Answer:Since pressure = force/area, the same force on a smaller area means more pressure. When you are walking on sand, the force being applied by your body is spread out over the entire surface of your foot. ... So, more pressure applied on a given area of your foot causes more pain.
Explanation:
Good Question
The peripheral speed of the tooth of a 10-in.-diameter circular saw blade is 230 ft/s when the power to the saw is turned off. The speed of the tooth decreases at a constant rate, and the blade comes to rest in 17 s. Determine the time at which the total acceleration of the tooth is 130 ft/s2.
Answer:
The time is [tex]t_r =21.58 \ s[/tex]
Explanation:
From the question we are told that
The diameter of the circular saw is [tex]d = 10 \ in = \frac{10}{12} = 0.833 \ feet[/tex]
The peripheral speed is [tex]u = 230 \ ft/s[/tex]
The time taken for the blade to come to rest is t = 17 s
The total acceleration of the tooth considered is [tex]a = 130 \ ft/s^2[/tex]
Generally the radius of the blade is mathematically represented as
[tex]r = \frac{0.833}{2}= 0. 4165 \ feet[/tex]
Generally the tangential acceleration of the blade is mathematically represented as
[tex]a__{t}} = \frac{v - u}{t}[/tex]
Here v is the final velocity of the tooth of the blade which is zero since the blade came to rest
so
[tex]a__{t}} = \frac{0 - 230}{ 17}[/tex]
=> [tex]a__{t}} = - 13.53 \ ft/s^2[/tex]
Generally the total acceleration of the tooth of the blade is mathematically represented as
[tex]a = \sqrt{a_t^2 + a_r^2}[/tex]
Here [tex]a_r[/tex] is the radial acceleration , now making [tex]a_r[/tex] the subject of the formula we have that
[tex]130= \sqrt{13.56 ^2 + a_r^2}[/tex]
=> [tex]a_r = \sqrt{130^2 -(- 13.56)^2}[/tex]
=> [tex]a_r = 129.3 \ m/s^2[/tex]
Generally radial acceleration is mathematically represented as
[tex]a_r = \frac{v_r^2}{r}[/tex]
Here [tex]v_r[/tex] is the velocity at which the total acceleration is 130 ft/s2.
=> [tex]v_r = \sqrt{a_r * r }[/tex]
=> [tex]v_r = \sqrt{129.3 * 0.4165 }[/tex]
=> [tex]v_r = 7.34 \ m/s[/tex]
Generally the time at which the total acceleration is 130 ft/s2. is mathematically represented as
[tex]t_r = \frac{7.34 - 300}{a_t}[/tex]
=> [tex]t_r = \frac{7.34 - 300}{-13.56}[/tex]
=> [tex]t_r =21.58 \ s[/tex]
At which temperature are the particles in a pencil moving faster: 20°C or 50°C?
Answer:
movement generates energy=heat so 50c should be it
a bowling ball hits two standing bowling pins at the same time. which of the following is true. assume that all collisions are elastic
Answer:
b?
Explanation:
A student was traveling to see his grandmother who lives 15 miles north oh his home he started from rest and maintained a pace of 4 m/s before stopping at his grandmother's house for lunch which of the following best describes the speed, velocity and acceleration of the student's walk?
Explanation:
Given parameters:
Distance = 15miles north = 24140.2m
Initial velocity = 0m/s
Final velocity = 4m/s
Unknown:
Speed, velocity and acceleration = ?
Solution:
The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.
Speed = [tex]\frac{distance }{time}[/tex]
The speed of the student is 4m/s
Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;
Velocity = [tex]\frac{displacement}{time}[/tex]
The velocity of the student is 4m/s due north
Acceleration is the change in velocity with time;
To find the acceleration, we use
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
4² = 0² + 2x a x 24140.2
a = [tex]\frac{16}{2 x 24140.2}[/tex] = 0.00033m/s²
Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?
Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.
Answer:
C) radio → infrared → ultraviolet → gamma
Explanation:
It Increases left to right therefore it decreases right to left
How would the photographer use the polarizing filter to find out the direction of polarization of the light coming from the blue sky?
Answer:
by rotating the filter
Explanation:
Rayleigh's scattering is given by the process of the scattering of light by molecules. This is very important physical phenomenon. Polarization is also an effect of light scattering.
A photographer wishes to capture photos of some cloud formation by using the polarizing filter. So the photographer will have to rotate the polarizing filter until the intensity of the light becomes maximum such that the light polarization is acts along the axis of the filter.
What is precipitation and how does it affect weather? (20 points)
Answer:
precipitation is any frozen or liquid that forms in the atmosphere and falls back to Earth in the form of rain, hail, snow, or sleet.
Explanation:
precipitation can give an excessive amount of rainfall which will result in freezing crops andcold temperatures
Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.
Answer:
v₃ = 1.625 [m/s]
Explanation:
To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.
Since the collision is inelastic, the two bodies are joined after the collision.
P = m*v [kg*m/s]
m = mass [kg]
v = velocity [m/s]
where:
P = lineal momentum [kg*m/s]
Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.
Pbefore = Pafter
(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃
where:
m₁ = mass one = 5 [kg]
v₁ = velocity of the mass one = 2 [m/s]
m₂ = mass two = 3 [kg]
v₂ = velocity of the mass two = 1 [m/s]
v₃ = velocity of the combined masses after the collision [m/s]
Now replacing we have:
(5*2) + (3*1) = (5 + 3)*v₃
10 + 3 = 8*v₃
v₃ = 13/8
v₃ = 1.625 [m/s]
Maggots feed on dead and decaying organisms for energy. What are maggots?
autotrophs
producers
decomposers
heterotrophs
Answer:
Explanation:
Decomposers is the correct answer
Answer:
Decomposers is the right answer
Explanation:
Maggots are decomposers because they eat the dead bodys for energy
I don't know if the thing I wrote it truse so ya
NEED HELP ASAP PLEASE
Answer:
It is Nice A since it's temp increases slower
Explanation:
hope this helped
When the wooden block is placed in the water and allowed to float to the top, what percentage of it is submerged
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, what is described in the question is known as upthrust. Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.
The percentage of the submerged wooden block can be calculated as
length (in height) of the wood block submerged in water/total length (in height) of the wood × 100
yes or no
1.the ink of a pen that is used for writing is not a colloid
2.the blood consists of solid particles and plasma are considered a kind of colloid.
Answer:
1. No, it is a colloid
2. Yes
Explanation:
The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.
The subject is science just to let you know.
Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
Nine, Brazil, Venezuela
Explanation:
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.
Answer:
4.2s
Explanation:
Given parameters:
Power = 2190W
Mass of box = 1.47 x 10⁴g
distance = 6.34 x 10⁴mm
Unknown:
Time = ?
Solution:
Power is the rate at which work is done;
Mathematically;
Power = [tex]\frac{work done}{time}[/tex]
Time = [tex]\frac{work done}{power}[/tex]
Work done = weight x height
convert mass to kg;
100g = 1kg;
1.47 x 10⁴g = 14.7kg
convert the height to m;
1000mm = 1m
6.34 x 10⁴mm gives 63.4m
Work done = 14.7 x 9.8 x 63.4 = 9133.4J
Time taken = [tex]\frac{9133.4}{2190}[/tex] = 4.2s
what is a factor that scientists use to classify orders of soil?
PLEASE HELP QUICKLY THANKS
Answer: the answer is d
Explanation:
Calculate the velocity of an object moved around a circle with a radius of 1.65 m and an
acceleration of 3.5 m/s2.
Answer:
2.4m
Explanation:
Given parameters:
Radius of circle = 1.65m
Acceleration = 3.5m/s²
Unknown:
Velocity of the object = ?
Solution:
To solve this problem, we have to apply the formula of centripetal acceleration;
Centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
v is the velocity
r is the radius
v² = centripetal acceleration x radius
Insert parameters and solve;
v² = 3.5 x 1.65
v = √5.775 = 2.4m
The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Given the data in the question;
Radius; [tex]r = 1.65m[/tex]Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]Velocity; [tex]v = \ ?[/tex]
From the centripetal force equation, we use the expression for centripetal acceleration:
[tex]a_c = \frac{v^2}{r}[/tex]
Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.
We substitute our given values into the equation
[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]
Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.
Learn more: https://brainly.com/question/17689540
Which of the following is made up of vibrating electric and magnetic fields
traveling together?
A. An electromagnetic wave
B. A generator
C. An induced current
D. An electromagnet
Answer:
A. An electromagnetic wave
Explanation:
A P E X
A 1,200 kg roller coaster car starts rolling up a slope at a speed of 15 m/s. What is the highest point it could reach?
Answer:
11.48 m
Explanation:
The following data were obtained from the question:
Mass (m) of the roller coaster = 1200 Kg
Initial velocity (u) = 15 m/s.
Final velocity (v) = 0 m/s (at highest point)
Acceleration due to gravity (g) = 9.8 m/s²
Highest point (h) =?
The highest point reached by the roller coaster can be obtained as illustrated below:
h = u²/2g
h = 15² / 2 × 9.8
h = 225/19.6
h = 11.48 m
Therefore, the highest point reached by the roller-coaster is 11.48 m
for a solar eclipse to occur which of the following alignments must be necessary
Which chemicals are major contributors to ozone layer destruction? Select two answer choices.
Answer:
what are the answers to select? or do you just say them
Explanation:
???
Answer:
c and d
Explanation:
QUESTION 13
Marci would describe almost a perfect person whenever her friends would ask her who she thought was
her ideal life partner. This "perfect" person would be ain)
O a prototype
b.reinforcer
oc. anagram
d. heuristic
Explain how you would determine how much air there is between a vector addition in the displacement of the actual trip taken. Why aren’t vectors true straight-line paths in the real world? Would you expect a vector addition to be larger or smaller than the actual trip taken? Why?
Answer:
This is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. This enables more atoms in the metal to become aligned hence becoming more magnetized.
or...
A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.
Hope this helps☺️
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.
Answer:
t = 4.17 [s]
Explanation:
We know that work is defined as the product of force by distance.
W = F*d
where:
F = force [N] (units of Newtons)
d = distance = 6.34 x 10⁴ [mm] = 63.4 [m]
In order to find the force, we must determine the weight of the box, the weight can be determined by means of the product of mass by gravitational acceleration.
w = m*g
where:
m = mass = 1.47 x 10⁴ [g] = 14.7 [kg]
g = gravity acceleration = 9.81 [m/s²]
w = 14.7*9.81
w = 144.2 [N]
Therefore the work can be calculated.
W = w*d
W = 144.2*63.4
W = 9142.72 [J] (units of Joules)
Power is now defined in physics as the relationship of work at a given time
P = W/t
where:
P = power = 2190 [W]
t = time [s]
Now clearing t, we have.
t = W/P
t = 9142.72/2190
t = 4.17 [s]
If a car traveled 50 meters in 2 seconds, what will the velocity be? (Write the answer with a number, on decimal if needed, then a space and the units, for example 5.7 m/s)
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{50}{2} \\ [/tex]
We have the final answer as
25 m/sHope this helps you
Explain the procedures used and data recorded to identify a crystalline mineral based on its properties.
Answer:
By examining its external shape, color, hardness, etc.
Explanation:
If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0 g's.
Answer:
The radius is [tex]r =1705.44 \ m[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 1140 \ km /h = \frac{1140 * 1000}{3600} = 316.67 \ m/s[/tex]
The centripetal acceleration is [tex]a = 6 g's = 6 * 9.8 = 58.8 \ m/s^2[/tex]
Generally the centripetal force acting on the jet is mathematically represented as
[tex]F_c = \frac{m * v^2 }{r}[/tex]
Generally this centripetal force is equal to the net force acting which according to Newton's third law is mathematically represented as
[tex]F = m * a[/tex]
So
[tex]\frac{m * v^2 }{r} = ma[/tex]
=> [tex]\frac{ v^2 }{r} = a[/tex]
=> [tex]r = \frac{v^2}{a}[/tex]
=> [tex]r = \frac{316.67^2}{58.8}[/tex]
=> [tex]r =1705.44 \ m[/tex]
What is the magnitude of the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 3.80 s
Answer:
The correct solution will be "12.48 in/s²".
Explanation:
The given values are:
Angular speed
= 79.0 rev/min
Time
= 3.80 seconds
Now,
⇒ [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]
[tex]=\frac{8.2}{3.8}[/tex]
[tex]=2.1 \ rad/s^2[/tex]
Tangential acceleration will be:
= [tex]Angular acc.\times radius[/tex]
= [tex]2.1\times 6.5\times 0.0254[/tex]
= [tex]0.3467 \ m/s^2[/tex]
= [tex]12.48 \ in/s^2[/tex]
The force of gravity acting on you will increase if you
A. burrow deep inside the planet.
B. stand on a planet with a radius that is shrinking
C. both of these
D.none of these
Answer:
C.
Explanation:
the closer you get to the centre of an object the greater its gravitational pull- A is correct
If the radius increases the gravity decreases and rise versa - B is correct
the answer is C
The force of gravity acting on you will increase if you stand on a planet with a radius that is shrinking. So, option (B) is orrect.
What is force?
Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.
The force of gravity acting on an object due to a planet is given by: F = GMm/R².
Where, G is universal gravitational constant . M and m is masses of the planet and the object respectively and R is distance between them.
Hence, when you stand on a planet with a radius that is shrinking; distance between you and planet decreases. So, the force of gravity acting on you will increase. So, option (B) is correct.
But in the case of burrow deep inside the planet: gravitational force due to outer shell becomes zero. So, effective gravitational force decreases.
Learn more about force here:
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