Answer:
Required Answer:-We don't use water as Water don't expand when it came in connection of temperature.Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
Answer:
TRUE
Explanation:
The answer is true.
Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.
In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.
In a container of negligible mass, 0.0400 kg of steam at 100∘C100 ∘ C and atmospheric pressure is added to 0.200 kg of water at 50.0∘C50.0 ∘ C.
(a) If no heat is lost to the surroundings, what is the final temperature of the system?
(b) At the final temperature, how many kilograms are there of steam and how many of liquid water?
If no heat is lost to the surroundings, the final temperature of the system is 100 C°, At the final temperature, 0.0214 kg and 0.219 kg kilograms are there of steam and how many of liquid water
What is heat ?heat can be defined as the form of energy that is spontaneously transferred from one object to another object as the differences in temperatures is otherwise called as heat transfer.
The Heat transfer occurs upto the equilibrium point of an object has been reached.
Internal Energy is the total amount of energy of all the molecules of a body is the internal energy within the object.
Specific Heat or heat capacity, is the amount of energy required to produce a unit change in its temperature.
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A 4 kg jug of juice is pulled forward across a horizontal breakfast table, by a 12 N forward-directed force. A frictional force also impedes the jug's motion. What is the coefficient of kinetic friction between the table and jug, if the jug accelerates to the right at 2 m/s^2 ?
A 0.08
B 0.1
C 0.2
D 0.3
Answer:
0.1Explanation:
According to equation of motion;
\sum F = ma
m is the mass of the body
a is the acceleration
\sum F = Fm - Ff (along the horizontal)
Fm is the moving force
Ff is the frictional force
Given;
Fm = 12N
Ff = nR = nmg
Ff = n(4)(9.8)
Ff = 39.2n
Substitute the given value into the expression above;
Fm - Ff = ma
12 - 39.2n = 4(2)
-39.2n = 8-12
-39.2n = -4
n = 4/39.2
n = 0.1
Hence the coefficient of kinetic friction between the table and jug is 0.1
When does an object reach its terminal velocity?
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
Explanation:.
Answer: Terminal velocity is achieved, therefore, when the speed of a moving object is no longer increasing or decreasing; the object's acceleration (or deceleration) is zero.
As others have said, 8 seconds to get to 90% of terminal velocity. But if you're falling from outer space, you could reach speeds much higher than terminal velocity, and slow down when you reach the atmosphere. If coming in from a long distance, you'll burn up like a meteorite.
Explanation:
Refinery EM can produce 22 gallons of gasoline or 18 gallons of flight fuel per barrel of crude oil. Refinery CG can produce 18 gallons of gasoline or 16 gallons of flight fuel per barrel of crude oil. Does OUTPUT vary or does INPUT vary in this problem?
Answer:
Output varies
Explanation:
Here the outputs of gallons of gasoline and flight fuel is mentioned of two refineries namely Refinery EM and Refinery CG. The output has been mentioned with respect to one barrel of crude oil. So, one barrel of crude is used by both the refineries.
So, here the output (gallons of gasoline and flight fuel) varies while the input (one barrel of crude oil) remains constant.
A cow standing atop a building in Times Square recalled a funny joke and began to laugh. The uncontrollable laughter caused the cow to fall over the side of the building. He fell for a time period of 3.5 s and landed in a bed of bushes. How fast was the cow moo-ving when he reached the bushes?
Which equation should be used to solve the problem?
Answer:
Vf = 34.3 m/s
1st equation of motion was used to solve.
Explanation:
In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity of Cow = ?
Vi = Initial Velocity of Cow = 0 m/s
g = acceleration due to gravity = 9.8 m/s²
t = time taken = 3.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.3 m/s
1st equation of motion was used to solve.
Hi, I don't really know I just guessed.
Answer:
direction
Explanation:
Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
A ball is thrown horizontally at a height of 2.20 meters at a velocity of 65.0 m/s. Assume no air resistance. How far did the ball travel horizontally when it hit the ground?
If a ball is thrown horizontally at a height of 2.20 meters at a velocity of 65.0 m/s. Assuming no air resistance, then the distance traveled by the ball horizontally when it hit the ground would be 43.55 meters.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem If a ball is thrown horizontally at a height of 2.20 meters at a velocity of 65.0 m/s. Assume no air resistance.
S = ut + 1/2 × a × t²
2.2 = 0 + 0.5 × 9.8 × t²
t² = 2.2 / 4.9
t = 0.67 seconds
The horizontal displacement of the ball = 0.67 × 65
= 43.55 meters
Thus, the distance traveled by the ball horizontally when it hit the ground would be 43.55 meters.
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The Total Kinetic Energy of moving particles of matter is called ______ energy?
Answer: thermal energy
Explanation: hope this helps
At a picnic, there is a contest in which hoses are used to shoot water at a beach ball from three different directions. As a result, three forces act on the ball, F1, F2, and F3. The magnitudes of F1 and F2 are F1=50.0N and F2=90.0N. F1 acts under the angle of 60degrees with respect to the x axis and F2 is directed along the x-axis. Find the magnitude and direction of F3 such that the resultant force acting on the ball is zero.
Answer:
F₃ = 122.88 N
θ₃ = 20.63°
Explanation:
First we find the components of F₁:
For x-component:
F₁ₓ = F₁ Cos θ₁
F₁ₓ = (50 N) Cos 60°
F₁ₓ = 25 N
For y-component:
F₁y = F₁ Sin θ₁
F₁y = (50 N) Sin 60°
F₁y = 43.3 N
Now, for F₂. As, F₂ acts along x-axis. Therefore, its y-component will be zero and its x-xomponent will be equal to the magnitude of force itself:
F₂ₓ = F₂ = 90 N
F₂y = 0 N
Now, for the resultant force on ball to be zero, the sum of x-components of the forces and the sum of the y-component of the forces must also be equal to zero:
F₁ₓ + F₂ₓ + F₃ₓ = 0 N
25 N + 90 N + F₃ₓ = 0 N
F₃ₓ = - 115 N
for y-components:
F₁y + F₂y + F₃y = 0 N
43.3 N + 0 N + F₃y = 0 N
F₃y = - 43.3 N
Now, the magnitude of F₃ can be found as:
F₃ = √F₃ₓ² + F₃y²
F₃ = √[(- 115 N)² + (- 43.3 N)²]
F₃ = 122.88 N
and the direction is given as:
θ₃ = tan⁻¹(F₃y/F₃ₓ) = tan⁻¹(-43.3 N/-115 N)
θ₃ = 20.63°
A complex arrangement of pulleys forms what is called the block in a block and tackle. The rope used to lift the pulleys and the load is the tackle. A block and tackle is used to lift a truck engine, which has a weight and output force of nearly 8000 N. The input force required to lift this weight using the block and tackle is 400N. What is the mechanical advantage of the block and tackle?
Answer:
Mechanical advantage = 20
Explanation:
Given:
Output force = 8,000 N
Input force = 400 N
Find:
Mechanical advantage
Computation:
Mechanical advantage = Output force / Input force
Mechanical advantage = 8,000 / 400
Mechanical advantage = 20
A bulldozer pushes on a boulder with a force of 600 N. It accelerates at 3 m/s. Find mass.
Answer:
Formula for mass: m=f/a
m=600/3
The mass is 200.
Explanation:
Hope this helps!
Weight is proportional to but not equal to mass. In which of the following situations would a person show an increase in weight but not an increase in mass?
Group of answer choices
a Landing on a planet with more gravity.
b Traveling on the highway in a SUV.
c Living in a chamber in an underwater habitat.
d Climbing to the top of a mountain.
Answer: c living in a camber in an under water habitat
Explanation:
10. Scientists created models that show a rocky asteroid crashing into a moon (less mass) a
planet (more mass). In both crashes, the asteroid was the same mass. Scientists want to kno
happened to the asteroid. Use the information in the diagram to answer.
In which crash did the asteroid experience a stronger force? How do you know?
a
Crash 2; the force on the planet was stronger in this crash, so the force on the astero
also stronger.
There was no force on the asteroid. Only the moon and planet experienced a force in
Answer:
The diagram doesn’t tell you anything about the force on the asteroid. It only gives information about the force on the planet and the moon.
Explanation:
(NEED HELP ASAP)
In a lab investigation one group of students (group a) measures the speed of a 0.1 toy car to be 2.5 m/s at the bottom of a ramp another group of students (group b) measures the speed of the car to be 3 m/s at the bottom of the ramp the cars starting position at the top of the ramp is 1 m high.
a. what is the potential energy of the car at the beginning of the experiment before it's speed is measured?
b. Calculate the kinetic energy of the car for group a.
C. Calculate the kinetic energy for the car for group b.
Answer:
a = 0.98J
Explanation:
PE = mgh
PE = 0.1 x 9.8 x 1
PE = 0.98J
(a) The potential energy of the car at the beginning of the experiment is 9.8(m) J.
(b) The kinetic energy of the car for group a is 3.125(m) J.
(c) The kinetic energy of the car for group b is 4.5(m) J.
Potential energy of the car at the beginning of the experimentThe potential energy of the car is calculated as follows;
P.E = mgh
where;
m is mass of the carg is accleration due to gravityh is height of the carP.E = m x 9.8 x 1
P.E = 9.8(m) J
Kinetic energy of the car for group aK.E = ¹/₂mv²
K.E = ¹/₂ x m x (2.5)²
K.E = 3.125(m) J
Kinetic energy of the car for group bK.E = ¹/₂mv²
K.E = ¹/₂ x m x (3)²
K.E = 4.5(m) J
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Name 2 fundamental units of SI system except that of MKS system.
The others are:
Ampere
Mol
Candela
Answer:
Ampare mole candelahope it is helpful to you
What made "Lunar Orbit Rendezvous" such an attractive method to get to the Moon that it was selected by NASA in July, 1962
Answer:
I don't know the answer
May someone please help?
Air is cooled and
becomes
[denser/less dense).
Less dense air
[rises/sinks).
Denser air
(rises/sinks).
The process repeats, producing a
Air is heated and
becomes
[denser/less dense]
within the gas
Air is cooled and
becomes denser.
Denser air sinks.
The process repeats, producing a (i wasn't sure about this one)
Air is heated and becomes less dense.
Less dense air rises.
hope this helps!
plz help i really need this
Answer:
The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.
Explanation:
Answer:
The Group Number of the elements.
Explanation:
If Marie knew the group number of the elements, then she could determine the amount of valence electrons each element has and their reactivity rate. For example, if one box tells her that an element is located in group 18, then she could determine that the element is not very reactive. This is because elements in group 18 have 8 valence electrons, which makes them stable/unreactive.
Hope this helps!
18) Why do you think divergent plate boundaries and transform fault boundaries only occur at places where the crust is the same on both plates?
Answer:
A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust. When two plates come together, it is known as a convergent boundary.
Explanation:
What are the Laws of conservation of atoms?
Answer:
Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.
Explanation:
Answer:
The law of conservation of atoms is simple but it has a great affect. An atom cannot be destroyed by such a force. Matter/atoms can't be created by any means. An atom exits only by nature and not by force.
Hope this helped! Please mark brainliest! Have a great day!
Which of the following has the greatest mass?
A. star
B. moon
C. planet
D.galaxy
Answer: I think the answer is d
Explanation: sry if wrong
Calculate the acceleration of gravity that the moon has, if an astronaut has a mass of 87 kg and the weight force he experiences on the moon is 141 N
Answer:
the acceleration of gravity is 1.62
Explanation:
w=mg
141=87g
141/87=87g/87
1.62=g
Susie Small finds she weighs 300 N.
Calculate her mass.
Answer:
30Kg
Explanation:
Weight = mass x gravitational field strength
300 = mass x 10
mass = 30kg
gravitational field strength is 9.8 on earth but normally we take it to be 10 for easy reference and calculations
The mass will be "30 kg". A further solution is provided below.
According to the question,
Weight,
300 NWe know that,
Gravitational field strength,
10The mass will be:
→ [tex]Weight = Mass\times Gravitational \ field \ strength[/tex]
or,
→ [tex]Mass = \frac{Weight}{Gravitational \ field \ strength}[/tex]
By putting the values, we get
→ [tex]= \frac{300}{10}[/tex]
→ [tex]= 30 \ kg[/tex]
Thus the above solution is right.
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PLSSSS HELPPP What effects do mutations have? Check all that apply.
A) could change protein shape
B)never change protein shape
C)might be neutral
D)always change the way a trait is observed
E)might be harmful
F)might be beneficial
Answer:
E, F, A, C
Explanation:
They cannot change the way a trait is observed
Mutations could change protein shape(A), could cause genetic disorders and harm you(E), could actually be beneficial and cause adaptations to your environment(F), or they could be neutral in which no changes are observantly notable(C).
Hope this helps
The force of 5N south acts concurrently with force of 5N 30 degrees South of East
A. Draw the diagram - TAIL to TAIL
B. Label both vectors (see page one for example)
C. Draw and LABEL the resultant and equilibrant
D.Find the magnitude and direction of the resultant and equilibrant
(scale: 1cm = 1N)
Answer:
The magnitude and direction of the resultant is 8.66 N and [tex]60^{\circ}[/tex] south of East.
The magnitude and direction the equilibrant is 8.66 N and [tex]60^{\circ}[/tex] North of West respectively.
Explanation:
Let
[tex]P=5\ \text{N}\ \text{south}[/tex]
[tex]Q=5\ \text{N}\ 30^{\circ}\ \text{south of east}[/tex]
[tex]\theta[/tex] = Angle between P and Q = [tex]60^{\circ}[/tex]
Magnitude of resultant
[tex]R=\sqrt{P^2+Q^2+2PQ\cos\theta}\\\Rightarrow R=\sqrt{5^2+5^2+2\times 5\times 5\cos60^{\circ}}\\\Rightarrow R=8.66\ \text{N}[/tex]
Direction is given by
[tex]\theta=\tan^{-1}\dfrac{Q\sin\theta}{P+Q\sin\theta}\\\Rightarrow \theta=\tan^{-1}\dfrac{5\sin60^{\circ}}{5+5\sin60^{\circ}}\\\Rightarrow \theta=30^{\circ}[/tex]
The magnitude and direction of the resultant is 8.66 N and [tex]30^{\circ}+30^{\circ}=60^{\circ}[/tex] south of East.
The magnitude and direction the equilibrant is 8.66 N and [tex]60^{\circ}[/tex] North of West.
Use the following v-t graph to answer the next questions
5
B
Velocity )
neters/second(s)
4
A
3
2
1
Time (1)
0
1
2
3
4
5
2
8
10
11
12
13
1015
16
second(s)
.1
D
-2
C С
3
5
Answer:
mag aral ka bubu
Explanation:
ang tanga mu hahahahhaha luko nandyan lang naman yan hahahhahahahahahahhahahahahahahahhahahahahahaahahahahahahahhahahahahahahahahahahahahaahhahahaahahhaahha09561782
Use words from the box to complete the sentences below.
-direction
-energy
-mass
-size
Vectors have size and ___
Scalars have only ____
Answer:
direction
size
Explanation:
Vectors are physical quantities with both magnitude or size and direction.
Scalars are physical quantities with only size but not direction.
Examples of vectors are velocity, displacement and force. Examples of scalar are distance and speedWhen describing a vector, on must specify its magnitude and direction.
Only the size of scalar quantities are needed to describe them.
1
Assertion (A): Potential energy of a body depends upon height of the body from the surface of earth.
Reason (R): Potential energy and height of the body from ground are directly proportional to each
other (h«<r)
a) Both A and R are true and R is the correct explanation of A
[ ]
b) Both A and R true and R is not the correct explanation of A
c) A is true but Ris false
d) A is false but R is true
beha
Answer:
a
Explanation:
it increases with increasing height