What are the characteristics of a socialist economy? What are the pros and cons of this type of economy?
Answer:
The pro is Political Control, the cons, however, are many.
Step-by-step explanation:
However, A Socialist Economy cons outweigh its pros. The only thing that is a PRO is you dictating it, preventing people from success. Wanna know the cons? The Cons are more Regulations, to which chokes more businesses of their money, they function, & motive. To which it has a chain reaction of: The Businesses not employing people, more people are out of work, which means more people ain't buying stuff to support the businesses, which means the businesses are out of business, they shut down.
The Economy ain't something that you can stop, or go, & it ain't statistics. An Economy is just.. people, that's it. It's just people, they are the ones that work, run businesses & factories, they are the ones that buy N' sell. They create, craft, invent, innovate, etc.
Here's a quote that I have: "The more you choke it from breathing in, the less it breathes out". That's my stance on regulation & Socialism, to which Socialism is just Voluntary Communism, & A Permanent Ideological belief that Big government Involvement is the way to go.
To which, it's not!
Describe fully the single transformation that’s maps triangle A onto triangle B.
Answer:
reflection of the axis y=4
Step-by-step explanation:
becuase it is reflected on itself
Answer:
Reflect Triangle A by the line y = 4
Step-by-step explanation:
The answer is reflect Triangle A by y = 4 because the two triangles are symmetric.
Tom takes a cancer test and the test is advertised as being 99% accurate: if you have cancer you will test positive 99% of the time, and if you don't have cancer, you will test negative 99% of the time. If 1% of all people have cancer and Tom tests positive, what is the prob that Tom has the disease
Answer:
99% chance tommy has it
Step-by-step explanation:
cuz do da math
The table represents an exponential function.
What is the multiplicative rate of change of the
function?
x
1
0 1 / 3
2
3
0 2 3
y
6
4
8
3
16
9
O 2
09
4.
Question Correction
The table represents an exponential function. What is the multiplicative rate of change of the function?
(A)1/3 (B)2/3 (C)2 (D)9
[tex]\left|\begin{array}{c|c}x&y\\--&--\\1&9\\2&6\\3&4\\4&\dfrac83\\\\5&\dfrac{16}{9}\end{array}\right|[/tex]
Answer:
(B) [tex]\dfrac{2}{3}[/tex]
Step-by-step explanation:
An exponential function is a function of the form
[tex]y= a (b)^{x}[/tex]
where a is the initial value and b is the multiplicative rate of change
When x=2, y=6, we have:
[tex]6= a (b)^{2}[/tex]
When x=3, y=4, we have:
[tex]4= a (b)^{3}[/tex]
Dividing the two equations:
[tex]\dfrac{a (b)^{3}}{a (b)^{2}} =\dfrac{6}{9} \\b=\dfrac{6}{9}\\b=\dfrac{2}{3}[/tex]
The multiplicative rate of change, b is [tex]\dfrac{2}{3}[/tex].
The correct option is B.
Answer: It's B) 2/3
Hope it helps :3
5x is equal to 8X raise to power - 1/3
Answer:
No solutions.
Step-by-step explanation:
5x = 8x^-1/3
Divide 8 into both sides.
5/8x = x^-1/3
Divide both sides by x.
5/8 = x^-4/3
Multiply both sides by the exponent -3/4.
5/8^-3/4 = x
1.422624 = x
Plug in 1.422624 for x to check.
It does not work. There are no real solutions.
A camera shop stocks eight different types of batteries, one of which is type A76. Assume there are at least 30 batteries of each type.
Required:
a. How many ways can a total inventory of 30 batteries be distributed among the eight different types.
b. How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?
c. How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory includes at most three A7b batteries?
Answer:
a. 10295472 ways
b. 4272048 ways
c. 6023424 ways
Step-by-step explanation:
Given that:
Camera shop stocks ----- 8 different types of batteries
one of which is ---- A76
Assume that there are ------ at least 30 batteries of each type.
a.
How many ways can a total inventory of 30 batteries be distributed among the eight different types.
The number of ways a total inventory of 30 batteries be distributed is :
[tex]= \left \{ {{30+8-1} \atop {30}} \right. \}[/tex]
[tex]= \left \{ {{37} \atop {30}} \right. \}[/tex]
[tex]=\dfrac{37!}{30! *7!}[/tex]
[tex]= \dfrac{37*36*35*34*33*32*31*30!}{30!*7*6*5*4*3*2*1}[/tex]
[tex]= \dfrac{37*36*35*34*33*32*31}{7*6*5*4*3*2*1}[/tex]
= 10295472 ways
b.
How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?
If we must include 4 A76 batteries; then the number of ways a total inventory of 30 batteries can be distributed among eight different types of batteries will be:
30 - 4 = 26 batteries
Now;
[tex]= \left \{ {{26+8-1} \atop {26}} \right. \}[/tex]
[tex]= \left \{ {{33} \atop {26}} \right. \}[/tex]
[tex]=\dfrac{33!}{26! \ \ 7!}[/tex]
[tex]=\dfrac{33*32*31*30*29*28*27*26!}{26! \ * \ 7*6*5*4*3*2*1}[/tex]
[tex]=\dfrac{33*32*31*30*29*28*27}{ \ 7*6*5*4*3*2*1}[/tex]
= 4272048 ways
c. If we must include at most three A7b batteries. the number of ways that a total inventory of 30 batteries can be distributed among eight different types of inventory is:
[tex]= \sum \limits ^3 _{x=0} \left \{ {{(30-x)+7-1} \atop {30-x}} \right. \} \\ \\ \\ = \sum \limits ^3 _{x=0} \left \{ {{(30-0)+7-1} \atop {30-0}} \right. \} = (^{36}_{30})+(^{35}_{29})+ (^{34}_{28})+ (^{33}_{27})[/tex]
[tex]= \dfrac{36!}{30! * 6!} + \dfrac{35!}{29! * 6!} + \dfrac{34!}{28! * 6!} + \dfrac{33!}{27! * 6!}[/tex]
= 1947792 + 1623160 + 1344904 + 1107568
= 6023424 ways
will give brainliest help plz i can't get back on the password won't go to my email and my little brother changed the password I am scared I lost everything PLZ HELP ME
Please answer this question now in two minutes
Answer:
ray UV and ray UT
Step-by-step explanation:
The sides are the rays that make up the angle
ray UV and ray UT make up the angle VUT
Stuck on this one .......
Answer:
Exponent Product Rule
Step-by-step explanation:
Exponent multiplication: (a^b)(a^c)= a^(b+c)
t^3=(t^2)t
Because t=t^1, we have
t^2+t^1=t^3
This can be shown by the Exponent Product Rule
Answer: t²⁺¹
Step-by-step explanation:
The law of exponents states that when multiplying terms with the same base, you ADD the exponents. Note that "t" has an exponent of 1.
t³ = (t²)t¹ = t²⁺¹
I hope this is what you were looking for.
For the data set represented by this box plot, what is the value of the maximum? maximum:
Answer:
140
Step-by-step explanation:
The maximum is the furthest the line that goes out the furthest, the minimum would be about 83-84
Answer:
the other person is correct!
Step-by-step explanation:
Find value of z and simplify completely.
Answer:
3√10Given:
A right triangle in which an altitude is drawn from the right angle vertex
To find: value of X
We have leg rule in similarity in right triangle as:
[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ [/tex]
Plugging the given values,
[tex] \frac{z}{3} = \frac{3 + 27}{z} \\ z \times z = 3(3 + 27) \: \: (cross \: multiplication) \\ {z}^{2} = 9 + 81 \\ {z}^{2} = 90 \\ z = \sqrt{90} \\ z = 3 \sqrt{10} [/tex]
Hope this helps...
Good luck on your assignment..
PLEASE HELPP! f(x)= -3x + 3
Which of the graphs represent the inverse of the function F??
Answer:
Answer is Y
Step-by-step explanation:
How much time will it take Jenny to bike 15 miles if she bikes at a speed of 6 mph?
Answer:
this lesson, we will investigate the relationship between the distance traveled, the rate or speed or travel, and the time that it takes to travel that distance at that rate. We will also look at a few other related products.
Distance = (Rate)(Time)
The equation that relates distance, rate, and time is
d = rt
Where d is the distance traveled, r is the rate, and t is the time. On the CAHSEE exam, you will be given two of these and will be asked to use the above equation to find
took Markus half an hour to drive home from work. He averaged 34 miles per hour. How far does Markus live from his work?SolutionWe are given that it takes 1/2 an hour for the trip. This is a time: t = 1/2We are given that he averages 34 miles per hour. This is a rate: r = 34We are asked how few he has traveled. This is a distance. We use the d=rt equation: d = rt = (34)(1/2) = 17Answer:
2.5 hours
Step-by-step explanation:
First, try rewriting Jenny's speed in it's fraction form: 6 mi/hr
Next, use the units to set up an equation that relates Jenny's speed to the distance they want to travel. Let's call the unknown time t:
6mi/hr=15mi/t
1/t=6/15 (mi/hr•1/mi)
t=15/6 (hrs/mi•mi)= 15/6 (hrs•mi/mi)= 15/6 hrs
t=2.5hrs
So it'd take Jenny 2.5hrs at 6mph to go 15 miles. The key here is to keep track of the units. You can treat them like fractions and reduce them away as if they were numbers or variables.
Write the equation of each line in slope-intercept form.
(If possible please show work)
Answer:
[tex]\displaystyle y = -\frac{2}{3}\, x - 9[/tex].
Step-by-step explanation:
The slope-intercept form of a line on a cartesian plane should be in the form:
[tex]y = m\, x + b[/tex],
where:
[tex]m[/tex] is the slope of the line, while [tex]b[/tex] is the [tex]y[/tex]-coordinate of the point where the line intersects the [tex]y[/tex]-axis.The question states that the slope of this line is [tex]\displaystyle -\frac{2}{3}[/tex]. In other words, [tex]\displaystyle m = -\frac{2}{3}[/tex]. The next step is to find the value of [tex]b[/tex]. That could be done using the information that the point [tex](-6,\, -5)[/tex] is on this line.
Note that the slope-intercept form of a line [tex]y = m\, x + b[/tex] is essentially an equation about [tex]x[/tex] and [tex]y[/tex]. For a point [tex](x_0,\, y_0)[/tex] to be on that line, [tex]x = x_0[/tex] and [tex]y = y_0[/tex] should satisfy its equation. In other words, it must be true that [tex]y_0 = m\, x_0 + b[/tex].
For the point [tex](-6,\, -5)[/tex], [tex]x_0 = -6[/tex] and [tex]y_0 = -5[/tex]. The equation would be:
[tex]\underbrace{-5}_{y_0} = m \times \underbrace{(-6)}_{x_0}+ b[/tex].
Besides, the slope of this line is already known to be [tex]\displaystyle m = -\frac{2}{3}[/tex]. Therefore, this equation would become:
[tex]\displaystyle \underbrace{-5}_{y_0} = \underbrace{\left(-\frac{2}{3}\right)}_{m} \times \underbrace{(-6)}_{x_0}+ b[/tex].
Solve this equation for [tex]b[/tex]:
[tex]b = -9[/tex].
Hence, the slope-intercept form ([tex]y = m\, x + b[/tex]) of this line would be:
[tex]\displaystyle y = -\frac{2}{3}\, x - 9[/tex].
Which parent function is f(x) = x^2?
O A. An exponential parent function
OB. The linear parent function
C. The absolute value parent function
D. The quadratic parent function
Answer:
D. Quadratic parent function.
Step-by-step explanation:
The payroll register of Wang Heritage Co indicates $2,058 of social security withheld and $514.50 of Medicare tax withheld on total salaries of $34,300 for the period. Earnings of $10,600 are subject to state and federal unemployment compensation taxes at the federal rate of 0.8% and the state rate of 5.4%. Provide the journal entry to record the payroll tax expense for the period. If an amount box does not require an entry, leave it blank. Round to two decimal places. Payroll Tax Expense Social Security Tax Payable Medicare Tax Payable State Unemployment Tax Payable Federal Unemployment Tax Payable
Answer:
Date X, Month Y, payroll taxes expense
Dr FICA (OASDI) taxes expense 2,058
Dr FICA (Medicare) taxes expense 514.50
Dr FUTA taxes expense 84.80
Dr SUTA taxes expense 572.40
Cr Dr FICA (OASDI) taxes payable 2,058
Cr FICA (Medicare) taxes payable 514.50
Cr FUTA taxes payable 84.80
Cr SUTA taxes payable 572.40
Step-by-step explanation:
The amount of employer's FICA taxes expense is the same as the FICA taxes withheld from employees' salaries. Since the question asked for the journal entry to record payroll taxes, wages expense is not included.
There are members on the board of directors for a certain non-profit institution. a. If they must elect a chairperson, first vice chairperson, second vice chairperson, and secretary, how many different slates of candidates are possible? b. If they must form an ethics subcommittee of four members, how many different subcommittees are possible?
Answer: a. 1320
b.495
Step-by-step explanation:
Complete question is provided in the attachment.
Total members on the board = 12
a. Persons to chose : chairperson, first vice chairperson, second vice chairperson, and secretary
i.e. Total 3 posts in an order.
Number of ways to choose 3 persons from 12 in an order = [tex]^{12}P_3[/tex] [By permutation]
[tex]=\dfrac{12!}{(12-3)!}\\\\=\dfrac{12!}{7!}\\\\=12\times11\times10\\\\=1320[/tex]
hence, 1320 different slates of candidates are possible .
b. number of ways to choose 4 members out of 12 ( order not matters)=[tex]^{12}C_{4}[/tex] [By combinations]
[tex]=\dfrac{12!}{4!8!}\\\\=\dfrac{12\times11\times10\times9}{24}\\\\=495[/tex]
Hence, the number of different subcommittees are possible =495
A fish population grew according to the following quadratic model, the number of fish a day is given by
P(t)=800t-t^2
What is the initial growth rate a t=0
Answer:
800 fish per day is the initial growth rate of the fish population
Step-by-step explanation:
The growth rate is the derivative of the population function with respect to time (t). Therefore, we need to calculate the derivative of P(t) and evaluate it at t=0:
[tex]\frac{d\,P(t)}{dt} =800-2\,t\\[/tex]
which evaluated at t = 0 becomes:
[tex]800-2\,(0)=800[/tex]
I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coins in cents in terms of k.
Answer:
(35k + 20) cents
Step-by-step explanation:
First of all, let us have the value of each unit:
1 quarter = 25 cents
1 nickel = 5 cents
1 dime = 10 cents
Given that number of quarter = k
Quarters are 5 lesser than Nickels, so number of nickels = k+5
One more than twice as many dimes as quarters:
k = 2 [tex]\times[/tex] Number of Dimes + 1
So, number of dimes = [tex]\frac{1}{2}(k-1)[/tex]
Value of quarters = [tex]25 \times k[/tex] cents
Value of nickels = [tex]5 \times (k+5) = (5k+25)\ cents[/tex]
Value of dimes = [tex]\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents[/tex]
So, total value of coins =
[tex]25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents[/tex]
The marketing research department of a computer company used a large city to test market the firm's new laptop. The department found the relationship between price p (dollars per unit) and the demand x (units per week) was given approximately by the following equation.
p= 1275 = 0.17x^2 0 < x < 80
So, weekly revenue can be approximated by the following equation.
R(x)= rp = 1275x- 0.17x^3 0 < x <80
Required:
a. Find the local extrema for the revenue function. What is/are the local maximum/a?
b. On which intervals is the graph of the revenue function concave upward?
c. On which intervals is the graph of the revenue function concave downward?
Answer:
a. Local maximum = 50 units per week.
b. The graph is never concave upward.
c. (0, 80)
Step-by-step explanation:
a. The revenue function is:
[tex]R(x) = 1275x-0.17x^3[/tex]
The derivate of the revenue function for which R'(x) = 0 gives us the local extrema:
[tex]R'(x) =0= 1275-0.51x^2\\x=\sqrt{2,500}\\x=50[/tex]
The second derivate of the revenue function determines if x =50 is local maximum or minimum:
[tex]R''(x) = -1.02x\\R''(50) = -1.02*50=-51\\[/tex]
Since the second derivate yields a negative value, x = 50 units per week is a local maximum.
b. Since there are no local minimums in the range of 0 < x < 80, the graph is never concave upward.
c. Since there is only one local maximum in the range of 0 < x < 80, the graph is concave downward from x>0 to x<80 or (0, 80)
What is the measure of angle ABC? Please answer quickly!
Answer:
ABC = 88
Step-by-step explanation:
Angle Formed by Two Chords = 1/2( sum of Intercepted Arcs)
ABD = 1/2 ( 131+ 53)
ABD = 1/2 (184)
=92
ABC = 180 -ABD
ABC = 88
Sketch the graph of the inequality. 3y − x ≥ 9
Answer:
The graph of inequality is shown below.
Step-by-step explanation:
The given inequality is
[tex]3y-x\geq 9[/tex]
Related equation is
[tex]3y-x=9[/tex]
At x=0,
[tex]3y-0=9\Rightarrow y=3[/tex]
At y=0,
[tex]3(0)-x=9\Rightarrow x=-9[/tex]
Plot (0,3) and (-9,0) on coordinate plane and connect them by a straight line.
Check the inequality for (0,0).
[tex]3(0)-(0)\geq 9[/tex]
[tex]0\geq 9[/tex]
This statement is false. So, (0,0) is not included in the shaded region.
The graph of inequality is shown below.
Each of 100 students in the Allen School can only take 1 CSE class each, between the four classes CSE 311, CSE 312, CSE 331, and CSE 332. Each student (independently of others) takes CSE 311 with probability 0.3, CSE 312 with probability 0.4, CSE 331 with probability 0.1, and CSE 332 with probability 0.2. What is the probability that exactly 31 sign up for CSE 311, 39 sign up for CSE 312, 7 sign up for CSE 331, and 23 sign up for CSE 332
Answer:
[tex]P(a=31,b=39,c=7,d=23) = 0.000668[/tex]
Step-by-step explanation:
Sample space, n = 100
Let the number of students signed up for CSE 311 = a
Let the number of students signed up for CSE 312 = b
Let the number of students signed up for CSE 331 = c
Let the number of students signed up for CSE 332 = d
Probability of taking CSE 311, [tex]P_a[/tex] = 0.3
Probability of taking CSE 312, [tex]P_b[/tex] = 0.4
Probability of taking CSE 331, [tex]P_c[/tex] = 0.1
Probability of taking CSE 332, [tex]P_d[/tex] = 0.2
[tex]P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a} p_b^{b} p_c^{c} p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} * 0.3^{31} * 0.4^{39} * 0.1^{7} 0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668[/tex]
Simplify e^ln4
A. 1/4
B. 4
C. 1n4
D. E^4
Answer:
The answer is option B.
4Step-by-step explanation:
Using the expression
[tex] {e}^{ ln(x) } = x[/tex]
[tex] {e}^{ ln(4) } = 4[/tex]
Hope this helps you
The half-life of a radioactive substance is one day, meaning that every day half of the substance has decayed. Suppose you have 95 grams of this substance. Construct an exponential model for the amount of the substance remaining on a given day. Use your model to determine how much of the substance will be left after 4 days
Answer:
Exponential model
Y = y0e-0.693(t½)
Amount remaining after 4 days
5.9413 grams
Step-by-step explanation:
The formula will he given by
Y = y0e-k(t½)
The half life t½ for this radioactive substance is a day.
Initial mass y0 = 95 grams
Mass after one day = 95/2
Mass after one day = 47.5
.
Value of the decay constant k is not given, let's look for k.
Y = y0e-k(t½)
47.5= 95e-k(1)
47.5/95= e-k(1)
0.5= e-k(1)
In 0.5 = -k
-0.693= -k
0.693 = k
Y = y0e-0.693(t½)
Amount remaining after 4 days
Y = y0e-0.693(t½)
Y = 95e-0.693(4)
Y= 95e-2.772
Y= 95(0.06254)
Y= 5.9413 grams
A publishing company sells 100,000 copies of certain books each year. It costs the company $1 to store each book for a year. Each time it must print additional copies, it costs the company $500 to set up the presses. How many books should the company produce during each printing in order to minimize its total storage and setup costs?
Answer:
10,000 books
Step-by-step explanation:
Let x be the number of print runs per year and let y the number of books per print run.
Thus, xy = 100,000.
Now from the question, we only start a new print run when we have sold all books in the storage. Thus;
Per print run we now have a cost of;
(x * 1)/(y * 2)
This is because right after the print run, we have y books that last 1/n years (until the next print run). Now, if we plot number of books in storage vs time, we will see a sawtooth pattern where the spikes begin at each print run and will linearly decrease to 0 until the next sprint run which implies constant demand. The area of each triangle will be how many book⋅years we have to pay the storage for. This area is;
(y * (1/x))/2
We'll have to multiply this number by 1 so we can then we get the storage cost per printrun:
(y * (1/x))/2 * 1 = y/2x
Since we do x print runs, the total storage costs is; y/2x * x = y/2
The total print run cost is (500 * x). Therefore, the total cost is;
C_total = (500x) + (y/2)
From initially, we saw that;
xy = 100000
So,x = 100,000/y
C_total = (500*100,000/y) + (y/2)
C_total = 50000000/y + y/2
To minimize its total storage and setup costs, we will find the derivative of the total cost and equate to zero.
So;
dC/dx = -50000000/y² + 1/2
At dC/dx = 0,we have;
0 = -50000000/y² + 1/2
50000000/y² = 1/2
2 × 50000000 = y²
y = √2 × 50000000
y = 10,000 books
-5 x = 4 what property of equality was use to solve this equation
Answer:
Division property of equality.
simplify the expression into form a+bi, where rational numbers
(4-i)(-3+7i) - 7i(8+2i)
Answer:
-12+28i+3i-7i-65i+28
14 -41i
A pallet of floor tiles contains 40 cases of tiles and the yard has 10 complete pallets of tile. If you remove 180 cases for one customer how many cases of tiles will be remaining in the yard? *
Answer:
220 cases
Step-by-step explanation:
Each pallet contains 40 cases of tiles.
The yard has 10 complete pallets.
The total number of cases of tiles is therefore:
40 * 10 = 400 cases
If 180 cases are removed for the customer, then the number of cases of tiles remaining is:
400 - 180 = 220 cases
220 cases of tiles will be remaining.
which of the following descriptions represent the transformation shown in the image? Part 3c
Answer: c) rotation of 180° & shift right 1 unit and down 2 units
Step-by-step explanation:
Rotation of 180° changes the signs of x and y
(x, y) → (-x, -y)
Shift right one unit adds 1 to x, Shift two down subtracts 2 from y
(-x, -y) → (-x + 1, -y - 2)
(x, y) (-x + 1, -y - 2)
(-1, -2) → (2, 0)
(-4, -1) → (5, -1)
(-4, -3) → (5, 1)