dfrac{1044.75~g/L}{60~g/mol}=17.41~mol/L[/tex]


3. A 240 mL sample of argon gas at 270 K is cooled until the volume is 180 mL. What is the new temperature?

Answers

Answer:

202.5 K

Explanation:

Some metal chips with a total volume of 3.29 cm3 are placed on a piece of paper and weighed. The combined mass is found to be 18.43 g, and the paper itself weighs 1.2140 g. Calculate the density of the metal to the proper number of significant figures.​

Answers

Answer:

d = 5.23 g/cm³

Explanation:

Given data:

Volume of metal chips = 3.29 cm³

Mass of metal chips and paper = 18.43 g

Mass of paper = 1.2140 g

Density of metal = ?

Solution:

Mass of metal = combined mass - mass of paper

Mass of metal = 18.43 g - 1.2140 g

mass of metal = 17.22 g

Density:

d = mass/ volume

d = 17.22 g/ 3.29 cm³

d = 5.23 g/cm³

Explain Joule's law in your own words. pls help

Answers

Answer:

Joules first law is a law that expresses the relatioship between heat that is generated and the current flowing heat thats through a conductor. The second law says that internal energy is independent of volume and pressure, depending only on temperature!

Explanation:

17. Calculate the percent composition of B2Br6

Answers

Answer:

%composition of B₂ = 4.3%

%composition of Br₆ = 95.7%

Explanation:

Given data:

Percent composition of B₂Br₆ = ?

Solution:

Total mass of B₂Br₆ = 10.8×2 + 79.9×6 = 501 g/mol

%composition of B₂ = ( 21.6 g/ 501 g ) × 100

%composition of B₂ = 0.043 × 100

%composition of B₂ = 4.3%

%composition of Br₆ = ( 479.4 g/ 501 g ) × 100

%composition of Br₆ = 0.957 × 100

%composition of Br₆ = 95.7%

How does Cyanoacrylate compare to the elements that make it up?

Answers

Answer: The elements of the cyanoacrylate are different as compared to the main cyanoacrylate.

Explanation:

The cyanoacrylate is a adhesive water based substance. It is used for developing fingerprints by fuming method. It is the acrylic monomer which has property to develop into a plastic form after application another of its composition is the acrylic resin which imparts adhesiveness to the cyanoacrylate.

Uranium contains two isotopes, U-235 with an atomic mas of 235 g/mol, and u-238 with an atomic mass of 238g/mol. U-235 is needed
as a fuel in nuclear reactors. Until recently, the method used to separate U-235 from U-238 was by gas diffusion. Use U-235 as R1, and
U-238 as R2 and determine the rate of diffusion and which gas will diffuse faster.

⚪︎U-235 diffused 10.01 times faster than U-238
⚪︎U-235 diffused 1.01 times slower than U-238
⚪︎U-235 effused 2.01 times slower than U-238
⚪︎U-235 effused 1.01 times faster than U-238
⚪︎U-235 diffused 1.01 times faster than U-238

Answers

Answer:

the answer is in the image

Explanation:

A gas with a volume of 2 L at 25°C is placed into a container that is 4 L. What is the new temperature of the gas?

Answers

Given :

A gas with a volume of 2 L at 25°C is placed into a container that is 4 L.

To Find :

The new temperature of the gas.

Solution :

Since, their is no information regarding pressure. We will assume that pressure is constant.

Now, we know when at constant pressure, volume is directly proportional to volume.

[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\\dfrac{2}{4} = \dfrac{25 + 273 }{x}\\\\x = 2 \times ( 25 + 273 )\\\\x = 596\ K[/tex]

Therefore, the new temperature of the gas is 596 - 273 K = 323  K.

How many moles of nitrogen are in 9.82x10^23 formula units of nitrogen? Please show work!

Answers

Answer:

1.63 mols

Explanation:

to convert mols to formula unit, or formula unit to mols, u need the avagadros number which is 6.022*10^23 and the number of mols/formula units

so since the given is formula units, u just have to divide the number by 6.022*10^23 to get the amount of mols

9.82*10^23 / (6.022*10^23) = 1.63 mols

*be careful for sig figs

which of the two metal ions mg2+ and zn2+ is the most reactive why?​

Answers

Answer:

Mg2+

Explanation:

The most reactive ions from the given choices is the magnesium ion. This is because it is higher in the activity series of metals.

Zinc ion is below this specie in the activity series.

As a rule, ions above another on the activity series are generally more reactive than those below.

From any solution, magnesium ion will displace the zinc ion in such process.

The position of metallic ions determines their reactivity.

Wass, volume and density are all properties of
matter
3
weight.
formula

Answers

Is this a question?

Answer:

:)

Explanation:

They are all properties of Matter. weight and formula wouldn't make sense.

The total number of the elements above with 2 valence electron is ____.

Answers

Answer:

four elements

Explanation:

He = 1s²

Be = 1s² 2s²

C = 1s² 2s² 2p²

Mg = 1s² 2s² 2p⁶ 3s²

Si = 1s² 2s² 2p⁶ 3s² 3p²

Ca = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Valence electrons are those electrons which are present in outer most electronic shell.

He, Be, Mg, Ca these four elements have 2 valence electrons.

While Si and C have four valance electrons.

The total number of the elements above with 2 valence electron is four.

The electronic configurations of the elements are given:

He = 1s²

Be = 1s² 2s²

C = 1s² 2s² 2p²

Mg = 1s² 2s² 2p⁶ 3s²

Si = 1s² 2s² 2p⁶ 3s² 3p²

Ca = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Valence electrons are those electrons which are present in outer most electronic shell.

He, Be, Mg, Ca these four elements have 2 valence electrons.

Learn more:

brainly.com/question/16089134

A 0.200 M NaOH solution was used to titrate a 18.25 mL HE
solution. The endpoint was reached after 31.20 mL of titrant
were added. Find the molar concentration of the original HF
solution.

Answers

Answer:

M₂ = 0.34 M

Explanation:

Given data:

Molarity of NaOH =M₁ =  0.200 M

Volume of HF =V₂=  18.25 mL

Volume of NaOH added = V₁ = 31.20 mL

Molarity of HF solution = M₂ = ?

Solution:

M₁V₁  =  M₂V₂

by putting values,

0.200 M × 31.20 mL = M₂ × 18.25 mL

M₂ = 0.200 M × 31.20 mL /  18.25 mL

M₂ = 6.24 M.mL / 18.25 mL

M₂ = 0.34 M

does something that is hot have more thermal energy than something that’s cold?

Answers

Answer:

Yes it does because the atoms/molecules are moving faster than they are in a cold substance.

Explanation:

1. List the types of fronts found on this map

Answers

Answer:

Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom). ...

Warm Front. ...

Stationary Front. ...

Occluded Front.

____ NaBr + ____ Ca(OH)2 ___ CaBr2 + ____ NaOH

Answers

Answer:

2 NaBr + 1 Ca(OH)2 ---> 1 CaBr2 + 2 NaOH

Aluminum metal reacts with hydrochloric acid to produce solid aluminum chloride and hydrogen gas. how many moles of aluminum are needed to produce 1.2 moles of hydrogen gas?

Answers

Moles of Aluminum needed : 0.8

Further explanation

Given

1.2 moles H₂

Required

moles of aluminum

Solution

The reaction coefficient in a chemical equation shows the mole ratio of the components of the compounds involved in the reaction (reactants and products)

Reaction(balanced equation)

2Al + 6 HCl = 2AlCl₃ + 3H₂

From the equation, mol ratio of Al : H₂ = 2 : 3, so mol Al :

= 2/3 x mol H₂

= 2/3 x 1.2

= 0.8 moles

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