What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original
magnitude?

Answers

Answer 1

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]

Apply new values,

[tex]F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F[/tex]

So, the new force becomes 64 times the initial force.


Related Questions

Why is physics used to study stars?
A. Stars are interesting.
O B. Stars are circular.
O C. Stars are useful.
O D. Stars are made of matter.

Answers

Answer:

stars are made of matter

please help me out on this...




Only dogs
Only reptiles
Both cats and dogs
Both amphibians and reptiles

Answers

ues guys please help him
both amphibians and reptiles!

A player prefers to make high passes that lift the puck above the ice. Which stick should the
player choose?

Answers

Answer:

i dont know

Explanation:

hello

If a force of 3000 N can move a crate at an acceleration of 9.2 m/s2, what is the mass of the object?

Answers

Answer:

326 kg

Explanation:

m=f/a

3000/9.2=326 kg

PLEASE HELP—ITS PHYSICS AND I NEED ANSWERS ASAP

Answers

The answer is Point D.

A construction worker transfers 6000000 J in a n 8 hour day of work. What is their average power output? just need a quick answer with the working, thanks

Answers

Answer:

208.33 W

Explanation:

Using,

P = W/t.......................... Equation 1

P = Average power output, W = total work, t = total time.

From the question,

Given: W = 6000000 J, t = 8 hours = (8×60×60) = 28800 s

Substitute these values into equation 1

P = 6000000/28800

P = 208.33 W.

Hence the average power output is 208.33 W

Caroline uses 20 N of force to move a box of books 10 m. How much work
did she do?

Answers

Work = (force) x (distance)

Work = (20 N) x (10 m)

Work = 200 Joules

PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?

Answers

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object  2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

If a motor is rated at 5.6KW, work done in 20minutes is equal to:​

Answers

Answer:

given Power= 5.6×1000=5600watt

t=20min=20×60=1200sec. work done=?

P=w/t

w=pt=5600×1200=672×10^4Joule

The amount of work done by the motor is equal to 6.72 Megajoules.

Given the following data:

Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.

Conversion:

1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.

To determine the amount of work done by the motor:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = power \times time[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 5600 \times 1200[/tex]

Work done = 6,720,000 Joules

Note: 1,000,000 Joules = 1 Megajoules.

Work done = 6.72 Megajoules.

Read more on work done here: https://brainly.com/question/13818347

The four balls in the diagram below are made of the same material are sold

Why is the force of gravity between the balls in pair 2 greater than the force of gravity between the balls in pair 1

The balls in pair 2 are closer together than the balls in part 1

The balls in pair 2 have a grater mass than the balls in pair 1

The balls in pair 1 have more rolling friction than the balls in pair 2

The balls in pair 2 have more magnetic force than the balls in pair 2

Answers

Answer:

The balls in Pair 2 have a greater mass than the balls in pair 1.

Explanation:

I took the test.

The Doppler Effect for sound occurs when:
a) the speed of the wave changes
b) the height of the wave changes
c) the distance between the waves change
d)the moving object decreases in speed

Answers

The answer should be A because it’s frequency of a sound per second

Convection currents will transfer heat throughout a gas until what condition arises?

A.
The gas condenses and forms a liquid.

B.
The gas particles stop moving entirely.

C.
The gas has the same temperature throughout.

D.
The gas has no thermal energy in it.

Answers

Answer:

C

Explanation:

pls mark brainlest ty

have a good day

The gas has the same temperature throughout. (C)

How does a physicist define work? a force applied for a certain length of time a force applied over a distance power applied for a certain length of time power applied to something over a distance

Answers

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

Explanation:

Definition of work in physics

A measure of energy expended in moving an object; most commonly, force times distance is work.

How many joules of heat energy are needed to raise the temperature of 10.0 g (0.0100 kg) of aluminum from 22 K to 55 K, if the specific heat of aluminum is 897 J/kg * K. Explain your answer

Answers

Answer:

296.01 J

Explanation:

From the question,

Q = cm(t₂-t₁)....................... Equation 1

Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature

Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k

Substitute these values into equation 1

Q = 897×0.01×(55-22)

Q = 897×0.01×33

Q = 296.01 J

Hence 296.01 Joules of heat is required.

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