Answer:
Step-by-step explanation:
y - 4 = 2x - 12
y = 2x - 8
perp slope: -1/2
y + 5 = -1/2(x + 3)
y + 10/2= -1/2x - 3/2
y = -1/2x - 13/2
Answer:
y+5 = -1/2(x + 3)
Step-by-step explanation:
Perpendicular lines have negative reciprocal slopes. The slope of the line
y - 4 = 2(x - 6) is 2. Its negative reciprocal slope is -1/2.
Using m = -1/2 and the point (-3,-5) in the point slope form.
y --5 = -1/2(x--3)
y+5 = -1/2(x + 3)
Want Brainliest? Get this correct Which of the following is the quotient of the rational expressions shown below?
Answer:
[tex]\dfrac{4x^2+12x+5}{6x^2-3x}[/tex]
Step-by-step explanation:
Invert the denominator and multiply.
[tex]\dfrac{2x+5}{3x}\div\dfrac{2x-1}{2x+1}=\dfrac{2x+5}{3x}\cdot\dfrac{2x+1}{2x-1}\\\\=\dfrac{(2x+5)(2x+1)}{(3x)(2x-1)}=\boxed{\dfrac{4x^2+12x+5}{6x^2-3x}}\qquad\text{matches choice A}[/tex]
Answer:
[tex]\frac{4x^2+12x+5}{6x^2-3x}[/tex]
Step-by-step explanation:
After using the reciprocal of the second term, the denominator will multiply out to be [tex]6x^2-3x[/tex]. There is only one option with that as the denominator so it must be the correct answer.
Determine whether the point (–3,–6) is in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2
Answer:
The point (–3,–6) is not in the solution set of the system of inequalities below.
x ≤ –3 y < 5∕3x + 2
Step-by-step explanation:
Given point (-3, -6)
inequality
x ≤ –3
It means that value of x should be less than or equal to -3
since in point (-3,-6) , -3 is point for representing x which is equal to -3 and hence satisfy the criteria for valid value of x,
thus, -3 lie in the solution set of inequality x ≤ –3
lets now see for y = -6
to do that we will put x = -3 in the given below inequality
y < 5∕3x + 2
y < 5∕3*-6 + 2
y < -10 + 2
y < - 8
Thus, inequality suggests that value of y should be less than -8.
but here y is -6, if we see number line -6 is greater than -8 and hence does not belong to the solution set y < 5∕3x + 2 when x = -3
Thus, the point (–3,–6) is not in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2
The total number of hamburgers sold by a national fast-food chain is growing exponentially. If 3 billion had been sold by 2003 and 9 billion had been sold by 2010, how many will have been sold by 2013
Answer:
F(10) = 14.41 Billion
The total number of hamburgers that will have been sold by 2013 is 14.41 billion.
Step-by-step explanation:
The exponential function representing the total number of hamburgers sold by a national fast-food chain which grows exponentially can be expressed as;
f(t) = p(a)^t
In 2003, t = 0 and f(0) = 3 Billion
f(0) = p = 3 billion
The initial value p = 3 billion
In 2010, t = (2010-2003) = 7
f(7) = p(a)^7 = 9 billion
3(a)^7 = 9
a^7 = 9/3 = 3
a = 3^(1/7)
Therefore, the function f(t) is;
f(t) = 3(3)^(t/7) .......2
In 2013, t = (2013 - 2003) = 10
Substituting t = 10 into equation 2;
f(10) = 3(3)^(10/7)
F(10) = 14.41195997001 Billion
F(10) = 14.41 Billion
The total number of hamburgers that will have been sold by 2013 is 14.41 billion.
I was having trouble solving #25 of this packet. Can you help?
Answer:
On Monday the temperature was 35 - 4 = 31°. On Tuesday, it was 31 + 2 = 33° and on Wednesday it was 33 - 5 = 28° F.
Which of the following shows the intersection of the sets? {1, 4, 8, 12} {2, 4, 6, 8}
Answer:
{ 4,8}
Step-by-step explanation:
The intersection is what the sets have in common
{1, 4, 8, 12}∩ {2, 4, 6, 8}
{ 4,8}
Answer:
{4, 8}
Step-by-step explanation:
The intersection of sets are the terms that appear in both sets. In this case, the only numbers that appear in both sets are 4 and 8.
Determine the critical value LaTeX: z_{\frac{\alpha}{2}}z α 2 that corresponds to a 96% level of confidence.
Answer:
The confidence level for this case is 96% or 0.96, then the significance level would be:
[tex]\alpha = 1-0.96 =0.04[/tex]
And then [tex]\alpha/2 =0.02[/tex]. We need to find a critical value who accumulates 0.02 of the area on each tail and we got:
[tex]z_{\alpha/2}=\pm 2.054[/tex]
Step-by-step explanation:
The confidence level for this case is 96% or 0.96, then the significance level would be:
[tex]\alpha = 1-0.96 =0.04[/tex]
And then [tex]\alpha/2 =0.02[/tex]. We need to find a critical value who accumulates 0.02 of the area on each tail and we got:
[tex]z_{\alpha/2}=\pm 2.054[/tex]
Write a two column proof Given: AB || DC; BC || AE Prove: BC/EA = BD/EB
Answer:
AB || DC Given
∠ABE ≅ ∠CDB Alternate interior angles are congruent
BC || AE Given
∠CBD ≅ ∠BEA Alternate interior angles are congruent
ΔAEB is similar to ΔCBD AA Similarity Postulate
BC / EA = BD / EB Similar sides are proportional
A person has a bag containing dimes and nickels. There are a total of 120 coins in the bag, and the total value of the coins is $9.25. Determine how many dimes and nickels are in the bag. There are _____dimes. There are _____ nickels.
Answer:
There are 65 dimes. There are 55 nickels.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of dimes
y is the number of nickels.
There are a total of 120 coins in the bag
This means that x + y = 120.
The total value of the coins is $9.25.
The dime is worth $0.10 and the nickel is worth $0.05. So
0.1x + 0.05y = 9.25
System:
[tex]x + y = 120[/tex]
[tex]0.1x + 0.05y = 9.25[/tex]
From the first equation:
[tex]y = 120 - x[/tex]
Replacing in the second:
[tex]0.1x + 0.05y = 9.25[/tex]
[tex]0.1x + 0.05(120 - x) = 9.25[/tex]
[tex]0.1x + 6 - 0.05x = 9.25[/tex]
[tex]0.05x = 3.25[/tex]
[tex]x = \frac{3.25}{0.05}[/tex]
[tex]x = 65[/tex]
[tex]y = 120 - x = 120 - 65 = 55[/tex]
There are 65 dimes. There are 55 nickels.
If a linear function passes through two points (x1, y1) and (x2, y2), what is the average value of the function on the interval from x1 to x2
Answer:
(y1+y2)/2
Step-by-step explanation:
adding and dividing by the total is the way to calculate the average
the construction of creating the perpendicular bisector of PQ is started below. How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?
Answer: It will not create a perpendicular bisector.
Explanation:
If the compass is the same setting as the first arc and drawn from point B, the points of intersection of the arcs will pass through the midpoint of AB (thus creating a perpendicular bisector).
If you change the setting of the compass and draw an arc from point B, the points of intersection of the arcs will still create a perpendicular line but will not pass through the midpoint of AB (creating a perpendicular line but not a perpendicular bisector).
A perpendicular bisector divides a line segment into two equal segments.
If the compass setting is changed, the line will not be bisected.
To bisect a line, the positioning of the compass must be done as follows:
Place the compass at the endpoint of the line segment, then draw an arcRepeat the above process for the other endpoint of the line segment.Trace the point of intersection of the two arcs, to the line that is being bisected.The above points are what is being done in the given construction.
Any step or setting other than that, would not create a perpendicular bisector.
Hence, if the compass setting is changed, the perpendicular bisector of the line would not be drawn.
Read more about perpendicular bisection at:
https://brainly.com/question/11050543
Legal descriptions tend to prefer neat straight lines from point to point, regardless of describing a square, rectangle, triangle or even a smooth circle. When might a property boundary end up being a squiggly line?
Answer:
When describing a property line drawn down the center of a creek bed
Find the missing side. Round your answer to the nearest tenth.
Answer:
answer is a 107 hope it halp u
Answer:
24.9
Step-by-step explanation:
To do this, we set cos(58) to 15/x.
Using a calculator and some math, we get x is about 24.9.
Here is why we do that:
Since cosine is adjacent over hypotenuse, and we have the adjacent but not the hypotenuse, we can use that to create an equation.
Hope this helped!
CAN SOMEONEHELP PLS ASAP
Answer:
a ≈ 2.2
Step-by-step explanation:
Using the Cosine rule in Δ ABC
a² = b² + c² - 2bc cos A
Here b = 3, c = 4 and A = 32° , thus
a² = 3² + 4² - (2 × 3 × 4 × cos32° )
= 9 + 16 - 24cos32°
= 25 - 24cos32° ( take the square root of both sides )
a = [tex]\sqrt{25-24cos32}[/tex] ≈ 2.2
Mrs. Tandy paid a $50 registration fee to join Fitness Club. She pays a monthly rate of $25. Write an equation to represent the total Mrs. Tandy pays for Fitness Club for x months. Determine if the equation you wrote represents a proportional relationship or non proportional relationship. Explain your reasoning.
Answer:
y=25x+50
non proportional relationship
Step-by-step explanation:
The relationship is not proportional because as you go along in the function and divide y by x, the ratios do not equal each other. In order for it to be a proportional relationship the y/x ratio must be equivalent throughout the function.
What is the length of Line segment A C? Round to the nearest tenth.
Step-by-step explanation:
To find AC we use tan
tan ∅ = opposite / adjacent
From the question
15 is the opposite
AC is the adjacent
tan 55 = 15 / AC
AC = 15 / tan 55
AC = 10.503
AC is 11 to the nearest tenthHope this helps you
Answer:
A: 10.5 m
Step-by-step explanation:
it's what i think it is, i may be wrong! hope this helps!!~
A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Three hundred feet of fencing is used
dimensions of the playground that maximize the total enclosed area. What is the maximum area?
The smaller dimension is
feet
Answer:
50 ft by 75 ft3750 square feetStep-by-step explanation:
Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...
y = (300 -2x)/3
And the enclosed area is ...
A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)
This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.
The maximum area is enclosed when the dimensions are ...
50 ft by 75 ft
That maximum area is 3750 square feet.
_____
Comment on the solution
The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).
Two cities whose longitudes are 10E and 20W on the equator are apart
Step-by-step explanation:
to be honest I'm not sure how to do
What is the solution to the system of linear equations below?
x+4y=22
2x+y=9
Answer:
[tex]\boxed{\sf \ \ \ x = 2 \ \ and \ \ y = 5 \ \ \ }[/tex]
Step-by-step explanation:
hello, we have two equation
(1) x + 4y = 22
(2) 2x + y = 9
let's multiply (1) by 2 and subtract (2)
2x + 8y - (2x + y) = 2*22 - 9 = 44 - 9 = 35
<=> 2x + 8y -2x -y = 35
<=> 7y = 35
<=> y = 35/7 = 5
we replace this value in (1) and it comes
x + 4*5 = 22
<=> x = 22 - 20 = 2
so the solution is
x = 2 and y = 5
hope this helps
what is tan 11 pie/6
Let S be a sample space and E and F be events associated with S. Suppose that Pr (Upper E )equals 0.6, Pr (Upper F )equals 0.2 and Pr (Upper E intersect Upper F )equals 0.1. Calculate the following probabilities. (a) Pr (E|F )(b) Pr (F|E )(c) Pr (E| Upper F prime )(d) Pr (Upper E prime | Upper F prime )
Answer:
(a)0.5
(b)0.17
(c)0.625
(b)0.375
Step-by-step explanation:
Pr(E)=0.6
Pr(F)=0.2
[tex]Pr(E\cap F)=0.1.[/tex]
(a)Pr (E|F )
[tex]Pr (E|F )=\dfrac{Pr(E \cap F)}{Pr(F)} \\=\dfrac{0.1}{0.2}\\\\=0.5[/tex]
(b)Pr (F|E )
[tex]Pr (F|E )=\dfrac{Pr(E \cap F)}{Pr(E)} \\=\dfrac{0.1}{0.6}\\\\=0.17[/tex]
(c)Pr (E|F')
Pr(F')=1-P(F)
=1-0.2=0.8
[tex]Pr(E \cap F')=P(E)-P(E\cap F)\\=0.6-0.1\\=0.5[/tex]
Therefore:
[tex]Pr (E|F' )=\dfrac{Pr(E \cap F')}{Pr(F')} \\=\dfrac{0.5}{0.8}\\\\=0.625[/tex]
(d)Pr(E'|F')
[tex]P(E'\cap F')=P(E \cup F)'\\=1-P(E \cup F)\\=1-[P(E)+P(F)-P(E\cap F)]\\=1-[0.6+0.2-0.1]\\=1-0.7\\=0.3[/tex]
Therefore:
[tex]Pr (E'|F' )=\dfrac{Pr(E' \cap F')}{Pr(F')} \\=\dfrac{0.3}{0.8}\\\\=0.375[/tex]
The initial population of a town in the year 2010 was 20 000. By 2014, the population had grown exponentially to 32 500 people. Write an equation to represent the population of the town (P) over time in years (n).
Answer:
P = 20000×1.625^(n/4)
Step-by-step explanation:
An exponential equation can be written using the given data:
value = (initial value)×(growth factor in period)^(n/(period))
Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...
P = 20000×1.625^(n/4)
P ( x ) = | x | and the image I ( x ) = 1 2 ⋅ P ( x ) graph
Answer:
The picture where the red image is the skinniest
Step-by-step explanation:
The graph P(x) denotes the graph of the parent graph for all the functions. And, It includes the vertex of (0,0) and points which are shown below:
x f(x)
-2 2
-1 1
0 0
1 1
2 2
Now as we can see in the attached figure i.e it changed the function points i.e given below for l(x) = 12P(x)
x f(x)
-2 24
-1 12
0 0
1 12
2 24
This depicts that it has a skinner graph that includes redish graph
At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men nor teachers. Find the number of women teachers attending the lecture
Answer:
20 teachers
Step-by-step explanation:
Because if you take 100 and minus it by 29, 23, 4 and 24 you get 20.
A half marathon is 13.1 miles long. Leah is running a half marathon and has completed 7.75 miles. How many miles to
the finish line?
Answer:
5.35 more miles
Answer:
5.35 miles to the finish line
Step-by-step explanation:
Step one
13.1-7.75=
5.35
Reflect the given pre-image over = −1 followed by = −7. Find the new coordinates.
Answer:
A'(8, -10)
B'(6, -12)
C'(2, -4)
A"(8, -4)
B"(6, -2)
C"(2, -10)
Step-by-step explanation:
The location of the points are at:
A(8, 8) , B(10, 6) and C(2, 2).
Reflection over y = -1:
For point A the y distance between the point and y = -1 line is 9 (8 - (-1)). The reflection of point a over y = -1 would give a point 9 units below y = -1 which is at -10.
The new A coordinate is at A'(8, -10)
For point B the y distance between the point and y = -1 line is 7 (6 - (-1)). The reflection of point a over y = -1 would give a point 7 units below y = -1 which is at -8.
The new B coordinate is at B'(10, -8)
For point C the y distance between the point and y = -1 line is 3 (2 - (-1)). The reflection of point a over y = -1 would give a point 3 units below y = -1 which is at -4.
The new C coordinate is at C'(2, -4)
Reflection over y = -7:
For point A' the y distance between the point and y = -7 line is 3 (-7 - (-10)). The reflection of point a over y = -1 would give a point 3 units above y = -7 which is at -4.
The new A coordinate is at A"(8, -4)
For point B' the y distance between the point and y = -7 line is 1 (-7 - (-8)). The reflection of point a over y = -7 would give a point 1 units above y = -7 which is at -6.
The new B coordinate is at B"(10, -6)
For point C' the y distance between the point and y = -7 line is 3 (4 - (-7)). The reflection of point a over y = -7 would give a point 3 units below y = -7 which is at -10.
The new C coordinate is at C"(2, -10)
A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66degreesF.Construct a 99%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body temperature?
Answer:
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body temperature is correct.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 104 - 1 = 103
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.624
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.
The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body temperature is correct.
A tank contains 3,000 L of brine with 16 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. (a) How much salt is in the tank after t minutes
Answer:
The amount of salt in the tank after t minutes is
y= 16e^(t/100)kg
Step- by-step Explanation
The tank contain 3000L of the brine
The rate is 30L/ min
The solution is mixed thoroughly, therefore, the rate in= rate out
dy/dt= rate in to the tank= rate out of the tank
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
What is the sign of f
Answer:
The sign of f is used to symbolize many things. In physics it is commonly used to mean frequency and in music it is used to symbolize forte, which means loud.
The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown population mean. If a random sample of 27 text messages is taken and results in a sample mean of 29 characters, find a 95% confidence interval for the population mean. Round your answers to two decimal places.
Answer:
29+/-2.26
= (26.74, 31.26) characters
Therefore the 95% confidence interval (a,b) = (26.74, 31.26) characters
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 29 characters
Standard deviation r = 6 characters
Number of samples n = 27
Confidence level = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
29+/-1.96(6/√27)
29+/-1.96(1.154700538379)
29+/-2.263213055223
29+/-2.26
= (26.74, 31.26) characters
Therefore the 95% confidence interval (a,b) = (26.74, 31.26) characters
What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.x + 14) – 3?
Answer:
[tex]x =-24[/tex]
Step-by-step explanation:
Given
[tex](\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3[/tex]
Required
Solve for x
[tex](\frac{2}{3})(\frac{1}{2}x + 12) = (\frac{1}{2})(\frac{1}{3}x + 14) - 3[/tex]
Open all brackets
[tex]\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x + \frac{1}{2}*14 - 3[/tex]
[tex]\frac{2 * 1}{3 *2}x + \frac{2 * 12}{3}= \frac{1 * 1}{2 * 3}x + \frac{1 * 14}{2} - 3[/tex]
[tex]\frac{1}{3}x + \frac{24}{3}= \frac{1}{6}x + \frac{14}{2} - 3[/tex]
[tex]\frac{1}{3}x +8= \frac{1}{6}x + 7 - 3[/tex]
Collect like terms
[tex]\frac{1}{3}x - \frac{1}{6}x =7 - 3 -8[/tex]
[tex]\frac{1}{3}x - \frac{1}{6}x =-4[/tex]
Solve fraction
[tex]\frac{2-1}{6}x =-4[/tex]
[tex]\frac{1}{6}x =-4[/tex]
Multiply both sides by 6
[tex]6 * \frac{1}{6}x =-4 * 6[/tex]
[tex]x =-4 * 6[/tex]
[tex]x =-24[/tex]
Answer:
Step-by-step explanation:
Given
Required
Solve for x
Open all brackets
Collect like terms
Solve fraction
Multiply both sides by 6