The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning
Answer:
law of action and reaction.
Explanation:
In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.
In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.
Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body
An electric force is an attractive or repulsive interaction. Newton's laws of motion define how it affects things, just like any other force. Yes, the second pulling on the first.
How does Newton's third law explain in terms of electricity?An electric force is an attractive or repulsive interaction between any two charged things. Newton's laws of motion define how it affects things, just like any other force.
The motion of objects under the influence of such a force or combination of forces is studied using Newton's laws.
The analysis generally starts with the creation of a free-body diagram in which the kind and direction of the various forces are represented by vector arrows.
Newton's laws of motion define how it affects things, just like any other force. Hence Yes, the second pulling on the first.
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A surfer paddles to where the waves are sinusoidal with crests 14 m apart. He bobs a vertical distance 3.6 m from trough to crest, which takes 1.5 s. Find the wave speed, & describe the wave.
Answer:
v = 9.34 m/s
Explanation:
Given that,
The distance between crests, [tex]\lambda=14\ m[/tex]
The vertical distance from trough to crest = 3.6 m
Time taken, t = 1.5 s
The amplitude of wave = vertical distance from trough to crest /2
= 3.6/2
= 1.8 m
The speed of the wave is given by :
[tex]v=f\times \lambda\\\\=\dfrac{\lambda}{T}\\\\=\dfrac{14}{1.5}\\\\=9.34\ m/s[/tex]
So, the speed of the wave is 9.34 m/s.
A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.
A) What is the magnitude of its angluar acceleration(rad/s^2)?
B) How many seconds does it take the merry-go-round to reachits operating speed?
Answer:
(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²
(B) Time of motion 240.2 s
Explanation:
Given;
final angular speed, ωf = 2.5 RPM
angular distance, θ = 5 rev = 5 x 2π = 10π rad
initial angular speed, ωi = 0
final angular speed in rad/s;
[tex]\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\[/tex]
(A) the magnitude of its angular acceleration(rad/s^2);
[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2[/tex]
(B) Time of motion;
[tex]\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s[/tex]
Three point charges are arranged along the x axis. Charge q1 = -4.10 nC is located at x= 0.250 mand charge q2 = 2.20 nC is at x= -0.320 m . A positive point charge q3 is located at the origin.
What must the value of q3 be for the net force on this point charge to have magnitude 3.10 μN ? (ans in nC)
What is the direction of the net force on q3? + or - direction
Where along the x axis can q3 be placed and the net force on it be zero, other than the trivial answers of x=+[infinity] and x=−[infinity]? (ans in m)
Answer:
1) q₃ is approximately -7.58 nC
2) The direction of the net force on 'q₃' is the negative '-' direction
3) For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m
Explanation:
1) The force, 'F', between two charged spheres is given as follows;
[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]
The net force acting on the point charge, 'q₃', is given as follows;
[tex]F_{NET} = \dfrac{k \cdot q_1 \cdot q_3}{x_1^2} + \dfrac{k \cdot q_2 \cdot q_3}{x_2^2}[/tex]
By substituting the given values, we have;
[tex]F_{NET} = 3.10 \ \mu N = \dfrac{k \cdot (-4.10 \ nC) \cdot q_3}{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC \cdot q_3}{(-0.320 \ m)^2}[/tex]
[tex]3.01 \ \mu N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.250 \ m) ^2} + \dfrac{k \cdot 2.20 \ nC }{(-0.320 \ m)^2} \right) = -\dfrac{14117 \ nC \cdot K}{320}[/tex]
[tex]\therefore q_3 = 3.01 \ \mu N \times -\dfrac{320 \ m^2}{14117 \ nC \cdot K}[/tex]
K = 9 × 10⁹ N·m²·C⁻²
[tex]\therefore q_3 = 3.01 \ \times 10^{-6} \ N \times -\dfrac{320 \ m^2}{14117 \times 10^{-9} \ C \times 9 \times 10^9 \ N \cdot m^2 \cdot C^{-2}}= -7.58 \ nC[/tex]
q₃ ≈ -7.58 nC
2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin
The net force's direction on q₃ will be in the '-' direction
3) For zero net force, we have;
The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m
Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1
By substitution, we have;
[tex]0 \ N= q_3 \cdot \left ( \dfrac{k \cdot (-4.10 \ nC) }{(0.57 - r_1 ) ^2} + \dfrac{k \cdot 2.20 \ nC }{(r_1)^2} \right)[/tex]
[tex]\therefore \dfrac{k \cdot 4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{k \cdot 2.20 \ nC }{(r_1)^2}[/tex]
From which we have;
[tex]\dfrac{4.10 \ nC }{(0.57 - r_1 ) ^2} = \dfrac{2.20 \ nC }{(r_1)^2}[/tex]
(r₁)²×4.10 = 2.20 × (0.57 - r₁)²
From the above equation, we have;
95,000·r₁²+ 125,400·r₁-35739 = 0
Solving, using a graphing calculator we get;
r₁ ≈ 0.241 or r₁ ≈ -1.561
Where, 'r₁', is measured from 'q₂', therefore, we have;
r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881
Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero
Please find the density of question 4,6 and 10!Be sure to show all steps!Thank you!
Answer:
Explanation:
4. Density of water = 1.01g/ml
6: Mass of silver = 892.5g
8: Mass of 157.8g I gave the answer as mass, even though it asked for weight.
2. What is the y-component of a 95.3 N force that is exerted at 57.1
degree to the horizontal, *
Answer: 80N
Explanation:
The y-component would be the magnitude of the force multiplied by the sine of the angle.
[tex]95.3*\sin(57.1)=80N[/tex]
The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
What is Force?Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.
It can be expressed as:
F = m a
Where, F= Force
m= mass of the object
a= acceleration
In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,
so, For x component [tex]F_x[/tex] = Fcosθ
For y component [tex]F_y[/tex] = F sinθ
Given, F= 95.3 N ; θ= 57.1 °
[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]
Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.
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What is the specific heat of water? A. 1.00 J/gºC
B. 4.18 J/gºC
C. 9.18 J/gºC
D. 8.36 J/gºC
Answer:
B 4.18J\g degree C is the specific heat of water
What reasoning correctly pairs a body system with its relationship to the digestive system?
Group of answer choices
excretory system; transports nutrients from the small intestine to other tissues
respiratory system; obtains oxygen so the energy in nutrients can be extracted
circulatory system; regulates and controls digestive functioning
nervous system; removes wastes from the blood SCIENCE
Answer:
I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.
Explanation:
Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.
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3V battery is used with a 15 ohm resistance.What is the current?
Answer:
0.2 A
Explanation:
V= IR
3 = I × 15
I = 3/15
= 1/5 = 0.2 A
The flow of current in a battery will be "0.2 A". To understand the calculation, check below.
Current, Resistance and VoltageAccording to the question,
Voltage, V = 3 V
Resistance, R = 15 ohm
We know the relation,
→ Voltage (V) = Current (I) × Resistance (R)
or,
→ Current, I = [tex]\frac{V}{R}[/tex]
By substituting the values,
= [tex]\frac{3}{15}[/tex]
= 0.2 A
Thus the above answer is correct.
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If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain using Newton's second law
Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
Answer:
the bike
Explanation:
it has less mass than the motorcycle so so it would have more acceleration
A net force of 30 N is applied to an object, causing it to accelerate at 20m/s^2. What is the mass of the object?
Answer:
mass of that object is = 30 × 29 = 870N
If a girl does 1,350 Joules of work to pedal her bike using a force of 75 N, how far did she ride her bike?
Answer:
D = 18m
Explanation:
We use this formula:
Work = Force * Distance
Now, we replace it:
W = F*D
1,350J = 75N * D
D = 1,350/75
D = 18m
Hope it was helpful ;)
83. A sailboat travels south at 12.0 km/h with respect to the
water against a current 15.0° south of east at 4.0 km/h.
What is the boat's velocity?
Answer:
The magnitude of the boat's velocity is 8.21 km/h.
Explanation:
We can find the boat's velocity as follows:
[tex] \Epsilon V_{x} = V_{w_{x}} + V_{b_{y}} [/tex]
[tex] \Epsilon V_{y} = V_{w_{y}} + V_{b_{y}} [/tex]
Where:
[tex]V_{w_{x}}[/tex] and [tex]V_{w_{y}}[/tex] are the components of the velocity of the water in the x and y-direction
[tex]V_{b_{x}}[/tex] and [tex]V_{b_{y}}[/tex] are the components of the velocity of the boat in the x and y-direction
Since the angle is 15° we have:
[tex] \Epsilon V_{x} = -4.0 km/h*sin(15) + 0 = -1.04 km/h [/tex]
[tex] \Epsilon V_{y} = 4.0 km/h*cos(15) - 12.0 km/h = -8.14 km/h [/tex]
Now, the velocity of the boat is:
[tex] V = \sqrt{V_{x}^{2} + V_{y}^{2}} = \sqrt{(-1.04 km/h)^{2} + (-8.14 km/h)^{2}} = 8.21 km/h [/tex]
Therefore, the magnitude of the boat's velocity is 8.21 km/h.
I hope it helps you!
According to the article, why might acting happy actually make one happy?
Answer: mirror neurons are the reason people usually reflect the behavior of those around them and have been linked to the ability to empathize. People are attracted to happy people because it seems to boost our mood.
Explanation:
Answer:
Some psychologists think that you can trick your brain into feeling happy by acting happy. Acting happy might actually make one happy by mirror neurons. This is the reason people usually reflect the behavior of those around them and have been linked to the ability to empathize. People are attracted to happy people because it seems to boost our mood. The three components of emotion are cognitive, physiological, and behavioral. There is actually some scientific evidence to suggest that smiling, even when you are not feeling happy, can make you happy. This idea is called the facial feedback hypothesis. Happiness, and smiling, can also be contagious and make others around them want to smile. People often mimic the facial expressions of others.
Explanation:
100% on Edge 2023!! You're welcome :) :) :) :)
A force of 20N acted on a ball thereby imparting an impulse of 70N's to the ball. For how long did the force act on the ball?
Answer:3.5 seconds
Explanation:
What might happen if the earth didn't have an atmosphere?
A Everything would go flying off into space.
B.
We wouldn't be able to breathe.
С
The earth's rotation would stop.
D
The seasons would be longer.
If the earth didn't have an atmosphere, we wouldn't be able to breathe. So, option B.
The atmosphere serves as a blanket, maintaining Earth's normal temperature. All of the gases required to support life on Earth are present in it. The ozone layer in the atmosphere shields the Earth from dangerous UV radiation.
Infrared radiation from the earth is reflected back to the surface by the lowest layers of the atmosphere. The atmosphere effectively traps the thermal radiation that the planet receives from the sun throughout the day.
The surface of the world would become too cold to support life if the atmosphere weren't present.
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Complete play the table by writing the location orientation size and type of image formed by the lenses below.
Please help me guyss!! :(
Answ
Explanation:
HOPE IT HELPS..
The image formed by the location of object is beyond 2F the image by convex lenses is between F and 2F and is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real.
What is a convex lens ?A convex lens is a type of lens that is projected outwards and shows the real image of an object. Whereas a concave lens is curved inwards and shows virtual image of objects.
The image formed at by the location of convex lenses beyond 2F is inverted, smaller and and real image. If it is at 2F, the image is inverted with the same size and real. If the lens is placed between F and 2F the image formed is beyond 2F and it will be inverted, enlarged and real.
If the object is at F , no image will be formed. If it at between F and the lens, then the image forms beyond 2 F which is upright, enlarged and virtual.
The object be at any position with respect to the focal length of lens, the image formed by a concave lens is between F and the lens and upright, small and virtual.
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Who thinks this a ufo? The following images are from a rare footage.
Answer:
That might be a sled ngl but it looks like a ufo but it's definitely not
Answer:
the reptilians gave there tech to the nazis and the reptilians are currently living underground in Antarctica but id'k about that pic
Explanation:
A solution contained 0.05g of sodium hydroxide in 25 cm3 of water
What is the concentration of the solution in g/dm3?
Given :
A solution contained 0.05g of sodium hydroxide in 25 cm3 of water.
To Find :
The concentration of the solution in g/dm³.
Solution :
We know, 1 cm = 0.1 dm
So, 1 cm³ = 0.001 dm³
Now, 25 cm³ = 25 × 0.001 dm³
25 cm³ = 0.025 dm³
Now, concentration of the solution in g/dm³ is [tex]\dfrac{0.05\ g}{0.025\ dm^3} = 2 \ g/dm^3[/tex].
Therefore, the concentration of the solution is 2 g/dm³.
Need help with physics.
Question: A 65 kg child riding a Ferris wheel has a tangential speed of 9.5 m/s. Find the magnitude of the centripetal force on the child if the distance from the child to the axis of the wheel is 20 m.
The centripetal force : F = 293.3125 N
Further explanationGiven
mass = 65 kg
v = 9.5 m/s
r = 20 m
Required
the centripetal force
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
[tex]\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}[/tex]
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
Input the value :
F = 65 x 9.5² / 20
F = 293.3125 N
Julieta kicks a 0.2 kg soccer ball already rolling in the same direction at 2.5 m/s. The ball leaves her foot at a speed of 20 m/s after the kick
Answer:
3.5kgm/s
Explanation:
We can calculate the momentum of Julieta
momentum = m(v-u)
Momentum = 0.2(20-2.5)
Momentum = 0.2(17.5)
Momentum = 3.5
Hence the momentum of Julieta is 3.5kgm/s
A refrigerator having a power rating of 350W operates for 12 hours a day. calculate the cost of electrical energy to operate it for 30 days. the rate of electrical energy is rs4.50 per kWh. calculate the minimum fuse rating to be put in the refrigerator circuit if the supply voltage is 240V.
Answer:
See the answers below.
Explanation:
The cost of energy can be calculated by multiplying each given value, a dimensional analysis must be taken into account in order to calculate the total value of the cost in Rs.
[tex]Cost=0.350[kW]*12[\frac{hr}{1day}]*30[days]*4.5[\frac{Rs}{kW*hr} ]=567[Rs][/tex]
The fuse can be calculated by knowing the amperage.
[tex]P=V*I[/tex]
where:
P = power = 350 [W]
V = voltage = 240 [V]
I = amperage [amp]
Now clearing I from the equation above:
[tex]I=P/V\\I=350/240\\I=1.458[amp][/tex]
The fuse should be larger than the current of the circuit, i.e. about 2 [amp]
If 59.1 g of pure metal uses 890.9 j of energy to heat it from 26.1 c to 59.6 c, identify the metal
Answer: The metal is iron.
Explanation:
We have 59.1 grams of a given metal.
We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C
First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.
ΔT = 59.6°C - 26.1°C = 33.5°C
Now we can find the specific heat, which is calculated as:
c = Ε/(ΔT*m)
Where:
E = energy given to the material = 890.9 J
m = mass of the material = 59.1 gr
ΔT = change in temperature = 33.5°C
Replacing these in the above equation we get:
c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)
Now we need to look at a table of specific heats and see which metal has this specific heat.
We can see that iron is the best match, so we can assume that the metal is iron.
Which of the following is part of the cycle of violence? (Select all that apply)
A. period of calm
B. violent episode
C. making up
D. tension-building
Which of the following technologies would produce the most energy in light
waves?
A. Infrared sensor on a DVD player
B. Wireless communications transmitter
C. Microwave industrial drying equipment
D. Compact fluorescent lightbulb
Answer:
D. Compact fluorescent lightbulb
Explanation:
Compact fluorescent lightbulb
A compact fluorescent light bulb would produce the most energy in light
waves, therefore the correct option is D.
What is electromagnetic radiation?Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.
Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.
Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.
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A train travels 20,000km in 500h. What is the average speed of the train?
Answer:
40 mph
Explanation:
pls mark as brainliest
If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?
F₂ = 1.723 x 10⁸ N
Further explanationGiven
Area of small piston : 0.004 m²
Area of large piston : 3.5 m²
Force 225 N
Required
Force applied
Solution
Pascal Law :
F₁/A₁=F₂/A₂
225/0.004 m² = F₂/3.5² m²
F₂ = 1.723 x 10⁸ N
Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.
Answer:
The first one with the big plus in the middle and negatively charged electrons around.
Explanation:
The first image with the plus sign in the middle and negatively charged electrons around it shows how J.J. Thomson envisioned the atom.
J.J. Thomson proposed the "plum pudding" model of the atom. This model suggested that atoms were composed of a positively charged "pudding" with negatively charged electrons embedded within it.
1. Thomson conducted experiments with cathode rays, which are streams of negatively charged particles emitted from cathodes in vacuum tubes. Through his experiments, Thomson discovered that cathode rays were composed of negatively charged particles, which he named electrons. Based on his observations, Thomson proposed the "plum pudding" model, also known as the "raisin bread" model.
According to this model, atoms were made up of a positively charged substance, like a pudding, with negatively charged electrons scattered throughout it, like raisins in bread. Thomson suggested that the positive charge was evenly distributed throughout the atom, creating a uniform positive charge in the "pudding." This model was a significant departure from the previous understanding of the atom as an indivisible, homogeneous sphere.
Thomson's plum pudding model provided an early depiction of atomic structure, showing that atoms were not indivisible but composed of smaller subatomic particles. However, later experiments, particularly those conducted by Ernest Rutherford, led to the discovery of the atomic nucleus, which necessitated the revision of Thomson's model.
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Two identical conducting spheres are charged with a net charge of +5.0 q on the first sphere and a net charge of −8.0 q on the second sphere. The spheres are brought together, allowed to touch, and then separated. What is the net charge on each sphere now?
Answer:
The net charge on each sphere is -1.5 q
Explanation:
Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q = \dfrac{Q_1 + Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]Q = \dfrac{5 \ q+ (-8 \ q)}{2} = -\dfrac{3 \ q}{2} = -1.5 \ q[/tex]
The net charge on each sphere, Q = -1.5 q.
The net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
What is charge?Conductors are materials that allow the electrons which are the carriers of the charges to move between them, and when two conductors come in contact, the available charge is shared by the two conductors and the resultant like charges will spread on the surface of the conductor due to the repellent effect between similar charges such that if the conductors are identical, the resultant charge becomes evenly shared by the conductors when they become separated again
The given parameters of the conducting spheres meant to touch are;
The net charge on the first sphere, Q₁ = +5.0 q
The net charge on the second sphere, Q₂ = -8.0 q
The net charge on each sphere after touching and then separated, 'Q', is given as follows;
[tex]Q=\dfrac{Q_1+Q_2}{2}[/tex]
Therefore, by substituting the known values of the variables, we have;
[tex]\dfrac{5q+(-8q)}{2}=-1.5q[/tex]
Hence the net charge on each sphere after spheres are brought together, allowed to touch is -1.5 q
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How would the force between two charged particles change if one of the charges were to triple in strength (3x stronger)?
A. 9x stronger
B. 1/3 as strong
C. 1/9 as strong
D. 3x stronger
Answer:
The correct option is (d). "3x stronger".
Explanation:
The force between two charged particle is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
If one charge is tripled, [tex]q_1'=3q[/tex]
New force will be :
[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]
It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.