Answer:
mass
Explanation:
Answer:
Mass wind water ice gravity
A ball has a mass of 140 g what is the force needed to accelerate the mall at 25 m/s squared
Answer:
[tex]\boxed {\boxed {\sf 3.5 \ Newtons}}[/tex]
Explanation:
Force is the product of mass (in kilograms) and acceleration (in meters per square second).
[tex]F=ma[/tex]
The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.
1 kg=1000 g[tex]140 \ g *\frac{1 \ kg}{1000 \ g}=\frac{140}{1000} \ kg =0.14 \ kg[/tex]Substitute the values into the formula.
[tex]F= 0.14 \ kg * 25 \ m/s^2[/tex]
Multiply.
[tex]F= 3.5 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 NewtonOur answer equals 3.5 Newtons[tex]F= 3.5 \ N[/tex]
3.5 Newtons of force are required.
2. Which one of the following liquids is more suitable for making a simple barometer?
Answer:
Emm I don't see the liquid options but usually mercury is used for making barometers...
Explanation:
the surface of a mirror is flat.
Answer:
plane on edge
Explanation:
A boy projects a ball vertically upwards with velocity v from
the top of a building where it rises and then it falls down to hit
the ground with velocity 2v. So, the total distance covered by
the ball is ....
(g = 10 m/s)
Answer:
yes? what is the quseten
Explanation:
v is the max speed it can go if you droped a egg and a watermelon off a roof 20ft high thay would hit the ground at the same time becuse gravaty will effect them qualy. if you drop them from a jet liner 20,000 ft up thay will hit max.v. wich depends on mass so thay will hit at differnt times.
3. Our favorite nature explorer Steve Irwin is currenty warking with crocodiles in the Nile River. One of the big boy crocs gets hungry and takes off after some prey. Steve and his wife Terri want to know how much kinetic energy the croc exhibits when chasing prey. The croc has a mass of 600 kg and can swim at a velocity of 4 m/s. Calculate the kinetic energy of the croc,
Answer:
K.E = 4800 Joules.
Explanation:
Given the following data;
Mass = 600 kg
Velocity = 4 m/s
To find the kinetic energy;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the equation, we have;
[tex] K.E = \frac{1}{2}*600*4^{2}[/tex]
[tex] K.E = 300 * 16 [/tex]
K.E = 4800 Joules.
A lever with a mechanical advantage of .4 is more advantageous than just picking up the object with your hands and lifting it up.
True
False
Answer:
true
Explanation:
The temperature of an object is -153°C. Its temperature is raiselt to 273°C. What is the
temperature change of the object?
426
699
153
120
Answer:
426
Explanation:
I think the answer is 426 or 120 but we. can get 120 when we add
A rain drop of radius 0.3mm has terminal velocity 1m/s in air. The viscosity of air is 18X10-5 poise, then viscous force is
Answer:
F = 1.0178 × 10^(-2) dyne
Explanation:
From stokes law, the viscous force also known as drag force on rain drop is given by the formula;
F = 6πηrv
Where;
η is viscosity
r is radius
v is velocity
We are given;
η = 18 × 10^(-5) poise
r = 0.3 mm = 0.03 cm
v = 1 m/s = 100 cm/s
Thus;
F = 6π × 18 × 10^(-5) × 0.03 × 100
F = 1.0178 × 10^(-2) dyne
what disadvantage of convex mirror
☁️ Answer ☁️
The main disadvantage of convex mirrors is that they show a distorted picture of what is behind you. Distances are seen not as they are in reality and things appear closer than they really are. They are showing cars approximately twice as far away as they actually are.
Hope it helps.
Have a nice day hyung!~ ￣▽￣❤️
Answer:
disadvantage is that convex mirror is that they make it appear like those objects are at a more noteworthy distance than they actually are. It always gives a virtual, erect and a diminished image.
Which of the following features make Earth and Venus similar to each other?
Answer:
A. size and mass
Explanation:
Can you make predictions about the Moon's appearance?
Answer:
answer: no
Explanation:
what instrument will be used to measure the volume of a box
Answer:
A ruler.
Explanation:
Just measure height, length and width and multiply each.
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?
Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3
v3=.26m/s 2.5+70
Which of the following statements is true? Thunderstorms are not dangerous The eye of a hurricane is the most danger Tornadoes form when wind change all of the above
honestly they all seem wrong to me but it's not giving me another option hurry if possible
Answer:
False
Explanation:
includess lighting and powerful winds over 50Mph,creates hail and causes flash flooding and also tornadoes
An object of mass m1= 5kg placed on a frictionless, horizontal table is connected to a string that passes over a pulley and then is fastened to a hanging object of mass m2= 8kg as shown in figure.
Calculate,
(a) the acceleration (a) of the objects
(b) the tension (T) in the string.
(a) The acceleration of the objects (in m/s2) is
Answer for part 1
(b) The tension in the string (in Newtons) is
Answer for part 2
Answer:
a. 6.04 m/s^2 (3 sig. fig.) b. T = 30.2 N
Explanation:
a) Assume that the acceleration due to gravity is 9.81 m/s^2 downwards
8x9.81 = (5+8)a
a = 6.04 m/s^2 (3 sig. fig.)
b) Using the results from (a)
T = 5(6.04)
T = 30.2 N
Which experimental result led to the inference that atoms have a dense,
positive center?
A. A few alpha particles bounced off a thin sheet of gold foil.
B. Most alpha particles passed straight through a thin sheet of gold
foil.
C. The beam in a cathode ray tube was moved by a magnetic force.
D. The beam in a cathode ray tube was moved by an electric force.
A few alpha particles bounced off a thin sheet of gold foil.
The correct option for the given question about Rutherford Gold Foil Experiment is Option A) "A few alpha particles bounced off a thin sheet of gold foil".
What caused Rutherford's gold-foil experiment's alpha particles to bounce off?Rutherford predicted that the particles will pierce the foil without any resistance. But he discovered that as the particle bounced off through the foil, its course would change or be deflected. Like charges repel one another, which is the reason behind this.
Thus we can conclude that Rutherford Gold Foil Experiment (A few alpha particles bounced off a thin sheet of gold foil) results led to the inference that atoms have a dense positive centre.
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The description of the structure of the atom is called the??
I think for this it is atomic model
why an inclined is considered as simple machine
What is 3^7*8^3*5^6?
Answer:
17496000000
Explanation:
4. You are walking at a leisurely pace of .75 m/s when you hear the train coming and start running to catch it. Over the next 10 seconds, you speed up to 3.5 m/s and catch your train! What was your acceleration over that time?
Answer:
0.275 m/s²
Explanation:
The acceleration of an object is defined as the change in velocity over the change in time.
a = Δv/Δt a = (v - v₀)/tWe are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.
The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.
a = (3.5 - 0.75)/10 a = 2.75/10 a = 0.275 m/s²Our acceleration over that time was 0.275 m/s² in order to catch the train.
Equal masses of water at 80°C and paraffin at 20°C are mixed in a container. The specific
heat capacity of water is twice that of paraffin. What is the final temperature of the
mixture?
O 60°C
O 50°C
O 40°C
O 30°C
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
b) Increases to its doute
d) Remains constant
a) Remains constant,
c) Increases to its four times
Answer:
Decreases to half.
Explanation:
From the question given above, the following data were obtained:
Initial mass (m₁) = m
Initial force (F₁) = F
Initial acceleration (a₁) =?
Final mass (m₂) = ½m
Final force (F₂) = ¼F
Final acceleration (a₂) =?
Next, we shall determine a₁. This can be obtained as follow:
F₁ = m₁a₁
F = ma₁
Divide both side by m
a₁ = F / m
Next, we shall determine a₂.
F₂ = m₂a₂
¼F = ½ma₂
2F = 4ma₂
Divide both side by 4m
a₂ = 2F / 4m
a₂ = F / 2m
Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:
a₁ = F / m
a₂ = F / 2m
a₂ : a₁ = a₂ / a₁
a₂ / a₁ = F/2m ÷ F/m
a₂ / a₁ = F/2m × m/F
a₂ / a₁ = ½
Cross multiply
a₂ = ½a₁
From the illustrations made above, the acceleration of the car will decrease to half the original acceleration
Speed versus Time
The graph below suggests
A. a constant speed of 3 m/s followed by speed of 1 m/s
B. a constant velocity of 2 m/s followed by speed of zero
C. a constant speed of 4 m/s followed by speed of zero
D. a constant acceleration of 2 m/s followed by speed of zero
F. a constant speed of 2 m/s followed by speed of zero
Answer:
a constant speed of 2 m/s followed by speed of zero
Explanation:
I got it right on the test.
All of the following are possible transition points that occur during adulthood except __________.
A.
marriage
B.
rapid physical growth
C.
parenthood
D.
divorce
Answer:
B
Explanation:
.....................
Answer:
B. Rapid Physical Growths
to what height will a 250g soccer ball rise to if it is kicked directly upwards at 8 meters per second
Answer:
h = 3.26 m
Explanation:
Given that,
Mass of the soccerball, m = 250 g
Speed of the ball, v = 8 m/s
We need to find the height upto which the soccerball is raised. Let the height be h. Using the conservation of energy i.e.
[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{8^2}{2\times 9.8}\\\\h=3.26\ m[/tex]
So, it will raised up to a height of 3.26 m.
Rahul is carrying a load of 80 kg a distance of 200m in 5 minutes but the same lord is carried by Reena to the same distance in 4 minutes who has. more power.
Answer:
Reena has more power.....
Hope it helps!!!
PSYW - Please Show Your Work
A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg
and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.
Determine the energy required to raise the temperature of the radiator-water system by
1°K
Answer:
9.66E4 J
Explanation:
We have that the energy required to raise the temperature of the radiator-water system by
1°K
E=116.85KJ
From the question we are told
A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.
Determine the energy required to raise the temperature of the radiator-water system by 1°K
Generally the equation for the Energy is mathematically given as
[tex]E=((mc)_i+mc_w)dt\\\\Therefore\\\\E=(45* 450 +4200*23)1\\\\E=116850J\\\\E=116.85KJ\\\\[/tex]
Therefore
the energy required to raise the temperature of the radiator-water system by
1°K
E=116.85KJ
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Therapeutic boarding schools help parents cope with their teens who have borderline personality disorder in all of the
following ways except
A. teaching the parents how to positively support their teen while they are at home
B. providing family therapy while the teen is in treatment
c. teaching the parents to persistently support the teen's unstable self-image
D. teaching the patient how to interact appropriately with their peers
C. Teaching the parents tp persistetly support the teen's unstable self-image
Explanation:
Therapeutic boarding schools doesn't help parents cope with their teens by: c. teaching the parents to persistently support the teen's unstable self-image.
The types of personality disorder.In Psychology, there are different types of personality disorder and these include the following:
Narcissistic personality disorder.Obsessive-compulsive personality disorder.Antisocial personality disorder.Avoidant personality disorder.Borderline personality disorder.Basically, a therapeutic boarding school is an institution that is established to help parents positively cope with offspring who have borderline personality disorder.
However, therapeutic boarding schools doesn't teach parents to persistently support any teen's unstable self-image.
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One mole of iron (6 x 10^23 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 x 10^-10 m. You have a long thin bar of iron, 2.3 m long, with a square cross section, 0.12 cm on a side. You hang the rod vertically and attach a 149 kg mass to the bottom, and you observe that the bar becomes 1.17 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.
ks = 20014.1 N/m
Number of side-by-side long chains of atoms = 4.81e^12
Number of bonds in total length = 1.096e^10
What is the stiffness of a single interatomic "spring"?
Answer:
Explanation:
Given that:
length l = 2.3 m
a = 0.12 cm = [tex]0.12 \times 10^{-2} \ m[/tex]
[tex]x = 1.17 \ cm = 1.17 \times 10^{-2}\ m[/tex]
m = 149 kg
[tex]\delta = 7.87 \ g/cm^3[/tex]
[tex]da = 2.28 \times 10^{-10}\ m[/tex]
[tex]F_{net} = F-mg\\ \\0 = F - mg \\ \\ F = mg \\ \\ k_sx = mg \\ \\[/tex]
∴
[tex]k_s = \dfrac{149(9.8)}{1.17 \times 10^{-2}} \\ \\ k_s = 124803.42 \ N /m[/tex]
[tex]N_{chain} = \dfrac{A_{wire}}{A_{atom}} = \dfrac{A_w}{da^2}[/tex]
[tex]N_{chain} = \dfrac{(a)^2}{(da)^2} = (\dfrac{a}{da})^2[/tex]
[tex]N_{chain} = (\dfrac{0.12 \times 10^{-2} }{2.28 \times 10^{-10}})^2[/tex]
[tex]N_{chain} = 2.77 \times 10^{13}[/tex]
[tex]N_{bond} = \dfrac{L}{da} \\ \\ = \dfrac{2.3}{2.28 \times 10^{-10}} \\ \\ N_{bond} = 1.009 \times 10^{10}[/tex]
[tex]\text{Finally; the stiffness of a single interatomic spring is:}[/tex]
[tex]k_{si} =\dfrac{N_{bond}}{N_{chain}}\times k_s[/tex]
[tex]k_{si} =\dfrac{(1.009 \times 10^{10})}{2.77*10^{13}}}\times (124803.42)[/tex]
[tex]\mathbf{k_{si} =45.46 \ N/m}[/tex]
a force of 500 Newton is used to stretch a spring with a 0.5 kg mass attached to it by 0.35 cm what is the value of the spring constant and frequency of the oscillator
Answer:
F. 20 cm m. The stretching force is the weight. (W = mg) of the 4 -kg mass: F = (4 kg)(9.8 m/s2) = 39.2 N.
Either the oscillating mass or the spring constant can be modified to alter the oscillator's natural resonant frequency.
What spring constant and frequency of the oscillator?Consider a spring with an unstretched length l, a spring constant of k, and a mass M hanging from it. The oscillation frequency would be k/M if the spring's mass were ignored. According to the rule that was cited, the effect of the spring mass would be to change M in the equation for to M + m/3.
The oscillating system's frequency would rise if the spring was firmer. The resonance frequency of the system would be lowered by adding mass to it.The spring mass would have the effect of changing M in the equation for to M + m/3 in accordance with the cited rule.
Therefore, F. 20 cm m. The weight (W = mg) of the 4 kg mass is the stretching force: F = (4 kg)(9.8 m/s2) = 39.2 N.
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