Answer:
[tex]F=6.67\times 10^{-11}\ N[/tex]
Explanation:
Given that,
The masses of two objects, m₁ = m₂ = 1 kg
The distance between masses, d = 1 m
We need to find the gravitational force between two masses. The force is given by the relation as follows :
[tex]F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N[/tex]
So, the force between two masses of 1 kg is [tex]6.67\times 10^{-11}\ N[/tex].
A 5 Kg bowling ball is thrown at a stationary 1.6 Kg bowling pin at 5 m/s. If the final velocity of the ball is 2.5 m/s. The final velicoty of the bowling pin is _____m/s.
Answer: hope this helps
Explanation:
If the final velocity of the ball is 2.5 m/s, the final velocity of the bowling pin is 7.8125 m/s.
What is principle of conservation of momentum?According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.
According to the principle of momentum conservation, total momentum of an system remains conserved.
Total initial momentum = total final momentum
5 kg × 5 m/s + 1.6 kg × 0 m/s = 5 kg × 2.5 m/s + 1.6 kg × v
1.6 kg × v = 5 kg × 5 m/s - 5 kg × 2.5 m/s
v = (5 kg /1.6 kg) (5 m/s - 2.5 m/s)
= 7.8125 m/s
Hence, If the final velocity of the ball is 2.5 m/s, the final velocity of the bowling pin is 7.8125 m/s.
Learn more about momentum here:
brainly.com/question/24030570
#SPJ5
A boat has a porthole window, of area 0.00849 m^2, 6.25 m below the surface. The density of sea water is 1027 kg/m^3. The air inside the boat is at 1 atm. What is the net force on the window?
Answer:
[tex]325.65\ \text{N}[/tex] outward.
Explanation:
[tex]\rho[/tex] = Density of water = [tex]1027\ \text{kg/m}^3[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
h = Height of the water = 6.25 m
A = Area of the window = [tex]0.00849\ \text{m}^2[/tex]
[tex]P_i[/tex] = Internal pressure of the boat = [tex]1\ \text{atm}=101325\ \text{Pa}[/tex]
Pressure by the water on the window
[tex]P=\rho gh\\\Rightarrow P=1027\times 9.81\times 6.25\\\Rightarrow P=62967.9375\ \text{Pa}[/tex]
Net pressure on the window
[tex]P_n=P-P_i=62967.9375-101325=-38357.0625\ \text{Pa}[/tex]
Force is given by
[tex]F=P_nA\\\Rightarrow F=-38357.0625\times 0.00849\\\Rightarrow F=-325.651460625\ \text{N}[/tex]
Net force on the window is [tex]325.65\ \text{N}[/tex] outward.
Answer: 534.6 N
Explanation:
This answer works for Acellus!
A force of 30 N is used to push a box along the floor a distance of 5 meters. How much workwas done
Answer:
the answer for how much work was done is 90
Work done to push a box is 150 J.
What is work?a force appearing upon an item to purpose a displacement.WORK = FORCE * DISPLACEMENTmechanical conservation of energy is the change in kinetic energy is equal to the work done.work energy theorem states that total energy change is equal to work done.
force= 30N
displacement= 5 meters.
work done= 30 * 5
⇒ 150 joule.
Learn more about work here:-https://brainly.com/question/2005046
#SPJ2
Georgia drops a brick from the top of an 80.0 m building. What is the velocity of the brick when it hits the ground?
Answer:
the velocity of the brick when it hits the ground is 39.60 m/s
Explanation:
Given;
height through which the ball is dropped, h = 80.0 m
the initial velocity of the brick, u = 0
The final velocity of the brick when it hits the ground is calculated as;
v² = u² + 2gh
v² = 0 + 2 x 9.8 x 80
v² = 1568
v = √1568
v = 39.60 m/s
Therefore, the velocity of the brick when it hits the ground is 39.60 m/s
Which guideline best reflects how private information should be protected when using social networks? All social media users are screened and safe to engage with. Protect your private information by setting your account to private and only adding people you actually know. Only share your passwords with close friends that you trust. It is safe to share personal information with companies on social networking sites.
Answer:
hescorrect i just took the test and that was the awnser
Explanation:
if u need i can give the other awnsers
Answer:
(A. 1.) Protect your private information by setting your account to private and only adding people you actually know.
Explanation:
7. The sketch shows a painter standing on a
scaffold that is supported by two ropes. The
person weighs 500 N and the force of each
rope is 400 N. Calculate the weight of the
scaffold.
Fr
Answer:
300NExplanation:
From the question
Weight of painter = 500N
Weight of scaffold = x
Weight of painter + weight of scaffold = 2* 400 (since they are supported by two ropes)
Substitute
500 + x = 2(400)
500+x = 800
x = 800-500
x = 300N
Hence the weight of the scaffold is 300N
What is the current if 4C of charge passes in 2 s?
Answer:
I hope 2 amperes of current passes
Describe the buoyant force acting on the Lucia before the torpedo attack.
Answer:
Explanation: positive
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfortunately, you have the density of mercury in units of kilogrammeter3 and the density of silicon in other units: 2.33 gramcentimeter3. You decide to convert the density of silicon into units of kilogrammeter3 to perform the comparison. By which combination of conversion factors will you multiply 2.33 gramcentimeter3 to perform the unit conversion?
Answer:
The fourth one
Explanation:
It's the only one to represent volume (cm³ vs. m³) and have kilograms in the denominator.
Have a wonderful weekend!
If we want to convert the density of the silicon from 2.33 gram/ centimeter3 to kilogram /meter3 unit we have to perform the operation
(1 kilogram/ 10³ grams) ×(1 centimeter/10⁻² meters)×(1 centimeter/10⁻² meters)×(1 centimeter/10⁻² meters)
Therefore the correct answer is option B.
What is density?
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem we have to convert the density of the silicon from 2.33 gram/ centimeter3 to kilogram /meter3 unit
1 kilograms = 1000 grams
1 meter = 100 cm
2.33 gram/ centimeter3 = 2.33×10 ⁻³kilogram / 10 ⁻⁶meter3 unit
= 2.33×10³kilogram / 10 ⁻⁶meter3 unit
Thus, the correct answer is option B.
Learn more about density from here,
brainly.com/question/15164682
#SPJ6
You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.
a)How long after it is launched does the walnut reach the ground?
b)How far does the walnut travel horizontally from launch point to landing point?
c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.
Answer:
a.3.51s
b.33.8m
c. 9.64,-22.9
Explanation:
(a) The time taken be "3.5083 sec".
(b) The distance will be "33.82 m".
(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".
Velocity and DirectionAccording to the question,
Speed, V₀x = 15 Cos (50.0°)
= 9.64 m/s
V₀y = 15 Sin (50.0°)
= 11.49 m/s
Vertical displacement = -20.0 m
(a) We know the relation between displacement, time and acceleration
→ y = vt + [tex]\frac{1}{2}[/tex]at²
By substituting the values,
→ -20.0 = 11.49 t - 4.9 t²
4.9 t² - 11.49 t - 20.0 = 0
t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]
= [tex]\frac{11.49 + 22.89}{9.8}[/tex]
= 3.5083 sec
(b) We know the formula,
Distance = Speed × Time
or,
→ X = 9.64 t
= 9.64 × 3.5083
= 33.82 m
(c) Again by using the above relation, we get
Vx = V₀x
= 9.64 m/s
Vy = V₀y - gt
By substituting the values,
= 11.49 - 9.8 × 3.5083
= 11.49 - 34.38
= -22.89 m/s
Thus the response above is correct.
Find out more information about velocity here:
https://brainly.com/question/2456181
A spring has a spring constant k = 20N/cm. What load is needed to produce an extension of 2.5cm?
ASAP please !
Answer:
50 N
Explanation:
We are given;
Spring constant; K = 20N/cm
Extension; Δx = 2.5 cm
We want to find the load which is the force. This is gotten from the equation;
F = k•Δx
F = 20 × 2.5
F = 50 N
Therefore the load needed is 50 N.
another A b c or d about the earth...
Answer:
B seismic wave
3. Why is static electricity not useful as a power
source?
A. Because electrons aren't transferred in bursts of
static electricity
B. Because all energy is released at once in static
electricity
C. Because static electricity is not a real form of
electricity
D. Because static electricity only occurs in lightning
Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.
When static electricity is discharged, such as in a spark or a sudden discharge of stored charge, it happens in a rapid and uncontrolled manner, resulting in a brief burst of energy rather than a steady and sustained flow.
Power sources typically require a continuous and controllable flow of electrical energy to be useful for various applications. Static electricity, in its nature, does not provide this continuous flow but instead releases energy in an instantaneous manner. Therefore, it is not suitable for most practical power needs and applications.
Option A is not correct because electrons can be transferred in bursts of static electricity. Option C is not correct because static electricity is a real form of electricity, even though it has unique characteristics. Option D is not correct because static electricity can occur in various circumstances, not just in lightning.
Therefore, Static electricity is not useful as a power source primarily because it releases all of its energy at once rather than providing a continuous and controlled flow of electrical energy. The correct answer is B.
To know more about static electricity:
https://brainly.com/question/30043326?referrer=searchResults
#SPJ6
Which green shape is the least reactive?
(Subjective is actually science)
Answer:
the green smiley face
Explanation:
its is farthest from the right
and as stated on the chart, the farther left, the more reactive
less stable=more reactive
more stable= less reactive
From base camp, a park ranger drives 27 meters at 32 degrees East of North, then 40 meters at 58 degrees West of North, and finally 39 meters directly West in an attempt to rescue a lost hiker.
Answer:
R = 73.34 m, θ = 37º North of West
Explanation:
In this exercise you are asked to find the distance traveled.
The best way to do this is with a Cartesian coordinate system, let's use a system where the x axis coincides with the West - East direction), to decompose the trajectories
First trajectory
distance d₁ = 27 m
Direction 32 East of North, this angle is measured from the vertical direction (y-axis)
cos 32 = y₁ / d₁
sin 32 = x₁ / d₁
y₁ = d₁ cos 32
x₁ = d₁ sin 32
y₁ = 27 cos 32 = 22.90 m
x₁ = 27 sin 32 = 14.31 m
second trajectories
distance d2 = 40 m
direction 58 West from North, the angle is measured with respect to the y axis, towards the negative side of the x axis
cos 58 = y₂ / d₂
sin 32 = x₂ / d₂
y₂ = d₂ cos58
x₂ = d₂ sin 58
y₂ = 40 cos 58 = 21.20 m
x₂ = 40 sin 58 = -33.92 m
The negative sign of the x coordinate is due to the fact that the displacement is towards the West (negative of the x axis)
third trajectory
distance d₃ = 39 m
West direction, negative part of x-axis
x₃ = - 39 m
the total distance is
= x₁ + x₂ + x₃
X_{total}l = 14.30 - 33.92 -39
X_{total}X_total = -58.6 m
Y_{total} = y₁ + y₂
Y_{total}= 22.90 + 21.20
Y_{total} = 44.1 m
we give the result in the form of module and angle
we use the Pythagorean theorem
R = [tex]\sqrt{X_{total}^2 + Y_{total}^2 }[/tex]
R =\sqrt58.6^2 + 44.1^2 }
R = 73.34 m
we use trigonometry
tan θ =
θ = tan⁻¹ \frac{ Y_{total} }{ X_{total} }
θ = tan⁻¹ \frac{ 44.1 }{ 58.6 } (44.1 / 58.6)
θ = -37º
this angle is in the second quadrant, given in the form of cardinal coordinates is
θ = 37º North of West
A book is sitting on the dashboard of a car that is stopped at a traffic light as the car starts to move forward the book slides backward off the dashboard what does the book actually do
Answer:
The book remained in its state of rest before the car started to move forward as no direct force acted on it.
Explanation:
According to Newton's first law of motion, a body will continue in its present state of rest, or if it is in motion, will continue to move with uniform speed in a straight line unless aced upon by an external force. This tendency of a body to remain in its state of reset or uniform motion in a straight line is known as inertia and is directly proportional to the mass of the body. The more massive a body, the more inertia it possesses. Thus Newton's first law is also known as the law of inertia.
Considering the case of the book on the dashboard of a stationary car which suddenly starts to move. While the car is stopped at the traffic light, the dashboard where the book sits and the book are both at rest. When the car begins to move forward, the dashboard moves forward with it. However as the book is not a part of the car, no force is directly acting on it, so the book so it stays at rest due to its inertia.
Therefore, as the car is moving forward, the stationary book appears to move backward from the reference point of the car, sliding off the dashboard.
A solid wooden cube, 30cm on each side can be totally submerged in water if it is pushed downward with a force of 54N. What is the density of the wood?
Answer:
the density of the wooden cube is 204.1 kg/m³
Explanation:
Given;
applied force, F = 54 N
length of each side of the solid wooden cube, L = 30 cm = 0.3 m
mass of the wooden cube is calculated as;
F = mg
m = F/g
m = 54/9.8
m = 5.51 kg
The volume of the wooden cube is calculated as;
V = L³
V = (0.3)³
V = 0.027 m³
The density of the wooden cube is calculated as;
ρ = m/V
ρ = (5.51 kg) / (0.027 m³)
ρ = 204.1 kg/m³
Therefore, the density of the wooden cube is 204.1 kg/m³
m/s
3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?
b. What is the velocity if the boat has traveled 50 m?
Answer:
a. Final velocity, V = 2.179 m/s.
b. Final velocity, V = 7.071 m/s.
Explanation:
Given the following data;
Acceleration = 0.500m/s²
a. To find the velocity of the boat after it has traveled 4.75 m
Since it started from rest, initial velocity is equal to 0m/s.
Now, we would use the third equation of motion to find the final velocity.
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.Substituting into the equation, we have;
[tex] V^{2} = 0^{2} + 2*0.500*4.75 [/tex]
[tex] V^{2} = 4.75 [/tex]
Taking the square root, we have;
[tex] V^{2} = \sqrt {4.75}[/tex]
Final velocity, V = 2.179 m/s.
b. To find the velocity if the boat has traveled 50 m.
[tex] V^{2} = 0^{2} + 2*0.500*50 [/tex]
[tex] V^{2} = 50 [/tex]
Taking the square root, we have;
[tex] V^{2} = \sqrt {50}[/tex]
Final velocity, V = 7.071 m/s.
how do you fix a broken foot
my sister is in literal tears and i dont have a phone and
our parents are out of the house rn
Robert hook used an early microscope to observed a cork sample. How did this help contribute to cell theory?
Answer:
Robert Hooke used an early microscope to observe a cork sample. How did this help contribute to cell theory? It helped to show that cells contain water. ... It helped to show that some cells are visible to the naked eye.
Explanation:
If your teacher checks if it was copied just put it in your on words
A man can row a boat at 4kmhr in still water. He rows the boat 2km upstream and 2 km back to his starting place in 2 hours. How fast is the stream flowing
Answer:
2.83km/hr
Explanation:
Let stream flowing at the rat x km/hr
In still water
Speed of boat=4km/hr
Upstream speed=4-x
Downstream speed=4+x
Total time=2 hr
Time=Distance/speed
According to question
[tex]\frac{2}{4+x}+\frac{2}{4-x}=2[/tex]
[tex]\frac{8-2x+8+2x}{(4+x)(4-x)}=2[/tex]
[tex]\frac{16}{4^2-x^2}=2[/tex]
Using the formula
[tex](a+b)(a-b)=a^2-b^2[/tex]
[tex]4^2-x^2=\frac{16}{2}[/tex]
[tex]16-x^2=8[/tex]
[tex]16-8=x^2[/tex]
[tex]8=x^2[/tex]
[tex]x=\sqrt{8}=2.83km/hr[/tex]
Hence, the stream is flowing at 2.83km/hr
which
In describing the motion of an object it is often helpful to identify a
allows you to describe its motion relative to that of another object.
O acceleration
O average velocity
O frame of reference
O speed
Need help ASAP
Thanks + BRAINLIST only for correct answer
1.Cell phones convert sound waves into______waves.
-light waves
-sound waves
-radio waves
2.Electromagnetic waves used in cell phone communications are called?
-microwave
-radio wave
-infrared
-all of the above
3.To send out a radio signal far and wide...it is called?
-broadcast
-casting
-antenna
Answer:
answer my question
Explanation:
How much force must be applied to a 4 kg to get it to accelerate at 3
m/s^2?
Answer:
12 g i think
Explanation:
brainliest pls
A weight of 4.0 N is used to extend a spring. The extension of the spring is 0.06 m. (i) Calculate the spring constant, k, of the spring.
(ii) State what measurements should be made to determine the extension of the spring produced by the 4.0 N weight.
Answer:
See explanation
Explanation:
Hookes law states that; the displacement due to a stretching force is directly proportional to the magnitude of the deforming force.
F = ke
F = deforming force
k = force constant
e = extention
k = F/e
k = 4N/0.06 m= 66.67 Nm^-1
To determine the extension of the spring produced by the 4.0 N weight
1) We measure the original length of the spring
2) We measure the length after hanging the 4 N mass
3) Subtract the new length from the original length to determine the extention.
Skater begins to spend with arms held out at shoulder height. The skater wants to match the speed of the spin to the beat of the music. How does the skater use knowledge of the conservation of momentum to do this?
Answer:
the moment of inertia with the arms extended is Io and when the arms are lowered the moment
I₀/I > 1 ⇒ w > w₀
Explanation:
The angular momentum is conserved if the external torques in the system are zero, this is achieved because the friction with the ice is very small,
L₀ = L_f
I₀ w₀ = I w
w =[tex]\frac{I_o}{I}[/tex] w₀
where we see that the angular velocity changes according to the relation of the angular moments, if we approximate the body as a cylinder with two point charges, weight of the arms
I₀ = I_cylinder + 2 m r²
where r is the distance from the center of mass of the arms to the axis of rotation, the moment of inertia of the cylinder does not change, therefore changing the distance of the arms changes the moment of inertia.
If we say that the moment of inertia with the arms extended is Io and when the arms are lowered the moment will be
I <I₀
I₀/I > 1 ⇒ w > w₀
therefore the angular velocity (rotations) must increase
in this way the skater can adjust his spin speed to the musician.
PLS ANSWER FAST WILL GIVE BRAINLY TIMED TEST
use the equation solving a= F divided by M
Also use metres per second squared [m/s2]
A loaded coal wagon with a total mass of 20, 000 kg is pushed by a force of 300,000 N. What was the wagon's acceleration?
how to make, and put out a fire in the SAFEST way.
Answer:
Surround the area of fire with water so the fire cant spread. And after, pour water on the fire. Always surround the fire first to stop it from spreading. When handling fire there are no specific "safe" ways but this is probably the best way to go orby fire estinguisher which is probably the easiest if you have one nearby which usually you should or do have.
I hope I helped. Pls mark brianliest if it helps. Bye, take care:)
A car traveling at 7.0m/s^2 accelerates uniformly at 2.5 m/s. Reach a speed of 12.0m/s.how long does it take for this acceleration to occur?
Answer:
2 sec
Explanation:
time taken = [tex]\frac{v-u}{a} = \frac{12-7}{2.5} = 2[/tex]
A raindrop falls from a cloud 100 m above the ground. Neglect air resistance. What is
the speed of the raindrop when it hits the ground? Is this a reasonable number? Explain.
Answer:
Explanation:
Use the kinematic equation
[tex]V^2=V^2_i+2a(x_f-x_i)[/tex]
The initial velocity was given from the word "falls." Acceleration due to gravity is 9.8 m/s^2.
[tex]V^2=0^2+200(9.8)[/tex]
[tex]V=\sqrt{1960} =44.27m/s[/tex]
A raindrop falls from a cloud 100 m above the ground. Neglect air resistance. The speed of the raindrop when it hits the ground would be 44.27 meters/ second.
What is mechanical energy?The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.
As given in the problem A raindrop falls from a cloud 100 m above the ground. Neglect air resistance, then we have to find out the speed of the raindrop when it hits the ground,
The speed of the raindrop = √(2gh)
=√(2*9.8*100)
=44.27 meters/seconds
Thus, if a raindrop falls from a cloud 100 m above the ground. Neglect air resistance. the speed of the raindrop when it hits the ground would be 44.27 meters/ second.
Learn more about mechanical energy from here, refer to the link;
brainly.com/question/12319302
#SPJ2