Answer:
It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit
Explanation:
What is a galvanometer?
A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.
A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant
The physical quantity which have both magnitude and direction is a vector?why?
Answer:
hiiiiiiiiiiiii baby.........
a car is initially at rest. ten seconds later it is moving 30 m/s. what is the car's acceleration
Answer:
The car's acceleration is [tex]3\ m/s^2[/tex]
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly over time.
The final speed is given by:
[tex]v_f=v_o+at[/tex]
Where a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
Using the equation above we can solve for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The car is initially at rest (vo=0) and t=10 seconds later it's moving at vf=30 m/s, thus its acceleration is:
[tex]\displaystyle a=\frac{30-0}{10}[/tex]
[tex]\displaystyle a=\frac{30}{10}=3[/tex]
[tex]a = 3\ m/s^2[/tex]
The car's acceleration is [tex]3\ m/s^2[/tex]
A 120V AC signal is available at the wall port. You are required to convert it to a constant DC voltage of 12V for a laptop to operate. What are the three electrical components you will be using to achieve the same? Name the components in order and the function it performs.
Answer:
The following components shall be used in given order:
1. Step Down Transformer 2. Diode as Rectifier 3. Capacitor
Explanation:
The following components shall be used in given order:
1. Step Down Transformer 2. Diode as Rectifier 3. Capacitor
1.STEP DOWN TRANSFORMER:
The step down transformer is first used to convert the 120 V AC signal into 12 V AC signal. Because the output required is of 12 V.
2.DIODE AS RECTIFIER:
Now, the PN Junction diode is used as a rectifier to convert the 12 V AC signal to 12 V DC signal.
3.CAPACITOR:
Now, the output is in waveforms. So, in order to linearize it in the form of DC current, we use capacitor. The main function of capacitor is to smoothen the signal into a straight line.
The world record for a woman running a marathon is approximately 2.25 hours. If a marathon's distance is 26.2 miles (42164.81 meters) and it is run
in a southeast direction, what is the velocity?
60 mph southeast
0.09 mph southeast
Omph southeast
11.6 mph southeast
Answer:
11.6mph South East
Explanation:
Given parameters:
Time = 2.25hrs
Displacement = 26.2miles south east
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.
Now;
Velocity = [tex]\frac{displacement}{time taken}[/tex]
Velocity = [tex]\frac{26.2}{2.25}[/tex] = 11.6mph South East
Answer:
11.6mph south east.
Elements known as noble gases do not have the ability or the room in their valence
electron shell to form bonds with other elements.
O True
O False
Answer:
true
Explanation:
noble gases are octet meaning they they have eight electrons in their outer shell so the are stable
A man fires a silver bullet of mass 2g with a velocity of200m/sec into wall. What is the temperature changeof the bullet? Note: Csilver = 234J/kg.°CL
F=nmv
where;
n=no. of bullets = 1
m=mass of bullets=2g *10^-3
V=velocity of bullets200m/sec
F=1
loss in Kinetic energy=gain in heat energy
1/2MV^2=MS∆t
let M council M
=1/2V^2=S∆t
M=2g
K.E=MV^2/2
=(2*10^-3)(200)^2/2
2 councils 2
2*10^-3*4*10/2
K.E=40Js
H=mv∆t
(40/4.2)
40Js=40/4.2=mc∆t
40/4.2=2*0.03*∆t
=158.73°C
Discuss the relationship between size and wieght of an object and the amount
What happens when light from the sun passes through any type of matter
Answer:
its it filled with energy
Answer:
The light slows down.
Explanation:
What will happen to the ice cubes in the two spoons? How will they be different?
Answer: the ice cube to melt more quickly on the metal block than on the wooden block.
Explanation:
Which describes one feature of the image formed by a convex mirror?????
Answer:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Explanation:
The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.
Also notice that convex mirror always makes virtual images.
Another feature of the convex mirror is that an upright image is always formed by the convex mirror.
An important mirror formula to remember which is applicable for both convex and mirrors
1/f= 1/u + 1/vHere:
'u' is an object which gets placed in front of a spherical mirror of focal
length 'f' and image 'u' is formed by the mirror.
Answer:
right side up
Explanation:
A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 7.1 m making 3.9 revolutions every 9.4 second. What is the centripetal acceleration of the ball?
Answer:
48,2 m/s²
Explanation:
We're gonna use the Centripetal Acceleration formula: v² / r but before that, we got to know the velocity, that is not shown clearly to us, so....
To know the velocity let's calculate the distance that the ball traveled
The circumference of a circle formula is:
2piR
2 . 3,14 . 7,1 | That is equal to 44,588 m
We know that the ball traveled this distance 3,9 times, so...
44,588 . 3,9 = 173,8932 m
Ok, now we have the distance, just need to know the time, that is 9.4 seconds.
Velocity = Distance / Time
V = 173,8932 / 9,4
V = 18,5 (approximate)
So...
We are back to the first formula:
Ca = v² / r
Ca = 18,5² / 7.1
Ca = 48,2 m/s² (approximate)
I hope it is correct, hahaha.
In the Vomitus carnival ride, passengers travel in a horizontal 4.0 m radius circle. For safe operation, the maximum sustained acceleration that riders may experience is 20 m/s2 , approximately twice the free fall acceleration. What is the period of the ride when it is being operated at the maximum acceleration?
Answer:
The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.
Explanation:
We can use the centripetal acceleration here:
[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]
Let's find the angular velocity ω at the maximum acceleration.
[tex]20=\omega^{2}*4[/tex]
[tex]\omega=2.24 rad/s[/tex]
The period is given by:
[tex]T=\frac{2\pi}{\omega}[/tex]
[tex]T=\frac{2\pi}{2.24}[/tex]
Therefore, the period will be T=2.81 s.
I hope it helps you!
The activity of mining has direct negative effects on
a. atmosphere
b.hydrosphere
c.biosphere
d.geosphere
Answer:
A
Explanation:
When coal is burned it releases many harmful chemicals into the air, such as methane (greenhouse gas) and contributes to global warming
A monatomic ideal gas with volume 0.230 L is rapidly compressed, so the process can be considered adiabatic. If the gas is initially at 1.01 105 Pa and 3.00 102 K and the final temperature is 489 K, find the work done by the gas on the environment, Wenv.
Answer:
The value is [tex]W = - 17.53 \ J[/tex]
Explanation:
From the question we are told that
The volume is [tex]V = 0.230 \ L = 0.230 *10^{-3} \ m^{-3}[/tex]
The initial pressure is [tex]P_1 = 1.01105 \ Pa[/tex]
The initial temperature is [tex]T_1 = 3.00*10^2 \ K[/tex]
The final temperature is [tex]T_2 = 489 \ K[/tex]
Generally for an adiabatic process the workdone is mathematically represented as
[tex]W = - \Delta U[/tex]
Here [tex]\Delta U[/tex] is the internal energy of the system which is mathematically represented as
[tex]\Delta U = \frac{3}{2} * nR \Delta T[/tex]
So
[tex]W = - \frac{3}{2} * nR \Delta T[/tex]
Generally from ideal gas equation we have that
[tex]n = \frac{P_1V }{ RT_1 }[/tex]
Here R is the gas constant with value [tex]R = 8.314 J/mol\cdot K[/tex]
So
[tex]n = \frac{1.01 *0^{5} * 0.230 *10^{-3}}{ 8.314 * 3.0*10^2 }[/tex]
=> [tex]n = 0.009313 \ mol[/tex]
So
[tex]W = - \frac{3}{2} * 0.009313 * 8.314 * (451 - 3.00*10^2)[/tex]
=> [tex]W = - 17.53 \ J[/tex]
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of 3.50 s. Find the force constant of the spring.
Answer:
17.71N/m
Explanation:
The period of the spring is expressed according to the expression;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]
m is the mass of the object
k is the force constant
Given
m = 5.50kg
T = 3.50s
Substitute into the formula;
[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]
Hence the force constant of the spring is 17.71N/m
An astronaut on the Moon releases a rock from rest and allows it to drop straight downward. If the acceleration due to gravity on the Moon is 1.62m/s2 and the rock falls for 2.4s before hitting the ground, what is its speed just before it lands?
Answer:
speed before landing = 3.9 m/s (3 s.f.)
Explanation:
As rock is released from rest, u = 0 m/s a = 1.62 m/s² t = 2.4 s v = ?
v = u + at
v = 0 + (1.62 x 2.4)
v = 3.888 = 3.9 s (3 s.f.)
Hope this helps!
The speed of the rock before hitting the ground is 3.89 m/s
The given parameters;
acceleration due to gravity on moon, g = 1.62 m/s²
time taken for the object to fall, t = 2.4 s
To find:
the speed of the object before hitting the ground;The maximum height of fall of the rock is calculated as;
[tex]h = v_0t + \frac{1}{2} gt^2\\\\v_0 = 0\\\\h = \frac{1}{2} gt^2\\\\h = 0.5 \times 1.62 \times 2.4^2 \\\\h = 4.67 \ m[/tex]
The speed of the rock before hitting the ground is calculated as;
[tex]v_f^2 = v_0 ^2 + 2gh\\\\v_f^2 = 0 + 2\times 1.62 \times 4.67\\\\v_f^2 = 15.13\\\\v_f = \sqrt{15.13} \\\\v_f = 3.89 \ m/s[/tex]
Thus, the speed of the rock before hitting the ground is 3.89 m/s
Learn more here: https://brainly.com/question/4617423
5. Correct the statement : Human being
can hear sounds of frequencies upto
60000Hz.
Answer:
Humans can detect sounds in a frequency range from about 20 Hz.
If you wanted to find a sample of fermium, which has an atomic number of 100, where would you look?
A. Deep within the earth
B. In the earths atmosphere
C. In outer space
D. In Science Lab
Answer:
B
Explanation:
Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.
It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.
A stretched string is 1.95 m long and has a mass of 19.1 g. When the string oscillates at 440 Hz, which is the frequency of the standard A pitch, transverse waves with a wavelength of 16.7 cm travel along the string. Calculate the tension T in the string.
T= ________ N
Answer:
The tension in the string is 52.89 N.
Explanation:
Given;
mass of the string, m = 19.1 g = 0.0191 kg
length of the string, L = 1.95 m
⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m
Also Given;
frequency of the string, F = 440 Hz
wavelength of the sound wave, λ = 16.7 cm = 0.167 m
⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s
The tension T in the string is calculated as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]
Therefore, the tension in the string is 52.89 N.
1. On a force vs. mass graph, what would be the slope of the line?
2. On a Free Body Diagram, if the forces are all balanced, what do you know about the
object? Can it be moving?
1. By Newton's second law,
F = m a
so the slope of the line would represent the mass of the object.
2. If all the forces are balanced, then the object is in equilibrium with zero net force, which in turn means the object is not accelerating. So the object is either motionless or moving at a constant speed.
A water-skier of mass 75.0 kg initially at rest is being pulled due east by a horizontal towrope. The rope exerts a force of 365 N (east). The water (and air) exerts a combined average frictional force of 190 N (in the opposite direction). How fast will the skier be moving after a distance of 38.0 m?
Answer:
The skier will be moving at 13.31 m/s.
Explanation:
To calculate the velocity of the skier we need to find the acceleration, as follows:
[tex] \Sigma F = ma [/tex]
[tex] F_{r} - F_{f} = ma [/tex]
Where:
[tex] F_{r}[/tex]: is the force due to the rope = 365 N
[tex] F_{f}[/tex]: is the combined average frictional force = 190 N
m: is the mass = 75.0 kg
[tex] a = \frac{365 N - 190 N}{75.0 kg} = 2.33 m/s^{2} [/tex]
Now, we can calculate the velocity of the skier by using the following kinematic equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
[tex] v_{f}[/tex]: is the final velocity =?
[tex] v_{0}[/tex]: is the initial velocity = 0 (the skier is initially at rest)
d: is the distance = 38.0 m
[tex] v_{f} = \sqrt{2*2.33 m/s^{2}*38.0 m} = 13.31 m/s [/tex]
Therefore, the skier will be moving at 13.31 m/s.
I hope it helps you!
help asap
what is the force responsible for seafloor spreading and the formation of new ocean floor at mid ocean ridges
Answer:
magma
Explanation:
I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma
Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.
What is seafloor spreading?Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.
Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.
Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.
Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.
The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.
Thus, the correct option is B.
For more details regarding seafloor spreading, visit:
https://brainly.com/question/15122129
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Pulmonary circulation involves blood flow to and from the heart and the ____?
body
digestive organs
skin
brain
lungs
Answer: Lungs
Explanation:
Newton's 2nd Law describes the relationship between force, mass, and acceleration of an object with the formula F=ma. Which scenario below will result in the greatest accleration? (AKS 8b / DOK 1)
A. A 20 kg rock thrown with a 100 N force.
B. A 10,000 kg rocket launched with 100,000 N of force.
C. A 2,000 kg car accelerated with a 1000 N force from the engine.
D. A 50 kg student pushed in a chair with a force of 1000 N.
Answer:D
Explanation:If you want to find the acceleration do Force/mass.
The greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.
As per the Newton's second law, " The applied force on an object is equal to the product of mass of object and acceleration cause by the applied force. Then, the mathematical expression is,
F = ma
Here, F is the applied force, m is the mass and a is acceleration.
(A)
For 20 kg mass and 100 N force, the acceleration is,
F = ma
100 = (20)a
a = 5 m/s²
(B)
For 10,000 kg mass of rocket and 100,000 N force, the acceleration is,
F = ma
100 ,000= (10,000)a
a = 10 m/s²
(C) For a 2,000 kg mass of car and force of 1000 N, the acceleration is,
F = ma
1000 = (2000)a
a = 0.5 m/s²
(D) For a mass of 50 kg student and applied force of 1000 N, the acceleration is,
F = ma
1000 = (50)a
a =20 m/s².
Thus, we can conclude that the greatest magnitude of acceleration is of 20 m/s², by the student of 50 kg pushing the chair with 1000 N of force. Hence, option (D) is correct.
Learn more about the Newton's Second law here:
https://brainly.com/question/13447525
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Answer:
After 3secondsExplanation:
A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer
Using the formula for calculating speed expressed as;
Speed = Distance/Time
Given;
Distance = 3km = 3000m
Speed = 1000m/s
Required
How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)
From the formula;
Time = Distance/speed
Time = 3000/1000
Time = 3seconds
Hence the sound of the aircraft is heard after 3 seconds
A person walks 5 meters north, which is vector 1. Then he walks 4 meters east, which is vector 2. The displacement vector is vector 3. Draw the vectors and calculate displacement and the angle between vectors 1 and 3
Explanation:
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As the mass of a body increases, its gravitational force of attraction to the Earth...
Answer:
the answer may be mass and distance
A section of a sphere has a radius of curvature of 0.72 m. If this section is painted with a reflective coating on both sides, what is the focal length of:
Answer:
The value is [tex]f = 0.36 \ m[/tex]
Explanation:
From the question we are told that
The radius of curvature is [tex]R = 0.72 \ m[/tex]
Generally the radius of curvature is mathematically represented as
[tex]R = 2f[/tex]
Here [tex]f[/tex] is the focal length hence
[tex]f = \frac{R}{2}[/tex]
=> [tex]f = \frac{0.72}{2}[/tex]
=> [tex]f = 0.36 \ m[/tex]
A box takes 450 N to start moving when the coefficient of static friction is 0.25. What is
the box's weight?
A rock is thrown straight up with an initial speed of 22 m/s. How long will it be in the air before it returns to the thrower?
Answer:
The time spent in air by the rock before it returns to the thrower is 4.5 s
Explanation:
Given;
initial velocity of the rock, u = 22 m/s
Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.
The time to go up is calculated as;
v = u - gt
where;
v is the final velocity at the maximum height
0 = u - gt
gt = u
t = u / g
t = 22 / 9.8
t = 2.245 s
thus time to go up = 2.245 s
and time to return to the thrower = 2.245s
The total time spent in air by the rock before it returns to the thrower
= 2.245 s + 2.245s
= 4.5 s