What are the numbers I’m supposed to mark

Answer: $3267.40

Step-by-step explanation:

A = P (1+r/n)^nt

A= 2500 (1+0.055)^nt

A= 2500 x 1.30696

A = 3267.40

Answer:

1/5

Step-by-step explanation:

20*5 = 100, so 20 is 1/5

Answer:

The second graph.

Step-by-step explanation:

0-9: 6 numbers

10-19: 2 numbers

20-29: 1 number

30-39: 3 numbers

40-49: 1 number

50-59: 2 numbers

60-69: 0 numbers

70-79: 5 numbers

80-89: 3 numbers

90-99: 1 number

Answer:

Step-by-step explanation:

i think its 3

Answer:

0

Step-by-step explanation:

You cannot make any triangles with this angle

Answer:

no solutions

Step-by-step explanation:

6-3x=4-x-3-2x

Combine like terms

6-3x =1 -3x

Add 3x to each side

6 -3x+3x = 1-3x+3x

6 =1

This is not true so there are no solutions

Answer:

No solutions.

Step-by-step explanation:

6 - 3x = 4 - x - 3 - 2x

Add or subtract like terms if possible.

6 - 3x = -3x + 1

Add -1 and 3x on both sides.

6 - 1 = -3x + 3x

5 = 0

There are no solutions.

Answer:

x = 2

Step-by-step explanation:

the equation of the line can be found using the slope intercept form

y = mx +b

y= -3/2 x + 3

x intercept is found by setting y=0 bc that will give you the x-value at which the line crosses the x -axis so

0 = -3/2x+3 (subtract the 3 on both sides) would cancel out the + 3 and would

-3 = -3/2 x  (divide by -3/2 on both sides to cancel out the -3/2)  

x = 2

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean score of in-state applicants

x2 = sample mean score of out-of-state applicants

s1 = sample standard deviation for in-state applicants

s2 = sample standard deviation for out-of-state applicants

n1 = number of in-state applicants

n2 = number of out-of-state applicants

For a 90% confidence interval, we would determine the z score from the t distribution table because the number of samples are small

Degree of freedom =

(n1 - 1) + (n2 - 1) = (8 - 1) + (17 - 1) = 23

z = 1.714

x1 - x2 = 1144 - 1200 = - 56

Margin of error = z√(s1²/n1 + s2²/n2) = 1.714√(25²/8 + 26²/17) = 18.61

Confidence interval = - 56 ± 18.61

Answer:

(-1)² = 1

-1² = -1

Step-by-step explanation:

(-1)² means you are squaring the value of -1 to -1.

-1² means you are squaring the value of -1 to 1.

Answer:

Hiking: 28%

Canoeing: 16%

Swimming: 24%

Fishing: 32%

Step-by-step explanation:

21 + 12 + 18 + 24 = 75 (there are 75 campers)

21 out of 75 = 28%

12 out of 75 = 16%

18 out of 75 = 24%

24 out of 75 = 32%

Hope this helps!

Please mark Brainliest if correct

Answer:

Let's solve your equation step-by-step.

[tex]x^7+64x^4=0[/tex]

Step 1: Factor left side of equation.

[tex]x^4(x+4)(x^2-4x+16)=0[/tex]

Step 2: Set factors equal to 0.

[tex]x^4=0[/tex]  or  [tex]x+4=0[/tex]  or  [tex]x^2-4x+16=0[/tex] 

[tex]x^4=0[/tex]  or  [tex]x=0[/tex]  

Answer:

I hope this help you :)

Answer:

The probability of healthcare expenses in the population being greater than $4,000 is 0.02275.

Step-by-step explanation:

We are given that yearly healthcare expenses for a family of four are normally distributed with a mean expense equal to $3,000 and a standard deviation equal to $500.

Let X = yearly healthcare expenses of a family

The z-score probability distribution for the normal distribution is given by;

                            Z  =  [tex]\frac{ X-\mu}{\sigma} }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean expense = $3,000

            [tex]\sigma[/tex] = standard deviation = $500

Now, the probability of healthcare expenses in the population being greater than $4,000 is given by = P(X > $4,000)

     P(X > $4,000) = P( [tex]\frac{ X-\mu}{\sigma} }[/tex] > [tex]\frac{4,000-3,000}{{500}{ } }[/tex] ) = P(Z > 2) = 1 - P(Z [tex]\leq[/tex] 2)

                                                                  = 1 - 0.97725 = 0.02275

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

Answer: x=45°

Step-by-step explanation:

Angles opposite from each other are equal. The angle 160 degrees in red on the bottom encompasses two angles: BEG and CEG. Angle BEG is on the opposite side as FEA which means it is equal to x.

Since angle FED on the other side is 115, you subtract 115 from 160 to get 45 degrees.

Answer: x=45°

The angle BEG, which is opposite to the angle FEA, is determined to be 45 degrees.

According to the information provided, in a figure with an angle of 160 degrees (red angle on the bottom), there are two angles labeled as BEG and CEG. It is stated that the angle BEG is opposite to the angle FEA, making them equal, so we can represent this angle as x.

Additionally, it is mentioned that the angle FED on the other side measures 115 degrees.

To find the value of x, we subtract 115 degrees from the angle of 160 degrees.
=160-115
= 45

Thus, the solution is x = 45°.

For more details about the angle visit the link below: https://brainly.com/question/16959514

#SPJ4

Answer:

C'A' = 10units (A)

Question

A complete question related to this found at brainly(question ID 2475535) is stated below.

Triangle ABC was dilated using the rule Dy, 5/4

If CA = 8, what is C'A'?

10 units

12 units

16 units

20 units

Step-by-step explanation:

Given:

Scale factor = 5/4

CA = 8units

Find attached the diagram for the question.

This is a question on dilation. In dilation, figures have the same shapes but different sizes.

Y is the center of dilation

Lengths of ∆ABC: CB, AB, CA

Lengths of ∆A'B'C': C'B', A'B', C'A'

C'B' = scale factor × CB

A'B' = scale factor × AB

C'A' = scale factor × CA

C'A' = 5/4 × 8

C'A' = 40/4

C'A' = 10units (A)

Answer:

3

Step-by-step explanation:

Step 1: Isolate y

5y < 20

y < 4

When we figure out the inequality, we see that y has to be less than 4. Therefore, the highest integer value will have to be 3.

Answer:

$394,772.11

Step-by-step explanation:

This requires using compound interest as follows:

Principal = $5,000

Time = 25 years

Interest rate per annum = 8%

1st year: principal = 5000

Interest capitalized (5000*0.08) = 400

Amount (5000 + 400) = $5400

2nd year: principal = 5400 + 5000 = 10,400

Interest capitalized (10,400*0.08) = 832

Amount (10,400 + 832) = $11,232

3rd year: principal = 11,232+5000 = $16,232

Interest capitalized (16,232*0.08) = 1,298.56

Amount (16,232+1,298.56) = $17,530.56

4th year: principal = 17,530.56+5000 = $22,530.56

Interest capitalized (22,530.56*0.08) = 1,802.45

Amount (22,530.56+1,802.45) = $24,333.01

5th year: principal = 24,333.01+5000 = $29,333.01

Interest capitalized (29,333.01 * 0.08) = 2,346.64

Amount (29,333.01 + 2,346.64) = $31,679.65

6th year: principal = 31,679.65 + 5000 = $36,679.65

Interest capitalized (36,679.65 * 0.08) = 2,934.37

Amount (36,679.65 + 2,934.37) = $39,614.02

7th year: principal = 39,614.02 + 5000 = $44,614.02

Interest capitalized (44,614.02 * 0.08) = 3,569.12

Amount (44,614.02 + 3,569.12) = $48,183.14

8th year: principal = 48,183.14 + 5000 = $53,183.14

Interest capitalized (53,183.14 * 0.08) = 4,254.65

Amount (53,183.14 + 4,254.65) = $57,437.79

9th year: principal = 57,437.79 + 5000 = $62,437.79

Interest capitalized (62,437.79 * 0.08) = 4,995.02

Amount (62,437.79 + 4,995.02) = $67,432.81

10th year: principal = 67,432.81 + 5000 = $72,432.81

Interest capitalized (72,432.81 * 0.08) = 5,794.63

Amount (72,432.81 + 5,794.63) = $78,227.44

11th year: principal = 78,227.44 + 5000 = $83,227.44

Interest capitalized (83,227.44 * 0.08) = 6,658.20

Amount (83,227.44 + 6,658.20) = $89,885.64

12th year: principal = 89,885.64 + 5000 = $94,885.64

Interest capitalized (94,885.64 * 0.08) = 7,590.85

Amount (94,885.64 + 7,590.85) = $102,476.49

13th year: principal = 102,476.49 + 5000 = $107,476.49

Interest capitalized (107,476.49 * 0.08) = 8,598.12

Amount (107,476.49 + 8,598.12) = $116,074.61

14th year: principal = 116,074.61 + 5000 = $121,074.61

Interest capitalized (121,074.61 * 0.08) = 9,685.97

Amount (121,074.61 + 9,685.97) = $130,760.58

15th year: principal = 130,760.58 + 5000 = $135,760.58

Interest capitalized (135,760.58 * 0.08) = 10,860.85

Amount (135,760.58 + 10,860.85) = $146,621.43

16th year: principal = 146,621.43 + 5000 = $151,621.43

Interest capitalized (151,621.43 * 0.08) = 12,129.71

Amount (151,621.43 + 12,129.71) = $163,751.14

17th year: principal = 163,751.14 + 5000 = $168,751.14

Interest capitalized (168,751.14 * 0.08) = 13,500.09

Amount (168,751.14 + 13,500.09) = $182,251.23

18th year: principal = 182,251.23 + 5000 = $187,251.23

Interest capitalized (187,251.23 * 0.08) = 14,980.10

Amount (187,251.23 + 14,980.10) = $202,231.33

19th year: principal = 202,231.33 + 5000 = $207,231.33

Interest capitalized (207,231.33 * 0.08) = 16,578.51

Amount (207,231.33 + 16,578.51) = $223,809.84

20th year: principal = 223,809.84 + 5000 = $228,809.84

Interest capitalized (228,809.84 * 0.08) = 18,304.79

Amount (228,809.84 + 18,304.79) = $247,114.63

21st year: principal = 247,114.63 + 5000 = $252,114.63

Interest capitalized (252,114.63 * 0.08) = 20,169.17

Amount (252,114.63 + 20,169.17) = $272,283.8

22nd year: principal = 272,283.8 + 5000 = $277,283.8

Interest capitalized (277,283.8 * 0.08) = 22,182.70

Amount (277,283.8 + 22,182.70) = $299,466.5

23rd year: principal = 299,466.5 + 5000 = $304,466.5

Interest capitalized (304,466.5 * 0.08) = 24,357.32

Amount (304,466.5 + 24,357.32) = $328,823.82

24th year: principal = 328,823.82 + 5000 = $333,823.82

Interest capitalized (333,823.82 * 0.08) = 26,705.91

Amount (333,823.82 + 26,705.91) = $360,529.73

25th year: principal = 360,529.73 + 5000 = $365,529.73

Interest capitalized (365,529.73 * 0.08) = 29,242.38

Amount (365,529.73 + 29,242.38) = $394,772.11

Answer:

11

Step-by-step explanation:

Answer:

9.34%

Step-by-step explanation:

p = 4%, or 0.04

n = Sample size = 667

u = Expected value = n * p = 667 * 0.04 = 26.68

SD = Standard deviation = [tex]\sqrt{np(1-p)} =\sqrt{667*0.04*(1-0.04)}[/tex] = 5.06

Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?

This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35

Since,

Z = (X - u) / SD

We have;

Z = (33.35 - 26.68) / 5.06

Z = 1.32

From the Z-table, the p-value of 1.32 is 0.9066

1 - 0.9066 = 0.0934, or 9.34%

Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.

Answer:

X=3 or x= -3

Step-by-step explanation:

2x^2 - 18 =0

Take a common factor

2(x^2 - 9) = 0

2(x-3)(x+3)=0

X-3=0 or x+3=0

X=3 x=-3

Hope this helps!

Step-by-step explanation:

Hope this is correct

HAVE A GOOD DAY!

Answer:

  see the attachment for a graph

Step-by-step explanation:

The vertex of f(x) is (0, 0). The transformation g(x) = f(x -h) +k moves the vertex to (h, k). That is, the graph is translated right by h units, and up by k units.

Your transformation has h = -2, and k = -4. That is, the original graph is translated left 2 units and down 4 units. The result is the blue curve in the attachment.

Answer:

a prism is a three dimensional shape with the same width all the way through.

Step-by-step explanation:

Step-by-step explanation:

i think this will help.

Answer:

Option 1.

Step-by-step explanation:

[tex]y=2x+1[/tex]

[tex]x=2y+1[/tex]

[tex]x-1=2y[/tex]

[tex]\frac{x-1}{2} = \frac{2y}{2}[/tex]

[tex]\frac{x-1}{2} = y[/tex]

[tex]\frac{1}{2}x -\frac{1}{2} = y[/tex]

Answer:

  see the attachment

Step-by-step explanation:

You can find the inverse by swapping the variables and solving for y.

  y = f(x) . . . . . original function

  x = f(y) . . . . . variables swapped

  x = 2y +1

  x -1 = 2y . . . subtract 1

  (x-1)/2 = y . . . divide by 2

  y = (1/2)x -1/2 . . . expand

If the inverse function is named h(x), then it is ...

  h(x) = x/2 -1/2

Answer:

True.

95% of all confidence intervals constructed similarly to this one with a sample size of 10 will contain the mean of the population.

Step-by-step explanation:

True.

The confidence level represents the proportion of possible confidence intervals that contain the true mean. In this case, 95% of all confidence intervals of sample size n=10 constructed similarly to this one will contain the population mean.

Answer:

18

Step-by-step explanation:

3/5 x 30

(3 times 30)divided by 5

= 18 children are going.

Hope this helps:-)

Answer:

A warranty of 6.185 years should be provided.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 8.2, \sigma = 1.3[/tex]

What warranty should be provided so that the company is replacing at most 6% of their blenders sold?

The warranty should be the 6th percentile, which is X when Z has a pvalue of 0.06. So X when Z = -1.55.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.55 = \frac{X - 8.2}{1.3}[/tex]

[tex]X - 8.2 = -1.55*1.3[/tex]

[tex]X = 6.185[/tex]

A warranty of 6.185 years should be provided.

Answer:

En álgebra, el teorema del factor es un teorema que vincula factores y ceros de un polinomio. Es un caso especial del teorema del resto polinómico.

Step-by-step explanation:

Answer:

  see below

Step-by-step explanation:

Subtracting 52 from the y-coordinate of a point moves its location on the graph down 52 units. y=f(x)-52 is shifted down by 52 units from y=f(x).

Answer:

y=5

solution,

X=2

now,

[tex] \\ 5x - y = 5 \\ or \: 5 \times x - y = 5 \\ or \: 5 \times 2 - y = 5 \\ or \: 10 - y = 5 \\ or \: - y = 5 - 10 \\or \: - y = - 5 \\ y = 5[/tex]

hope this helps..

Good luck on your assignment..

Answer:

49.95+/-0.5543

= ( 49.3957, 50.5043) pounds

the 95% confidence interval (a,b) = ( 49.3957, 50.5043) pounds

And to 2 decimal points;

the 95% confidence interval (a,b) = ( 49.40, 50.50) pounds

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 49.95 pounds

Standard deviation r = 1.9999 pounds

Number of samples n = 50

Confidence interval = 95%

z value(at 95% confidence) = 1.96

Substituting the values we have;

49.95+/-1.96(1.9999/√50)

49.95+/-1.96(0.282828570338)

49.95+/-0.554343997864

49.95+/-0.5543

= ( 49.3957, 50.5043) pounds

Therefore, the 95% confidence interval (a,b) = ( 49.3957, 50.5043) pounds

Answer:

We need a sample of at least 1937.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

For this problem, we have that:

[tex]\pi = 0.72[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

How large a sample should be if you want your estimate to be within 0.02 with 95% confidence.

We need a sample of at least n.

n is found when M = 0.02. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.02 = 1.96\sqrt{\frac{0.72*0.28}{n}}[/tex]

[tex]0.02\sqrt{n} = 1.96\sqrt{0.72*0.28}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.72*0.28}}{0.02}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.96\sqrt{0.72*0.28}}{0.02})^{2}[/tex]

[tex]n = 1936.16[/tex]

Rounding up to the nearest number.

We need a sample of at least 1937.