What is an equation of the line that is perpendicular to y- 3 = -4(x + 2) and
passes through the point (-5, 7)?
O A. y-7=-4(x + 5)
O B. y+7--(-5)
O C. y-7-1(x+5)
O D.y+ 7 = 4(x - 5)
Help
Answers
Answer:
it appears the answer options are typed incorrectly
Step-by-step explanation:
First of a line perpendicular to another line has the inverse opposite slope
if m is the slope m of line 1 the perpendicular line slope is -1/m
y - 3 = -4(x + 2) equarion 1
y - 3 = -4x - 8 -4 × (x+2)
y = -4x - 5 added 3 to both sides to get the y intercept form y=mx+b
the slope of the perpendicular line will be 1/4
using the point slope method
y - y1 = m(x -x1)
the gives the (x,y) point of the perpendicular as (-5, 7)
x1 = -5
y1 = 7
y - 7 = 1/4(x - (-5))
y - 7 = 1/4(x +5) <-------------- Answer
the attached graph shows the line and the perpendicular going through point (-5, 7)
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If you need this in English here it is because I don't understand what you needed but ya ok bye - Translate : Si necesita esto en inglés aquí es porque no entiendo lo que necesita, pero ya está bien, adiós
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do you have a picture to help?
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