We can model the human back as a pivoted rod?

Answer:

[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]

Explanation:

From the information given;

The surface area of a sphere = [tex]4 \pi r ^2[/tex]

If the sphere is from the collection of spherical shells of infinitesimal thickness = dr

Then,

the volume of the  thickness and the sphere is;

V = [tex]4 \pi r ^2 \ dr[/tex]

Using Gauss Law

[tex]V(r) = \dfrac{k_cq(r)}{r}[/tex]

here,

q(r) =charge built up contained in radius r

since we are talking about collections of spherical shells, to work required for the next spherical shell r +dr is

[tex]-dW= dU = V(r) dq = \dfrac{k_c \ q(r)}{r} \ dq[/tex]

where;

[tex]q (r) = \dfrac{4}{3} \pi r^3 \rho[/tex]

dq which is the charge contained in the  next shell of charge

here dq = volume of the shell multiply by the density

[tex]dq = 4 \pi r^2 \ dr \ \rho[/tex]

equating it all together

[tex]dU = \dfrac{k_c \frac{4}{3} \pi r^3 \rho}{r} 4 \pi r^2 \ dr \ \rho = \dfrac{16 \pi^2 \ k_c \ \rho^2}{3} \ r^4 \ dr[/tex]

Integration the work required from the initial radius r to the final radius R, we get;

[tex]U = \int^R_0 \ dU[/tex]

[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} r^4 \ dr[/tex]

[tex]U = \int^R_0 \dfrac{16 \pi^2 \ k_c \rho^2}{3} [\dfrac{r^5}{5}]^R_0[/tex]

[tex]U = \dfrac{16 \pi^2 k_c \rho^2}{15} \ R^5[/tex]

Recall that:

the total charge on a sphere, i.e [tex]Q_{total} = \dfrac{4}{3} \pi R^3 \rho[/tex]

Then :

[tex]\mathbf{U = \dfrac{3 k_c Q^2_{total}}{5R}}[/tex]

Answer:

The dimensionality of B is length per cubic time.

Explanation:

Units for displacement and time are length [tex][L][/tex] and time [tex][T][/tex], respectively. Then, formula can be tested for dimensional analysis as follows:

[tex][L] = B\cdot [T]^{3}[/tex]

Now, let is clear [tex]B[/tex] to determine its units:

[tex]B = \frac{[L]}{[T]^{3}}[/tex]

The dimensionality of B is length per cubic time.

Answer:

3.68 m/s

Explanation:

Full answer in the attached picture

Answer:

The force is [tex]3.2\times10^{-20}\ N[/tex]

Explanation:

Given that,

A long, straight wire carries a current.

Suppose, a long, straight wire carries a current 0.86 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.50 cm from the wire and traveling at speed of [tex]6\times10^{4}\ m/s[/tex] directly toward the wire. What are the magnitude of the force that the magnetic field of the current exerts on the electron?

We need to calculate the magnetic field

Using formula of magnetic field

[tex]B=\dfrac{\mu_{0}I}{4\pi r}[/tex]

Where, I = current

r = distance

Put the value into the formula

[tex]B=\dfrac{4\pi\times10^{-7}\times0.86}{2\pi\times4.5\times10^{-2}}[/tex]

[tex]B=0.0000038\ T[/tex]

[tex]B=3.8\times10^{-6}\ T[/tex]

We need to calculate the force

Using formula of force

[tex]F=qvB\sin\theta[/tex]

Here, [tex]\theta=90^{\circ}[/tex]

Where, q = charge of electron

v = velocity of electron

B = magnetic field

Put the value into the formula

[tex]F=1.6\times10^{-19}\times6\times10^{4}\times3.8\times10^{-6}\sin90[/tex]

[tex]F= 3.2\times10^{-20}\ N[/tex]

Hence, The force is [tex]3.2\times10^{-20}\ N[/tex]

Answer:

Explanation:

Momentum is defined as a physical quantity that takes into cognisance the product of mass of a body and its velocity. It's unit is kgm/s

Momentum = mv

Angular Momentum is defined as the quantity of rotation of a body that measures the product of its moment of inertia with respect to its angular velocity. Because it deals with rotation is what differs it from ordinary momentum. It's unit is kgm²/s

Angular Momentum = mvr

Kinetic Energy is defined as the energy a body posses as a result of it being in motion. The unit of Kinetic Energy is J

Kinetic Energy = ½mv²

The dimensions of these quantities are

Momentum => MLT^−1

Angular Momentum => ML²T^−1

Kinetic Energy => ML²T^-2

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Answer:

 E = k λ₀ / x₀, the field is in thenegative direction of the x axis (-x)

Explanation:

In this problem the electric field of a line of charge is requested, the expression for the electric field is

          E = k ∫ dq / r²

where k is the Coulomb constant that you are worth 9 10⁹ N m²/C², that the charge and r the distance to the point of interest, in this case it is the origin (x = 0)

let's use the definite linear density

        λ₀ = dq / dx

        dq = λ₀ dx

we replace and integrate

       E = k λ₀ ∫ dx / x²

       E = k λ₀ ( -1 / x)

we evaluate the integral from the lower limit of load x = x₀ to the upper limit x = ∞

       E = - k λ₀ (1 /∞ - 1 / x₀)

       E = k λ₀ / x₀

as the field is positive the direction is away from the charges, so it is in the negative direction of the x axis (-x)

In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

tbh google

Your question has been heard loud and clear.

Energy propogates through different media in different ways.

Through a medium like water , energy is carried(propogated) from particle to particle in water waves.

Thank you.

Answer:

K = 202.5 J

Explanation:

Given that,

Mass of pie is 5 kg

Velocity of pie is 9 m/s

We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :

[tex]K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5\times (9)^2\\\\K=202.5\ J[/tex]

So, the kinetic energy of the pie is 202.5 J.

Answer:

Explanation:

Generally, roads are meant to have very rough surfaces to allow for friction between car tyres hence the motion of vehicles.

What is a paved surface?

Paved roads are roads that are covered with a firm surface suitable for travel, like paving stones or concrete or asphalts.

Another good example of a paved road is a  small paved courtyard, covered with a hard layer of concrete/cement.

The other two examples sited in this problem are glossy materials with very low surface friction, that is their surfaces are very smooth.

Answer:

stream B.

Explanation:

Stream B has higher mass flow rate of water due to higher temperature i.e. 25◦C as compared to stream A which has a lower temperature i. e. 15◦C because temperature affect the viscosity of liquid. Higher temperature make liquid or water thinner which means lower viscosity. This thinning of liquid make easier the flow of water in the pipes or other medium with the increase in temperature.

Answer:

abcd

Explanation:

Answer:

where is the answer pls send me answer on my what.s up number

Explanation:

Answer:

b) directional

Explanation:

The prediction that alcohol slows reaction time is Directional . This is because for alcohol to be known as one which slows reaction time means there have been various hypothesis conducted which supports this.

In this case, formulation of a null hypothesis is usually necessary which means that alcohol does not slow reaction time and another alternative hypothesis that suggests that alcohol slows reaction time.

Answer:

2.15 mV

Explanation:

The complete question is

You have a coil of wire with 17 turns each of 1.5 cm radius. You place the plane of the coil perpendicular to a 0.50-TB?  field produced by the poles of an electromagnet.

Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 1.9 s .

Radius of the coil = 1.5 cm = 0.015 m

number of turns = 17

Initial magnetic field [tex]B_{1}[/tex] = 0.50 T

Final magnetic field [tex]B_{2}[/tex] = 0 T

time taken dt = 1.9 s

Area pf the coil = π[tex]r^{2}[/tex] = 3.142 x [tex]0.015^{2}[/tex] = 7.1 x 10^-4 m^2

magnetic flux = BA

initial flux = [tex]B_{1}[/tex]A = 0.5 x 7.1 x 10^-4 = 3.55 x 10^-4 Wb

Final flux = [tex]B_{2}[/tex]A = 0 x 7.1 x 10^-4 = 0 Wb

change in flux dФ = 3.55 x 10^-4  -  0 = 3.55 x 10^-4 Wb

Induced EMF E = NdФ/dt = (17 x 3.55 x 10^-4)/2.8 = 2.15 x 10^-3 V

==> 2.15 mV

Answer:

Explanation:

This is due to an increase in hydrostatic pressure, the force per unit area exerted by a liquid on an object. The deeper you go under the sea, the greater the pressure of the water pushing down on you. For every 33 feet (10.06 meters) you go down, the pressure increases by one atmosphere .

Answer:

d. beach is the correct answer

Beach is the most likely site for deposits in this photograph. So, the correct option is (D).

A beach is defined as a narrow strip of land separating a body of water from inland areas usually made up of small grains of sand, rocks and minerals that have been eroded by frequent pounding by wind and waves. become The beach has both sandy and rocky features.

Beaches provide protection to residents living near the sea by acting as a buffer against high winds and powerful storms or waves of rough seas which also play an important role in the economy. This is the most likely site for deposits in this photograph,

Thus, Beach is the most likely site for deposits in this photograph. So, the correct option is (D).

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Answer:

2 m/s²

Explanation:

Given that

mass of the car, m = 1200 kg

Initial velocity of the car, u = 0 m/s

Distance covered, s = 450 m

Time taken, t = 15 s

Final velocity of the car, v = s/t = 30 m/s

there are four equations of motion. In this question, we will be attempting to solve it using the first equation of motion to solve this question

v = u + at, where

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v = u + at

30 = 0 + 15a

30 = 15a

a = 30/15

a = 2 m/s

Answer:

0.995*c= 2.98*10^8m/s

Explanation:

Using

E= mc²

10.5 mc² = mc²/√1-v²/c²

So

1-v²/c²=( 1/10.5)²

V= √1-0.009c

V= 0.995 x 3E8m/s

= 2.98*10^8m/s

Answer:

Explanation:

⁶₃Li will have 3 protons and 3 neutrons .

mass of proton in amu = 1.00727 amu

mass of neutron in amu = 1.00866 amu

mass of lithium nucleus in amu = 6.01512 amu

mass defect = 3 (  1.00727  + 1.00866 ) - 6.01512 amu

= .03267 amu

Binding energy = mass defect in amu x 931 Mev

= 30.41 MeV

binding energy per nucleon

no of nucleon = 3 + 3 = 6

binding energy per nucleon = 30.41 / 6 Mev

= 5.068 MeV .

The binding energy of  ⁶₃Li nucleus in MeV per nucleon is 5.26  MeV per nucleon.

We can see that Li has three protons and three neutrons. The total mass of the Li nucleus is obtained from;

3(1.007277) + 3(1.008665) = 3.023 + 3.026 = 6.049 amu

Actual mass of Li - 6 =  6.0151 amu

Mass defect = 6.049 amu - 6.0151 amu = 0.0339 amu

We can obtain the binding energy in MeV as follows;

Binding energy = 0.0339 amu × 931 = 31.56 MeV

The binding energy per nucleon in MeV per nucleon =  31.56 MeV/6

= 5.26  MeV per nucleon

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Answer:

An electron configuration is used to name the sublevels in which electrons are found within an atom

Explanation:

An electron configuration is used to name the sublevels in which electrons are found within an atom for example for the atom carbon has 6electrons so its configuration is 1s²2s²2p²

With the 1s 2s and 2p showing the various energy sublevels

Concerning the concepts and fundamentals of the atomic model, an electron configuration is used to name the sublevels in which electrons are found within an atom. Hence, option (C) is correct.

The arrangement of electrons in specific energy levels around the atomic nucleus of an atom is known as the electron configuration of an atom.

As per the atomic shell model, "The electrons occupy the various energy levels from the first shell nearest to the nucleus, upto the farthest shell from the nucleus.

Consequently, an electron configuration is used to name the sublevels in which electrons are found within an atom. For example for the atom carbon has 6 electrons so its configuration is 1s²2s²2p². With the 1s 2s and 2p showing the various energy sublevels.

Thus, we can conclude that an electron configuration is used to name the sublevels in which electrons are found within an atom.

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Answer:

The current reduces to ¼ of the original current because a smaller voltage indicates that there is less energy to move the charge. As voltage decreases in a circuit, current also decreases.  

Explanation:

Answer:

the speed at which a moving clock lose 4,5ns in 1.0 day is 98.58 m/s

Explanation:

Let's first find the relation for the time dilation by using the formula:

[tex]\Delta t' = \Delta t \gamma[/tex]

Making [tex]\gamma[/tex] the subject of the formula, we have:

[tex]\gamma= \dfrac{\Delta t'}{\Delta t}[/tex]

Number of day(s) = 1

1 day in seconds = 24 × 60 × 60

= 84600 seconds

[tex]\gamma= \dfrac{86400 \ s}{86400 \ s - 4.5 \ ns}[/tex]

[tex]\sqrt{1- \dfrac{v^2}{c^2} }= \dfrac{86400 \ s - 4.5 \ ns}{86400 \ s}[/tex]

[tex]\sqrt{1- \dfrac{v^2}{c^2} }= 1 - 5.4 \times 10^{-14}[/tex]

From the above equation, if we apply binomial expansion to it, we have the following,

[tex]\sqrt{1- \dfrac{v^2}{c^2} }=(1-\dfrac{v^2}{c^2})^{\frac{1}{2}}[/tex]

⇒[tex]1 -\dfrac{1}{2}(\dfrac{v^2}{c^2})[/tex]

So;

[tex]1 -\dfrac{1}{2}(\dfrac{v^2}{c^2}) = 1 - 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{1}{2}(\dfrac{v^2}{c^2}) = 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{v^2}{c^2} = 2 \times 5.4 \times 10^{-14}[/tex]

[tex]\dfrac{v^2}{c^2} = 1.08 \times 10^{-13}[/tex]

[tex]v^2 = 1.08 \times 10^{-13} \times c^2[/tex]

where ;

[tex]c = 3 \times 10^8 \ m/s[/tex]

[tex]v^2 = 1.08 \times 10^{-13} \times (3 \times 10^8 \ m/s)^2[/tex]

[tex]v = \sqrt{ 1.08 \times 10^{-13} \times (3 \times 10^8 \ m/s)^2}[/tex]

[tex]v = \sqrt{ 1.08 \times 10^{-13} } \times (3 \times 10^8 \ m/s)[/tex]

[tex]v =3.286 \times 10^{-7} \times (3 \times 10^8 \ m/s)[/tex]

[tex]\mathbf{v =98.58 \ m/s}[/tex]

Therefore, the speed at which a moving clock lose 4,5ns in 1.0 day is 98.58 m/s

Answer:

-19.9m/s²

Explanation:

Given that

vi = 14cm/s

xi = 2.94 cm

xf=-5.00 cm

t= 1.85s

So

Using xf-xi= vi t + 1/2at²

Which is = -5-2.94= 14*1.85+1/2a1.85²

= -7.94= 25.9+1.7a

-33.9= 1.7a

a= - 19.9m/s²

Answer:

1) p₀ = 45000 N / s ,   p₀ '= 1800 , b)  I = -45000 N s ,  I = 1800 Ns

Explanation:

Impulse equals the change in momentum

         I = Δp

1) the initial moment of the car

         p₀ = M v

          p₀ = 1500 30

          p₀ = 45000 N / s

the change at the moment is

          Δp = 45000

because the end the car is stopped

moment of the person

          P₀ ’= m v

         p₀ '= 60 30

          p₀ '= 1800

          D₀ '= 1800

2) of the momentum change impulse ratio

        car

              I =  Δp

              I = -45000 N s

        person

              I = Δpo '

              I = 1800 Ns

3) the object that give the momentum to stop the wall motoring

The person is stopped by the impulse given by the car

a) This area is the one that absorbs most of the vehicle impulse

be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease

c) The air bag helps reduction in the speed of the person relatively quickly.

Answer:

1.45

Explanation:

Answer:

Explanation:

Force = mass × acceleration

F = ma

Answer:

The tension is  [tex]T = 4326.7 \ N[/tex]

Explanation:

From the question we are told that

   The  total mass is  [tex]m = 200 \ kg[/tex]

    The  radius is [tex]r = 5 \ m[/tex]

     The  density of air is  [tex]\rho_a = 1.225 \ kg/m^3[/tex]

Generally the upward  force acting on the balloon is mathematically represented as

        [tex]F_N = T + mg[/tex]

=>     [tex](\rho_a * V * g ) = T + mg[/tex]

=>   [tex]T = (\rho_a * V * g ) - mg[/tex]

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      [tex]V = \frac{4}{3} * \pi r^3[/tex]

=>   [tex]V = \frac{4}{3} * 3.142 *(5)^3[/tex]

=>   [tex]V = 523.67\ m^3[/tex]

So

    [tex]T = (1.225 * 523.67* 9.8 ) - 200 * 9.8[/tex]

   [tex]T = 4326.7 \ N[/tex]

This question is incomplete

Complete Question

Three equal point charges are held in place as shown in the figure below

If F1 is the force on q due to Q1 and F2 is the force on q due to Q2, how do F1 and F2 compare? Assume that n=2.

A) F1=2F2

B) F1=3F2

C) F1=4F2

D) F1=9F2

Answer:

D) F1=9F2

Explanation:

We are told in the question that there are three equal point charges.

q, Q1, Q2 ,

q = Q1 = Q2

From the diagram we see the distance between the points d

q to Q1 = d

Q1 to Q2 = nd

Assuming n = 2

= 2 × d = 2d

Sum of the two distances = d + 2d = 3d

F1 is the force on q due to Q1 and

F2 is the force on q due to Q2,

Since we have 3 equal point charges and a total sum of distance which is 3d

Hence,

F1 = 9F2

Answer:

high density can withstand high acceleration and applied forces

Heavy metals are toxic to humans,

the clay is quite abundant and in general it is not toxic

Explanation:

The selection of materials for the construction of rockets takes into account many aspects, the technical resistance to the demands of space travel, but also the abundance of the material. Heavy metals have two very serious problems. The first one, some of them are a little scarce in nature, but the most serious problem is that almost all of them are toxic to humans, for example: lead and mercury.

On the other hand, the clay is quite abundant and in general it is not toxic to living beings.

If we use Newton's second law

          F = m a

let's use the concept of density

         rho = m / V

        m = rho V

let's substitute

         F = rho V a

From this expression we see that a material with high density can withstand high acceleration and applied forces, such as those existing in spacecraft clearance and re-entry to Earth.

Unfortunately with this law there is no criterion to select a material unless its density is high, in addition to this criterion low toxicity criteria for human beings are used,

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

[tex]v = u + at[/tex]

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.