What is an example of a Low Energy-created depositional environment?

Answers

Answer 1

Answer:

River flood plains, swamps, lakes, lagoons, marshes, and offshore.

Explanation:

Slow-moving currents prevent coarse-grained sediment from migrating into low-energy depositional environments. Fine materials can be carried long distances before they can settle out in the absence of waves and currents.


Related Questions

Heat is added to two identical samples of a monatomic ideal gas. In the first sample, the heat is added while the volume of the gas is kept constant, and the heat causes the temperature to rise by 80 K. In the second sample, an identical amount of heat is added while the pressure (but not the volume) of the gas is kept constant. By how much does the temperature of this sample increase

Answers

Answer:

The temperature of the sample increase by 48 Kelvin

Explanation:

The sample is identical.

Hence the heat at constant pressure is equal to the heat at the constant Volume

Q1 = Q2

Q 1 = heat at constant pressure

Q2 = heat at the constant Volume

Substituting the given values, we get -

[tex]\frac{3}{2} nRT_1 = \frac{5}{2} nRT_2\\3 * 80 = 5 * T_2\\T_2 = 48[/tex]

The temperature of the sample increase by 48 Kelvin

Which best compares kinetic energy and temperaturo?
A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.
B. Temperature is energy of motion, whilo kinetic energy is a measure of that energy in substances,
C.Kinetic energy is internal transferable energy, while temperature is a measure of that energy in substances,
D.Temperature is internal transferable energy, while kinetic energy is a measure of that energy in substances.

Answers

Which best compares kinetic energy and temperature?

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A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances. ✅

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer:

A. Kinetic energy is energy of motion, while temperature is a measure of that energy in substances.

Explanation:

got it right on edge 2021

Draw the structures of all possible isomers for the following complexes. Indicate which isomers are enantiomer pairs. (a) Bromochloro(ethylenediamine)platinum(II) (square-planar) (b) Tetra-amminedichloroiron(III) ion (octahedral) (c) Amminechlorobis(ethylenediamine)iron(III) ion (octahedral)

Answers

Answer:

structures B and C are: enantiomer pair.

Explanation:

Attached below are the structures of all possible Isomers

structures B and C  under solution 3 are enantiomer pair. this is because they posses the same connectivity but exhibit opposite three dimensional shapes .

For the reaction 2Na + Cl2 2NaCl, calculate the percent yield if 200g of chlorine react with excess sodium to produce 240g of sodium chloride?
A.61.2%
B.88.4%
C.83.4%
D.72.8%
The answer is D but I need the explanation

Answers

percentage yield =(actual yield/theoretical yield) ×100/1

chlorine is the limiting reagent hence would be the major determinant of the product

71[Cl2]=2×58.5[NaCl]

200[Cl2]=x[NaCl]

x=(200×58.5×2)/(71)

x=329.58g(theoretical yield of NaCl)

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

The answer is that the percentage yield is 72.8 % .

What is Percentage Yield ?

Chemical reactions in the real world do not always go exactly as planned on paper.

In the course of an experiment, many things will contribute to the formation of less product than would be predicted.

Besides spills and other experimental errors, there are often losses due to an incomplete reaction, undesirable side reactions, etc.

Chemists need a measurement that indicates how successful a reaction has been. This measurement is called the percent yield.

Percentage yield =(actual yield/theoretical yield) ×100 %

Chlorine is the limiting reagent hence would be the major determinant of the product

Molecular weight of Cl₂ is 71

Molecular weight of NaCl is 58.5

For 1 mole of Cl₂ 2 moles of NaCl is produced

so it is given that Cl₂ is 200 grams

= 200/71

=2.82 moles.

=5.63 moles of NaCl

=5.63* 58.5 grams

=329.58 g of Nacl

So , 329.58g is theoretical yield of NaCl

percentage yield = (240/329.58) ×100

percentage yield= 72.8℅

Therefore the percentage yield = 72.8%

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What is the mass of a gas with a molar mass of 44.01 g/mol at a temperature of 298 K, a pressure of 0.957 atm and a volume of 1.30L?

Answers

Answer:

2.24 g

Explanation:

First we use the PV=nRT formula to calculate the number of moles of the gas:

0.957 atm * 1.30 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 Kn = 0.0509 mol

Then we can use the given molar mass to calculate the mass:

Molar Mass = Mass / number of moles44.01 g/mol = Mass / 0.0509 molMass = 2.24 g

What volume is occupied by 0.108 mol of helium gas at a pressure of 0.96 atm and a
temperature of 315 K?

Express your answer using two significant figures.

Answers

Answer:

[tex]V=2.9L[/tex]

Explanation:

Hello there!

In this case, by considering the given information in this problem, it is possible  for us to infer that this problem is solved by using the ideal gas equation:

[tex]PV=nRT[/tex]

Next, since we are given the moles, pressure and temperature, we proceed as follows:

[tex]V=\frac{nRT}{P}[/tex]

Then, we plug in the given data to obtain:

[tex]V=\frac{0.108mol*0.08206\frac{atm*L}{mol*K}*315K}{0.96atm}\\\\V=2.9L[/tex]

Best regards!

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A 25.0 L balloon at 20ºC is placed in a hot water bath at 90ºC. After 15 minutes, the volume of the balloon stops expanding. What is the new volume of the balloon?

Answers

Answer:

After 15 minutes,the volume of the balloon stops expanding

One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/Kg.K.

Answers

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ([tex]s_{2} - s_{1}[/tex]), in joules per gram-Kelvin, by the following model:

[tex]s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }[/tex]

[tex]s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]c_{w}[/tex] - Specific heat of water, in joules per kilogram-Kelvin.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures of water, in Kelvin.

If we know that [tex]m = 1\,kg[/tex], [tex]c_{w} = 4190\,\frac{J}{kg\cdot K}[/tex], [tex]T_{1} = 373.15\,K[/tex] and [tex]T_{2} = 288.15\,K[/tex], then the change in entropy for the entire process is:

[tex]s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}[/tex]

[tex]s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}[/tex]

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Answer:

The change in entropy = [tex]-1083.534 J/k[/tex]

Explanation:

Change in entropy,

[tex]\delta S = mCp * In[\frac{T2}{T1}][/tex]

The initial temperature,

[tex]T1 = 100^oC\\\\T1 = 100+273\\\\T1 = 373k[/tex]

Final value of temperature,

[tex]T2 = 15^oC\\\\T2 = 15+273\\\\T2 = 288k[/tex]

where,

[tex]m = 1kg\\\\Cp = 4190 J/kg.k[/tex]

Substitute into [tex]\delta S[/tex]

[tex]\delta S = mCp * In[\frac{T2}{T1}]\\\\\delta S = 1 * 4190 * In[\frac{288}{373}]\\\\\delta S = 4190 * In[0.7721]\\\\\delta S = 4190 * [-0.2586]\\\\\delta S = -1083.534 J/k[/tex]

The negative sign exists because the change in entropy will be decreasing due to cooling.

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Carla is using a fertilizer that contains nitric acid. How is nitric acid classified?

strong acid
weak acid
strong base
weak base

Answers

Answer:

Strong acid.....(A)

Explanation:

hope this helps, the person above me is also correct

Answer:

a

Explanation:

What mass of a concentrated solution of nitric acid (68.0% HNO3 by mass) is needed to
prepare 400.0 g of a 10.0% solution of HNO3 by mass?

Answers

Answer:

58.8 grams.

Explanation:

First we calculate how many HNO₃ grams are there in 400.0 g of a 10.0% solution:

Out of 100 g of a 10.0% solution, 10 g will be of HNO₃.400.0 g * 10.0/100 = 40 g HNO₃

Then we calculate the mass of a 68.0% solution that would contain 40 grams of HNO₃:

40 g HNO₃ * 100 g Solution/68 g HNO₃ = 58.8 g

Two iron-clad characteristics of matter
are that it has mass and also exhibits
which of the following?
A. It flows from hot to cold.
B. It can do work,
C. It has volume (takes up space).
D. It is a solid.

Answers

Answer:

it has volume( takes up space).

Explanation:

The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

What is Matter ?

A physical substance in general, that which occupies space and possesses rest mass, especially as distinct from energy.

Matter is important because it makes up everything around us and matter can not be created or destroyed but instead, they just transformed into a different form.

Any characteristic that can be measured, such as an object's density, colour, mass, volume, length, malleability, melting point, hardness, odour, temperature, and more, are considered properties of matter.

Therefore, The characteristics of matter are that it has mass and also exhibits volume (takes up space).Hence Option (C) is Correct.

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What you know about rolling ' down in the deep?

When your brain goes numb, you can call that mental freeze

When these people talk too much, put that sh ei t in slow motion, yeah

I feel like an astronaut in the ocean, aye

What you know about rolling' down in the deep?

When your brain goes numb, you can call that mental freeze

When these people talk too much, put that s h e it in slow motion, yeah

I feel like an astronaut in the ocean

Answers

Answer:

She say that im cool

I'm like "yeah thats true"

I believe in G-O-D

Dont believe in T-H-O-T

Explanation:

Answer:

rolling in the deep

Explanation:

what is displacement reaction​

Answers

A displacement reaction (also known as a replacement reaction) is when one element is replaced by another compound. Ex) Fe+CuSO4=FeSO+Cu

A displacement reaction is a type of reaction that replaces part of one reactor with another. Often known as a substitution reaction or metathesis reaction is a displacement reaction

What happens if more product is added to a system at equalibrium

Answers

Answer:

There won't be any equilibrium.

Explanation:

Because when we add a product to a system then the equilibrium will not be the same since the weight will be more on one system which will make it unstable.

If the reaction described by this chemical equation started with 5.77 grams of PbO2 and resulted in 0.331 grams of O2, what is the percent yield of O2

Answers

Answer:

42.9%

Explanation:

Step 1: Write the balanced decomposition reaction

PbO₂ ⇒ Pb + O₂

Step 2: Calculate the theoretical yield of O₂ from 5.77 g of PbO₂

According to the balanced equation, the mass ratio of PbO₂ to O₂ is 239.2:32.00.

5.77 g PbO₂ × 32.00 g O₂/239.2 g PbO₂ = 0.772 g O₂

Step 3: Calculate the percent yield of O₂

The real yield of O₂ is 0.331 g. The percent yield of O₂ is:

%yield = real yield / theoretical yield × 100%

%yield = 0.331 g / 0.772 g × 100% = 42.9%

How does increasing the concentration of the reactants help a chemical reaction
rate to increase? (check all that apply) *
1. makes molecules collide with more energy
2. helps with the direction or orientation of the collision
3. increases the number of collisions
No links I’ll report you

Answers

Answer: 3

When the number of collisions increase, it increases the reaction rate leading to chemical reactions

What is the percent yield when 1.72 g of H2O2 decomposes and produces 375 mL of O2 gas measured at 42 oC and 1.52 atm

Answers

Answer:

87.0%

Explanation:

Step 1: Write the balanced reaction

H₂O₂ ⇒ H₂O + 0.5 O₂

Step 2: Calculate the real yield of oxygen, in grams

We have 375 mL (0.375 L) of O₂ at 42 °C (315 K) and 1.52 atm. First, we will calculate the number of moles using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.52 atm × 0.375 L / (0.0821 atm.L/mol.K) × 315 K = 0.0220 mol

The molar mass of oxygen is 32.00 g/mol.

0.0220 mol × 32.00 g/mol = 0.704 g

Step 3: Calculate the theoretical yield of oxygen, in grams

According to the balanced equation, the mass ratio of H₂O₂ to O₂ is 34.01:16.00.

1.72 g H₂O₂ × 16.00 g O₂/34.01 g H₂O₂ = 0.809 g O₂

Step 4: Calculate the percent yield of oxygen

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 0.704 g / 0.809 g × 100% = 87.0%

Considering the reaction stoichiometry and the ideal gas law, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

Theoretical yield of oxygen

The balanced reaction is:

2 H₂O₂ → 2 H₂O +  O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂O₂: 2 moleH₂O: 2 mole O₂: 1 moles

The molar mass, this is the amount of mass a substance contains in one mole, of H₂O₂ is 34 [tex]\frac{g}{mole}[/tex]. Then, the amount of moles of H₂O₂ that decomposes when 1.72 grams of H₂O₂ reacts is calculated as:

[tex]1.72 gramsx\frac{1 mole}{34 grams}= 0.0506 moles[/tex]

Then you can apply the following rule of three: if by stoichiometry 2 moles of H₂O₂ produce 1 moles of O₂, 0.0506 moles of H₂O₂ will produce how many moles of O₂?

[tex]amount of moles of O_{2} =\frac{0.0506 moles of H_{2} O_{2} x1 mole of O_{2} }{2 moles of H_{2} O_{2}}[/tex]

amount of moles of O₂= 0.0253 moles

Real yield of oxygen

On the other side, an ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P× V = n× R× T

In this case, for O₂ gas you know:

P= 1.52 atmV= 375 mL= 0.375 L (being 1000 mL= 1 L)n= ?R= 0.082 [tex]\frac{atmL}{molK}[/tex]T= 42 °C= 315 °K (being 0°C= 273°K)

Replacing:

1.52 atm× 0.375 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 315 K

Solving:

[tex]n=\frac{1.52 atmx 0.375 L}{0.082\frac{atmL}{molK}x 315 K }[/tex]

n= 0.022 moles

Percent yield of oxygen

The percent yield is calculated as

[tex]Percent yield= \frac{real yield}{theoretical yield} x100[/tex]

In this case, for oxygen the percent yield is calculated as

[tex]Percent yield of oxygen= \frac{0.022 moles}{0.0253 moles} x100[/tex]

Percent yield of oxygen= 86.96 %

Finally, the percent yield when 1.72 g of H₂O₂ decomposes and produces 375 mL of O₂ gas measured at 42 °C and 1.52 atm is 86.96%.

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what is a saturated organic compound and unsaturated organic compound?​

Answers

Answer:

Saturated organic compound has only single bonds between carbon atoms. An important class of saturated compounds are the alkanes. Many saturated compounds have functional groups, e.g., alcohols.

Unsaturated organic compound have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may be added to the hydrocarbon to make it saturated (i.e. consisting all single bonds).

A flask contains 85.5 grams C12H2011 (sucrose) in 1.00 L of solution. What is the molarit
Your answer.
3.8 M
25 M
10M
1.2M

Answers

Answer:

0.25 M

Explanation:

First we convert 85.5 grams of sucrose into moles, using its molar mass:

Molar Mass of C₁₂H₂₂O₁₁ = (Molar Mass of C)*12 + (Molar Mass of H)*22 + (Molar Mass of O)*11Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol85.5 g ÷ 342.3 g/mol = 0.25 mol

Then we divide the number of moles by the number of liters to calculate the molarity:

0.25 mol / 1.00 L = 0.25 M

A gas has a volume of 450. mL at 55.0 °C. If the volume changes to 502 ml, what is the new temperature?

Answers

Answer:

92.9 °C

Explanation:

Step 1: Given data

Initial volume (V₁): 450. mLInitial temperature (T₁): 55.0 °CFinal volume (V₂): 502 mL

Step 2: Convert 55.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 55.0 + 273.15 = 328.2 K

Step 3: Calculate the final temperature of the gas

If we assume constant pressure and ideal behavior, we can calculate the final temperature of the gas using Charles' law.

T₁/V₁ = T₂/V₂

T₂ = T₁ × V₂/V₁

T₂ = 328.2 K × 502 mL/450. mL = 366 K = 92.9 °C

What is the mass in grams of 5.50 moles of Copper, Cu?

Answers

Answer:

349.503 g

https://www.convertunits.com/from/moles+Copper/to/grams

here is a link, you can convert moles of copper to grams here

The answer is 5.50 moles of Cu (Copper) has 349.503 grams mass .

What is a mole ?

A mole is defined as 6.02214076 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10 23 atoms, molecules, or formula units of that substance.

1 mole of Cu has 63.546 grams of Cu

So 5.50 moles will have 5.50 * 63.546 grams

=349.503 grams

Therefore 5.50 moles of Cu (Copper) has 349.503 grams mass .

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What are the characteristics of acids and bases, and some examples of each?

Answers

Answer:

Acids taste sour while bases taste bitter. An acid reacts with metals to produce bubbles of hydrogen gas while a base feels slimy to the touch. Acids turn blue litmus paper red while bases turn red litmus paper blue.

21. A piece of metal with a a mass of 15.2 g is heated from 17°C to 42°C. In the process it absorbs 1362 J of
energy as heat. What is the specific heat of the metal?

Answers

Answer:

3584.21 J/kg.K

Explanation:

Applying

Q = cm(t₂-t₁)........... equation 1

Where Q = Quantity of heat absorb, c = specific heat capacity of the metal, m = mass of the metal, t₁ = intial temperature, t₂ = Final temperature.

make c the subject of the equation

c = Q/(m(t₂-t₁)........... Equation 2

From the question,

Given: Q = 1362 J, m = 15.2 g = 0.0152 kg, t₁ = 17°C, t₂ = 42°C

Substitute these values into equation 2

c = 1362/0.0152(42-17)

c = 1362/0.38

c = 3584.21 J/kg.K

Hydrogen gas and nitrogen gas react to form ammonia gas. What volume of ammonia would be produced by this reaction if 5.53 mL of hydrogen were consumed

Answers

Answer:

5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

Explanation:

The complete balance equation for the given reaction is

N2 + 3H2 --> 2 NH3

Thus, 3 moles of hydrogen produces 2 moles of NH3

Hence, the volume of ammonia produced = 5.53 * (2/3) = 3.6867 mL

Hence, 5.53 mL of hydrogen will produce 3.6867 mL of Ammonia

Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. CCl4 C5H12 CH3NH2 NaF CH2I2

Answers

Answer:

CH3NH2

Explanation:

Hydrogen bonding is a bond that occurs between hydrogen and a highly electronegative element. It is a kind of dipole - dipole interaction. Hydrogen bonding only occurs when hydrogen is bonded to a highly electronegative element.

If we look at the options stated, it is only in CH3NH2  that hydrogen is bonded to a very electronegative element (nitrogen). Hence, CH3NH2  exhibits hydrogen bonding as its strongest intermolecular force among other intermolecular forces.

Answer:

CH3NH2

Explanation:

To form hydrogen bondings between the molecules, the compound needs a highly electronegative atom (usually N, O, or F) bonded with a hydrogen atom;

WILL GIVE BRAINLIEST!!!
Which of the following conditions remain constant in Boyle's law?

Volume and pressure
Density and temperature
Pressure and number of moles
Temperature and number of moles

Answers

Answer: Temperature and number of moles are the conditions which remain constant in Boyle's law.

Explanation:

Boyle's law states that at constant temperature the pressure of a gas is inversely proportional to the volume of gas.

Mathematically, it is represented as follows.

[tex]P \propto \frac{1}{V}[/tex]

As equation for ideal gas is as follows.

PV = nRT

And, at constant temperature the pressure is inversely proportional to volume which also means that number of moles are also constant in Boyle's law.

Thus, we can conclude that temperature and number of moles are the conditions which remain constant in Boyle's law.

Answer:

Temperature and number of moles

Explanation:

Why should the oil be removed from a low pressure system at 130F

Answers

When removing oil from a low pressure system, the temperature should be 130°F because, less refrigerant will be contained in the oil at higher temperature. Liquid charge into a deep vacuum will boil and may lower temperatures enough to freeze water in the tubes.

Which type of scientist would observe the spread of a species of red fire ants

Answers

It would be a biologist

Calculate the mass percent (m/m) of a solution prepared by dissolving 51.56 g of NaCl in 164.2 g of H2O. Express your answer to four significant figures. View Available Hint(s)

Answers

Answer:

"23.896%" is the right answer.

Explanation:

The given values are:

Mass of NaCl,

= 51.56 g

Mass of H₂O,

= 165.6 g

As we know,

⇒  Mass of solution = [tex]Mass \ of \ (NaCl+H_2O)[/tex]

                                 = [tex]51.56+164.2[/tex]

                                 = [tex]215.76 \ g[/tex]

hence,

⇒ [tex]Mass \ percent =\frac{Mass \ of \ NaCl}{Mass \ of \ solution}\times 100[/tex]

                           [tex]=\frac{51.56}{215.76}\times 100[/tex]

                           [tex]=23.896 \ percent[/tex]

An unbalanced chemical equation:a. does not obey Conservation of Mass law b.does obey Conservation of Mass law c.has equal numbers of atoms of each element in both reactants and productsd.none of the above

Answers

Answer:

a. Does not obey Conservation of Mass law

Explanation:

An example of an unbalanced chemical equation is:

H₂SO₄ + NaOH → Na₂SO₄ + H₂O

As you can see, there are two Na atoms on the right side of the equation, while only one on the left side, causing the masses on both sides of the equation to not be equal. In other words, not fulfilling the Conservation of Mass law.

Compare with the correctly balanced equation:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

Now both sides of the equation possess the same number of atoms for each element.

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