What are the characteristics of SAAS? (Choose all that apply)​ a. ​ Services are usually available during specified time periods b. ​ Software is installed remotely with no local involvement c. ​ Little, if any, software is installed on the user’s computer d. ​ Costs are calculated on a "use" basis e. ​ User data is stored and isolated on central computers f. ​ SAAS company often deploys an on sight employee to assist the client

Answer:

Let f be a function  

a) f(n) = n²  

b) f(n) = n/2  

c) f(n) = 0  

Explanation:  

a) f(n) = n²  

This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.  

Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:

                               f(a) = f(b) ⇒ a² = b² ⇒ a = b  

The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number.  For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.  

b) f(n) = n/2  

The above function example is an onto function because every natural number, let’s say n is a natural number that belongs to N, is the image of 2n. For example:

                               f(2n) = [2n/2] = n  

The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:  

When the value of n=1, then

                                  n/2 = [1/2] = [0.5] = 1  

When the value of n=2 then  

                                   n/2 = [2/2] = [1] = 1  

c) f(n) = 0

The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image.  The above function example is also not an onto function because every positive integer is not an image of any natural number.

Answer:The key to analytics success is not about searching for answers, ... If you are trying to determine where to find new customers, there is a recipe for how to do that, and it ... As we work with small businesses, we help them answer their big ... Moving forward, there is going to be a lot more data of varying types.

Explanation:

Answer:

The correct option is (d) Use a service account and prohibit users from accessing this account for development work

Explanation:

Solution

As regards to the above requirement where the application and database server in the production environment will need to exchange the data once ever day, the following access control account practices would be used in this situation:

By making use of a service account and forbids users from having this account for development work.

The service account can be useful to explicitly issue a security context for services and thus the service can also access the local and the other resources and also prohibiting the other users to access the account for the development work.

Submitting an adhoc request daily is not a choice as this is required daily. Also, the servers can be different and cannot be put in one place. and, we cannot make use of the read-write permission to the members of that group.

Answer:

Explanation:

The degree of relationship can be defined as the number of occurrences in one entity that is associated with the number of occurrences in another entity. There is the three degree of relationship: One-to-one (1:1) One-to-many (1:M)

Answer:

(1) Carry flag (2) Overflow flag (3) Sign or negative Flag

Explanation:

Solution

(1) The carry flag : It refers to the adding or subtracting. a two registers has a borrow or carry bit

(2) The over flow flag: This flag specify that a sign bit has been modified during subtracting or adding of operations

(3) The sign flag: This is also called a negative sign flag is a single bit status in a register that specify whether the last mathematical operations  generated a value to know if the most significant bit was set.

All of the following are true about hacksaws, except a coarse hacksaw blade (one with fewer teeth) is better for cutting thick steel than a fine blade. The correct option is b.

A hacksaw is a saw with fine teeth that were originally and primarily used to cut metal. Typically, a bow saw is used to cut wood and is the corresponding saw.

Hacksaw is used by hand, it is a small tool for cutting pipes rods wood etc that is very common and homes and in shops. The different types of hacksaws. The main three types of hacksaws are course-grade hacksaws, medium-grade hacksaws, and fine-grade hacks. The difference is just for the quality, and the design of the blade.

Therefore, the correct option is b. Cutting thick steel is easier with a coarse hacksaw blade (one with fewer teeth) than a fine one.

To learn more about hacksaw, refer to the below link:

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Answer:

Explanation:

Disk space is a limited resource on the spooling partition and once it is filled the will cause a deadlock. Every single block that comes into the spooling partition claims a resource, and the one behind that wants resources as well, and so on. Since the spooling space is limited and half of the jobs arrive and fill up space then no more blocks can be stored, causing a deadlock. This can be prevented allowing one job to finish and releasing the space for the next job.

Answer:

Explanation:

The solution is written in Java.

Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).

Create a Scanner object and get user entry the number of input (Line 6-7).

Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).

At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).

Answer:

The answer is The Cache Sets (S) = 32, Tag bits (t)=24, Set index bits(s) = 5 and Block offset bits (b) = 3

Explanation:

Solution

Given Data:

Physical address = 32 bit (memory address)

Cache size = 1024 bytes

Block size = 8 bytes

Now

It is a 4 way set associative mapping, so the set size becomes 4 blocks.

Thus

Number of blocks = cache size/block size

=1024/8

=128

The number of blocks = 128

=2^7

The number of sets = No of blocks/set size

=128/4

= 32

Hence the number of sets = 32

←Block ←number→

Tag → Set number→Block offset

←32 bit→

Now, =

The block offset = Log₂ (block size)

=Log₂⁸ = Log₂^2^3 =3

Then

Set number pc nothing but set index number

Set number = Log₂ (sets) = log₂³² =5

The remaining bits are tag bits.

Thus

Tag bits = Memory -Address Bits- (Block offset bits + set number bits)

= 32 - (3+5)

=32-8

=24

So,

Tag bits = 24

Therefore

The Cache Sets = 32

Tag bits =24

Set index bits = 5

Block offset bits = 3

Note: ←32 bits→

Tag 24 → Set index  5→Block offset 3

Answer & Explanation:

To print 10 on a line and each number separated by space; you make the following modifications.

print(str(i)+" ",end=' ')

str(i)-> represents the actual number to be printed

" "-> puts a space after the number is printed

end = ' ' -> allows printing to continue on the same line

if(count == 10):

     print(' ')

The above line checks if count variable is 10;

If yes, a blank is printed which allows printing to start on a new line;

The modified code is as follows (Also, see attachment for proper indentation)

count = 0

for i in range(100,201):

     if(i%6 == 0 and i%5!=0) or (i%5 ==0 and i%6!=0):

           print(str(i)+" ",end=' ')

           count = count + 1

           if(count == 10):

                 print(' ')

                 count = 0

Answer:

In this example, the wireless router uses NAT to allocate private IP addresses to five PC's and router interface, since only one IP address is assigned or given to the wireless router by the ISP.

Explanation:

Solution

The Dynamic Host Configuration Protocol server provides the IP addresses to clients, dynamically.

Generally a wireless router contains DHCP server. a wireless router can also  assign IP addresses dynamically to its clients.

So, the wireless router assigns IP addresses to five PC's and the router interface dynamically using the DHCP.

It is stated that the Internet Service Provider (ISP) assigns only one IP address to the wireless router. Here there are five PC's and one router interface need to be allocated IP addresses.

In such cases the NAT (Network Address Translation)protocol is important and allows all the clients of the home network to sue a single internet connection (IP address) assigned or given by the ISP.

NAT permits the router to allocate the private IP addresses to client from the private IP address space reserved for the private networks. these private IP addresses are valid only in the home or local network .

Answer:

The Following are the outputs:

a. vroom

b. car 1

c. car 2

d. vroom

e. truck 1

f. car 2

Explanation:

The first statement System.out.println(mycar);  prints an instance of the Car object my car which calls the toString() method.

The second statement mycar.m1();  Calls the method m1() which prints car1

The third statement mycar.m2(); calls the method m2() which prints car2

Then another class is created Truck, and Truck inherits all the methods of Car since it extends Car. Truck has a method m1() which will override the inherited method m1() from the Car class.

The fourth statement System.out.println(mytruck); will print print vroom just as the first statement since it inherits that method toString()

The fifth statement calls m1() in the Truck class hence prints Truck 1

Finally the sixth statement will print car 2 because it also inherited that method and didnt overide it.

Answer:

Here is the C++ program:

#include <iostream> // for using input output functions

using namespace std; // to identify objects as cin cout

void merge(int array[], int left, int mid, int right);  

// to merge the  array into two parts i.e. from left to mid and mid+1 to right

int minimum(int a, int b) { return (a<b)? a :b; }

//to find the minimum of the 2 values

void IterativeMergeSort(int array[], int num) { //function to sort the array

  int size; //determines current size of subarrays

  int left;  //to determine the start position of left subarray

//to merge the sub arrays using bottom up approach          

  for (size=1; size<=num-1; size = 2*size)    {

      //to select start position of different subarrays of current size  

      for (left=0; left<num-1; left += 2*size)   {    

// To determine the end point of left sub array and start position of right //which is mid+1    

          int mid = minimum(left + size - 1, num-1);  

          int right = minimum(left + 2*size - 1, num-1);  

// Merge the sub arrays from left to mid and mid+1 to right

         merge(array, left, mid, right);        }    } }

 // function to merge the  array into two parts i.e. from left to mid and mid+1 //to right

void merge(int array[], int left, int mid, int right){

   int i, j, k; // variables to point to different indices of the array

   int number1 = mid - left + 1;

   int number2 =  right - mid;  

//creates two auxiliary arrays LEFT and RIGHT

   int LEFT[number1], RIGHT[number2];  

//copies this mid - left + 1 portion to LEFT array

   for (i = 0; i < number1; i++)

       LEFT[i] = array[left + i];

//copies this right - mid portion to RIGHT array

   for (j = 0; j < number2; j++)

       RIGHT[j] = array[mid + 1+ j];  

   i = 0;

   j = 0;

   k = left;

//merge the RIGHT and LEFT arrays back to array from left to right i.e //arr[left...right]

   while (i < number1 && j < number2)     {

       if (LEFT[i] <= RIGHT[j])    

/*checks if the element at i-th index of LEFT array is less than or equals to that of j-th index of RIGHT array */

{             array[k] = LEFT[i];

//if above condition is true then copies the k-th part of array[] to LEFT //temporary array

           i++;         }

       else //when the above if condition is false

       {  array[k] = RIGHT[j];

//moves k-th part of array[] to j-th position of RIGHT temporary array

           j++;         }

       k++;     }  

   while (i < number1)     {  //copies remaining elements of LEFT array

       array[k] = LEFT[i];

       i++;

       k++;     }  

   while (j < number2)     { //copies remaining elements of RIGHT array

       array[k] = RIGHT[j];

       j++;

       k++;     } }  

int main() {

   int Array[] = {9, 18, 15, 6, 8, 3}; // an array to be sorted

   int s = sizeof(Array)/sizeof(Array[0]);

//sizeof() is used to return size of array

   cout<<"Input array:  ";

   int i;

   for (i=0; i < s; i++) //to print the elements of given array

       cout<<Array[i]<<" ";

       cout<<endl;

   IterativeMergeSort(Array, s);   //calls IterativeMergeSort() function

   cout<<"Sorted array after applying Iterative Merge Sort:"<<endl;

  for (i=0; i < s; i++) //to print the elements of the sorted array

      cout<<Array[i]<<" "; }

Explanation:

The program is well explained in the comments mentioned above with each line of the code. The screenshot of the program along with its output is attached.

Answer:

d. Port mirror

Explanation:

Port mirroring is a method to monitor network traffic and it is used in the Intrusion Detection Systems. It is also called Switched Port Analyzer and is used to analyse the network errors. This technique basically copies the network packets and sends or transmits these copied packed from one port to another in a network device such as a switch. This means that this technique is used to copy the network packets from one switch port and send the copy of these packets to another port where these packets are monitored. This is how it analyses the network errors and incoming traffic for irregular behavior and also this can be done without affecting the normal operation of the switch and other network processes. It is simple, inexpensive and easy to establish and use. The most important advantage of using mirrored ports is that it catches the traffic on several ports at once or can capture all of the network traffic.

Answer:

This function (along with the main)is written using python progrmming language.

The function is written using for loop;

This program does not make use comments (See explanation section for detailed line by line explanation)

def is_prime(num):

    if num == 1:

         print(str(num)+" is not prime")

    else:

         for i in range(2 , num):

              if num % i == 0:

                   print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")

                   break;

         else:

              print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")

num = int(input("Number: "))

is_prime(num)

Explanation:

This line defines the function is_prime

def is_prime(num):

The italicize line checks if the user input is 1; If yes it prints 1 is not prime

    if num == 1:

         print(str(num)+" is not prime")

If the above conditional statement is not true (i.e. if user input is greater than 1), the following is executed

    else:

The italicized checks if user input is primer (by using for loop iteration which starts from 2 and ends at the input number)

         for i in range(2 , num):

              if num % i == 0:

This line prints if the number is not a prime number and why it's not a prime number

                   print(str(num)+" is not prime because it can b divided by "+str(i)+" and "+str(int(num/i))+" with no remainder")

                   break;

If otherwise; i.e if user input is prime, the following italicized statements are executed

         else:

              print(str(num) + " is prime because only 1 and "+str(num)+" divide it with no remainder")

The function ends here

The main begins here

num = int(input("Number: "))  This line prompts user for input

is_prime(num) This line calls the defined function

Answer:

Use the average function for viewer ratings

Use the min function for the earliest airing year

Explanation:

The average function gives the minimum value in a set of data

The min function gives the lowest value in a set of data

Answer:

The program doesn't use comments; See explanation section for detailed line by line explanation

Program starts here

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

Line by Line explanation

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

If input score is less than 0 or greater than 100, "Invalid Score" is printed

     else:

           print("Invalid Score")

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Answer:

The java program is as follows.

import java.lang.*;

public class Triangle

{

   //variables to hold sides of a triangle

   static double height;

   static double base;

   static double hypo;

   //method to compute hypotenuse

   static double rightTriangle(double h, double b)

   {

       return Math.sqrt(h*h + b*b);

   }

public static void main(String[] args) {

    height = 4;

    base = 3;

    hypo = rightTriangle(height, base);

 System.out.printf("The hypotenuse of the right-angled triangle is %.4f", hypo);

}

}

OUTPUT

The hypotenuse of the right-angled triangle is 5.0000

Explanation:

1. The variables to hold all the three sides of a triangle are declared as double. The variables are declared at class level and hence, declared with keyword static.

2. The method, rightTriangle() takes the height and base of a triangle and computes and returns the value of the hypotenuse. The square root of the sum of both the sides is obtained using Math.sqrt() method.

3. The method, rightTriangle(), is also declared static since it is called inside the main() method which is a static method.

4. Inside main(), the method, rightTriangle() is called and takes the height and base variables are parameters. These variables are initialized inside main().

5. The value returned by the method, rightTriangle(), is assigned to the variable, hypo.

6. The value of the hypotenuse of the triangle which is stored in the variable, hypo, is displayed to the user.

7. The value of the hypotenuse is displayed with 4 decimal places which is done using printf() method and %.4f format specifier. The number 4 can be changed to any number, depending upon the decimal places required.

8. In java, all the code is written inside a class.

9. The name of the program is same as the name of the class having the main() method.

10. The class having the main() method is declared public.

11. All the variables declared outside main() and inside another method, are local to that particular method. While the variables declared outside main() and inside class are always declared static in java.

Answer:

0.119

Explanation:

50 independent fair games

Mean will be 50/2 = 25

Standard deviation of the loosing probability is :

[tex]\sqrt{50*0.5*0.5}[/tex] * 10 = 33.536

we have to loose 33 times out of 50 games.

To find the approximate probability we use z- value table.

z value =  [tex]\frac{33-25}{3.35}[/tex]

z - value = 2.2659

Looking at the z-value table we get 0.119.

The topic sentence states paragraphs main idea. Check more about sentence below.

A topic sentence is known to be one that tells the main point of any given paragraph.

It is said to be a supporting sentences that has the details and gives proof of one's point.

Therefore, The topic sentence states paragraphs main idea.

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Answer:

paragraph's main idea

Explanation:

Answer:

#include <iostream>

#include <string>

using namespace std;

int main()

{

   double charge = 0.00;

   int numChars = 8;

   string color = "gold";

   string woodType = "oak";

   if(numChars > 5){

       charge += (numChars - 5) * 4;

   }

   if(woodType == "oak"){

       charge += 20;

   }

   if(color == "gold"){

       charge += 15;

   }

   charge += 35;

   cout << "The charge is: $" << charge << endl;

   return 0;

}

Explanation:

Include the string library

Initialize the variables as specified

Check if the number of characters is greater than 5 or not. If it is, add 4 to the charge for each character that is greater than 5

Check if the sign is made of oak or not. If it is, add 20 to the charge

Check if the color is gold or not. If it is, add 35 to the charge

Add the minimum cost to the charge

Print the charge

In this exercise we have to use the knowledge of the C++ language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

#include <iostream>

#include <string>

using namespace std;

int main()

{

  double charge = 0.00;

  int numChars = 8;

  string color = "gold";

  string woodType = "oak";

  if(numChars > 5){

      charge += (numChars - 5) * 4;

  }

  if(woodType == "oak"){

      charge += 20;

  }

  if(color == "gold"){

      charge += 15;

  }

  charge += 35;

  cout << "The charge is: $" << charge << endl;

  return 0;

}

See more about C++ at brainly.com/question/26104476

sorry I was testing something

Answer:

This question is answered using C++ programming language.

This program does not make use of comments; However, see explanation section for detailed line by line explanation.

The program starts here

#include <iostream>

using namespace std;

int main()

{

 double quantity,seconds;

 int minutes;

 cout<<"Quantity (mph): ";

 cin>>quantity;

 minutes = int(60/quantity);

 cout<<minutes<<" minutes and ";

 seconds = (60/quantity - int(60/quantity))*60;

 printf("%.1f", seconds);

 cout<<" seconds per mile";

 return 0;

}

Explanation:

The following line declares quantity, seconds as double datatype

 double quantity,seconds;

The following line declares minutes as integer datatype

 int minutes;

The following line prompts user for input in miles per hour

 cout<<"Quantity (mph): ";

User input is obtained using the next line

 cin>>quantity;

The next line gets the minute equivalent of user input by getting the integer division of 60 by quantity

minutes = int(60/quantity);

The next statement prints the calculated minute equivalent followed by the string " minuted and " without the quotes

 cout<<minutes<<" minutes and ";

After the minutes has been calculated; the following statement gets the remainder part; which is the seconds

 seconds = (60/quantity - int(60/quantity))*60;

The following statements rounds up seconds to 1 decimal place and prints its rounded value

 printf("%.1f", seconds);

The following statement prints "seconds per mile" without the quotes

 cout<<" seconds per mile";

Following are the program to the given question:

Program Explanation:

Program:

#include<iostream>//header file

using namespace std;

int main()//defining main method

{

   double mph,sec,min_per_mile;//defining a double variable  

int min;//defining integer variable

cout<<"Enter the speed of the treadmill in mph:";//print message

cin>>mph;//input double value

min_per_mile=(1/mph)*60;//defining a double variable that calculates minutes per mile

min=static_cast<int>(min_per_mile);//defining int variable that converts min_per_mile value into integer

sec=(min_per_mile-min)*60;//defining double variable that calculates seconds per mile value  

cout<<"A common pace is the "<<min<<" minutes and "<<sec<<" seconds per mile"<<endl;//print calculated value with message  

return 0;

}

Output:

Please find the attached file.

Learn more:

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Answer:

Following are the uses of kerning in the word is given below .

Explanation:

The keening in the Microsoft word is the method of pushing the characters nearer in by removing the unnecessary space between the character Following are the steps of using the kerning in the Microsoft word .

Answer:

to adjust the spacing between characters that make up a word

Explanation:

Answer:

Following are the program in C programming language

#include<stdio.h> // header file

int main() // main function  

{

int n1;// variable declaration

int c=0; // variable declaration

float sum=0; // variable declaration

float avg1;

printf("Enter Numbers :\n");

while(1) // iterating the loop

{

scanf("%d",&n1); // Read the value by user

if(n1==9999) // check condition  

break; // break the loop

else

sum=sum+n1; // calculating sum

c++; // increment the value of c

}

avg1=sum/c;

printf("Average= %f",avg1);

return 0;

}

Output:

Enter Numbers:

10  

8  

11

7  

9  

9999

Average= 9.000000

Explanation:

Following are the description of program

The program takes in several value numeric values until 9999 is inputed, the program calculates the average of these values. The program is written in python 3 thus :

n = 0

#initialize the value of n to 0

cnt = 0

#initialize number of counts to 0

sum = 0

#initialize sum of values to 0

while n < 9999 :

#set a condition which breaks the program when 9999 is inputed

n = eval(input('Enter a value : '))

#accepts user inputs

cnt += 1

#increases the number of counts

sum+=n

#takes the Cummulative sum

print(sum/cnt)

#display the average.

A sample run of the program is attached.

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Answer:

Both b and c

Explanation:

Dotted Decimal notation is a presentation of numerical data which is expressed as decimal numbers separated by full stops. Dotted decimal notation expresses each eight bit sections of 32 bit numbers as decimal value. It provides convenient notation which is easy to understand by the people who are IT experts.

Answer:

A template

Explanation:

The type of construct he should create is a Template.

Template: A template is a file that serves as a beginning point for a document that is new.

When you open a template, it is pre-formatted in a way. for instance you might make use of a template in Microsoft Word that is arranged as a business letter, the template would mostly have a space for your address also a name in the left (upper)corner, which is an area for the receivers's address.

Now a little below that on the left site, is an area for the message (body) and after that, is a spot for your signature at the bottom.

Answer:

You absolutely should throw an exception from a constructor if you're unable to create a valid object. This allows you to provide proper invariants in your class. ... Throw an exception if you're unable to initialize the object in the constructor, one example are illegal arguments.

Explanation:

Error codes cannot be used in constructors since they lack a return type. Therefore, throwing an exception is the most effective technique to indicate constructor failure. Here is a workaround if you don't have or are unwilling to use exceptions.

When an exception is thrown in a constructor, memory for the actual object has already been set aside before the constructor is even invoked. Therefore, after the exception is thrown, the compiler will immediately deallocate the memory the object was using.

There are two solutions to that: Simple and conventional approach: Use arrows. To make use of a two-stage construction, use a custom “construct” function after a default constructor that cannot throw exceptions.

Therefore, The constructor has the ability to “zombie” an object if it fails.

Learn more about Constructors here:

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Answer:

The cout<<numInsects<<""; statement should be placed before numInsects = numInsects * 2;  in the while loop.

Explanation:

Your program gives the following output:

16  32  64  128

However it should give the following output:

8  16  32  64

Lets see while loop to check what you did wrong in your program:

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100.

So the body of while loop executes. numInsects = numInsects * 2;  statement in the body multiplies the value of numInsects i.e 8 with 2 and then cout << numInsects << " ";  prints the value of numInsects  AFTER the multiplication with 2 is performed. So 8 is not printed in output but instead 16 (the result of 8*2=16) is printed as the result of first iteration.

So lets change the while loop as follows:

while (numInsects < 100) {

cout << numInsects << " ";

numInsects = numInsects * 2;

Now lets see how it works.

The while loop checks if numInsects is less than 100. It is true as numInsects =8 which is less than 100

So the body of while loop executes. cout << numInsects << " "; first prints the value of numInsects i.e. 8. Next numInsects = numInsects * 2;  multiplies the value of numInsects i.e 8 with 2. So first 8 is printed on the output screen. Then the multiplication i.e. 8*2=16 is performed as the result of first iteration. So now value of numInsects becomes 16.

Next the while loop condition numInsects < 100 is again checked. It is true again as 16<100. Now cout << numInsects << " "; is executed which prints 16. After this, the multiplication is again performed and new value of numInsects becomes 32 at second iteration. This is how while loops continues to execute.

So this while loop stops when the value of numInsects exceeds 100.

Answer:

I am writing the Python program. Let me know if you want the program in some other programming language.

def convertMillis(millis):  #function to convert milliseconds to hrs,mins,secs

   remaining = millis  # stores the value of millis to convert

   hrs = 3600000  # milliseconds in hour

   mins = 60000  # milliseconds in a minute

   secs = 1000  #milliseconds in a second

   hours =remaining / hrs  #value of millis input by user divided by 360000

   remaining %= hrs  #mod of remaining by 3600000

   minutes = remaining / mins  # the value of remaining divided by 60000

   remaining %= mins  #mod of remaining by 60000

   seconds = remaining / secs  

#the value left in remaining variable is divided by 1000

   remaining %= secs  #mod of remaining by 1000

   print ("%d:%d:%d" % (hours, minutes, seconds))

#displays hours mins and seconds with colons in between

def main():  #main function to get input from user and call convertMillis() to #convert the input to hours minutes and seconds

   millis=input("Enter time in milliseconds ")  #prompts user to enter time

   millis = int(millis)  #converts user input value to integer

   convertMillis(millis)   #calls function to convert input to hrs mins secs

main() #calls main() function

Explanation:

The program is well explained in the comments mentioned with each line of code. The program has two functions convertMillis(millis) which converts an input value in milliseconds to hours, minutes and seconds using the formula given in the program, and main() function that takes input value from user and calls convertMillis(millis) for the conversion of that input. The program along with its output is attached in screenshot.