Answer:
Mechanical Engineering
Chemical Engineering
Civil Engineering
Explanation:
I got it from my old homework And I learn those at school ( Thank You For The Points)
could I please get help with this
Answer:
1.[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴
[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴
Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴
[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴
2. [tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴
[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴
Iₓ = 457.[tex]\overline 3[/tex] in.⁴
[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴
3. The maximum deflection of the beam is 2.55552 inches
Explanation:
1. The height of the beam having a rectangular cross section is h = 2.5 in.
The breadth of the beam, is = 5.5 in.
The moment of inertia of a rectangular beam through its centroid is given as follows;
[tex]I_{xc}[/tex] = b·h³/12 = 5.5 × 2.5³/12 = 1375/192 = 7.161458[tex]\overline 3[/tex]
[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴
[tex]I_{yc}[/tex] = h·b³/12 = 2.5 × 5.5³/12 = 6655/192 = 36.661458[tex]\overline 3[/tex]
[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴
The moment of inertia about the base is given as follows;
Iₓ = b·h³/3 = 5.5 × 2.5³/3 = 625/24 = 28.6458[tex]\overline 3[/tex]
Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴
[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 6655/48= 138.6548[tex]\overline 3[/tex]
[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴
2. The height of the beam having a rectangular cross section is h = 7 in.
The breadth of the beam, b = 4 in.
The moment of inertia of a rectangular beam through its centroid is given as follows;
[tex]I_{xc}[/tex] = b·h³/12 = 4 × 7³/12 = 114.[tex]\overline 3[/tex]
[tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴
[tex]I_{yc}[/tex] = h·b³/12 = 7 × 4³/12 = 37.[tex]\overline 3[/tex]
[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴
The moment of inertia about the base is given as follows;
Iₓ = b·h³/3 = 4 × 7³/3 = 457.[tex]\overline 3[/tex]
Iₓ = 457.[tex]\overline 3[/tex] in.⁴
[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 149.[tex]\overline 3[/tex]
[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴
3. The deflection, [tex]\delta _{max}[/tex], of a simply supported beam having a point load at the center is given as follows;
[tex]\delta_{max} = \dfrac{W \times L^3}{48 \times E \times I}[/tex]
The given parameters of the beam are;
The length of the beam, L = 22 ft. = 264 in.
The applied load at the center, W = 750 lbs
The modulus of elasticity for Cedar = 10,000,000 psi
The height of the wood, h = 3 in.
The breadth of the wood, b = 5 in.
The moment of inertia of the wood, [tex]I_{xc}[/tex] = b·h³/12 = 5 × 3³/12 = 11.25 in.⁴
By plugging in the given values, we have;
[tex]\delta_{max} = \dfrac{750 \times 264^3}{48 \times 10,000,000 \times 11.25} = 2.55552[/tex]
The maximum deflection of the beam, [tex]\delta _{max}[/tex] = 2.55552 inches
Which dimension of wellness focuses on finding enjoyment and satisfaction in daily endeavours?
Answer:
I believe its emotional because it says satisfaction and most of the time that has to deal with emotions running through the body.
Explanation:
Pls answer ASAP 7. A GOOD SAFETY RULE, WHEN YOU ARE SURE YOU HAVE A LEGAL RIGHT-OF-
WAY, IS:
A. Always take it
B. Never insist on it
C. Always let the other driver have
Answer:
A
Explanation:
I don`t know I need points hope it was correct.
A good safety rule, when you are sure you have a legal right of way is: B. Never insist on it.
What is safety rule?Even if you are certain that you have a legal right-of-way, it is still crucial to put safety first and avoid being overly insistent on it. When driving, safety should always come first, even if you have the right-of-way legally.
Being cautious and courteous while driving are essential components of defensive driving, and this includes letting other drivers go ahead of you if doing so will help you avoid potential collisions or problems.
Therefore the correct option is B.
Learn more about safety rule here:https://brainly.com/question/29789032
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help asap 9) A poorly tied down blimp falls over in a field. If the blimp exerts a downward force of 4000 N over an area
of 250 m2, what pressure is put on the ground by the blimp?
Answer:
[tex]Pressure = 16\ pa[/tex]
Explanation:
Given
[tex]Force = 4000N[/tex]
[tex]Area = 250m^2[/tex]
Required
Determine the pressure
Pressure is calculated using:
[tex]Pressure = \frac{Force}{Area}[/tex]
Substitute values for Force and Area
[tex]Pressure = \frac{4000N}{250m^2}[/tex]
[tex]Pressure = 16N/m^2[/tex]
Change units
[tex]Pressure = 16\ pa[/tex]
Helpppppp
The location of a vertical section through an object is shown by a(n)
_____ in the top view.
Answer:
Among us is the answer
Explanation:
If you play among is everyday then Among us is always the answer