what is the
structure and symmetry operation of naphthalene​

Answers

Answer 1

Answer:

Naphthalene has C2-rotational axis passing through the C9-C10 bond. It has two C2-axes perpendicular to the principal C2-rotational axis (one is passing through the mid-point of the C9-C10 bond another passing through the midpoints of C2-C3, C9-C10, C6-C7 bonds).

Explanation:


Related Questions

HELP ME ASAP PLEASE

I need the answers I’m in a hurry

Answers

Answer: First box----Hail

             Second Box-------Snow

             Thrid Box-------Sleet

              Forth Box-----Rain

Hope that helped! :)

“When an animal looks a lot like another animal, even though they’re not the same kind of creature at all, it’s called

Answers

Answer:

cryptic biodiversity

Explanation:

A sample of sodium reacts completely with 0.497 kg of chlorine, forming 819 g of sodium chloride. What mass of sodium reacted?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

[tex]819 \: g = 819 \times {10}^{ - 3} \: kg = 0.819 \: kg \\ 0.819 \: kg - 0.497 \: kg \\ = 0.322 \: kg[/tex]

What will occur when potassium reacts with sulfur?

Answers

The electrons are transferred from potassium to sulphur, in this reaction, potassium is being oxidised and sulphur is being reduced. Two potassium atoms each lose one electron forming K+ ions. Sulphur gains two electrons forming S2-/2- ions. The resultant formula will be: K2S, bonding in this compound is ionic.

PPLLLLLZZZZZ HELPPPPPPPPP ME WITH THIS QUESTION BRAINLIEST PLUS 20 POINTS If CO2 was added to this system what would the outcomes for this reaction be?

CO2 + H2O <-> H2CO3
Question 4 options:


It would shift to the right, favor the forward reaction and the rate of reaction would decrease.


It would shift to the left, favor the forward reaction and the rate of reaction would increase.


It would shift to the right, favor the forward reaction and the rate of reaction would increase.


It would shift to the left, favor the reverse reaction and the rate of reaction would decrease.

Answers

It would shift to the right, favor the forward reaction and the rate of reaction would increase.

(third option)

What is the major organic product obtained from the reaction of (R)-2-bromohexane with sodium cyanide/acetone

Answers

Answer:

Option C

Explanation:

The complete question is

What is the major organic product obtained from the reaction of

(R)-2-bromohexane with sodium cyanide/acetone?

A) ) trans-2-pentene

B) ( S)-2-Methylpentanenitrile

C) ( S)-2-Methylhexanenitrile

D) (plus or minus)-2-Methylpentanenitrile

Solution

This is an inversion reaction in which (R) 2 Bromohexane convert into (S) -2 – methyl hexane in the presence of Acetone and NaCN.  

The reaction occurs through the SN2 mechanism and  there is inversion of confiruration

Hence, option C is correct

True or false: A skeleton equation in chemistry shows the relative amounts of all materials in the reaction

Answers

Answer:

false im pretty sure.

Calculate the percent composition of Ca3P2

Answers

Calculate the molar mass of Ca3P2 in grams per mole or search for a chemical formula or substance.

Answer:

Ca - 66%, P - 34%

Explanation:

So, this is the formula we can use to find the amount of each element:

Element count * Atomic mass = Mass

Plug in our elements for this:

Ca - 3*40.078=120.234

P - 2*30.973=61.946

Now, to find the percentage of mass, we must find total mass, and divide the two elements mass count by this total mass:

120.234+61.946=182.18

Now divide each element mass by the total mass:

Ca - 120.234/182.18=0.6599(Round to 0.65)

P - 61.946/182.18=0.34002(Round to 0.34)

Then multiply both numbers by 100 to get the percentage:

Ca - 65%

P - 34%

So these our your two answer!

Hope this helps!

Please answer these quickly. :)

Answers

Q.1

a) 1 mol of N2 requires 3 moles of H2

so 4 moles of hydrogen will require = 4/3 = 1.33 moles

Answer of A) 1.33 moles

b) 2.5 moles of nitrogen gas were require to produce 5.00 moles of NH3

c) 7.5 moles of hydrogen gas were require to produce

5.00 moles of NH3

Q.2

a) 6 moles of H2 gas were require to make 6.00 mol H2S

b)24 moles of H2 gas were required to react with 3 moles of S8

c)56 moles of H2S are produced from 7 mol of S8



A gas cylinder with a volume of 5.00 L contains 6.00 moles of oxygen gas
at a temperature of 90.0 K. What is the pressure inside the cylinder? The
Ideal gas law constant( R) is 0.0821 L atm/mol K*
8.87 torr
8.87 atm
0.0821 atm
0.0821 torr

Answers

Answer:

8.87 atm

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 5 L

Number of mole (n) = 6 moles

Temperature (T) = 90 K

Gas constant (R) = 0.821 atm.L/Kmol

Pressure (P) =?

The pressure inside the container can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 5 = 6 × 0.0821 × 90

P × 5 = 44.334

Divide both side by 5

P = 44.334 / 5

P = 8.87 atm

Therefore, the pressure inside the container is 8.87 atm

How many molecules of sodium fluoride (NaF) are found in 7.2 moles of sodium fluoride?

Answers

Answer:

well please answer me it's question too after you get it

Explanation:

i am also stucked in that question

No. of molecules of any substance is one mole

= Avogadro's Number = (6.022 x 10^23)

So, no. of molecules in 7.2 moles of sodium fluoride

= 7.2 × (6.022 x 10^23)

= 4.33584^24

You dissolve 14 g of [tex]Mg(NO_{3} )_{2}[/tex] in water and dilute to 750 mL. What is the molarity of this solution?



Show your work

Answers

I didn’t get the answer

Qualitatively explain the effect of changing concentration of Cu2+ on voltage using your experimental observations and the Keq values below. (No calculations are required).
(a) Cu^2+(aq) + 4NH3(aq) ⇄ [Cu(NH^3)4]^2+(aq) Keq = 1.2 x 10^12
(b) CuS(s) ⇄ Cu^2+(aq) + S^2-(aq) , Keq = 8.5 x 10^-45
Cu/Zn = 0.525 V
after 1 drop NH3: 0.505 V
after 2 drops NH3: 0.435 V
Cu/Zn = 0.510 V
after 1 drop Na2S: 0.452 V
after 2 drops Na2S: 0.393 V

Answers

its the second one hope this helps

What is the thermal efficiency of an engine that takes n moles of diatomic ideal gas through the cycle

Answers

Answer:

The thermal efficiency of an engine is [tex]0.15[/tex] that is 15%

Explanation:

Specific heat of a gas at constant volume is

[tex]C_{v}=\frac{fR}{2}[/tex]

here, [tex]f=[/tex]degree of freedom

[tex]R=[/tex]universal gas constant

Thermal efficiency of a cycle is

[tex]\frac{total workdone}{gross heat absorbed}[/tex]

Gross heat absorbed is amount of heat that absorbed.

ω[tex]=P_{o} V_{o}[/tex]

[tex]Q_{AB}=[/tex]Δ[tex]V_{AB}+[/tex]ω[tex]_{AB}[/tex][tex]=nC_{v}(T_{f}-T_{i} )[/tex]

       [tex]=n\frac{f}{2}(RT_{f}-RT_{i} )[/tex][tex]=\frac{f}{2}(P_{o}V_{o} )[/tex]

[tex]Q_{BC}=n(\frac{f}{2}+1 )R(T_{f}-T_{i} )[/tex]

       [tex]=(\frac{f}{2} +1)(4P_{o}V_{o}-2P_{o}V_{o} )[/tex]=[tex]=(\frac{f}{2}+1)2P_{o}V_{o}[/tex]

[tex]Q_{CD}=-ve and Q_{DA}=-ve[/tex]    these 2 are not the part of gross heat

η[tex]=\frac{P_{o}V_{o} }{(\frac{3f}{2}+2 )(P_{o}V_{o})}[/tex]

  [tex]=\frac{1}{(\frac{3f}{2}+2 )}[/tex]

For monoatomic gas [tex]f=3[/tex]

η[tex]=\frac{2}{13}[/tex]

  [tex]=0.15[/tex]

The free energy of ATP hydrolysis is used to maintain the concentration of Ca2 inside the cell to be constant. Calculate the number of moles of ATP required to pump out one mole of Ca2 when the cell is placed in a liquid culture containing 1 M CaCl2 at 25oC. The concentrations of ADP and Pi inside the cell are 250 mM and 10 mM, respectively, and that of ATP is 1.5 mM. The standard free energy of ATP hydrolysis at 25oC is O31.0kJ.

Answers

Answer:

The response can be defined as follows:

Explanation:

ATP is a hydrolysis energy-saving money of the cell. It is used to support the cell's endothermic processes.

[tex]ATP\ +\ H_{2}O\ \rightleftharpoons \ ADP\ +\ P_{i}\\\\Q\ = \ \frac{[ADP][P_{i}]}{[ATP][H_{2}O]}\\\\ADP= 0.250 \ M\\\\P_i = 0.010 \ M\\\\ATP = 0.150 \ M\\\\H_2O = 55.55 \ M\\\\\Delta G \ =\ \Delta G^{o}\ +\ 2.303\ RT\ \log\ Q\\\\R = 8.314 \frac{J}{mol\ K}\\\\T = 298\ K\\\\[/tex]

What is the general form for the simplest type of acid-base reaction?
O A. Acid + base > H+ + OH-
B. Acid + base → base + acid
C. Acid + base + salt + water
D. Acid + base → solid + water

Answers

Answer:

Your answer is C

Explanation:

When an acid and base react, the acidic hydrogen ion and the basic hydroxide ion in each acid and base neutralize each other and form water. Meanwhile the conjugate base and conjugate acid (the leftover compounds) react to form an ionic molecule, or a salt. (In chemistry, when an anion and a cation form an ionic bond the new molecule is called a salt). Hope this helps!

Pls help which law is that???

Answers

Answer:

it is newtons third law

Explanation:

Answer:

Newton's Third Law: Action & Reaction

A weather balloon is inflated to a volume of 26.7 L at a pressure of 748 mmHg and a
temperature of 28.4 °C. The balloon rises in the atmosphere to an altitude where the pressure is
400. mmHg and the temperature is -15.6 °C.

Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.

Answers

Answer:

42.64 L

Explanation:

Using the combined law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information in this question,

P1 = 748mmHg

P2 = 400mmHg

V1 = 26.7 L

V2 = ?

T1 = 28.4 °C = 28.4 + 273 = 301.4K

T2 = -15.6 °C = -15.6 + 273 = 257.4K

Using P1V1/T1 = P2V2/T2

748 × 26.7/301.4 = 400 × V2/257.4

66.26= 1.554 V2

V2 = 66.26 ÷ 1.554

V2 = 42.64 L

help ! thank u / ill give brainlist !

Give two examples of energy transformations that occur throughout the journey to or on the planet.

Answers

Answer:

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy

Reword it tho

Hope this helps!!

The following experiment was performed: A white solid was added to a test tube containing water. The solid completely dissolved and the solution was colorless. Chlorine was added the the solution turned an dark orange color. Hexane was added, the test tube was corked, and the contents was mixed. It was then noted that the hexane was purple in color. What was likely the identity of the white solid

Answers

Answer:

Potassium iodide

Explanation:

The white solid introduced into the solution is potassium bromide. This is an ionic solid thus it quickly dissolves in water to yield a colorless solution.

When chlorine is added to this solution, the iodine is displaced since chlorine is above iodine in the electrochemical series.

When mixed with hexane, the color of the solution changes to purple.

How many moles are in 482 mL of a 1.91 M solution of NaBr?

Answers

Answer:

0.921 moles

Explanation:

1.91 M means 1.91 moles/liter

482 mL = 0.482 L

0.482 L × 1.91 moles/liter = 0.92062 moles

Part B
Explain what happened to make the water in the plastic bowl different from the water in the pot.

Answers

Answer:

I'd say the plastic particles in the bowl boiled off into the water to make the water cloudy and taste different. While the water boiled in the pot was clearer and tasted no different than regular water

Explanation:

I'm doing the course activity now.

Three solutions are mixed together to form a single solution; in the final solution, there are 0.2 mol Pb(CH3COO)2, 0.1 mol Na2S, and 0.1 mol LiCl present. find preciptate

Answers

Three solutions are mixed together to form a single solution. The precipitate in the solution is PbS and PbCl₂.

What are precipitates?

Precipitates are the residues that are present in the solution. These residues are solid that came out of the solution.

Here given 3 compounds are water-soluble.

From the solution, we have to find the possible combination which is water-soluble.

Consider,

Pb(CH3COO)₂ Pb₂+(aq) + 2CH₃COO-(aq)

Na₂S₂Na+(aq) + S₂-(aq)

LiCl Li+(aq) + Cl-(aq)

Now consider a potential accumulation of positive and negative ions which is water-soluble.

The possible accumulations are,

PbS , PbCl₂

Ca(CH₃COO)₂ , CaS

Now viewing with solubility charge, we can find that both PbS and PbCl2 are water indissoluble and create a precipitate.

But both Ca(CH₃COO)₂ and CaS are water-soluble.

Therefore, the precipitates are PbS and PbCl₂.

To learn more about precipitates, refer to the link:

https://brainly.com/question/20925010

#SPJ2

When a balloon containing 635 mL of air is taken from sea level (at standard pressure) to a higher altitude, the balloon expands to 829 mL. What is the air pressure at this new altitude (in atm)?

Answers

Answer:

0.766atm

Explanation:

Boyles law

P1V1=P2V2

1×635=P2×829

P2=635/829

P2=0.766atm

Which best explains the relationship between evaporation and temperature?
• A liquid evaporates slower at lower temperatures because the molecules are more spread apart and are not pushed
as easily from the liquid's surface.
O A liquid evaporates faster at lower temperatures becaus the attractions are decreased and more particles can
escape the surface of the liquid.
© A liquid evaporates slower at higher temperatures because the vapor pressure of the liquid is higher, SO fewer
molecules can escape the surface.
• A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome
attractions in the liquid.

Answers

Answer: D

Explanation:

liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.

Answer:

D. A liquid evaporates faster at higher temperatures because more particles have a higher speed and can overcome attractions in the liquid.

Explanation:

Correct on Edge 2022!!!

Good luck everyone, you got this! Have a great day!

If 15L of neon is at 25C is allowed to expand to 45L. What is the new temperature to maintain constant pressure?

Answers

Answer:

[tex]T_2=894.45K=621.30\°C[/tex]

Explanation:

Hell there!

In this case, according to the given information, it turns out possible for us to calculate the new temperature by applying the Charles' law as a directly proportional relationship between temperature and volume:

[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]

Thus, we solve for the final temperature, T2, as shown below (make sure T1 is in Kelvins):

[tex]T_2=\frac{V_2T_1}{V_1} \\\\T_2=\frac{(25+273.15)K*45L}{15L}\\\\T_2=894.45K=621.30\°C[/tex]

Regards!

Calculate ΔG∘rxn at 298 K for the following reaction:
I2(g)+Br2(g)⇌2IBr(g)Kp=436

Answers

The change in free energy can help us to discover whether a reaction can be sponteanous or not. The change in free energy fro this reaction is -1.51 kJ/mol.

What is change in free energy?

The change in free energy is referred to as that which determines the spontenity of a chemical reaction. For a spontenous reaction the change in free energy must be negative.

Now;

ΔG = -RTlnK

R = gas constant

T = temperature

K = equilibrium constant

So;

ΔG = -(8.314 * 298 * ln 436)

ΔG = -1.51 kJ/mol

Learn more about free energy: https://brainly.com/question/15319033

If it takes 720. mL of 0.00125 M Mg(OH)2 to neutralize 425 mL of an HCI
solution, what is the concentration of the HCI? Mg(OH)2 + HCl →MgCl2
+ H20

Answers

Answer:

0.004235 M

Explanation:

The neutralization reaction of this question is given as follows:

Mg(OH)2 + 2HCl → MgCl2 + 2H2O

Using the formula below:

CaVa/CbVb = na/nb

Where;

Ca = concentration of acid (M)

Cb = concentration of base (M)

Va = volume of acid (mL)

Vb = volume of base (mL)

na = number of moles of acid = 2

nb = number of moles of base = 1

From the information provided in this question;

Ca = ?

Cb = 0.00125 M

Va = 425 mL

Vb = 720 mL

na (HCl) = 2

nb = (Mg(OH)2) = 1

Using the formula; CaVa/CbVb = na/nb

Ca × 425/0.00125 × 720 = 2/1

425Ca/0.9 = 2

472.2Ca = 2

Ca = 2/472.2

Ca = 0.004235 M

The boiling point of Kelvin scale is:
a) 237º K
b) 100°C
c) 100°K
d) 373°​

Answers

Answer:

The boiling point of Kelvin scale is: 373° k

hope it is helpful to you

What is the activity of a 52.3 μCi sample of carbon‑14 in becquerels?

Answers

Answer:

1935100 Bq

Explanation:

Let us recall that:

If 1 μCi can be equivalent to 37000 Bq

Then; the activity of 52.3 μCi will be:

[tex]\dfrac{37000 \ Bq}{1 \ \mu Ci}\times 52.3 \ \mu Ci \\ \\ \\ \\ \mathbf{= 1935100 \ Bq}[/tex]

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