What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?

Answers

Answer 1

Answer:

Explanation:

The centripetal acceleration:

aₙ = F /m = 125 /19 ≈ 6.6 m/s²


Related Questions

calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s​

Answers

The braking distance traveled by the car is 73.5 m.

What is the braking distance of the car?

The braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s​ at a deceleration rate of 3 m/s² is calculated as follows.

v² = u² - 2as

where;

v is the final velocity of the car, when it stops = 0u is the initial velocity of the car = 21 m/sa is the deceleration of the car = 3 m/s²s is the braking distance of the car

Substitute the given parameters and solve for the braking distance of the car as shown below.

0 = u² - 2as

2as = u²

s = (u²) / (2a)

s = (21²) / (2 x 3)

s = 73.5 m

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The complete question is below:

calculate the braking distance traveled as the speed of the car is reduced from 21 m/s to 0m/s​, when the car is decelerating at 3 m/s².

A body of ma 50kg ret on a plane inclined at 60 degree to the horizontal calculate the force that keep it from liding down the plane

Answers

250N is the friction force that keep body from sliding down the plane of inclination of 60 degrees.

What is friction force ?

Friction force is the force which resists the relative motion of the body or object in motion.

Solution:

Given :

Mass = 50kg

inclination = 60 degree

normal force acting on body =

F=mg

F=50*10

F=500N

Now the friction force which stops it from sliding is ;

Friction= FcosФ

Friction=500*cos 60

Friction=500*0.5

Friction=250N

Hence, 250N is the friction force that keep body from sliding down the plane of inclination of 60 degrees.

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a block of mass 100kg falls down a waterfall. the waterfall is 5m high. calculate: a) the potential energy of the block at the top of the waterfall. b) the kinetic energy of the block at the bottom of the waterfall. c) the magnitude of the velocity of the block at the bottom of the waterfall.

Answers

(a) Potential energy can be calculated using the formulae

[tex]P= mgh[/tex]

where,

[tex]m[/tex] is the mass of block

[tex]g[/tex] is acceleration due to gravity

[tex]h[/tex] is height

Therefore,

[tex]P= (100)(9.8)(5)[/tex]

[tex]P=4900[/tex]

(b) Kinetic Energy can be calculated using the formulae

[tex]\frac{1}{2} mv^{2}[/tex]

for this velocity ([tex]v[/tex]) can be calculated using

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{(2)(9.8)(5)}[/tex]

[tex]v=9.899[/tex]

now,

[tex]k=\frac{1}{2}mv^{2}[/tex]

[tex]k=-\frac{1}{2}(100)(9.8)^{2}[/tex]

[tex]k=-5000J[/tex]

(c) Velocity ([tex]v[/tex]) can be calculated using

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{(2)(9.8)(5)}[/tex]

[tex]v=9.899[/tex]

What is Potential energy?

Potential energy is a type of energy that results from a change in position or state.

What is kinetic energy?

The kinetic energy of something is the amount of work it can do due to its motion.

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7. A raindrop has a mass of 0.003 kg

a) Assume the raindrop takes 15 s to reach its terminal velocity of 7 m/s. Calculate
the average acceleration of the raindrop.

b) Determine the average air resistance force on the raindrop.

Answers

(a) The average acceleration of the raindrop is 0.467 m/s².

(b) The average air resistance force on the raindrop is 1.4 x 10⁻³ N.

What is the average acceleration of the raindrop?

The average acceleration of the raindrop is calculated as follows;

Mathematically, the formula for average acceleration is given as;

a = Δv/Δt = v/t

where;

v is the velocity of the raindropt is the time of motion of the raindrop

a = (7 m/s) / (15 s)

a = 0.467 m/s²

The average air resistance force on the raindrop is calculated as follows;

F = ma

where;

m is mass of the raindropa is the acceleration of the raindrop

F = 0.003 x 0.467

F = 1.4 x 10⁻³ N

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light rays coming from an object are observed to be parallel. what does this imply about the distance to the object

Answers

Since the distance from the source point is always finite, light beams are never precisely parallel in reality. So, theoretically, we may refer to two rays as being parallel if their spacing is near to zero and their distance traveled is about infinite.

What is a light beam and give an example?

Three types of light beams are possible. Both convergent and divergent, they are parallel. A parallel Light Beam is created when the rays from a distant point source move in the same direction alongside one another. An illustration of a parallel beam of light is the sun Ray.

What materials make up light beams?

Many photons in the same condition make up coherent beams, including laser and radar beams. A light beam's photon count is more of a measurement of its brightness than of its breadth.

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a sled of mass 1375 kg has four identical rockets. with all four rockets burning, the sled initial acceleration is 45.0 m/s2. assume that the force of friction opposing the motion is 450 n, what is the force exerted by the rockets?

Answers

The force exerted by the rockets is 62,325 N.

What is the force exerted by the rockets?

The force exerted by the rockets is determined by applying Newton's second law of motion.

According to Newton's second law of motion, the force exerted by an ob ject is directly proportional to the product of mass and acceleration of the object.

F(net) = ma

where;

F(net) is the net force on the objectm is the mass of the objecta is the acceleration of the object

F - Ff = ma

where;

F is the force exerted by the rocketsFf is the force of frictiona is the acceleration of the sled

F - 450 = (1375 x 45)

F = 61,875 + 450

F = 62,325 N

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3. What photonic energy would be required to move an electron from energy level:
a.
1 to 5?
b.
1 to 3?
c.
d.
e.
2 to 3?
2 to 4?
2 to 6?

Answers

Answer:

Energy of nth orbit of H-atom, E

n

=−

n

2

13.6

eV

∴ ΔE=E

5

−E

1

=−13.6(

5

2

1

1

2

1

) eV

∴ ΔE=13.6×

25

24

=13.056 eV

the filament of a light bulb has a temperature of 2580oc and radiates 60 w of power. the emissivity of the filament is 0.36. what is the surface area of the filament?

Answers

The surface area of the filament of a light bulb is 0.159×10⁻⁴m².Surface area is inversely to  emissivity and directly proportional to power.

Every body in this universe emits some radiations whether it will be large or small.

We know that surface area of filament of bulb=Power radiated by the body/Emissivity of the body, or

=>A=P/I

Now, Power radiated by the  body is given(P)=σAT⁴,where

σ is Stefan constant having value 5.67040×10⁻⁸ w/m²-K⁴.

A is the surface area

and T is the temperature of body.

Now, temperature is given in degree celsius.

So, on converting temperature into kelvin, we get

K=C+273

=>K=2580+273

=>K=2853Kelvin

Value of T⁴ is =(2853)⁴ =(8139609×8139609)K⁴

On putting values of power, area and temperature, we get

=>A=P/σT⁴

=>A=60 / [(5.67040×10⁻⁸)×(8139609×8139609)

=>A=60/(5.67040×10⁻⁸)×(66.21×10¹²)

=>A=60/375.48×10⁴

=>A=0.159×10⁻⁴m²

Hence, surface area is 0.159×10⁻⁴m².

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What is the most accurate way to describe the motion of bird in flight?
A. The bird flew real far and fast
B. The bird flew 5 miles over the course of 1 hour
C. The bird flew 5 miles per hour, directly north
D. The bird flew 5 miles

Answers

Answer:

Explanation:

A. The bird flew real far and fast.

"far" and "fast" describe the type of motion.

light inside an optical fiber tube hits the wall between the tube and air. we find that if the incident light makes and angle of 30 degrees with respect to the tube wall it is totally internally reflected, but if the angle is greater, it is not. what is the index of refraction of the tube?

Answers

The total internal reflection is the complete reflection of a ray of light within a medium such as water or glass from the surrounding surfaces back into the medium. The phenomenon occurs if the angle of incidence is greater than a certain limiting angle, called the critical angle.

This is an internal total reflection exercise, the equation that describes this process is

        sin θ = n₂ / n₁

where n₂ is the index of the incident medium and n₁ the other medium must be met n₁> n₂

       θ = sin⁻¹ n₂ / n₁

let's calculate

      30⁰ = sin⁻¹ (n₂ / n₁)

Therefore, if the angle is greater then the totally internal reflection also increases.

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the shanghai maglev train takes 8 minutes to travel a distance of 30.5 kilometres.work out the average speed of the train. give your answer in kilometres per hour.

Answers

The average speed is 228.75 km/h.

What is speed?

Speed is the time rate at which an object is travelling along a route. To put it another way, velocity is a vector, whereas speed is a scalar value.

What is the speed-distance formula?

Speed is equal to distance traveled and time spent.

Distance is determined by multiplying the time and the speed.

Time is determined by speed and distance.

Given:

Distance = 30.5 kilometers

Time= 8 minutes

= 8/60 hour = 2/15 hour

Now, average speed equals distance / time.

= 30.5 x 15/2

= 228.75 Km/ h

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A 2. 00 kg, frictionless block is attached to an ideal spring with force constant 300 n/m. At t = 0 the block has velocity -4. 00 m/s and displacement +0. 200 m away from equilibrium.

Answers

Position of the mass as a function of time is:

x(t) = 0.3829cos(12.247×t +58.511∘) m

When a mass m is connected to a spring of spring constant k the system executes a simple harmonic motion with angular frequency ω =

[tex]\sqrt{k/m[/tex]

The location of the mass at any given time t is given by

x(t) = A cos (ωt+Ф)

Where Ф = Initial phase

A = amplitude

solving our question:

mass of block m = 2 kg

spring constant k = 300 n/m

At t = 0, the velocity of the block v(0) = -4.00m/s

displacement x(0) = -0.200 m

angular frequency w = [tex]\sqrt{k/m[/tex] = 300/2 = 12.247 [tex]radian^{-1[/tex]

So, position of the mass at time t is written as

x(t) = A cos ( 12.247×t+Ф)

     0.2 = A cosФ

and v(t) = -12.247×A×sin(12.247 t +Ф)

-4 = -12.247 A sinФ

A sinФ = 0.3266

squaring and adding the two equations

[tex]A^{2}[/tex] = [tex]0.3266^{2}[/tex] + [tex]0.2^{2}[/tex]

and cosФ = 0.2/0.3829

Ф = 58.511

Therefor position of the mass is

x(t) = 0.3829cos(12.247×t +58.511∘) m

The given question is incomplete, the complete question is

A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. At t = 0, the block has velocity -4.00 m/s and displacement +0.200 m. Write an equation for the position as a function of time.

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if the planes were not frictionless, which block would have the most mechanical energy at the bottom of the inclined plane?

Answers

Since. The frictionless incline and uniform height "h" at which all the blocks are released. Therefore, the total energy at the bottom of the incline will be equal to the initial potential energy (PEi = mgh). - In line with energy conservation.

What is kinetic energy?

Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. When the project is complete, the item will be moving at a new, constant speed because energy has been transferred to it.

In other words, the amount of work done is equal to how much the object's K.E. has changed! This is the relationship between Kinetic energy and Work Done, or the Work-Energy Theorem. In other words, the change in an object's kinetic energy represents the work done on it. W = Δ(K.E.).

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what is the wavelength of light that is deviated in the first order through an angle of 15.0 ∘ by a transmission grating having 5000 slits/cm ? assume normal incidence.

Answers

The wavelength of light will be  5.17 x10⁻⁷ m

Since we are given the angle of  15.0, and transmission grating having 5000 slits/cm, for a normal incidence

since we know the diffraction of first-order formula is :

d sineθ =nλ ,and the separation os the slits are : d= 1/N

=>d=1/ 5000  = 2x 10^-6 m

Now subsituing the value of d in the main formula of diffraction, where we get the wavelength of :

λ = dsine θ/ n

since here n is 1

λ=  2x 10 *sine 15.0/ 1

λ = 2x 10^-6 *0.2588   = 5.17 x10⁻⁷ m

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a two-slit fraunhofer interference-diffraction pattern is observed with light of wavelength 660 nm. the slits have widths of 0.01 mm and are separated by 0.19 mm. how many bright fringes will be seen in the central diffraction maximum?

Answers

38 Bright fringes will be seen in the central diffraction maximum when a two-slit Fraunhofer interference-diffraction pattern is observed.

Diffraction is when waves such as light or sound spread as they travel around an object or through a slit.

As the light passes through each of the slits, it expands and overlaps with the light from the other slit. Through this overlap, a diffraction pattern of dark and light areas is created.

In case of diffraction , angular width of central maxima = 2 λ/d

λ is wave length of light  = 660 nm

d is slit width = 0.01 mm

In case of interference , angular width of each fringe = λ /D

D is distance between two slits = 0.19 mm

Number of interference fringe in central diffraction fringe can be calculated by the formula

=2 λ/d x D/λ

= 2 x D /d = 2 x .19/0.01

= 38

38 bright fringes will be seen in the central diffraction maximum.

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what is the mass-to-light ratio of a 0.8 msun white dwarf with luminosity 0.001 lsun ? here, msun is the mass of the sun, and lsun is the sun's luminosity g

Answers

The mass-to-light ratio will be [tex]\frac{M_{\omega D}}{L_{\omega D}}=4.6 \times 10^6 \mathrm{~kg}/ watt[/tex]

As per the data given in the question,

We have,

Mass of white dwarf [tex]$M_{\omega_D}=0.8 M_{\text {sun }}$[/tex] where [tex]$M_{\text {sun }}$[/tex] is the mass of the Sun

We have, Luminosity of the white dwarf [tex]$$L_{\omega_D}=0.001 L_{\text {sun }} .$$[/tex] ,where [tex]$L_{\text {sun }}$[/tex] is the Luminosity of the Sun.

Calculating Mass to light Ratio =M/L

Mass to light Ratio for Sun, [tex]\frac{M_{\text {sun }}}{L_{\text {sun }}}=\frac{1.989 \times 10^{30} \mathrm{~kg}}{3.867 \times 10^{26} \text { watts. }}[/tex]

[tex]\frac{M_{\text {sun }}}{L_{\text {sun }}}=Y_0 \approx 5133 \mathrm{~kg} / \text { watt }[/tex]

Hence,

[tex]\frac{M_{w D}}{L_{w D}}=\frac{0.9 M_{\text {sim }}}{0.001 L_{\text {sun }}}=900 \frac{M_{\text {sun }}}{L_{\text {sun }}}\\\\\therefore \frac{M_{\omega D}}{L_{\omega D}}=900 Y_{\odot}[/tex]

[tex]\frac{M_{\text {wD }}}{L_{\text {sun }}} & =900 \times(5133) \mathrm{kg} / \text { watt } \\\\=4.6 \times 10^6 \mathrm{~kg} / \text { watt. }[/tex]

Therefore, [tex]\frac{M_{\omega D}}{L_{\omega D}}=900 Y_0=4.6 \times 10^6 \mathrm{~kg}/ watt[/tex]

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Objects A and B interact with each other via both conservative and nonconservative forces. Let KA and KB be the kinetic energies, U be the potential energy, and Eint be the thermal energy. If no external agent does work on the objects then:
A. KA + U is conserved
B. KA + U + Eint is conserved
C. KA + KB + Eint is conserved
D. KA+KB+Uisconserved
E. KA +KB +U +Eint is conserved

Answers

(D) Since both conservative and non-conservative forces are involved, so the sum of all of them will be conserved. The kinetic energy, potential energy and thermal energy all together is conserved in the system.

What is Kinetic energy?

A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion. The type of motion can be vibration, rotation on an axis, translation (or travel along a path from one place to another), or any combination of these.

What is Thermal energy?

Heat is the transfer of thermal energy, whereas thermal energy is the entire internal energy of a system's temperature.

Hence, the kinetic energy, potential energy and thermal energy all together is conserved in the system.

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the air in an inflated balloon (defined as the system) warms over a toaster and absorbs 115 j of heat. as it expands, it does 77 kj of work. what is the change in internal energy for the system? (ans: -77 kj)

Answers

ΔU = q+w The system does work, which gives a negative value: -77kJ

The heat absorbed is q, which is 115J = 0.115kJ

Change of internal energy= 0.115kJ + (-77kJ) = -76.885kJ

Taking two sig figs: -77kJ

What is internal energy and an illustration?

The term "internal energy" describes the power contained in all of the chemical bonds that hold a system's molecules together as well as the kinetic energy of the molecules themselves. Every time heat, work, and internal energy interact, there is a transfer of energy and a conversion.

What makes it internal energy?

W. Thomson first used the word in thermodynamics in 1852. (the later Lord Kelvin). Because certain energy contributions are ignored, the adverb "internal" is used. For instance, the entire system possesses kinetic energy when it is moving uniformly.

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what is the approximate age of the universe indicated by that erroneous value of h0 ? express your answer in years to one significant figure.

Answers

With the Hubble's constant H₀, the estimated age of the universe would be:

T = 8,332,452,617.49 years.

How to get the age of the universe?

We know that the age of the universe is something near to the time the galaxies needed to reach their current distance:

T = D/V

And by Hubble's law, we know that:

V = H₀*D

Then we can write:

T = D/(H₀*D) = 1/H₀

So, we can say that the age of the universe is something near the inverse of Hubble's constant.

Then we have

T = 1/(36 km/s*Mly) = (1/36)  s*Mly/km

Now we need to perform the correspondent change of units.

1 Mly = 1 million light-years

Such that:

1 ly = 9.461*10^12 km

Then 1 million light-years over km is equal to:

1 Mly/km = 1,000,000*(9.461*10^12 km)/km = 9.461*10^18

Then we can replace it:

T = (1/36) s*Mly/km = (1/36)*9.461*10^18 s

T = 2.628*10^17 s

This is the age in seconds, but we want it in years.

We know that:

1 year = 3.154*10^7 s

Then to change the units, we compute:

T = (2.628*10^17 s/3.154*10^7 s)* 1 yea

T = 8,332,452,617.49 years.

Therefore, the age of universe according to Hubble's constant will be 8,332,452,617.49 years.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Suppose that Hubble's constant were H0 = 36 km/s/Mly (which is not its actual value). What would the approximate age of the universe be in that case? Express your answer in years to two significant figures.]

A red wagon with a mass of 7\, {\text{kg}}7kg7, start text, k, g, end text is moving with a velocity of 4\,\dfrac{\text{m}}{\text{s}}4
s
m

4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction straight toward a blue wagon at rest. The red wagon’s mass is 777 times the mass of the blue wagon. The final velocity of the red wagon is 3\,\dfrac{\text{m}}{\text{s}}3
s
m

3, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction .
What is the velocity of the blue wagon immediately after the red wagon collides with it?

Answers

The velocity of the blue wagon immediately after the red wagon collides with it is 7 m/s

How do I determine the velocity of the blue wagon after collision.?

From the law of conservation of linear momentum, we understood that momentum before collision is equal to momentum after collision as shown below:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Where

m₁ and m₂ are the masses of the two objectsu₁ and u₂ are the initial velocities of the two objectsv₁ and v₂ are the final velocities of the two objects

With the above formula, we can obtain the velocity of the blue wagon as follow:

Mass of red wagon (m₁) = 7 KgInitial velocity of red wagon (u₁) = 4 m/sMass of blue wagon (m₂) = m₁ / 7 = 7 / 7 = 1 KgFinal velocity of red wagon (v₁) = 3 m/sFinal velocity of red wagon (v₂) = ?

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(7 × 4) + (1 × 0) = (7 × 3) + (1 × v₂)

28 = 21 + v₂

Collect like terms

v₂ = 28 -21

v₂ = 7 m/s

Thus, the velocity of the blue wagon after collision is 7 m/s

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1. Which, if any, of these people are nearsighted (myopic)?
List the first letter of all correct answers in alphabetical order. For example, if Avishka and Edouard are the only nearsighted ones, enter AE.
2.Which, if any, of these people require bifocals to correct their vision?
3.Which, if any, of these people's vision can be corrected using only converging lenses?
Please show work and units.
The near point (the smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an object can be seen clearly) are measured for six different people.

Answers

Nearsightedness affects Berenice, Chadwick, and Edouard.The near point, or minimum distance at which an object can be seen clearly with the unaided eye, is 25 cm.The greatest distance at which an object can be seen clearly with the unaided eye is called the far point. Diverging lenses, which create virtual images at the user's far point when presented with things at infinity, can be used to treat nearsightedness.

Does Z come after A in the alphabet?

The sort order for words and letters is A through Z.Most frequently, an alphanumeric sort is used for data including both numbers and letters and words, such as address lines. This means that Z to A is sorted first, then 9-0, before any further operations.

What does a distance mean in mathematics?

The distance is explained.The distance between any two points along a line or line segment.

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a tuning fork produces a steady 400 hz tone. when struck and held near a vibrating guitar string, twenty beats are counted in 5 seconds. what are the possible frequencies produced by the guitar string? 380 hz or 420 hz 396 hz or 404 hz 395 hz or 405 hz 400 hz click here to check your answer 12.5 pts.100% 25% try penalty

Answers

Frequency = 404 Hz

Frequency of tuning Fork V0 = 400HZ

beat frequency= 20 / 5= 4hz

= possible frequency = V0 - 4 = 396 Hz or V0 + 4 = 404 Hz

In physics, the term frequency refers back to the number of waves that skip a hard and fast factor in unit time. It also describes the number of cycles or vibrations undergone for the duration of one unit of time by using a frame in periodic motion.

Frequency is expressed in units of hertz (Hz), which is equivalent to 1 event consistent with 2d. The corresponding period is the time length of one cycle in a repeating collection of events, so the length is the reciprocal of the frequency.

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What is the maximum possible amplitude the end of the board can oscillate at, so that a pebble placed there never loses contact with the board at any point of the oscillation?.

Answers

If the pebble on the board do not want to lose contact with one another, so the maximum acceleration would be equal, rather would be equal to four pies square times the frequency squared times the amplitude and this has to be less than G.

Oscillation is defined as the process of repeating variations of any quantity or measure about its equilibrium value in time.Oscillation can also be defined as a periodic variation of a matter between two values or about its central value.However, oscillations also occur in dynamic systems or more accurately in every field of science. Even the beating of our heart creates oscillations.The amplitude of a wave is the maximum displacement of the particle of the medium from its equilibrium position.

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what do we mean by dimension in the context of relativity? what do we mean by dimension in the context of relativity? the number of sides that we can see when we look at an object the size of an object the letter used to represent length mathematically the number of independent directions in which movement is possible

Answers

The number of independent directions in which movement is possible  dimension in the context of relative motion.

To discuss relative motion in one or more dimensions, the idea of reference frames was initially developed. When we refer to an object's velocity, we are referring to it in relation to the so-called reference frame. When measuring an object's velocity in daily life, the ground or the earth is assumed to be the reference frame.

As an illustration, if you are travelling in a train that is moving at 100 km/h, then from the perspective of another passenger in the train, you are moving at a speed of zero. He says you're standing still. However, if a bystander sees you standing on the ground outside the train, he claims that you are going with the train.

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an image of the lateral skull taken at 68 kvp, 20 mas and is repeated. if the kvp is increased to 78 kvp, what should be the new mas?

Answers

The new mAs should be a half of 20mAs, which is 10mAs.

How does kVp and mAs affect image quality?The first experiment demonstrated that, when the film density is held constant, the resolution and image contrast % decrease with increasing kVp and increase with increasing mAs, respectively.In the second portion of the experiment, several mAs were selected, and many kVps were employed for each mAs. The radiographs were read by five observers.The second experiment demonstrated that the correlation between kVp and resolution and between kVp and the picture contrast % were the same as in the first experiment when the film density was not maintained constant. The relationship between mAs and resolution and mAs and the percentage of picture contrast was, however, hardly significant.

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a puuck of mass m pslides across a horizontal surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations ap physics

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surafe cand collides with a stationary, nonuniform rod that is pivoted about its left end in three configurations with angular velocity ω=MpVpL/(1/12 ML²+MpL²)

The moment of inertia of a rod rotated about one end is 1/12 ML².

The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.

Write the expression of the conservation of the angular momentum.

.L1=L2

MpVpL=(1/12 ML²+MpL²)ω

ω=MpVpL/(1/12 ML²+MpL²)

Thus, the angular velocity is  ω=MpVpL/(1/12 ML²+MpL²)

The rotational axis is the direction in which the angular velocity is moving. The angular velocity of an object rotating counterclockwise is along the axis of rotation, away from you. The angular velocity of an object rotating counterclockwise points in your direction along the axis of rotation.

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how much net work is required to accelerate it from rest to a rotation rate of 1.00 revolution per 8.00 s ? assume it is a solid cylinder.

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The net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.

What is work?
Work in physics is the energy that is transmitted to or from a object when a force is applied along a displacement. In its simplest form, it equals this same product of a force's magnitude and the distance travelled for a constant force directed in the same direction as the motion. When a force is applied, it is said to have a component that moves the point of application, or it is said to have positive work. If the component of a force at the point of application is in the opposite direction of the displacement, the force is said to do negative work.

The net work required to accelerate a solid cylinder from rest to a rotation rate of 1 revolution per 8.00 s is equal to the torque multiplied by the angle of rotation. Since the angle of rotation is 360 degrees, the net work required is equal to the torque multiplied by 360 degrees.

The torque is equal to the moment of inertia of the cylinder multiplied by its angular acceleration. The moment of inertia of a solid cylinder is equal to (1/2)mr^2, where m is the mass of the cylinder and r is its radius. The angular acceleration is equal to the change in angular velocity divided by the time interval. In this case, the angular velocity is 1 revolution per 8.00 seconds, so the angular acceleration is 1/8 rad/s^2.

Therefore, the net work required is equal to (1/2)mr^2 x 1/8 x 360 = 90mr^2.

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a 2.0 kg , 20-cm-diameter turntable rotates at 140 rpm on frictionless bearings. two 510 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.
What is the turntable's angular velocity, in rpm, just after this event?

Answers

The turntable's angular velocity, in rpm, just after this event is 39,72 rad/m

How to determine angular velocity?

We can use the law of conservation of angular momentum.

Its a law that states the amount of momentum before and after producing is equal or constant collision.

The equation:

L₁ = L₂

I₁ x ω₁ = I₂ x ω₂

We have,

Mass of the table = 2.0 kg ⇒ m₁

Diameter of the table = 20 cm = 0.2 m ⇒ d, so R = 0.1

Angular speed = 140 rpm = 14.65 rad/s ⇒ ω₁

Mass of the blocks = 520 g = 0.52 kg ⇒ m₂

So,

I₁ x ω₁ = I₂ x ω₂

(½ mR²) ω₁ = (½ mR² + m₁R² + m₂R²)  ω₂

(½ (2.0) (0.1)² (14.65) = (½ (2.0) (0.1)² + (2.0) (0.1)² + (0.52) (0.1)²  ω₂

0.1465 = (0.01 + 0.02 + 0.02 + 0.0052) ω₂

ω₂ = 4.16 rad/s ⇒ 39,72 rad/m

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If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion?.

Answers

The frequency of simple pendulum will become 1/√2 times of original frequency  if length of simple pendulum is doubled.

We know that frequency of simple pendulum is given by the formula

=>f=(1/2π)×√g/√l

where f is the frequency of simple pendulum,

l is the length of simple pendulum

and g is the acceleration due to gravity

We can see that frequency is directly proportional to length of pendulum and inversely proportional of acceleration due to gravity. Since value of  acceleration due to gravity  remains same on observations, therefore only factor where frequency gets changed when length of simple pendulum gets changed. 1/2π is constant value, it does not affected on changing the length of simple pendulum.

So, if we double the length of simple pendulum, new frequency will become

New Frequency=(1/2π) × (√g / √2l)

=>New Frequency=(1/√2)×[(1/2π×√g/√l)]

=>New Frequency=(1/√2)f.

Hence, new frequency will become 1/√2 times of original frequency.

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an aluminum nail has an excess charge of 4.8 c. how many electrons must be added to the nail to make it electrically neutral?

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3.3×10⁻²⁰ electrons must be added to the nail to make it electrically neutral.

Why is an atom neutral in terms of electricity?

Although heavier atoms typically have more neutrons than protons, there are always the same number of electrons in an atom as there are protons. As a result, an atom is electrically neutral overall. An atom becomes positively charged when one or more of its electrons are taken away.

An atom has no overall charge when it is electrically neutral, which is defined as this. Positively charged particles called protons, negatively charged particles called electrons, and non-charged particles called neutrons make up atoms.

q = ne

q = 1.6×10⁻¹⁹

e = 4.8μc

n = ?

1.6×10⁻¹⁹ = ne

n = 1.6×10⁻¹⁹ /4.8

n = 3.3×10⁻²⁰.

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