What is the electrical energy of a 750 W waffle iron that is used for 15 min *

Answers

Answer 1

Answer:

675 kj

Explanation:

Energy = power × time

Energy = 750 × 15min

Energy = 750× 15 × 60 sec

Energy = 675000 joules = 675 kilo joules


Related Questions

Can someone help me with this, please? I have the answer but I need help with why the answer is that :(

A block of mass m is placed against the inner wall of a hollow cylinder of radius R that rotates about a vertical axis with a constant angular velocity, ω, as shown above. In order for friction to prevent the mass from sliding down the wall, the coefficient of static friction, μ, between the mass and the wall must satisfy which of the following inequalities? (Ans: μ is greater than or equal to g/(w^2r)

Answers

Answer:

See explanation below

Explanation:

Recall that the force of static friction is the product of the coefficient of static friction between surface and object, times the force applied perpendicular to the surface.

In our case, that perpendicular force has magnitude equal to the centripetal acceleration times the mass m of the block. The centripetal acceleration is defined as the quotient between the square of the tangential velocity divided by the radius at which the rotating mass is located (in our case R).

In order to estimate the tangential velocity given the angular velocity ω, we simply multiply it by R:  

[tex]v_t=\omega\,R[/tex]

and therefore the force acting on the surface of the cylinder is:

[tex]F=m\,*\,a_c=m\,*\,\frac{v_t^2}{R} =m\,*\, \frac{\omega^2\,R^2}{R} =m\,*\,\omega^2\,*R[/tex]

The force of friction between the block and the inner wall of the hollow cylinder will then be:  [tex]f=\mu\, *\,m\,*\omega^2\,*\,R[/tex]

In order for this force of static friction to be able to prevent the mass to slide down due to gravity, we need that the friction force is at least equal to the gravitational force. That is:

[tex]f\geq F_g\\f\geq m\,*\,g\\\mu\,*\,m\,*\,\omega^2\,*\,R\geq m\,*\,g\\\mu\geq \frac{g}{\omega^2\,*\,R}[/tex]

The force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or greater than to the gravitational force.

The force of static friction is the product of the coefficient of static friction between surface,and force applied perpendicular to the surface.

 

The tangential velocity,

[tex]\bold {V_t = \omega R}[/tex]

So,  the force acting on the surface of the cylinder,

[tex]\bold {F= m\times a_c}\\\\\bold {F= m \times \dfrac {V_t^2 }{R}}\\\\\bold {F = m \times \dfrac {\omega ^2R2}{R}}}\\\\\bold {F = m \times \omega ^2 \times R}[/tex]

The force of friction between the block and the inner wall of the hollow cylinder,

[tex]\bold {F_f = \mu \times m \times \omega ^2 \times R}[/tex]

Therefore, the force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or grater than to the gravitational force.

To know more about static friction,

https://brainly.com/question/8790433

What are the two parts of the SCM
A. Sternal head, Lateral Head
B. Bilateral Head, Long Head
C. Sternal Head, Clavicular Head
helpp me please

Answers

Answer:

C. Sternal Head, Clavicular Head

write Newton's third low of motion and verify it with an experiment​

Answers

Answer:

to something in action there is always a equal and opposite reaction. Like if you bounce a bounce ball on the ground, it will bounce back.

Explanation:

find the kinetic energy of a 985 g bunny rabbit when running at 3.82 m/s. show work plz

Answers

Answer:

9.2m/s sir Thank me later

Answer:

Given

mass (m) =985 ☓ 0.001 , 0.985 kg

velocity (v) =3.82m/s

kinetic energy(k. e) =?

Form equation

[tex]k.e = \frac{1}{2} mv {}^{2} \\ = \frac{1}{2} \times 0.985 \times 3.82 {}^{2} \\ = 7.1868kj \\ kinetic \: enegy = 7.1868kj[/tex]

I hope this help

Calculate GPE, when height is 3m, gfs is 9.8n/kg and mass 10kg.

Answers

Answer:

The gravitational potential energy (GPE) of the object is 294 J.

Explanation:

Given;

height of object, h = 3 m

mass of the object, m = 10 kg

acceleration due to gravity, g = 9.8 m/s²

The gravitational potential energy (GPE) of the object is calculated as follows;

GPE = mgh

substitute the given values and solve for GPE

GPE = 10 x 9.8 x 3

GPE = 294 J

Therefore, the gravitational potential energy (GPE) of the object is 294 J.

If each contour line represents 50 meters, what is a reasonable height of the mountain peak in the topographic map? Record your answer and fill in the bubbles on your answer document. Be sure to use the correct

Answers

Answer:

Explanation:

Answer: None of the above I got it right on my test

A day-care center has a merry-go-round that consists of a uniform 240-kg circular wooden platform 4.00m in diameter. Four children run alongside the merry-go-round and push tangentially along the platform’s circumference until, starting from rest, the merry-go-round is spinning at a rate of 2.14 rev/minute. During the spin-up:

a) If each child exerts a sustained force of 26N, how far does each child run?
b) What is the angular acceleration of the merry-go-round?
SHOW ALL WORK AND STEPS PLEASE.

Answers

Answer:

a) The distance each child ran is approximately 0.232 m

b) The angular acceleration is 0.21[tex]\overline 6[/tex] rad/s²

Explanation:

The given parameters of the merry-go-round are;

The mass of the merry-go-round, m = 240-kg

The diameter of the merry-go-round, d = 4.00 m

The number of children pushing tangentially on the merry-go round = Four children

The spinning rate of the merry-go-round, n = 2.14 rev/minute

a) Given that the force exerted by each child = 26 N, we have;

The total force applied by the four children, F = 26 N × 4 = 104 N

The tangential acceleration, [tex]a_t[/tex] = F/m = 104 N/240-kg = 0.4[tex]\overline 3[/tex] m/s²

The angular acceleration, α = [tex]a_t[/tex]/r

Where, the radius of the merry-go-round, r = d/2

∴ r = 4.00 m/2 = 2.00 m

α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²

We have;

ω² = ω₀² + 2·α·Δθ

The merry-go-round starts from rest, therefore; ω₀ = 0 rad/s

ω² = 2·α·Δθ

Δθ = ω²/(2·α)

n = 2.14 rev/minute

∴ ω = 2·π×2.14/60 rad/s ≈ 0.22410 rad/s

∴ Δθ = (0.22410 rad/s)²/(2 × 0.21[tex]\overline 6[/tex] rad/s²) ≈ 0.11589 rad

Therefore, the angle each child ran, θ = 0.11589 rad

The distance each child ran = r·θ

∴ The distance each child ran = 2.00 m × 0.11589 rad ≈ 0.232 m

b) From part 'a' above, the tangential acceleration, [tex]a_t[/tex] = 0.4[tex]\overline 3[/tex] m/s²

Angular acceleration, α = [tex]a_t[/tex]/r

∴ α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²

The angular acceleration = 0.21[tex]\overline 6[/tex] rad/s²

Hydrogeneous Sediment include_____.

A) granite
B) evaporative salts
C) igneous rocks
D) metamorphic rocks

Answers

the answer is B :). i need 20 words so sjd jdbd skms

Which state helps produce light in fluorescent lightbulbs?

A.
Solid

B.
Plasma

C.
Gas

D.
Liquid

Answers

The Answer Second one , Plasma
The answer is B: plasma

What is the density of the material in g/cm³

Answers

Thus 1 cm–3 = 1/cm3 and the units for our densities could be written as gcm3, g/cm3, or g cm–3. In each case the units are read as grams per cubic centimeter, the per indicating division.) We often abbreviate "cm3" as "cc", and 1 cm3 = 1 mL exactly by definition.

...

1.9: Density.

The weight of an object is the effect of the gravitational pull on the object. Weight is calculated by multiplying mass of the object by the force of gravitational pull acting on it. A man weigh 120 N on earth. What will be his weight on the Moon, which has a gravity 1/6 of the gravity of Earth?​

Answers

Answer:

20N

Explanation:

mass=weight/gravitational pull

mass=120/10

mass=12Kg

weight=mass×gravitational pull

=12× (⅙of 10)

=12×1.666666666667

=20N

can someone help me please?

Answers

Answer:

is this math of science

Explanation:

Finish the sentence
Newton’s 3rd law states that for every force there is an _____________________
Forces always occur in ________
Whenever one object exerts a force on a second object, the second object always exerts a force __________ back on the first object.

Answers

Answer:

1. Equal and opposite reaction

2. Pairs

3. That is equal

Explanation:

I have tried my best but without knowing your curriculum or the possible answers it is difficult to know exactly what the answer would be... :(

Please mark as branliest ;)

- Hope this helped!

2. The frequency of the vibrating body decreases by increasing the periodic time.​

Answers

Answer:

True

Explanation:

When the periodic time increases the frequency is lower.

23. How does the microwave appliance work?

Answers

Answer: The microwaves are reflected within the metal interior of the oven where they are absorbed by food. Microwaves cause water molecules in food to vibrate, producing heat that cooks the food.

Explanation:

Why is food considered “potential energy” even though it does not have mass suspended in air?

Answers

Answer:

Food is potential energy because as our bodies digest it then the stored energy will turn into energy that helps us to move and grow

Explanation:

i hope this helps

Food contains chemical potential energy as our bodies digest it, the stored energy is converted into energy for us to move and grow.

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s east. Find the velocity of the tennis racket after the collision.

Answers

The velocity of the tennis racket after the collision 14.966 m/s.

Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of tennis racket = 0.311 kg
m₂ = mass of the ball = 0.057 kg
u₁ = velocity of tennis racket before collision = 30.3 m/s
u₂ = velocity of the ball before collision = -19.2 m/s
v₁ = velocity of tennis racket after collision
v₂ = velocity of the ball after collision
Right (+) , Left (-)
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)
= 14.966 m/s.
So, the velocity of the tennis racket after the collision 14.966 m/s.

Paul turns up the volume on his TV. The TV sends an electrical signal to the speakers. The signal changes the sound's

Answers

Answer:

increases its amplitude.

Explanation:

. Draw a Cartesian coordinate system on a sheet of paper. On this Cartesian coordinate system, draw each vector to scale, starting at the origin. (a) Dd > 5 8.0 cm [S 15° E] (b) Dd > 5 5.7 cm [N 35° W] (c) Dd > 5 4.2 cm [N 18° E]

Answers

Answer:

a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis

b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction

c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis

Explanation:

For this exercise we draw a Cartesian coordinate system in this system: East coincides with the positive part of the x-axis and North with the positive part of the y-axis.

a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis

b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction

c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis

In the attachment we can see the representation of the three vectors

A 60 kg skateboarder accelerates themselves at 1.5m/s2. How much force was required to do this?

Answers

Answer:

90 N

Explanation:

m = 60 kg

a = 1.5 m/s^2

F = m × a = 1.5 × 60 = 90 N

What’s the quotient in 80.64 ÷ 3.6

Answers

Answer:

30 30 30 yuhhhhhhhhhhhh

If an object can make 10 revolutions in two minutes, what’s it’s period?

Answers

Answer:

the answer is 12 second easy

A 18 g ball is swung at a 1m long string.It revolves every 1 s,what is the magnitude of swing's tension?

Answers

Answer:

The magnitude of swing's tension is 0.71 N.

Explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

[tex]\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s[/tex]

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π  m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

[tex]F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N[/tex]

Therefore, the magnitude of swing's tension is 0.71 N.

Why does an ice cube melt in your hand? Question 3 options: The ice remains in a solid state even though heat is applied The temperature of the ice is greater than the temperature of your hand Sound energy creates vibrations which make the ice melt Heat is transferred from your hand to the ice making it melt

Answers

Answer:

3rd choice

Explanation:

heat is transfered causing it to melt

Answer:

C

Explanation:

what is the meaning of SMTWTFS​

Answers

Answer:

um Saturday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday?

Explanation:

How does the euglena differ from the paramecium? Question 20 options: Euglena are photosynthetic. Paramecia use flagella to move. Paramecia have an "eye spot" to detect light. Euglena have both a macronucleus and a micronucleus

Answers

Answer: Euglena are photosynthetic

Explanation: USA test prep

Observa a tu alrededor y escribe el nombre de diez objetos que se encuentren en movimiento, Luego escribe el de otros diez que pienses que se encuentran en reposo. ¿Qué criterio tuviste en cuenta para considerar que están en reposo?

Answers

Answer:

Objetos que se encuentran en movimiento:

1) Un automóvil pasando por la calle.

2) Una crustácea que se acerca a mi casa.

3) Un avión volando en el cielo.

4) Un repartidor de comida desplazándose en una bicicleta.

5) Las aspas del ventilador en rotación.

6) Una hojarasca afuera de la casa.

7) La puerta de mi habitación abrirse.

8) Un mosquito entrando por la ventana.

9) Un metrónomo en movimiento.

10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.

Objetos que se encuentran en reposo:

1) El semáforo de la esquina.

2) El automóvil de mi madre.

3) Las sillas del comedor.

4) Un jarrón de porcelana.

5) La nevera de la cocina.

6) La mesa de noche de mi habitación.

7) El automóvil de policía en la calle.

8) La impresora de memes.

9) El estante de libros.

10) El cesto de galletas.

Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:

(i) Traslación.

(ii) Rotación.

(iii) Deformación.

Explanation:

Objetos que se encuentran en movimiento:

1) Un automóvil pasando por la calle.

2) Una crustácea que se acerca a mi casa.

3) Un avión volando en el cielo.

4) Un repartidor de comida desplazándose en una bicicleta.

5) Las aspas del ventilador en rotación.

6) Una hojarasca afuera de la casa.

7) La puerta de mi habitación abrirse.

8) Un mosquito entrando por la ventana.

9) Un metrónomo en movimiento.

10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.

Objetos que se encuentran en reposo:

1) El semáforo de la esquina.

2) El automóvil de mi madre.

3) Las sillas del comedor.

4) Un jarrón de porcelana.

5) La nevera de la cocina.

6) La mesa de noche de mi habitación.

7) El automóvil de policía en la calle.

8) La impresora de memes.

9) El estante de libros.

10) El cesto de galletas.

Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:

(i) Traslación.

(ii) Rotación.

(iii) Deformación.

A convex mirror is used in automobiles to have a Clear View of the traffic behind? give reason​

Answers

Answer:

Explanation:

A convex mirror is used in automobiles to have a Clear View of the traffic behind because they give an erect, virtual, full size diminished image of distant objects with a wider field of view.

hope it helps :)

Which of the following is not a vector
A) Acceleration
B) Length
C) Velocity
D) Force

Answers

Length is not a vector because you only need to state a unit (etc. meters, centimetres, or feet) and not a direction
The answer is b length

Which acids are found in acid precipitation?

Answers

understand friend

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