Answer:
2.2m/s
Explanation:
s = d/t
s = 13/5.9
s= 2.2m/s
btw I rounded this, not rounded it's 2.20338983
The velocity of an object with mass = 2kg is given as a function of time:
V = 2ti + 4[tex]t^{2}[/tex]j
Find the force acting on the object at t = 2 seconds.
Answer:
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
Explanation:
Given that object has a constant mass in time, the force acting on the object ([tex]\vec F[/tex]), in newtons, is defined by following expression:
[tex]\vec F = m\cdot \vec a[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]\vec a[/tex] - Acceleration, in meters per square second.
By definition of acceleration, we know that:
[tex]\vec a = \frac{d}{dt} \vec v[/tex] (2)
Let suppose that given vector velocity is expressed in meters per second. If we know that [tex]m = 2\,kg[/tex], [tex]\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right][/tex] and [tex]t = 2\,s[/tex], then the force acting on the object is:
[tex]\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec F = (4, 16\cdot t)\,[N][/tex]
[tex]\vec F = (4, 32)\,[N][/tex]
The force acting on the object at [tex]t = 2\,s[/tex] is [tex]\vec F = (4, 32)\,[N][/tex].
8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?
Explanation:
We use Hooke's Law, which states that,
F=kx
F- is the force in newtons
k- is the spring constant
x- is the extension of the spring in meters
Solving for k we get k=F/x
k= 10N/0.50m
=100 N/m
What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨
Answer:
Information from the leading mathematicians was considered "classified".
A person drives a car around a circular road with a constant speed of 20 m/s. The
radius of the circular road is twenty-five meters. What is the acceleration of the car?
o 20 m/s2
O 16 m/s2
O 10 m/s2
O 8 m/s2
Answer:
16 m/s^2
Explanation:
acceleration tangential = (v^2)/r
a=400/25
a=16 m/s^2
Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:
angular acceleration=acceleration tangential/r
angular acc.=16/25
angular acc.=0.64 rad/s^2
Calculate the acceleration of a school bus that was stopped at a bus stop and then traveled down the road at a speed of 15 meters per second in 13 seconds
A 2-C charge experiences a force of 40 N when put at a certain location in
space. The electric field at that location is a. 2 N/C.b. 20 N/C. c. 30 N/C. d.
40 N/C. e. 60 N/C.
Answer:
E = 20 N/C
Explanation:
Given that,
Charge, q = 2 C
Force experience, F = 40 N
We need to find the electric field at that location.
The electric field in terms of electric force is given by :
F = qE
Where
E is the electric field
[tex]E=\dfrac{F}{q}\\\\E=\dfrac{40\ N}{2\ C}\\E=20\ N/C[/tex]
So, the electric field at that location is 20 N/C.
The lab you are working in has asked you to select a data acquisition board as part of a new instrument designed to record a voltage waveform. The waveform to be measured is a triangle shape with a duration of 100 ms and an amplitude of 50 mV. Your budget is $1500 and you must purchase a data acquisition board from National Instruments with a USB interface.
Required:
Draw a model to purchase and include an explanation of why you selected this model.
Answer:
USB-6000
Explanation:
For this strange exercise, you must take into account two fundamental aspects of the data acquisition cards;
* The resolution of the cards, which for a 12-bit card is 2.24mV =2.24 10⁻³V , for which a card of this resolution is sufficient
In your case, the amplitude is 50 mv, which is why it is much higher than the resolution of the card.
* The sampling rate or the frequency in which the card can acquire the data, the typical frequencies go from 200 Khz to the MHz, in general a card that has more than double the frequency to be measured should be selected.
In this case the frequency of your wave is
f = 1 / T
f = 1/100 10⁻³
f = 10 Hz
therefore a low frequency card is suitable.
- The third point is the requirement that it has a USB interface, most of the card do not have it
If you check the National Instruments catalog, there are low-cost cards for example: USB-6000 of 12bits and 10KS / s the latter is the samples taken per second
On top labeled A 2 waves 1 above the other, with crests and troughs that line up. On bottom labeled B 2 waves, 1 above the other, so that the crests of the top wave line up with the troughs of the bottom wave.
Will there be noise cancellation in example A or example B?
Answer:
b
Explanation:
Answer:
B B*
Explanation:
B BBBBB
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject, John Stapp, had a mass of 84.0 kg: a) what is the amount of Work done to stop the John Stapp? b) how much Force was applied to John Stapp?
Light passing through a double slit
with separation d = 2.42x10-5 m
creates its second maximum (m = 2)
at an angle of 2.74 deg. What is the
wavelength of the light, IN
NANOMETERS?
(Hint: The answer will be between 400 and
700.) (Unit = nm)
Answer:
573
Explanation:
totally not stealing previous answer cause I know it's right
The wavelength of the light is 578.45 nm.
Light passing through a double slit with separation is given as
d = 2.42 × 10⁻⁵ m.
Line number m = 2
Angle θ = 2.74°
How wavelength is calculated and what is the wavelength of the light?The distance between two sound waves i.e., crest and trough is called the wavelength.
To find the wavelength, here we use the formula as,
sin θ = Line number × λ ÷ ( distance )
By substituting all the given values,
Sin ( 2.74° ) = 2 × λ ÷ ( 2.42 × 10⁻⁵ )
Rearranging the equation,
λ= (Sin ( 2.74° ) × ( 2.42 × 10⁻⁵ ) ) ÷ (2)
λ = 578.45 nm.
Thus, wavelength λ of the light is 578.45 nm.
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[O.04H]The table below shows the use of some energy production methods over time.
Type of energy Average energy used annually in the past (in million tons) Average energy used annually at present (in million tons) Average energy most likely to be used annually in the future (in million tons)
Oil 200 4000 300
Gas 100 2500 700
Coal 1000 2500 1500
Wind 0.1 50 2000
Hydropower 0.7 60 150
Tidal power 0.02 50 500
Based on the table, which of these statements best describes the impact of different methods of energy production on the environment in the past?
There was a rise in the height of tides.
There was a rise in greenhouse gases.
The coastal ecosystem was harmed.
The coastal areas were highly polluted.
I think The coastal areas were highly polluted
Answer:
i think its greenhouse gases may increase
Explanation:
Which are uses of convex mirrors? Check all that apply.
magnifying mirrors for putting on makeup
side-view mirrors on vehicles
hallway safety mirrors
focusing automobile headlights
lenses in sunglasses
Answer:
B. Side-view mirrors on vehicles
C. Hallway safety mirrors
E. Lenses in sunglasses
Explanation:
Trust Me, Look At Attachment.
Answer:
2, 3, and 5 on Edge, 2022.
Explanation:
I had this question on Edge.
(See the attachment below.)
The rest of the answers are:
O Slide 8 - Sample Response: The image seems to be behind the mirror, but nothing is really there.
O Slide 9 - Concave
O Slide 10 - Same size
explain the role of good marketing in the success of business
Answer:
I am joker if you are mad x_________-..............,,,,,,........ €£
write any three utilities of plastics
Explanation:
container, bottles, boxes, cups
An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
A.
The vibrations of the fields are perpendicular to the direction in which the wave moves.
B.
The wave moves back and forth through the fields.
C.
The vibrations of the fields are parallel to the direction in which the wave moves.
close
D.
The wave moves through the fields in a random motion.
A. The vibrations of the fields are perpendicular to the direction in which the wave moves.
An electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
What is the significance of an electromagnetic wave?Electromagnetic waves have many applications, including the transmission of information and energy, and they are also used in other technologies such as radio, television, hospitals, wireless communications, and so on. Other different rays, such as microwaves, infrared radiation, visible light, ultraviolet radiation, etc., are used in different fields, such as X-rays for imaging, etc.
Hence, an electromagnetic wave moves through electric and magnetic fields, and the movement of the wave can be described as the vibrations of the fields being perpendicular to the direction in which the wave moves, as in option A.
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a mass of 0.8kg at the end of a rope 0.5m long is whirled round ina horizontal circle at an angular speed of 10 rads^-1. what is it's angular momentum?
Answer:
L = 2 J.s
Explanation:
The angular momentum of an object travelling in a horizontal circle is given by the following formula:
[tex]L = mvr[/tex]
where,
L = Angular momentum = ?
m = mass = 0.8 kg
v = linear speed = rω
r = radius of circular path = length of rope = 0.5 m
ω = Angular Speed = 10 rad/s
therefore,
[tex]L = mr^2\omega\\L = (0.8\ kg)(0.5\ m)^2(10\ rad/s)\\[/tex]
L = 2 J.s
PLEASE HELP!!!!
ITS URGENT!
Answer:
the answer is D
Explanation:
Look at the graph. What is the slope of the line?
For the first hour, the slope is zero.
After that, the slope is -2 miles per hour.
Studying children's interactions by watching them play on the school playground is
an example of
a survey.
naturalistic observation.
a case study.
a single-blind study.
Answer:
a survey
Explanation:
how kids like the playground or they do not like it at all
Suppose it takes at least 5 people to push a very heavy box up a 400-cm ramp. If there are actually 6 people there to help push, which ramp(s) could they use to get the box moved? (Assume no friction.)
Suppose it takes at least 5 people to push a very heavy box up a 400-cm ramp. If there are actually 6 people there to help push, they could use ramp(s) = 480 cm to get the box moved.
What is force?According to newton if there is a object at rest then a physical or non physical thing acting on it and it helps him to move a bit that called the force. It is a vector quantity. It can be measured in newton, dyne.
How can we calculate the ramp?To calculate the ramp we are using the formula,
s= s₁×(p₂/p₁)
Here we are given,
s₁= The initial length of the ramp. = 400m
p₂= The final number of people. = 6
p₁=The initial number of people. = 5
We have to calculate the final length of ramp.= s cm
Now we put the values in above equation, we get
s= s₁×(p₂/p₁)
Or, s= 400×(6/5)
Or, s=480 cm
From the above calculation we can say that, If there are actually 6 people there to help push, they could use ramp(s) = 480 cm to get the box moved.
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A student lifts their 75 N backpack 0.50 m onto their chair. How much work is done?
Answer:
37.5 J
Explanation:
With work done equation: W=Fs
W=75*0.50=37.5 J
or use mgh=(75)(0.5) which is the same
A heat engine does 200 J of work per cycle while exhausting 400 J of waste heat. what is the engine's thermal efficiency?
The engine thermal efficiency is 50%
The engine does 200 joules of work per cycle
It exhausts 400 j
The thermal efficiency can be calculated as follows
= 200/400
= 0.5 × 100
= 50 %
Hence the engine thermal efficiency is 50%
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A voltage is applied to a resistor,
which creates a 1.50 A current. If
you double the resistance, keeping
the voltage the same, what will the
new current be?
(Unit = A)
Answer:
Explanation:
By Ohms Law, Voltage = Current * Resistance
Keeping the voltage the same and doubling the resistance, the current will be halved.
So the new current = 1.5/2 = 0.75A
By using Ohms law, the current will be 0.75A.
What is Ohm's law?Ohm's law states that the current flowing through a resistance is proportional to potential difference across the resistance under constant temperature and pressure conditions. Ohm's law can be expressed as:
V =IR
Here, I = 1.50 AR = R Ωso, V = 1.50 R Now Voltage is same but resistance is doubled so new resistance is
Now, put the values of given data in ohms law formula:
2RI = 1.50 R/ 2R = 0.75A
Hence current is 0.75A
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If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,
what is the mass of the copper?
The specific heat of copper is 385 J/kgK.
Answer:
The mass of the copper is 3.00kg
Explanation:
Which of the following planets were the ancient Greeks able to see and make careful observations of?
Saturn and Neptune
Neptune and Uranus
Mars and Venus
Mercury and Uranus
Answer:
Neptune and Uranus
Explanation:
Did a quiz on this not to long ago
HELPP!!!! URGENT!!!!
What is the value of the angular deviation? step by step justify your answer.
1-The angular difference is 15 degrees.
2-The angular difference is worth 1.67 rad.
3-The angular difference is 0.60 degrees.
4-The angular difference is worth 0.60 rad.
Answer:
How Urgent are we talking?
Explanation:
Oberon is a moon of Uranus. It has a mass of 3.01 x 1021 kg and is 761.4 km away from Uranus. If the force of gravity
of Uranus is pulling 3.00 x 1025 N on Oberon, what is the mass of Uranus? (6 points)
Answer:
acc to formula= F= G m1m2/rsq
mass of Uranus= F×r sq/G×m
M=3.00×10^25×761.4×761.4×10^6/6.67×10^ -11×3.01×10^21
=3×10^25-8×7614×7614/667×301×10^-2-11+21-2
=173918988×10^11/200767
=866×10^11(approx)
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling with a force of 60 Newtons. The third child, Eric, is pulling with enough force to exactly balance Abe and Barry (no child is winning the tug-o-war for the toy). We can label our forces A, B, and E (from each child's name). These three forces are in equilibrium.
If Abe is pulling toward the North and Barry is pulling toward the East, we want to find the total force R due to Abe and Barry (the Resultant of their forces). Note: in THIS case the two forces and R form a right-triangle (with R as the hypotenuse) - as seen using graphical vector addition. As a convention let's have NORTH upward and EAST rightward on this page.
a. Sketch an ACCURATE free-body diagram (three arrows outward from a point showing LABELED forces A, B, and E - each arrow a reasonable length and correct direction):
b. Sketch a labeled diagram for graphical addition of A and B to get R:
c. Show the calculation of the magnitude of R from the magnitudes of A and B:
d. Give the magnitude of force E (in units of Newtons):
e. Describe the direction of force E in terms of the "cardinal" directions (north, east, south, and/or west):
Solution :
c). [tex]$\vec{F}_A = $[/tex] force applied by Abe
[tex]$\vec{F}_B = $[/tex] force applied by Barry
[tex]$\vec{F}_E = $[/tex] force applied by Eric
[tex]$\vec{F}_R = $[/tex] Resultant force
[tex]$\vec{F}_A $[/tex] in the vector form can be written as :
[tex]$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$[/tex]
[tex]$\vec{F}_B $[/tex] in the vector form can be written as :
[tex]$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$[/tex]
The resultant,
[tex]$\vec{F}_R= \vec{F}_A+\vec{F}_B $[/tex]
[tex]$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$[/tex]
[tex]$=60 \hat i + 60 \hat j$[/tex]
[tex]$|\vec{F}_R| = \sqrt{60^2+60^2}$[/tex]
= 84.853 N
d). As the three forces are in equilibrium, therefore,
[tex]$|\vec F_E| = |\vec F_R|$[/tex]
[tex]$|\vec F_E| =84.853 \ N$[/tex]
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
[tex]$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$[/tex]
[tex]$ = \tan ^{-1}\left(\frac{60}{60}\right)$[/tex]
= 45° north east
The direction of the force E is 45° west or 45° south west.
Martin has hypothesized that the size and types of trees differ between valleys and higher elevations. He sets up a transect line in a wooded valley and randomly creates three 10 x 10 meter plots along the transect line, recording GPS coordinates for the northwest corner of each plot. He identifies and measures (diameter at breast height) every tree within the plots. He repeats this procedure in a wooded area on the ridge above the valley.
Using the scenario above, state the independent and dependent variables.
Answer: The dependent Variables include: Size and Types of trees.
The independent Variables include:
geographic elevations that is, valleys and the higher elevations.
Explanation:
The dependent variable simply refers to the variable a researcher tests or measures during an experiment. On the other hand, the independent variable simply refers to the variable that's controlled during an experiment.
Based on the definition above, the dependent variables include the size and the types of trees while the independent variables include the
geographic elevations that is, the valleys and the higher elevations.
A Body OF Volume 36cc Floats With 3/4 of its volume submerged in water . The density Of Body is
1. 0.25g/cc 2. 0.75g/cc
3. 0.9g/cc 4. 0.1g/cc
Answer:
Density of body = 0.25g/cc
Explanation:
Given:
Volume submerged in water = 3/4
Find:
Density Of Body
Computation:
Density of body = fraction of body in liquid x density of water
Density of body = [1-3/4]1
Density of body = 0.25g/cc