What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon. ​

Answer:

Gravitational force can be seen as the pull that the earth has on an piece of matter. Everything on earth has a force acting on it which is gravity. It tries to pull two object closer to each other but never apart. The numerical value for gravitational force is 9.8 m/s^2 for free falling objects

Answer:

Sound as a Longitudinal Wave

For a sound wave traveling through air, the vibrations of the particles are best described as longitudinal. Longitudinal waves are waves in which the motion of the individual particles of the medium is in a direction that is parallel to the direction of energy transport.

Answer:

Hey!

Here is your answer!

Explanation:

LONGITUDINAL WAVES:

These are waves where the transferral of energy is PARALLEL to the direction it travels in...For Example...Sound Waves are Longitudinal as they move in a series of COMPRESSIONS and RAREFACTIONS (typical of all Longitudinal Waves)...

The compressions are known in diagrams to be an area of a dense collection of PARTICLES where the energy (or sound in this case) is being transferred in the same direction as the movement...

The rarefactions are shown as almost empty area of particles where the medium (the matter of which the wave travels in) is moving...

Hope this helps!

*here's a diagram*

Answer:

Part A:

They will repel each other because same poles repel each other.

Part B)

They will attract each other because different poles attract each other..

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

The acceleration of the airplane is 3m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Initial velocity of the airplane: u=o.

Time taken: t=25s.

Final velocity of the airplane: v=75m/s.

We have to find acceleration of the plane: a = ?

We know that for accelerating motion of the air plane; final velocity can be expressed as:

    v=u+at

⇒ 75=0+a(25)

⇒ 75=25a

⇒ a= 75/25

⇒ a= 3m/s².

hence, acceleration of the airplane is 3m/s².

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Answer:

B, Parallel.

Explanation:

Mark as brainliest pls!

The wave motion does longitudinal waves transfer energy in the direction Parallel to the wave motion. Hence, option B is correct.

Waves are disturbances that move regularly and orderly from one location to another. Although sound, lighting, and the movement of elementary particles all have wave-like characteristics, surface waves that move on water are the most well-known.

The disturbance periodically oscillates with a set frequency and wavelength in the simplest waves (see periodic motion). In contrast to electromagnetic waves, which do not require a medium to travel and may move through a vacuum, mechanical waves, like sound, need a medium to go through. A medium's characteristics determine how a wave will travel across it. Seismic wave is also seen.

Therefore, option B is correct.

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Answer: 390, right

explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.

the net force acting on the buggy is 390 and The net force is pointing to the is right

The following information should be considered:

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Answer:

As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.

Answer:

The apparent weight of a freely falling body is zero. When a body falls freely, it is falling with an acceleration =g. Thus the entire gravitational force acting on it is utilized in accelerating it and hence its weight is not felt.

Answer:

The correct option is;

Hire an environmental company to study the wetland and give recommendations of how to prevent flooding

Explanation:

Due to the environmental importance of wetlands which are important plant and animal habitats and a source of filtration of reserve of water moving into other surface water bodies and underground aquifers, serving also as a buffer zone to prevent erosion and flooding during heavy rain storms, proper, detailed and well informed environmental considerations are required

As such an environmental consultant services is needed for site analysis, appraisal and recommendation will be required to fast track the process of obtaining a permit.

Answer:

A

Explanation:

Answer:

A) OA, AB, BC

B) 25m/s^2

C) see explanation

D) 25

E) Rest

Explanation:

From the Velocity time graph shown:

The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.

Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.

-ve slope = BC

B) Acceleration of body in path OA.

Acceleration = change in Velocity / time

Acceleration = (150 - 0) / 6

Acceleration = 150/6 = 25m/s^2

C) Path AB is Parallel to the because it marks the period of constant velocity (that is Velocity does not increase or decrease during the time interval).

D) Length of BC

BC corresponds to the distance moved, that velocity / time

Velocity = 150 ; time = 6

Therefore Distance (BC) = 150/6 = 25

E.) Velocity =0 ; Hence body is at rest

Answer:

v = 3.24 m/s

Explanation:

Since we don't have time, we can use the formula;

(Final distance - initial distance)/time = (initial velocity + final velocity)/2

Thus;

(x_f - x_i)/t = ½(v_xi + v_xf)

We are given;

x_i = 0 m

x_f = 5 m

v_xi = 0 m/s

v_xf = 5 m/s

Thus, plugging in the relevant values;

(5 - 0)/t = (0 + 5)/2

5/t = 5/2

t = 2 s

Using Newton's first law of motion, we can find the acceleration.

v = u + at

Applying to this question;

5 = 0 + a(2)

5 = 2a

a = 5/2

a = 2.5 m/s²

To get the speed, in m/s, of the block when it had traveled only 2.1 m from the top, we will use the formula;

v² = u² + 2as

v² = 0² + 2(2.5 × 2.1)

v² = 10.5

v = √10.5

v = 3.24 m/s

Answer:

Light from star would take 100 years to reach the Earth.

Explanation:

1 light year = speed of light × 1 year

1 light year = 9.46 × 10¹⁵ m

hope i helped

-lvr

Answer:

a

Explanation:

;)

Answer: C.) Neptune

Explanation:

The Gravitational Potential Energy (GPE) of a body is calculated using the formula :

GPE = mgh

Where m = mass of the body

g = acceleration due to gravity

h = distance above a surface

Mass = 10kg

h = 2m

Using the formula :

GPE of lamp on Earth: g = 9.8

GPE = 10 × 9.8 × 2 = 71.8J

GPE of lamp on Mercury: g = 3.59

GPE = 10 × 3.59 × 2 = 196J

GPE of lamp on Mars: g = 3.7

GPE = 10 × 3.7 × 2 = 74J

GPE of lamp on Neptune: g = 14.07

GPE = 10 × 14.07 × 2 = 281.4J

GPE of lamp on Uranus: g = 9

GPE = 10 × 9 × 2 = 180J

GPE of lamp on Pluto: g = 0.42

GPE = 10 × 0.42 × 2 = 8.4J

Neptune has the highest gravitational potential energy as the value of acceleration due to gravity acting on objects is highest on Neptune.

Answer:

The correct option is;

C) Neptune

Explanation:

The force of gravity is given by the equation;

[tex]F_g = G\dfrac{m_1m_2}{r^2} = m_2 \times g[/tex]

Where:

m₁ = Mass of the planet

m₂ = Mass of the body = 10 kg

r = The distance between the body and the planet = 2 m

g = Gravitational acceleration on the planet

G = Gravitational constant

Given that the potential energy, PE = m × g × h

We have that,

[tex]PE = m_2 \times g \times (r + 2) = G\dfrac{m_1m_2}{r^2} \times (r + 2) \approx G\dfrac{m_1m_2}{r^2} \times r = G\dfrac{m_1m_2}{r}[/tex]

Therefore, the gravitational potential energy is directly proportional to the acceleration of gravity, such that the body will have the most gravitational potential energy in the planet with the highest acceleration due to gravity which is Neptune with acceleration due to gravity of 14.07 m/s².

Answer:

A) F_g = 8.9278 × 10^(-30)

B) F_e = 1.6 × 10^(-17) N upwards

C) F_m = 6.8 × 10^(-17) N downwards

Explanation:

A) Formula for gravitational force is;

F_g = m_e × g

m_e is mass of electron = 9.11 x 10^(-31) kg

F_g = 9.11 x 10^(-31) × 9.8

F_g = 8.9278 × 10^(-30) N downwards

B) Formula for Electric force is;

F_e = qe

q is charge on electron = 1.6 × 10^(-19) C

E is electric field = 100 N/C

F_e = 1.6 × 10^(-19) × 100

F_e = 1.6 × 10^(-17) N upwards

C) Magnetic force is given by the formula;

F_m = qVB

q is charge on electron = 1.6 × 10^(-19) C

V is velocity given as 8.50 × 10^(6) m/s

B is magnetic field = 50.0 μT = 50 × 10^(-6) T

F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)

F_m = 6.8 × 10^(-17) N downwards

Answer:

amongst the properties that makes aluminium a metal is that it is malleable and ductile...and it has high melting and boiling points

I hope that helps

Explanation:

properties of metals include

1. high melting and boiling points

2 high densities

3 malleability and ductility

Answer:

Take a look at the attachment below.

Explanation:

Current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.

An electric current is defined as a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space, which is described as the flow of electric charge through a surface or in a control volume.

Current is expressed as:

I=V/R

Where, I is the current

V is the voltage

R is the resistance

For above given information,

Since all resistors have the same resistance, it would be fine to find only 1 branch as the current would be the same for all branches.

[tex]I=V/R_1[/tex]

I= 30/15= 2 A

Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.

[tex]1/R= 1/R_1+ 1/R_2+ 1/R_3[/tex]

1/R= 1/15+ 1/15 + 1/15

1/R=3/15

R = 15/3= 5 ohms

I = V/R

Where I is current, V is voltage and R is the equivalent resistance

=> I = 30/5

=> I = 6 A

Thus, current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.

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Explanation:

time spent to run from house to school=100/5=20s

time spent to return from school=100/10=10s

average velocity=200m/(10+20)

Answer:

1:281.25m

2:75m/s

Explanation:

using the equation

[tex]v^{2} = u^{2} + 2gs[/tex]

at maximum height v is zero so using that you can make s the subject of the formula

[tex]h \: max = u^{2} \div \: 2g[/tex]

so substitute the velocity 75 and the constant g-10m/s^2

as for the returning velocity we say displacement is zero since you go and come back the same distance

so

[tex]v = { + or - }u[/tex]

u is the initial speed in this case it's positive since going in the direction of gravity

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + [tex]v_{oy}[/tex] t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        [tex]v_{y}[/tex] = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero ([tex]v_{oy}[/tex] = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s

Answer:

The weight of barbell acting on a weight lifter is 80N.

Explanation:

Answer:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Answer:

Writing of a story that ends with the character becoming poor with no friends.

Explanation:

There was a young girl who believed that all things revolve around her. She had the money, the power, the family, and the beauty to ensure she was the center of attention. She would always be the main focus, everywhere she goes.

But there came a time when she had a major misfortune. Her family had come upon unfortunate times. They are going to lose their money and may even be jailed for embezzlement. It was true that she had no idea what her parents had done but she was also so familiar with the 'princess' lifestyle that she did not know how to downgrade her lifestyle. And so, when this misfortune happened, she was unsure how to react. She also assumed that her friends will be there for her. Little did she know everyone was just after her wealth and influence and had nothing to do with genuine friendship.

In a few months, their family position moved from top to bottom, which everyone found hard to accept. She had to maintain her status while at the same time try to live up with that without losing her circle. But as rumors spread fast and she wasn't able to spend the way she would normally send, she eventually experienced a dwindled friend circle. And in about a year, she had lost all of her friends, couldn't even convince someone to stay with her faithfully and worse of all, she was also poor, the very status she had degradingly taunted other people with.

Given that,

Mass of satellite = 500 kg

Gravitational force = 3000 N

We need to calculate the radius of the circular orbit

Using formula of gravitational force

[tex]F_{g}=\dfrac{GMm}{(R+h)^2}[/tex]

Where, G = gravitational constant

R = radius of earth

h = radius of the circular orbit

M = mass of earth

m = mass of satellite

Put the value into the formula

[tex]3000=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}}{(6.4\times10^{6})^2+h^2}[/tex]

[tex]h^2=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}[/tex]

[tex]h=\sqrt{\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}}[/tex]

[tex]h=5073460.35\ m[/tex]

[tex]h=5.1\times10^{6}\ m[/tex]

(II). We need to calculate the speed of the satellite

Using formula of velocity

[tex]v=\sqrt{\dfrac{GM}{r}}[/tex]

Put the value into the formula

[tex]v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{5.1\times10^{6}}}[/tex]

[tex]v=8858.36\ m/s[/tex]

[tex]v=8.8\times10^{3}\ m/s[/tex]

[tex]v=8.8\ km/s[/tex]

(III). We need to calculate the period of the orbit

Using formula of  time period

[tex]T=2\pi\sqrt{\dfrac{r^3}{GM}}[/tex]

Put the value into the formula

[tex]T=2\pi\sqrt{\dfrac{(5.1\times10^{6})^3}{6.67\times10^{-11}\times6\times10^{24}}}[/tex]

[tex]T=3617.40\ sec[/tex]

[tex]T=1.00\ hr[/tex]

Hence, (I). The radius of the circular orbit is [tex]5.1\times10^{6}\ m[/tex]

(II). The speed of the satellite is 8.8 km/s.

(III). The period of the orbit is 1.00 hr.

Answer:

The impacts of modern communication in our socio economic life includes;

a) Staying connected

b) Carrying out business transaction

c) Exceeding boundaries

d) Overcoming weakness and disability

e) Reaching out to a wider audience

2. It is possible to make long distant call to our relatives in other part of the country by direct distance dialing (DDD)

Explanation:

The telecommunication service called direct distance dialing allows a caller to make a call to a location outside the area where they are calling without the assistance of an operator. To make a direct dialing call, a subscriber or caller will be required to include extra prefix digits to the original number than for numbers within hers or his particular local area code.

Answer:

The two forms of energy that increase during the time after take off are;

1) The kinetic energy KE

1) The potential energy PE

Explanation:

1) Given that the airplane is accelerating, we have that the velocity, v, of the airplane is increasing, such that the we have the kinetic energy, KE, for a given mass, m, of the airplane increasing as follows;

KE₂ = 1/2×m×v₂² > KE₁ = 1/2×m×v₁²

2) Also, as the height, h, of the airplane increases during the ascent, we have that the potential energy increasing along side as follows;

PE₂ = m × g × h₂ > PE₁ = m × g × h₁

Therefore, the two forms of energy that increase during the time after take off are the kinetic  and the potential  energy.

Answer:

8.43 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv/Δt

First, convert km/h to m/s.

45 km/h = 12.5 m/s

500 km/h = 138.9 m/s

Now find the acceleration.

a = (138.9 m/s − 12.5 m/s) / 15.0 s

a = 8.43 m/s²

Answer:

Índice de refracción entre los dos medios = 1,43

Refractive index between the two media = 1.43

Explanation:

El índice de refracción entre dos medios se explica mejor entendiendo primero la refracción.

Cuando las olas se mueven de un medio a otro, a menudo experimentan un cambio de dirección con respecto al medio en el que viajan.

Por lo tanto, el índice de refracción se expresa como el seno del ángulo de incidencia dividido por el seno del ángulo de refracción.

El seno del ángulo de incidencia y la refracción utilizados en esta fórmula de índice de refracción se miden respectivamente con respecto a la vertical.

En esta pregunta Ángulo de incidencia = 35° a la horizontal = (90° - 35°) a la vertical = 55° a la vertical.

Ángulo de refracción = 35°

Índice de refracción entre los dos medios

= (Sin 55°) ÷ (Sin 35°)

= 0.8192 ÷ 0.5736

= 1.428 = 1.43 a 2 d.p.

¡¡¡Espero que esto ayude!!!

English Translation

The light passes from medium A to medium B at an angle of 35 ° with the horizontal border between the two. If the angle of refraction is also 35 °, what is the relative refractive index between the two media?

Solution

The refractive index between two media is best explained by first understanding refraction.

When waves move from one medium to another, they often experience a change in direction with respect to the medium in which they are travelling.

Hence, refractive index is expressed as the sine of angle of incidence dibided by the sine of angle of refraction.

The sine of angle of incidence and refraction used in this refractive index formula are both respectively measured with respect to the vertical.

In this question,

Angle of incidence = 35° to the horizontal = (90° - 35°) to the vertical = 55° to the vertical.

Angle of refraction = 35°

Refractive index between the two media

= (Sin 55°) ÷ (Sin 35°)

= 0.8192 ÷ 0.5736

= 1.428 = 1.43 to 2 d.p.

Hope this Helps!!!

Answer: 3.75 m/s

Explanation:

Average speed is distance covered per time taken.

If the time interval is from t = 2 to t = 10s

Then, the time taken will be

t = 10 - 2 = 8s

Given that the distance covered are 10 + 8 - 2 + 10

Since distance is a scalar quantity, we will only consider the magnitude and not the direction.

Total distance = 10 + 8 + 2 + 10 = 30m

Average speed = total distance/time

Substitute total distance and time into the formula

Average speed = 30/8

Average speed = 3.75 m/s

Answer:

the ability of data to be duplicated well described reproducibility

Explanation:

Reproducibitity of a data is the ability of a data to be produced in multiple times using the same procedure. It is used to test how precise a data is and it's usually known as standard deviation

Reproducibility is the closeness of the understanding between the consequences of measurements of the equivalent measurand did with a similar procedure depicted in the relating logical proof (for example a distribution in a companion surveyed diary).

Answer:

the ability of data to be duplicated well described reproducibility

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

3) Maximum elevation is maximum time reached

h = v² sin²Ф / 2g

h = 4²sin² 60 / 2*9.8

h = 0.61 m