What is the distance from P to Q? A. 25 units B. 7 units O C. 5 units D. 1 unit​

Answer:

A= -8

Step-by-step explanation:

Subtract 5a from both sides.

Combine 4a and −5a to get −a.

Add 7 to both sides.

Finally, Multiply both sides by −1.

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Answer:

a = -8

Step-by-step explanation:

4a - 7 = 5a + 1

subtract 1 from both sides of the equation

4a - 7 - 1 = 5a + 1 - 1

4a - 7 - 1 = 5a

4a - 8 = 5a

subtract 4a from both sides of the equation

4a - 4a - 8 = 5a - 4a

-8 = 5a - 4a

-8 = 1a

-8 = a

Answer: Slope: 2/3

y-intercept: 9

Step-by-step explanation:

The value of midpoint of AC will be 0.5.

Number line is a horizontal line where numbers are marked at equal intervals one after another form smaller to greater.

Given that;

Point A is at - 2 and C is at 3 on the number line.

Now,

Since, Point A is at - 2 and C is at 3 on the number line.

Hence, The midpoint of AC = (- 2 + 3 ) / 2

                                           = 1/2

                                           = 0.5

Thus, The midpoint of AC = 0.5

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Answer:

Sarah: £15

Fiona: £15

David: £10

Step-by-step explanation:

3 + 3 + 2 = 8

40 ÷ 8 = 5

3 × 5 = 15

3 × 5 = 15

2 × 5 = 10

Answer:

3+3+3+3

Step-by-step explanation:

it's ans is 3+3+3

Answer:

I think the answer is D.

sorry if I'm wrong..

A≈116.06,  the area of the triangle.

In geometry, an isosceles triangle is a triangle that has two sides of equal length. Sometimes it is specified as having exactly two sides of equal length, and sometimes as having at least two sides of equal length, the latter version thus including the equilateral triangle as a special case.

Area: ½ × base × height

here, we have,

the side= 18, 18

base = 14

here, it is a isosceles triangle.

So, using the formula ,

we get,

area= 116.06

hence, A≈116.06,  the area of the triangle.

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Answer:

$3573. 64

Step-by-step explanation:

Convert 11.25% to the decimal fraction 0.1125.  Then subtract this result from 1.0000:  0.8875.

After 14 years, the formerly $19000 car will have the value

$19000(0.8875)^14 = $3573. 64

Answer:

$66.60

Step-by-step explanation:

Find out how much money Jerome earns from the 1.8% interest.

100% = 3700

1% = 3700 ÷ 100 = 37

1.8% = 37 x 1.8 = 66.60

(Final answer)

Answer:

4 2/3!

Step-by-step explanation:

Answer: [tex]4 \frac{2}{3}[/tex]

Step-by-step explanation:

Lets start by subtracting 6 by 1.

                  6 - 1 = 5

Now we need to subtract 1/3 by 2/3. Which means we will need to take one from the 5 and add it to the 1/3. So we get [tex]1 \frac{1}{3}[/tex]. Now we subtract 1 1/3 by 2/3. The answer to that is 2/3.

So our answer is 4 2/3

Answer:

y minus 8 + 2 less-than-or-equal-to negative 2 + 2

Step-by-step explanation:

Which inequality is equivalent to this one?

y minus 8 less-than-or-equal-to negative 2

y minus 8 + 8 greater-than-or-equal-to negative 2 + 8

y minus 8 + 8 less-than negative 2 + 8

y minus 8 + 2 less-than-or-equal-to negative 2 + 8

y minus 8 + 2 less-than-or-equal-to negative 2 + 2

Take the last option:

y minus 8 + 2 less-than-or-equal-to negative 2 + 2

remove the +2 on each side to get

y minus 8 less-than-or-equal-to negative 2

Answer:

R= {7, 11, 15}

Step-by-step explanation:

Since we already know what the Domain is for f (2, 4, 6) we can use that to get the range

Since the domain is also x let's replace x for 2

y=2(2)+3= 4+3=7

One of the range is 7

Replace x for 4

y=2(4)+3= 8+3= 11

One of the other range is 11

Replace x for 6

y= 2(6)+3= 12+3= 15

The last range is 15

So the range is R= {7, 11, 15}

Answer: Jireh flew his crop duster from the ground to an altitude of 3,500 feet.

Step-by-step explanation:

That is an example of an increasing interval.

Answer:

a

Step-by-step explanation:

Answer:

[tex]\frac{1-\tan x }{1+\cot x}[/tex]

Step-by-step explanation:

Let [tex]\frac{\sin 2x+\cos 2x-1}{\sin 2x+\cos 2x + 1}[/tex], we proceed to prove the given identity by trigonometric and algebraic means:

1) [tex]\frac{\sin 2x+\cos 2x-1}{\sin 2x+\cos 2x + 1}[/tex] Given

2) [tex]\frac{2\cdot \sin x \cdot \cos x +\cos ^{2}x - \sin^{2}x-1}{2\cdot \sin x \cdot \cos x +\cos ^{2}x - \sin^{2}x+1}[/tex] [tex]\sin 2x = 2\cdot \sin x \cdot \cos x[/tex]/[tex]\cos 2x = \cos^{2}x - \sin^{2}x[/tex]

3) [tex]\frac{2\cdot \sin x \cdot \cos x -\sin^{2}x-(1-\cos^{2}x)}{2\cdot \sin x\cdot \cos x +\cos^{2}x+(1-\sin^{2}x)}[/tex] Commutative, associative and distributive properties/[tex]-a = (-1)\cdot a[/tex]

4) [tex]\frac{2\cdot \sin x \cdot \cos x -2\cdot \sin^{2}x}{2\cdot \sin x \cdot \cos x +2\cdot \cos^{2}x}[/tex] [tex]\sin^{2}x + \cos^{2}x = 1[/tex]

5) [tex]\frac{(2\cdot \sin x)\cdot (\cos x-\sin x)}{(2\cdot \cos x)\cdot (\sin x +\cos x)}[/tex] Distributive and associative properties.

6) [tex]\frac{\sin x\cdot (\cos x-\sin x)}{\cos x\cdot (\sin x +\cos x)}[/tex] Existence of multiplicative inverse/Commutative and modulative properties.

7) [tex]\frac{\frac{\cos x -\sin x}{\cos x} }{\frac{\sin x + \cos x}{\sin x} }[/tex] [tex]\frac{\frac{x}{y} }{\frac{w}{z} } = \frac{x\cdot z}{y\cdot w}[/tex]

8) [tex]\frac{\frac{\cos x}{\cos x}-\frac{\sin x}{\cos x} }{\frac{\sin x}{\sin x}+\frac{\cos x}{\sin x} }[/tex] [tex]\frac{x+y}{w} = \frac{x}{w} + \frac{y}{w}[/tex]

9) [tex]\frac{1-\tan x }{1+\cot x}[/tex] Existence of multiplicative inverse/[tex]\tan x = \frac{\sin x}{\cos x}[/tex]/[tex]\cot x = \frac{\cos x}{\sin x}[/tex]/Result

the hypotenuse is equal to twice the length of the shorter leg, which is the side across from the 30 degree angle. the longer leg, which is across from the 60 degree angle, is equal to multiplying the shorter leg by the square root of 3. so quite basically, hypotenuse = short leg square root, long leg = short leg squared :3 ( ex: short leg is 2 , 2^2 = 4, 2^3= 6 )

Answer:

39

Step-by-step explanation:

9514 1404 393

Answer:

  solve for f(n) in terms of f(n-1)

Step-by-step explanation:

In general, you solve for f(n) in terms of f(n-k) for k = 1, 2, 3, ....

__

Usually, such questions arise in the context of arithmetic or geometric sequences.

Arithmetic sequence

The explicit formula for an arithmetic sequence has the general form ...

  a(n) = a(1) +d(n -1) . . . . . . . first term a(1); common difference d

The recursive formula for the same arithmetic sequence will look like ...

  a(1) = a(1) . . . . . . . the first term is the first term

  a(n) = a(n-1) +d . . . the successive terms are found by adding the common difference to the term before

__

Note: The explicit formula may be given as the linear equation a(n) = dn +b. Then the first term is a(1) = d+b.

__

Geometric sequence

The explicit formula of a geometric sequence has the general form ...

  a(n) = a(1)·r^(n -1) . . . . . . first term a(1); common ratio r

The recursive formula for the same geometric sequence will be ...

  a(1) = a(1) . . . . . . the first term is the first term

  a(n) = a(n-1)·r . . . the successive terms are found by multiplying the term before by the common ratio

__

Note: The explicit formula may be given as the exponential equation a(n) = k·r^n. Then the first term is a(1) = kr.

__

Other sequences

Suppose you're given the quadratic sequence ...

  a(n) = pn^2 +qn +r

Since the sequence is known to be quadratic (polynomial degree 2), we expect that we will only need the two previous terms a(n-1) and a(n-2). Effectively, we want to solve ...

  a(n) = c·a(n-1) +d·a(n-2) +e

for the values c, d, and e. Doing that, we find ...

  (c, d, e) = (2, -1, 2p)

So, the recursive relation is ...

  a(1) = p +q +r

  a(2) = 4p +2q +r

  a(n) = 2a(n-1) -a(n-2) +2p

__

Additional comment

The basic idea is to write the expression for a(n) in terms of terms a(n-1), a(n-2) and so on. That will be easier for polynomial sequences than for sequences of arbitrary form.

There are some known translations between explicit and recursive formulas for different kinds of sequences, as we have shown above. If you recognize the sequence you have as being of a form with a known translation, then you would make use of that known translation. (For example, Fibonacci-like sequences are originally defined as recursive, but have explicit formulas of a somewhat complicated nature. If you recognize the form, translation from the explicit formula may be easy. If you must derive the recursive relation from the explicit formula, you may be in for a lot of work.)

Answer:

C.41

Step-by-step explanation:

Thats the answer!!

Answer:Each step in this pattern increases by on block

Step-by-step explanation:

1-1 block

1-2 block

3-3

4-4

Answer:

x=5

Step-by-step explanation:

2x-3(3x-11)= -2

2x-9x+33= -2

-7x-33= -2

-7x= -33-2

-7x= -35

÷ -7= ÷ -7

x= 5

Answer:

Volume of the Tetrahedron T =[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = [tex]\frac{2}{4} = \frac{1}{2}[/tex] = 0.5

⇒x = 2([tex]\frac{1}{2}[/tex]) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = [tex]\frac{x}{2}[/tex]

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - [tex]\frac{x}{2}[/tex]

∴ The limits of y are :

[tex]\frac{x}{2}[/tex] ≤ y ≤ 1 - [tex]\frac{x}{2}[/tex]

So, we get

Volume = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \, \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \, \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx[/tex]

             = [tex]\int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2}) -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2} + (\frac{x}{2} )^{2} ] {} \, \, dx[/tex]

             = [tex]\int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx[/tex]

             = [tex]{(x - x^{2} + \frac{x^{3}}{3} )}\limits^1_0[/tex]

             = 1 - 1² + [tex]\frac{1^{3} }{3}[/tex] - 0 + 0 - 0

             = 1 - 1 + [tex]\frac{1 }{3}[/tex] =  [tex]\frac{1}{3}[/tex]

So, we get

Volume =[tex]\frac{1}{3}[/tex]

The volume of Tetrahedron will be [tex]\frac{1}{3}[/tex] units.

Given,

The tetrahedron T is bounded by the planes,

[tex]x+2y+z=2......(1)\\ x=2y....(2)\\ x=0......(3) \\ z=0.....(4)[/tex]

From equation (1),

[tex]z=2-x-2y[/tex]

So the limits of z will be from 0 to [tex]2-x-2y[/tex].

Now, from equation (2),

[tex]y=\frac{x}{2}[/tex]

and from equation (1), putting z=0 we get,

[tex]x+2y=2\\y=1-\frac{x}{2}[/tex]

So the limits of y will be from [tex]\frac{x}{2}[/tex] to [tex]1-\frac{x}{2}[/tex].

On solving equation (1), for x we get

[tex]x+x+0=2[/tex] [tex](x=2y \ and \ z=0 )[/tex]

[tex]x=1[/tex].

So the limits of x will be from 0 to 1.

The volume of tetrahedron will be,

[tex]V=\int\limits^1_0 \, dx \int\limits^{1-\frac{x}{2} }_{\frac{x}{2} } \, dy \int\limits^{2-x-2y}_0 \, dz[/tex]

[tex]V=\int\limits^1_0 \, dx \int\limits^{1-\frac{x}{2} }_{\frac{x}{2} } \, dy [2-x-2y-0][/tex]

[tex]V=\int\limits^1_0 \, dx (1-2x+x^2)\\[/tex]

[tex]V=1-1+\frac{1}{3}[/tex]

[tex]V=\dfrac{1}{3}[/tex]

Hence the volume of tetrahedron is [tex]\frac{1}{3}[/tex] units.

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Answer:

y = c

Step-by-step explanation:

A line with a gradient of 0 is a horizontal line, parallel to the x- axis

Its equation is y = c

where c is the value of the y- coordinates the line passes through.

Answer: 4.8lbs, This claim is false

Step-by-step explanation:

Leo weighs 192 pounds. Then Leo's heart weight will be 76.258 ounces. So, its claim is false.

A ratio is a group of sequentially ordered numbers a and b expressed as a/b, where b is never equal to zero. When two objects are equal, a statement is said to be proportional.

Hummingbirds have abnormally huge hearts for their body size. In the event that an individual's heart was essentially as large as a hummingbird's, their heart would weigh as much as an enormous canine's. A typical hummingbird weighs 0.3524 ounces and has a heart that weighs 0.00875 ounces.

The ratio of heart to weight is given as,

Ratio = 0.00875 / 0.3524

Ratio = 0.024829

The average weight of a large dog is usually more than 80 pounds. Leo weighs 192 pounds. Then Leo's heart weight is calculated as,

⇒ 0.024829 x 192 x 16

⇒ 76.28 ounces

Their heart weight of Leo is less than the weight of the dog. So, its claim is false.

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Answer:

it has no pic

Step-by-step explanation:

Answer: 6,-6

Step-by-step explanation:

Because when you add the same number and one of them is a negative it will always be a zero. For example: (-2+2)= 0

I'm sorry if this didn't help.

Answer:

So it depreciates at a rate of 1.4% so 25% a year and you do £2700 multiply by 25 each year £2700 multiply by 25 x 5 = £540 in 5 years

Step-by-step explanation:

Answer:

£

2516.22

Step-by-step explanation:

£

2516.22

Answer:

45°

Step-by-step explanation:

If sum of two angles is 90° , then they are called complementary angles.

Complement of 45 = 90 - 45 = 45