what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a pulley onto a hanging body of mass 10kg​

Answers

Answer 1

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a               (1)

m₂g - T = m₂a    (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

What Is The Acceleration Of Each Body Of Mass 5kg Rests On A Frictionless Table And Is Connected To A
What Is The Acceleration Of Each Body Of Mass 5kg Rests On A Frictionless Table And Is Connected To A

Related Questions

An object of mass 25kg is falling from the height h=10 m. calculate
a. The total energy of an object at h=10m.
b. Potential energy of the object when it is at h= 4m
c. Kinetic energy of the object when it is at h= 4m
d. What will be the speed of the object when it hits the ground?​

Answers

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

Explanation:

V²=U²+2gh

V²=0 + 2×10×10=200m/s

a).kinetic energy=(1/2)mv²=(1/2)25×200=2500

potential energy=mgh

p.e=25×10×10=2500J

pe+ke=2500+2500=5KJ

b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

V²=80

kinetic energy=(1/2)mv²

=(1/2)25×80

=1KJ

d). From my first paragraph V²=200

V=√200

V=14.142m/s

I stand 0.72 meters in front of a mirror and look at the person on the other side who looks like me. That person is actually younger than me by a small amount. How much?

Answers

Answer:

Younger by nanoseconds

Explanation:

Not entirely sure :O

Q: Winding roads and sharp curves are inherently dangerous
because -

A- You can't see far ahead

B- The speed limit is so slow

C- There may be other vehicles traveling in the
opposite direction

D- You may struggle to stay at the same speed

Answers

Answer:

A) you can't see far ahead

D. You may struggle to stay at the same speed.

Winding roads and sharp curves are dangerous because of centrifugal forces while taking curves, whose classic formula is described below:

[tex]F = m\cdot \frac{v^{2}}{r}[/tex] (1)

Where:

[tex]F[/tex] - Centrifugal force, in newtons.[tex]v[/tex] - Speed, in meters per second.[tex]r[/tex] - Radius of curvature, in meters per second.

Sharps curves are characterized by low radii of curvature. Given that centrifugal force is inversely proportional to the square radius of curvature and it is opposed to friction force between tires and pavement, if centrifugal force is higher than maximum static friction force, then a car accident could if driver does not decelerate.

Therefore, correct choice is D.

We kindly invite to see this question on centrifugal forces: https://brainly.com/question/545816

What is the speed of the wave above of the frequency is 7.0 hertz

Answers

Answer:

Umm

Explanation:

A flying stationary kite is acted on by a force of 9.8 N downward. The wind exerts a force of 45 N at an angle of 50.0 degrees above the horizontal. Find the force that the string exerts on the kite.

Answers

Answer:

38 N, 40.0° below the horizontal

Explanation:

Force exerted by an object equals mass times acceleration of that object: F = m ⨉ a. To use this formula, you need to use SI units: Newtons for force, kilograms for mass, and meters per second squared for acceleration.

For variables control, a circuit voltage will be measured using a sample of five circuits. The past average voltage for samples of 5 units has been 3.4 volts, and the range has been 1.3 volts.

Required:
What would the upper and lower control limits be for the resulting control charts (average and range)?

Answers

Answer:

Average :

UCL = 4.15

LCL = 2.65

Range :

UCL = 2.75

LCL = 0

Explanation:

Given :

Sample size, n = 5

Average, X = 3.4

Range, R = 1.3

A2 for n = 5 ; equals 0.577 ( X chart table)

For the average :

Upper Control Limit (UCL) :

X + A2*R

3.4 + 0.577(1.3) = 4.1501

Lower Control Limit (LCL) :

X - A2*R

3.4 - 0.577(1.3) = 2.6499

FOR the range :

Upper Control Limit (UCL) :

UCL = D4*R

D4 for n = 5 ; equals = 2.114

UCL = 2.114*1.3 = 2.7482

Lower Control Limit (LCL) :

LCL = D3*R

D3 for n = 5 ; equals = 0

LCL = 0 * 1.3 = 0

Describe the formation of galaxies.

Answers

Today's cosmologists assume that matter was not uniformly distributed in the universe after the Big Bang. Dense places attract more matter than the surrounding area according to their gravitational forces. Over the course of billions of years, these gas agglomerations eventually led to the formation of the galaxies we see today.

Water droplets forming on the outside of a cold glass of water on a hot, summer day is a example of which part of the water cycle?

Answers

Answer:

Condensation can also produce water droplets on the outside of soda cans or glasses of cold water. When warm air hits the cold surface, it reaches its dew point and condenses. This leaves droplets of water on the glass or can.

Explanation:

1. How would the forces from a header with such a light soccer ball cause a concussion? Draw
Two free body diagrams showing how the amount of peak force on the head would compare
to the amount of peak force on a soccer ball in a header that causes a collision.

Answers

Answer:

soccer when the ball hits an unprepared player in the head. He also gave examples of concussions occurring when players accidentally knock their heads into other players while attempting to head the ball, particularly if they are attempting to flick the ball backwards.

Explanation:

Heading in soccer can increase your risk of concussions. Over time, repeated subconcussive injuries can also accumulate and cause brain damage.

what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​

Answers

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

[tex]f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\[/tex]

f = - 0.143 m = - 14.3 cm

Negative focal length indicates that combination will act as diverging lens.

the official world land speed record is1228.0km/h are on October 15,1997,by Andy green in the jet engine car then express the speed in the meters per second​

Answers

Answer:

v = 341.11 m/s

Explanation:

Given that,

The official world land speed was recorded as 1228.0km/h on October 15,1997.

We need to find the speed in m/s.

We know that,

1 km = 1000 m

1 h = 3600 s

So,

[tex]v=1228\ km/h\\\\=1228\times \dfrac{1000\ m}{3600\ s}\\\\v=341.11\ m/s[/tex]

So, the required speed is 341.11 m/s.

Drag and drop a term to match these examples with the correct level of organization.

Tissue:

Organ:

Organ system:

--------------------------------------------------------------------------------------------------------------

A-cardiac muscle

B-circulatory system

C-heart

D-human body

Answers

Answer:

Tissue: cardiac muscle

Organ: Heart

Organ System: Human Body, Circulatory System

Explanation:

The cardiac muscle makes up an organ, making it a tissue

The Heart makes up a organ system, making it an organ

Both the human Body and The Circulatory System make up an organism, making them organisms

Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the aperture. The diameter of the central bright area is 5.4 cm. What is the diameter of the aperture?

Answers

Answer:

The answer is "[tex]1.144 \times 10^{-4} \ m[/tex]".

Explanation:

[tex]w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\[/tex]

   [tex]=\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m[/tex]

WILL MARK BRAINLIEST PLS HELP. A 3.33 x 10-6 F capacitor stores
8.15 x 10-4 J of energy. What is the
voltage across the capacitor?
(Pic shown)

Answers

Answer:

15.64 V

Explanation:

From the question given above, the following data were obtained:

Capacitor (C) = 3.33x10¯⁶ F

Energy (E) = 8.15×10¯⁴ J

Voltage (V) =?

The voltage across the capacitor can be obtained as follow:

E = ½CV²

8.15×10¯⁴ = 3.33x10¯⁶ × V²

Divide both side by 3.33x10¯⁶

V² = 8.15×10¯⁴ / 3.33x10¯⁶

Take the square root of both side

V = √(8.15×10¯⁴ / 3.33x10¯⁶)

V = 15.64 V

Thus, the voltage across the capacitor is 15.64 V

Answer:

22.12

Explanation:

on accellus

The center of mass of a uniform disk of radius
Ris located where?​

Answers

Answer:

At the centre

Explanation:

To prove the position of the centre of mass, usually we take a strip across the circular disc and call it dy; calculate the length of the strip; calculate the mass per unit area of the disc. And then when we carry out some integral operations using R and -R as the boundaries we will arrive at y_cm = 0 which means the centre y_cm is at the centre of mass of this uniform disc.

Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note that the latent heat is equal to the change in enthalpy, and that liquid nitrogen boils at 77 K. The system is kept at a constant pressure of 1 atm. Assuming that you can treat the gas as ideal gas and that the volume of the liquid is approximately zero, compute the binding energy of a nitrogen molecule in the liquid. (the binding energy is the difference in internal energy per molecule between the liquid and gas)

a. 4.2e^-18 J
b. 9.4e^-21 J
c. 4.8e^ 24 J
d. 2.1e^-19 J
e. 1.3e^-23 J

Answers

Suppose that we use a future boil liquid nitrogen

in which reaction is there a transformation of mass into energy

Answers

Answer:

There is a transformation of mass into energy un nuclear fusion

Magnesium hydroxide is a common ___?

Answers

Answer:

Hello There!!

Explanation:

The answer is=> It is a common component of antacids.

hope this helps,have a great day!!

~Pinky~

HELP: I’ve been stuck on this problem for a while now.

Answers

Answer:

a.work done=force *displacement

=500N*46m

=23000 Joule

b.power=work done/time taken

=23000/25

=920 watt

c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)

=60kg*9.8m/s*14m

=8232 joule

Explanation:

A student pushes a laptop cart down the hallway by applying 20 Newtons force. The student pushes it 10 meters and
then stops at the water fountain with the cart and haves a sip of water. While he drinks from the water fountain, what
type of work is being done to the laptop cart.

Answers

Answer:

None.

Explanation:

By definition, work is a process that it happens when an applied force

        causes an object to change its position, i.e. to have a displacement.

        Since the laptop cart is at rest while he stops at the water fountain, no  

       net work done is on the laptop cart.

how hot can the desert get​

Answers

Answer:

134 f

Explanation:

The hottest temperature ever reliably measured in a desert was 134 degrees F, in Death Valley of the Mojave Desert in 1913.

not as hot as me.jk.

Temperature. During the day, desert temperatures rise to an average of 38°C (a little over 100°F). At night, desert temperatures fall to an average of -3.9°C (about 25°F). At night, desert temperatures fall to an average of -3.9 degrees celsius (about 25 degrees fahrenheit).

Desert surfaces receive a little more than twice the solar radiation received by humid regions and lose almost twice as much heat at night. Many mean annual temperatures range from 20-25 degrees Celsius. The extreme maximum ranges from 43.5-49 degrees Celsius. Minimum temperatures sometimes drop to -18 degrees Celsius.

A spacecraft is powered by electricity generated by the heat produced when 23894Pu decays with a half-life of 87.75 y. Engineers predict that the spacecraft will have insufficient power to operate its instruments when the amount of 238 94Pu in its power generators drops below 67 % of the amount it had at launch on September 1, 1977

Required:
In what year will its instruments cease to function?

Answers

And what year will it’s instruments used to function

40 points! Will give brainliest!

Which of the following describes an advantage of AC electricity over DC electricity?

A) AC is found in most low voltage operations.
B) AC is provided as strong, short bursts of electricity.
C) AC can be transported over long distances.
D) AC can be used is small electronic devices.

Answers

It’s C “ Ac can be transported over long distances.”

PLEASE HELP ME ASAP!!!!

Answers

Both mic and speaker

Explain how newtons first law applies to the image to the left.

Answers

can i get the images plz

What is the period of a wave, with a frequency of 0.75 Hertz?

Answers

Answer:

wavelength  4 cm

Explanation:

Write a method which prevents ice from melting quickly.​

Answers

Answer:

blocks of ice are usually covered with cloth or sawdust while being stored

A bat emits a sound at a frequency of 30.0 kHz as it approaches a wall. The bat detects beats such that the frequency of the echo is 900 Hz higher than the frequency the bat is emitting. The speed of sound in air is 340 m/s at emits a sound at a frequency of 30.0 kHz
(a) What is the speed of the bat?
(b) What is the wavelength of the sound that the bat hears15?

Answers

Answer:

a) the speed of the bat is 5.02 m/s

b) the wavelength of the sound that the bat hears is 0.011 m

Explanation:

Given the data in the question;

Frequency of sound emitted by a bat f = 30.0 kHz = 30000 Hz

detected frequency by the bat δf = 900 Hz

speed of sound in air c = 340 m/s

Let speed of sound and speed of bat be c and [tex]v_s[/tex] respectively;

Now, frequency of the sound that is coming from the bat towards the wall due to DROPPLER EFFET will be;

f₁ = ( c / ( c - [tex]v_s[/tex] ) )f ----- let this be equ 1

Also, frequency does not change after deflection. The bat becomes an observer as the dropper is shifted because the reflected sound wave is coming towards it;

Hence, Doppler shifted frequency will be;

f₂ = ( (c + [tex]v_s[/tex] ) / c )f₁

from equ 1, f₁ = ( c / ( c - [tex]v_s[/tex] ) )f, so we substitute

f₂ = ( (c + [tex]v_s[/tex] ) / c ) × ( c / ( c - [tex]v_s[/tex] ) )f

f₂ = ( (c + [tex]v_s[/tex] ) / ( c - [tex]v_s[/tex] ) )f

∴ beat frequency will be;

δf = f₂ - f = ( (c + [tex]v_s[/tex] ) / ( c - [tex]v_s[/tex] ) )f - f

δf = ( 2[tex]v_s[/tex] / c - [tex]v_s[/tex] )f

δf = ( 2[tex]v_s[/tex] / c - [tex]v_s[/tex] )f

2f/δf = c - [tex]v_s[/tex] / [tex]v_s[/tex]

2f/δf = c/[tex]v_s[/tex] - [tex]v_s[/tex] / [tex]v_s[/tex]

2f/δf = c/[tex]v_s[/tex] - 1

c/[tex]v_s[/tex] = 2f/δf + 1

[tex]v_s[/tex] =  c / (2f/δf + 1)

now, we substitute in our values;

[tex]v_s[/tex] =  340 / ((2×30000 / 900 ) + 1)

[tex]v_s[/tex] =  340 / (66.6666 + 1)

[tex]v_s[/tex] =  340 / 67.6666

[tex]v_s[/tex] =  5.02 m/s

Therefore, the speed of the bat is 5.02 m/s

b) the wavelength of the sound that the bat hears

frequency of reflected wave is;

f₂ = f + δf = 30000 + 900 = 30900 Hz

λ₂ = c / f₂

we substitute

λ₂ = 340 / 30900

λ₂ = 0.011 m

Therefore, the wavelength of the sound that the bat hears is 0.011 m

A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what
depth it sinks when placed in a tank of water (assume the sides are sufficiently high,
so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.​

Answers

Answer:

60

Explanation:

A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what

depth it sinks when placed in a tank of water (assume the sides are sufficiently high,

so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.​

what are conductors and insulators​

Answers

Conductors are materials that permit electrons to flow freely from particle to particle. ... Conductors allow for charge transfer through the free movement of electrons. In contrast to conductors, insulators are materials that impede the free flow of electrons from atom to atom and molecule to molecule.
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