What do Ice core samples with lower ratios of O-18 to O-16 isotopes tell scientist about past climates

Answers

Answer 1

Answer:

Ocean-floor sediments can also be used to determine past climate. ... Ice cores contain more 16O than ocean water, so ice cores have a lower 18O/ 16O ratio than ocean water or ocean-floor sediments. Water containing the lighter isotope 16O evaporates more readily than 18O in the warmer subtropical regions

Explanation:


Related Questions

A 4.00-m-long, 470 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 75.0 kg construction worker stands at the far end of the beam. For the steps and strategies involved in solving a similar problem, you may view a Video Tutor Solution. What is the magnitude of the torque about the point where the beam is bolted into place?

Answers

Answer:

12164.4 Nm

Explanation:

CHECK THE ATTACHMENT

Given values are;

m1= 470 kg

x= 4m

m2= 75kg

Cm = center of mass

g= acceleration due to gravity= 9.82 m/s^2

The distance of centre of mass is x/2

Center of mass(1) = x/2

But x= 4 m

Then substitute, we have,

Center of mass(1) = 4/2 = 2m

We can find the total torque, through the summation of moments that comes from both the man and the beam.

τ = τ(1) + τ(2)

But

τ(1)= ( Center of m1 × m1 × g)= (2× 470× 9.81)

= 9221.4Nm

τ(2)= X * m2 * g = ( 4× 75 × 9.81)= 2943Nm

τ = τ(1) + τ(2)

= 9221.4Nm + 2943Nm

= 12164.4 Nm

Hence, the magnitude of the torque about the point where the beam is bolted into place is 12164.4 Nm

a toy train is moved towards a magnet that cannot move. what happens to the potential energy in the system of magnets during the movement​

Answers

Answer:

Dakota moves a magnetic toy train toward a magnet that cannot move. What happens to the potential energy in the system of magnets during the movement? The potential energy increases because the train moves against the magnetic force. The potential energy decreases because the train moves against the magnetic force.

I hope this helps you :)

can someone please help me I am so behind I neee to catch up but I need it to be correct both of them

Answers

Answer:

1.B, 2.A

Explanation:

Se desea elevar un cuerpo de 1000 kg utilizando una elevadora hidráulica de plato grande circular de 50 cm de radio y plato pequeño circular de 8cm de radio, calcula: a) El peso del cuerpo. b) Cuanta fuerza hay que hacer en el émbolo pequeño, c) Si el émbolo pequeño desciende 60 cm, ¿qué volumen de fluido desplaza hacia el émbolo mayor?​

Answers

Answer:

a) [tex]W=9810\: N[/tex]

b) [tex]F_{1}=251.14\: N[/tex]        

c) [tex]V_{g}=0.012\: m^{3}[/tex]

Explanation:

a)

El peso del cuerpo es:

[tex]W=mg[/tex]

g es la gravedad (9.81 m/s²)

[tex]W=1000*9.81[/tex]

[tex]W=9810\: N[/tex]

b)

Usando el principio de Pascal tenemos:

[tex]P_{1}=P_{2}[/tex]

y la presion es la fuerza sobre el area.

[tex]\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}[/tex]

F(1) es la fuerza aplicada en el embolo pequeñoA(1) es el area del disco pequeñoF(2) es la fuerza aplicada en el embolo grandeA(2) es el area del disco grande

Despejando F(1):

[tex]F_{1}=F_{2}\frac{A_{1}}{A_{2}}[/tex]

el area del plato es: [tex]A=\pi R^{2}[/tex]

[tex]F_{1}=F_{2}\frac{\pi R_{1}^{2}}{\pi R_{2}^{2}}[/tex]

[tex]F_{1}=F_{2}\frac{R_{1}^{2}}{R_{2}^{2}}[/tex]

F(2) es el peso del cuerpo de 1000 kg (W)

[tex]F_{1}=9810\frac{8^{2}}{50^{2}}[/tex]

Por lo tanto, la fuerza que se debe hacer es:

[tex]F_{1}=251.14\: N[/tex]          

c)

Como tenemos un sistema cerrado el volumen de agua que desciende por el embolo pequeño debe ser igual al que sube por el grande, por lo tanto:

[tex]V_{p}=V_{g}[/tex]

Vp es el volumen de agua en el émbolo pequeño

Vg es el volumen de agua en el émbolo grande

Como sabemos que son cilindros (V=πR²h)

[tex]\pi R^{2}h=V_{g}[/tex]

Entonces el volumen del émbolo mayor será:

[tex]V_{g}=\pi 0.08^{2}0.6[/tex]

[tex]V_{g}=0.012\: m^{3}[/tex]

Espero te haya sido de ayuda!

The Hall effect can be used to determine the density of mobile electrons in a conductor. A thin strip of the material being investigated is immersed in a magnetic field and oriented so that its surface is perpendicular to the field. In a particular measurement, the magnetic field strength was 0.685 T, the strip was 0.107 mm thick, the current along the strip was 2.25 A, and the Hall voltage between the strip's edges was 2.59 mV.Find the density nof mobile electrons in the material. The elementary charge is 1.602×10−19 C.

Answers

Answer:

the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

Explanation:

Given the data in the question;

we make use of the following expression;

hall Voltage VH = IB / ned

where I = 2.25 A

B = 0.685 T

d =  0.107 mm =  0.107 × 10⁻³ m

e = 1.602×10⁻¹⁹ C

VH = 2.59 mV = 2.59 × 10⁻³ volt

n is the electron density

so from the form; VH = IB / ned

VHned = IB

n = IB / VHed

so we substitute

n = (2.25 × 0.685) / ( 2.59 × 10⁻³ × 1.602×10⁻¹⁹ × 0.107 × 10⁻³ )

n = 1.54125 /  4.4396226 × 10⁻²⁶

n = 3.4716 × 10²⁵ m⁻³

Therefore, the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

If the object on the Moon were raised to a height of 30.0 m, what would be the potential energy? PE=mgh (g on the Moon is 1.62m/s)

Answers

PE= mgh
m=mass =?
g=1.62
h= height = 30

PE= m(1.62)(30)
PE = 48.6m Joules

( if you left out the mass by mistake just multiply it by 48.6)

A 45.0 kilogram boy is riding a 15.0-kilogram bicycle with a speed of 8.00 meters per second. What is the combined kinetic energy of the boy and the bicycle? A)480.J B)240.0J C)1920J D)1440J​

Answers

Answer:

1920Joules

Explanation:

The formula for calculating the kinetic energy of a body is expressed as;

KE = 1/2 mv²

m isthe mass

V is the speed

For the two masses, the combined KE is expressed as;

KE  = 1/2(m1+m2)v²

KE = 1/2(45+15)(8)²

KE  = 1/2 * 60 * 64

KE  = 30 * 64

KE  = 1920J

Hence the combined kinetic energy of the boy and the bicycle is 1920Joules

The combined kinetic energy of the boy and the bicycle is of 1920 J.

Given data:

The mass of boy is, m = 45.0 kg.

The mass of bicycle is, M = 15.0 kg.

The speed of bicycle is, v = 8.00 m/s.

The kinetic energy of an object is defined as the energy possessed by an object by virtue of motion of object. The combined kinetic energy of the boy-bicycle system is given as,

[tex]KE = \dfrac{1}{2}(m+M)v^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2}(45+15) \times 8^{2}\\\\KE = 1920 \;\rm J[/tex]

Thus, we can conclude that the combined kinetic energy of the boy and the bicycle is of 1920 J.

Learn more about the concept of kinetic energy here:

https://brainly.com/question/12669551

Scott travels north 3 Km and then goes west 3 Km before coming straight
back south 3 km. What is his displacement? *
9 Km
3 km, W
3 Km, E
9 km, S

Answers

Answer:

you have to times them all ti get the answer

Wind is formed when hot air rises and cool air sinks. This process is called __________

conduction
insulation
radiation
convection
plsssssssss answer this correct i put in 12 points and i will give you brainliest if you answer correct

Answers

Answer:

conduction is the correct answer

Lex launched a golfball with his lego catapult. It traveled 7 meters and was in the air for 2 seconds. Please determine the object’s maximum height, horizontal velocity, vertical velocity, actual velocity, and time it reached its maximum height. The angle of release (the catapult’s arm) is 40°.


Horizontal Velocity = vx
Vertical Velocity = V1y
Actual Velocity: V1 = Vactual
Time reached highest point
Height reached!= h
Givens:

dx=

a=

t=


Angle of release:



Table B:
What you need to determine
Formula used
Answer: remember to label the correct units
Distance
Measure it with a meter stick


Time Traveled
Measure it with a stopwatch


Horizontal Velocity




Vertical Velocity




Actual Velocity




Time reached Highest Point




What was the object’s highest point

Answers

Answer:

Explanation:

Range R = 7 m

angle of projection θ = 40⁰

u² sin2θ / g = R where u is velocity of throw.

u² sin 80 / g = 7

u² = 69.71

u = 8.35 m/s

horizontal velocity = u cos 40 = 8.35 cos 40

= 6.4 m /s

vertical velocity = u sin 40 = 8.35 sin40

= 5.37 m /s

Maximum height :-

v² = u² - 2gh , u is initial vertical component of throw.

0 = 5.37² - 2 x 9.8 x h

h = 1.47 m

Time to reach max height :--

v = u - gt

o = 5.37 - 9.8 t

t = .55 s

In 2014, physicists from FOM Foundation at the University of Amsterdam introduced a new hypothesis of how the Pyramids at Giza were built. The group of physicists suggestedthat ancient Egyptians wetted sand in an effort toreduce friction and then pulled the 3000 kg stoneblocks to their final resting place. 15 men couldmove a block at a rate of 0.5m/sby pulling a largerope angled at 30owith respect to the plane anda tension of 7,200 N.

Required:
a. What is net work done on block?
b. What is speed of blck after it moved .25m?
c. What is work done by block if kinetic friction coefficient is 0.3?
d. What is net work including friction?

Answers

Answer:

The correct answer is:

(a) 0

(b) 0.5 m/s

(c) 7740 N

(d) 0

Explanation:

The given values are:

mass,

m = 3000 kg

Tension,

T = 7,200 N

Angle,

= 30°

(a)

Even as the block speed becomes unchanged, the kinetic energy (KE) will adjust as well:

⇒ [tex]\Delta K =0[/tex]

By using the theorem of energy, the net work done will be:

⇒  [tex]\Delta K =0[/tex]

(b)

According to the question, After 0.25 m the block is moving with the constant speed

= 0.5 m/s.

(c)

The given kinetic friction coefficient is:

u = 0.3

The friction force will be:

= [tex]u(mg-Tsin30^{\circ})[/tex]  

On substituting the values, we get,

= [tex]0.3[(3000\times 9.8)-(7200\times 0.5)][/tex]

= [tex]0.3[29400-3600][/tex]

= [tex]0.3\times 25800[/tex]

= [tex]7,740 \ N[/tex]

(d)

On including the friction,

The net work will be:

⇒ [tex]\Delta K=0[/tex]

i need this literally asap

which of these statements are true?
1. it is always correct to use a 3 Amp fuse.
2. Fuses come in several different sizes and values
3. A fuse can be re-set and used again
4. A fuse once ‘blown’ needs replacing
5. Fuses are the ‘weak point’ in a circuit

Answers

Answer:

I only know number 4 is correct

Explanation:

An object swings in a horizontal circle, supported by a 1.8-m string. It swings at a speed of 3 m/s. What is the mass of the object given that the tension in the string is 90 N?

Answers

Answer:

Mass = 18 kg

Explanation:

Formula for force in centripetal motion is;

F = mv²/r

We have;

Mass; m.

Speed; v = 3 m/s

radius; r = 1.8 m

Force; F = 90 N

Thus;

Making m the subject;

m = Fr/v²

m = 90 × 1.8/3²

m = 18 kg

HELP DUE 3 MINUTESSSSD

Answers

Answer:

Break down small pebbles and sediments, like sand

Break down large rocks like mountains

Explanation:

In the legend of William Tell, Tell is forced to shoot an apple from his son's head for failing to show respect to a high official. In our case, let's say Tell stands 8.7 meters from his son while shooting. The speed of the 144-g arrow just before it strikes the apple is 20.4 m/s, and at the time of impact it is traveling horizontally. If the arrow sticks in the apple and the arrow/apple combination strikes the ground 8 m behind the son's feet, how massive was the apple

Answers

Answer:

M = 0.31 kg

Explanation:

This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved

let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple

initial instant. Just before the crash

          p₀ = m v₁ + M 0

instant fianl. Right after the crash

          p_f = (m + M) v

          p₀ = p_f

          m v₁ = (m + M) v

          v =[tex]\frac{m}{m+M} \ v_1[/tex]                          (1)

now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set

          x = v t

          y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when it reaches the ground, its height is y = 0 and as it comes out horizontally, [tex]v_{oy} = 0[/tex]

          0 = h - ½ g t²

          t² = 2h / g

     

For the solution of the exercise, the height of the child must be known, suppose that h = 1 m

            t = [tex]\sqrt{ \frac{ 2 \ 1}{9.8} }[/tex]

            t = 0.452 s

let's find the initial velocity

             v = v / t

             v = 8 / 0.452

             v = 17.7 m / s

From equation 1

              v = m / (m + M) v₁

              m + M = [tex]m \ \frac{v_1}{v}[/tex]

              M = m + m \  \frac{v_1}{v}

we calculate

              M = 0.144 + 0.144  [tex]\frac{20.4}{17.7}[/tex]

              M = 0.31 kg

Four bicyclists travel different distances and times along a straight path. Which cyclist traveled with the greatest average

speed?

A

B

Cyclist 2 travels

87 min 22 s

Cyclist 4 travels

108 min 24 s

D

Cyclist 1 travels

95 m in 27 s

Cyclist 3 travels

106 m in 26 s

Answers

Answer:

The cyclist with the greatest average speed is Cyclist 4 with average speed of 4.5 m/s

Explanation:

Given;

Cyclist 1 travels 9 m    in    27 s

Cyclist 2 travels 87 m  in    22 s

Cyclist 3 travels 106 m  in   26 s

Cyclist 4 travels 108 m   in   24 s

Determine the average speed of the cyclists as follows;

Average speed of Cyclist 1:    v =  9/27  = 0.33 m/s

Average speed of Cyclist 2:    v = 87/22 = 3.96 m/s

Average speed of Cyclist 3:    v =   106/26 = 4.08 m/s

Average speed of Cyclist 4:     v =   108/24 = 4.5 m/s

Therefore, the cyclist with the greatest average speed is Cyclist 4 with average speed of 4.5 m/s

Count how many significant figures each of the quantities below has:
a. 2.590 km
b.12.303 ml
c. 7800kg​

Answers

a. 3 sigfigs
b. 5 sigfigs
c. 2 sigfigs

* ending zeros do not count as significant figures (no matter if they are behind a decimal point or not. ex: 40 has 1 sigfig.)

* but zeros between digits always count!

We know that there is a relationship between work and mechanical energy change. Whenever work is done upon an object by an external force (or non-conservative force), there will be a change in the total mechanical energy of the object. If only internal forces are doing work then there is no change in the total amount of mechanical energy. The total mechanical energy is said to be conserved. Think of a real-life situation where we make use of this conservation of mechanical energy (where we can neglect external forces for the most part). Describe your example and speak to both the kinetic and potential energy of the motion.

Answers

Answer:

* roller skates and ice skates.

* roller coaster

Explanation:

One of the best examples for this situation is when we are skating, in the initial part we must create work with a force, it compensates to move, after this the external force stops working and we continue movements with kinetic energy, if there are some ramps, we can going up, where the kinetic energy is transformed into potential energy and when going down again it is transformed into kinetic energy. This is true for both roller skates and ice skates.

Another example is the roller coaster, in this case the motor creates work to increase the energy of the car by raising it, when it reaches the top the motor is disconnected, and all the movement is carried out with changes in kinetic and potential energy. In the upper part the energy is almost all potential, it only has the kinetic energy necessary to continue the movement and in the lower part it is all kinetic; At the end of the tour, the brakes are applied that bring about the non-conservative forces that decrease the mechanical energy, transforming it into heat.

PLEASE HELP!!!! ITS URGENT!!!

Answers

Answer:

dude the answer is upright

What happens to solar radiation when it is absorbed

Answers

Answer:

Absorbed sunlight is balanced by heat radiated from Earth's surface and atmosphere. ... The atmosphere radiates heat equivalent to 59 percent of incoming sunlight; the surface radiates only 12 percent. In other words, most solar heating happens at the surface, while most radiative cooling happens in the atmosphere

1. An object with a mass of 5 kg is pushed by a force of 10 N. What is the object's acceleration?

Answers

i believe the answer is 2ms^-2

Answer:2m/s^2

Explanation:

a=f/m

Which type of biological molecule would control cell activities?
A) Amino Acids.
C) Nucleic Acids.
B) Lipids.
D) Carbohydrates.

Answers

Answer:

C. Nucleic Acids.

Explanation:

Nucleic acids are thus uniquely capable of directing their own self-replication, allowing them to function as the fundamental informational molecules of the cell. The information carried by DNA and RNA directs the synthesis of specific proteins, which control most cellular activities.

Did some simple research, if that's fine and I hope this is correct as it says on the sites. Have a good one :)

It’s c I hope that’s right if it’s not sorry

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes them apart, and they then fly off in opposite directions, free of the spring. The mass of A is 8.00 times the mass of B, and the energy stored in the spring was 73 J. Assume that the spring has negligible mass and that all its stored energy is transferred to the particles. (a) Once that transfer is complete, what is the kinetic energy of particle A

Answers

Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

          p₀ = p_f

          0 = m_a v_a + m_b v_b

tells us that

          m_a = 8 m_b

         

           0 = 8 m_b v_a + m_b v_b

           v_b = - 8 v_a                    (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

           Em₀ = K₀ = 73 J

final point. After separating the body

          Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

           

we substitute equation 1

           73 = ½ m_a (v_a² + 8² v_a² / 8)

           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

An elevator suspended by a vertical cable is moving downward at a constant speed. The tension in the cable must be A) greater than the weight of the elevator. B) less than the weight of the elevator. C) equal to the weight of the elevator.

Answers

Answer:

(C) because the elevator is not accelerating

Note  F = M a = M g (the resultant force on the elevator is due to gravity)

or  Fup = Fc   the force exerted on the elevator by the cable

and Fdown = Fe    the force exerted on the elevator by gravity

F = M a = Fup - Fdown = zero    resultant force on elevator

Which of these would have the highest temperature?
ice
· Water
water vapor

Answers

Answer:

water vapor

Explanation:

did assignment on edge

A student picks up two spheres that are the same size. One is made of steel and the other is made of aluminum. The student notices that the steel sphere feels much heavier than the aluminum sphere. He then holds one sphere in each hand at eye level and lets go of them at the same time. They fall to the floor. Which ball, if any, will hit the ground first and for what reason

Answers

Answer:

They will fall at the same time.  This is because gravity accelerates all objects at the same speed, Earth's gravity being approximately 9.8m/s²

They'll both fall at the same time. This is because gravity accelerates everything at the same rate, with Earth's gravity being approximately 9.8 m/s2.

What is gravity with some instances?The energy that holds the gases inside the sun together. the force that causes a ball to fall after being thrown into the air the force that causes a car to coast downhill even when the gas pedal is not depressed the force that causes a glass to shatterGravity, also known as gravitation, affects all material objects in the universe. Gravity attracts any two objects or particles with nonzero mass toward one another. Gravity affects everything from subatomic particles to galaxy clusters. Gravity is the attraction force between two objects. It's what causes things to fall and keeps us from floating away into space. Gravity is a fundamental natural force.

To learn more about gravity, refer to:

https://brainly.com/question/16275567

#SPJ2

The slope of a displacement time graph for a uniform motion represent what

Answers

Answer:

Velocity.

Explanation:

The slope of a displacement time graph for a uniform motion represent the gradient of the line i.e. the velocity of the object.

The velocity of an object is given by :

v = d/t

Where

d is displacement

t is time

Hence, the slope of the displacement-time graph gives the velocity of the object.

Are we within earths Roche limit

Answers

Answer: Closer to the Roche limit, the body is deformed by tidal forces. Within the Roche limit, the mass' own gravity can no longer withstand the tidal forces, and the body disintegrates. hope this helps can u give me brainliest

Explanation:

For the circuit in the previous part, the current flowing in the wire between the positive terminal of the battery and the resistor is ___________ the current flowing between the resistor and the negative terminal of the battery. For the circuit in the previous part, the current flowing in the wire between the positive terminal of the battery and the resistor is ___________ the current flowing between the resistor and the negative terminal of the battery. less than equal to greater than

Answers

Answer:

Explanation:

because it is godhood

If the net force acting on an object is 0 N, you can be sure that the forces acting on the object are
A. balanced B.Unbalanced C. acting at the same direction

Answers

I think the answer would be A.

After all, it is 0 which is technically a dead center number meaning that the net should be balanced and still.

Hope this helps and have a nice day.

-R3TR0 Z3R0

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