Look where the parabola crosses the x axis. This is where the x intercepts are located. The term "x intercept" is the same as "root" and also the term "zero".
How should a musician effectively convey emotions or ideas in a performance?
Answer:
Within the factors hindering expression in music, tempo is the most important number of factors such as your mood.
Step-by-step explanation:
If one wants to convey a message, they should try these:
a) Use real life
b) introduce symbolism
c) convey sensory disruption, e.t.c.
Hope these helps.
arthur walks 5/8 mi to school jonathan rides a bus 8 times that far> How far does Jonathan ride to school
Answer:
Step-by-step explanation:
Distance walked by Arthur = 5/8 miles
Distance ride by Jonathan = 8 times that of Arthur
it means that Distance rode on bus by Jonathan is 8 multiplied by Distance walked by Arthur
Distance rode on bus by Jonathan = 8 * Distance walked by Arthur
Distance rode on bus by Jonathan = 8 * 5/8 = 5 Miles Answer
g (1) = ?
Evaluate piecewise functions
Answer:
g(1) = 1
Step-by-step explanation:
g(1) with x = 1 corresponds to x ≠ - 2, - 1 with g(x) = x³ - x² + 1 , then
g(1) = 1³ - 1² + 1 = 1 - 1 + 1 = 1
Answer:
g ( 1 ) = 1
Step-by-step explanation:
→ Substitute x = 1 into x³ - x² + 1
( 1 ) ³ - ( 1 )² + 1
→ Simplify
1 - 1 + 1 = 1
PLEASE HELP!!!
The following data are the distance from the workplace ( in miles) for the 5 employees of a small business.
10,17,12,14,12
Assuming that these distance constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.
Answer:
stdev= 2.366431913
Step-by-step explanation:
10 stdev= 2.366431913
17
12
14
12
What is the product of all values of b that satisfy (b-2)(b-8) +4= 0 ?
A) 10
B) 12
C) 16
D) 20
Answer:
D
Step-by-step explanation:
(b-2)(b-8)+4=0
b^2-10b+16+4=0
b^2-10b+20=0
Product of roots is given by c/a=20. So the answer is 20
5
Select the correct answer.
What is this expression in simplified form?
5/2 . 9/6
Answer:
Bro 1st expression is in simplest form and 2nd in simplest is 3/2
Step-by-step explanation:
If you like my answer than please mark me brainliest
Answer:
(5/2)*(9/6)
three can go into the fraction(9/6) giving(3/2)
(5/2)*(3/2)=15/4
mark as brainliest
A baking scale measures mass to the tenth of a gram, up to 650 grams. A cup of flour is placed on the scale and results in a measure of 121.8 grams. Which of the following statements is not true?
a.The exact mass of the cup of flour must be between 121.7 and 121.9 grams.
b.The cup of flour has a mass of exactly 121.8 grams.
c.Given the limitations of the scale, the measurement has an appropriate level of accuracy.
d.To the nearest gram, the cup of flour has a mass of 122 grams.
Answer
Is it C I may have done my math wrong lol
Step-by-step explanation:
I will mark u brainleist if u help me and 5 stars and a thanks
Answer:
1. Jan checks the weather. It is 27 degrees outside. Jan did chores for two hours. After Jan was done, she checked the weather again. The temperature had decreased 11 degrees.
2. (See screen shot below.)
Step-by-step explanation:
1. It doesn't have to be as complicated as I made it. You can just say that the weather started out with 27 degrees, and decreased later on. Remember, decreased means subtracted and 27+(-11) is the same as 27-11 because when a + and - are together - always wins. So no.1 wants you to say something got subtracted.
2. On the number line, make a dot at 29 because it said it was 29 degrees. Then drag the dot at the number 29 to 13 because it said it decreased 16, so it is 19 minus 16 which is 13.
how do i solve this, i’m really confused
Answer:
x = 10
Step-by-step explanation:
[tex]x = 3 \times 2 + 4[/tex]
[tex]x = 6 + 4[/tex]
[tex]x = 10[/tex]
What is the equation of the parabola that has its vertex at (8,-1) and a y-intercept of (0,-17)?
y = a(x + 1.5)^2 - 12.5
y intercept is (0,-8) so:-
-8 = a(0+1.5)^2 - 12.5
-8 = 2.25a - 12.5
a = 4.5/ 2.25 = 2
so we have
y = 2 ( x +1.5)^2 - 12.5
solving for x when y = 0:-
(x + 1.5)^2 = 12.5/2 = 6.25
taking sqrt's x + 1.5 = +/- 2.5
x = -4, 1
so the x intercepts are (-4,0) and (1,0)
Answer:
y = –1∕4(x – 8)^2 – 1
Step-by-step explanation:
I took the exam and got it right.
a sample from a mummified bull was taken from a certain place. The sample shows that 71% of the carbon-14 still remains. how old is the sample
Answer:
Step-by-step explanation:
Decay of carbon - 14 is exponential in nature . It decays as follows .
[tex]N=N_0e^{-\lambda t}[/tex] λ is called decay constant .
λ = .693 / T where T is half life .
Half life of carbon-14 is 5700 years
λ = .693 / T
= .693 / 5700
= 12.158 x 10⁻⁵ year⁻¹
[tex]N=N_0e^{-\lambda t}[/tex]
N = .71 N₀
[tex].71 N_0 =N_0e^{-\lambda t}[/tex]
[tex].71 =e^{-\lambda t}[/tex]
Taking ln on both sides
ln .71 = - λ t
ln .71 = - 12.158 x 10⁻⁵ t
-0.3425 = - 12.158 x 10⁻⁵ t
t = .3425 / 12.158 x 10⁻⁵
2817 years .
evaluate -7x^2 -5 + y^2- forx = -2, y=4
Answer:
The (y^2 ) or (y^–2) It is not clear, I solved it in both ways (y^2) and (y^-2) .^_^
[tex] - 7 {x }^{2} - 5 + {y}^{2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{2} \\ - 7( - 4) - 5 + 16 \\ 28 - 5 + 16 \\ = 39[/tex]
_______o_____o_______
[tex] - 7 {x }^{2} - 5 + {y}^{ - 2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{ - 2} \\ - 7( - 4) - 5 + \frac{1}{16} \\ 28 - 5 + \frac{1}{16} \\ = 23.06[/tex]
I hope I helped you^_^
The product of a number and 3 is equal to 15 minutes twice the number, find the number.
Answer:
The answer is 3Step-by-step explanation:
Let the number to be found be x
The product of a number and 3 is written as
3 × x = 3x15 minus twice the number is written as
15 - 2xNow equate the two statements
That's
3x = 15 - 2x
Group like terms
3x + 2x = 15
5x = 15
Divide both sides by 5
the final answer is
x = 3Hope this helps you
The deck for a card game contains 30 cards. 10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards. Each player is randomly dealt a five-card hand. a) What is the probability that a hand will contain exactly two wild cards? b) What is the probability that a hand will contain two wild cards, two red cards, and one blue cards?
Answer: a) 0.1095 b) 0.0095
Step-by-step explanation:
Given : The deck for a card game contains 30 cards.
10 are red, 10 yellow, 5 blue, and 1 green, and 4 are wild cards.
Each player is randomly dealt a five-card hand.
Number of ways to choose 5 cards out of 30 = [tex]C(30,5)=\dfrac{30!}{5!25!}=142506[/tex]
a) Cards other than wild card = 30-4=26
Number of ways to choose exactly two wild cards = [tex]C(26,3)\timesC(4,2)[/tex]
[tex]=\dfrac{26!}{3!23!}\times\dfrac{4!}{2!2!}\\\\=15600[/tex]
Probability that a hand will contain exactly two wild cards = [tex]\dfrac{15600}{142506}=0.1095[/tex]
b) Number of ways to choose two wild cards, two red cards, and one blue cards = [tex]C(4,2)\times C(10,2)\times C(5,1)[/tex]
[tex]=\dfrac{4!}{2!2!}\times\dfrac{10!}{2!8!}\times5=1350[/tex]
Probability that a hand will contain two wild cards, two red cards, and one blue cards = [tex]\dfrac{1350}{142506}=0.0095[/tex]
Which polynomial function has zeros when ? A: B: C: D:
 evaluate the expression for r=-10 -54-r=
Answer:
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
Step-by-step explanation:
Evaluate Algebraic Expressions. ... To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.
An economist is interested in studying the income of consumers in a particular region. The population standard deviation is known to be $1,000. A random sample of 50 individuals resulted in an average income of $15,000. What is the width of the 90% confidence interval
Answer:
The width is [tex]w = 282.8[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 50
The population standard deviation is [tex]\sigma = \$ 1000[/tex]
The sample size is [tex]\= x = \$ 15,000[/tex]
Given that the confidence level is 90% then the level of significance can be mathematically represented as
[tex]\alpha = 100 - 90[/tex]
[tex]\alpha = 10 \%[/tex]
[tex]\alpha = 0.10[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the value is
[tex]Z_{\frac{0.10 }{2} } = 1.645[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{0.10}{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]E = 1.645 * \frac{1000 }{\sqrt{50 }}[/tex]
=> [tex]E = 141.42[/tex]
The width of the 90% confidence level is mathematically represented as
[tex]w = 2 * E[/tex]
substituting values
[tex]w = 2 * 141.42[/tex]
[tex]w = 282.8[/tex]
Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.
Square root x + 6 - 4 = x
Answer:
-2, (-5 is extraneous)
Step-by-step explanation:
assuming √(x+6) -4 =x
√(x+6) = x+4
square both side
x+6 = (x+4)^2
x+6 = x^2+8x+16
x^2+7x+10=0
(x+2)(x+5) = 0
x = -2, -5
put -5 back into org equation and it is not true
√(-5+6) -4 ≠ -5
ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2 . If the area of ΔMNO is 10 square units, what's the area of ΔABC? Question 12 options: A) 45 square units B) 90 square units C) 22.5 square units D) 15 square units
Answer:
The area of ΔABC= 6.667 square units
Step-by-step explanation:
ΔABC is similar to ΔMNO.
The scale factor from ΔMNO to ΔABC is 3∕2
the area of ΔMNO is 10 square units,
The area of ΔABC/the area of ΔMNO
= 2/3
The area of ΔABC/10= 2/3
The area of ΔABC= 2/3 * 10
The area of ΔABC= 20/3
The area of ΔABC= 6 2/3
The area of ΔABC= 6.667 square units
Answer:
22.5 square units
Step-by-step explanation:
i multiplied 10 by 2 to get 20 and went with the closest answer and got it right.
i dont know how to do math but i guess it worked
which expression is equivalent to x^-5/3
Answer:
B
Step-by-step explanation:
Since the power is negative, you automatically know it has to be a or b, because the only way it would be negative is if it was brought from the denominator to the numerator.
The answer is B, because the numerator of the power, is what is inside the square root, while the denominator is what is outside the square root.
How many solutions does this system of equations have?
y = -1/3x+7
y = -2x3 + 5x2 + x - 2
O A.
no solution
OB
1 solution
O C.
2 solutions
OD
3 solutions
Answer:
1 solution
Step-by-step explanation:
the two equations only cross once
The system of equations may have either 2 or 1 solution, but we cannot determine the exact number of solutions without further information or analysis.
We have,
The given system of equations consists of two equations in two variables:
y = (-1/3)x + 7 _______(1)
y = -2x³ + 5x² + x - 2 _______(2)
To find the solutions of the system, we need to find the values of x and y that satisfy both equations simultaneously.
Since both equations are in the form y = ...,
we can set the expressions on the right-hand sides of the equations equal to each other:
(-1/3)x + 7 = -2x³ + 5x² + x - 2
Rearranging and simplifying, we get:
2x³ - 5x² - (2/3)x + 9 = 0
To solve for x, we can use factoring or the rational root theorem.
However, the polynomial on the left-hand side of the equation does not appear to have any rational roots or easily factorable forms.
Therefore, to determine the number of solutions,
we can use Descartes' rule of signs to find the possible number of positive and negative roots of the polynomial:
The number of positive roots is either equal to the number of sign changes in the coefficients or less than it by an even integer.
There are two sign changes in the coefficients, so there can be either 2 or 0 positive roots.
The number of negative roots is either equal to the number of sign changes in the coefficients or less than it by an even integer.
There is one sign change in the coefficients, so there can be either 1 or 0 negative roots.
Since the sum of the possible number of positive and negative roots is either 2 or 1, the total number of solutions is either 2 or 1.
Therefore,
The system of equations may have either 2 or 1 solution, but we cannot determine the exact number of solutions without further information or analysis.
Learn more about solutions of equations here:
https://brainly.com/question/545403
#SPJ7
In the Cash Now lottery game there are 8 finalists who submitted entry tickets on time. From these 8 tickets, three grand prize winners will be drawn. The first prize is one million dollars, the second prize is one hundred thousand dollars, and the third prize is ten thousand dollars. Determine the total number of different ways in which the winners can be drawn. (Assume that the tickets are not replaced after they are drawn.)
Answer:
The number of ways is [tex]\left n} \atop {}} \right. P_r = 336[/tex]
Step-by-step explanation:
From the question we are told that
The number of tickets are [tex]n = 8[/tex]
The number of finalist are [tex]r =3[/tex]
Generally the number of way by which this winners can be drawn and arrange in the order of [tex]1^{st} , \ 2nd , \ 3rd[/tex] is mathematically represented as
[tex]\left n} \atop {}} \right. P_r = \frac{n\ !}{(n-r) !}[/tex]
substituting values
[tex]\left n} \atop {}} \right. P_r = \frac{ 8!}{(8-3) !}[/tex]
[tex]\left n} \atop {}} \right. P_r = \frac{ 8* 7*6*5*4*3*2*1}{ 5*4*3*2*1}[/tex]
[tex]\left n} \atop {}} \right. P_r = 336[/tex]
5.39 jings =15.4 hings
4.9 hings = 2.8 gings
According to the conversion rates above, how
many jings equal 1 ging?
E. 7/40
F. 5/8
G. 49/80
H. 20/7
Step-by-step explanation:
It is given that,
5.39 jings =15.4 hings ....(1)
4.9 hings = 2.8 gings ...(2)
From equation (2), the value of 1 ging is :
[tex]1\ \text{ging} = \dfrac{4.9}{2.8}\ \text{hing}\ .....(3)[/tex]
From equation (1), the value of 1 jing is :
[tex]1\ \text{jing} = \dfrac{15.4}{5.39}\ \text{hing}\ .....(4)[/tex]
From equation (3) and (4), we get :
[tex]\dfrac{\text{1 ging}}{\text{1 jing}}=\dfrac{4.9}{2.8}\times \dfrac{5.39}{15.4}\\\\\dfrac{\text{1 ging}}{\text{1 jing}}=\dfrac{49}{80} \\\\1\ \text{ging}=\dfrac{49}{80}\ \text{ jings}[/tex]
Hence, the correct option is (g) "49/80"
Cases Prudence has a special (cubic) die. The values on its face are the integers from 1 to 6, but they are not arranged ae in a normal die. When Prudence first tosses the die, the sum of the values on the four side faces is 15. In her second toss, the sum of these values is 12. Find what value appears in the face opposite 6 on Prudence’s special die. (Hint: what are possible values for the top and bottom face when the sum of the side faces is 12).
Answer: 3
Step-by-step explanation:
first, we know that:
1 + 2 + 3 + 4 +5 +6 = 21
Now, which two numbers we should take out in order to have 15?
we can remove the 2 and the 4, or the 1 and the 5.
so here we have two possibilities, 2 and 4 are opposite, or 1 and 5 are opposite (they are located in opposite faces of the die)
in the other arrange, we have that removing two numbers we should get 12.
in order to reach 12, we should remove two numbers that add 9 together.
those can be 4 and 5, or 6 and 3.
Now, notice that in the first restriction we have that:
Or 2 and 4 are opposite,
or 1 and 5 are opposite.
So 4 and 5 can never be opposite, so we should have that 6 and 3 are opposite.
Then we can affirm that the value that appears in the face opposite to the 6, is the 3.
Given the graph, find an equation for the parabola.
Answer:
[tex]\Large \boxed{\sf \bf \ \ y=\dfrac{1}{16}(a-3)^2-2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
When the parabola equation is like
[tex]y=a(x-h)^2+k[/tex]
The vertex is the point (h,k) and the focus is the point (h, k+1/(4a))
As the vertex is (3,-2) we can say that h = 3 and k = -2.
We need to find a.
The focus is (3,2) so we can say.
[tex]2=-2+\dfrac{1}{4a}\\\\\text{*** We add 2. ***}\\\\\dfrac{1}{4a}=2+2=4\\\\\text{*** We multiply by 4a. ***}\\\\16a=1\\\\\text{*** We divide by 16. ***}\\\\a=\dfrac{1}{16}[/tex]
So an equation for the parabola is.
[tex]\large \boxed{\sf y=\dfrac{1}{16}(a-3)^2-2 }[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Write the equation of the line that passes through (-1,5) and has a slope of 3 in point slope form
Answer:
y-5=3(x+1)
Step-by-step explanation:
we use the point-slope formula to plug all of our values in.
[tex]y-y_{1}=m(x-x_{1})[/tex]
graph 3x-y-2=0 using the x- and y-intercepts
Step-by-step explanation:
I used an app called DESMOS It Is usually super helpful!!!
The amount of money spent on textbooks per year for students is approximately normal.
A. To estimate the population mean, 19 students are randomly selected the sample mean was $390 and the standard deviation was $120. Find a 95% confidence for the population meam.
B. If the confidence level in part a changed from 95% 1 to 1999%, would the margin of error for the confidence interval:
1. decrease.
2. stay the same.
3. increase not.
C. If the sample size in part a changed from 19% 10 to 22, would the margin of errot for the confidence interval:
1. decrease.
2. stay the same.
3. increase
D. To estimate the proportion of students who purchase their textbookslused, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.
Answer:
(A) A 95% confidence for the population mean is [$332.16, $447.84] .
(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval would increase.
(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval would decrease.
(D) A 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477] .
Step-by-step explanation:
We are given that 19 students are randomly selected the sample mean was $390 and the standard deviation was $120.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean = $390
s = sample standard deviation = $120
n = sample of students = 19
[tex]\mu[/tex] = population mean
Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-2.101 < [tex]t_1_8[/tex] < 2.101) = 0.95 {As the critical value of t at 18 degrees of
freedom are -2.101 & 2.101 with P = 2.5%}
P(-2.101 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.101) = 0.95
P( [tex]-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.101 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.101 \times {\frac{s}{\sqrt{n} } }[/tex] ]
= [ [tex]\$390-2.101 \times {\frac{\$120}{\sqrt{19} } }[/tex] , [tex]\$390+2.101 \times {\frac{\$120}{\sqrt{19} } }[/tex] ]
= [$332.16, $447.84]
(A) Therefore, a 95% confidence for the population mean is [$332.16, $447.84] .
(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval which is [tex]Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }[/tex] would increase because of an increase in the z value.
(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval which is [tex]Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }[/tex] would decrease because as denominator increases; the whole fraction decreases.
(D) We are given that to estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion students who purchase their used textbooks = [tex]\frac{210}{500}[/tex] = 0.42
n = sample of students = 500
p = population proportion
Here for constructing a 99% confidence interval we have used a One-sample z-test statistics for proportions
So, 99% confidence interval for the population proportion, p is ;
P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5%
level of significance are -2.58 & 2.58}
P(-2.58 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 2.58) = 0.99
P( [tex]-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.99
P( [tex]\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.99
99% confidence interval for p = [ [tex]\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]
= [ [tex]0.42 -2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }[/tex] , [tex]0.42 +2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } }[/tex] ]
= [0.363, 0.477]
Therefore, a 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477] .
find the least number that can be divided 9and 12 without leaving remainder
Answer:
By finding LCM of 9 and 12 the answer is 36
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Question 3 Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.
Answer:
4x
Step-by-step explanation:
Given:
√x • 4√x
Required:
Simplify in rational exponent form
SOLUTION:
Recall => [tex] \sqrt{a} = a^{\frac{1}{2}} [/tex]
Thus,
[tex] \sqrt{x}*4\sqrt{x} [/tex] can be expressed in exponent form as [tex] x^{\frac{1}{2}}*4x^{\frac{1}{2} [/tex]
When multiplying 2 bases having exponents together, their exponents should be added together, while you multiply the bases. I.e. [tex]x^m*x^n = x^{m+n }[/tex]
[tex] = x*4^{\frac{1}{2}+\frac{1}{2} [/tex]
[tex] = 4x^{1} = 4x [/tex]
The answer is 4x