Using the image below, identify the numbered parts of the wave

Answer:

Time needed for one revolution is 0.38 s

Explanation:

The formula for the frequency of rotation of a spaceship, to create the desired artificial gravity, is as follows:

f = (1/2π)√(a/r)

where,

f = frequency of rotation = ?

a = artificial gravity required = 0.5 g

g = acceleration due to gravity on surface of Earth = 9.8 m/s²

r = radius of ship = 35 mm/2 = 17.5 mm = 17.5 x 10⁻³ m

Therefore,

f = (1/2π)√[(0.5)(9.8 m/s₂)/(17.5 x 10⁻³ m)]

f = 2.66 Hz

Now, for the time required for one revolution, is given as:

Time Period = T = 1/f

T = 1/2.66 Hz

T = 0.38 s

The time required for one revolution to simulate the desired gravity is 0.38 s.

The frequency can be calculate by the formula

[tex]\bold {f = (\dfrac {1}{2\pi})\sqrt{ar}}[/tex]

where,

f - frequency of rotation = ?

a-  artificial gravity required = 0.5 g

g -  gravitational acceleration on surface of Earth = 9.8 m/s²

r -  radius of ship = 35 mm/2 = 17.5 mm = 17.5 x 10⁻³ m

Put the value in the equation,

[tex]\bold {f = \dfrac {1}{2\pi}\squrt {(0.5)(9.8\ m/s^2)}{(17.5 x 10^{-3} m)}}\\\\\bold {f = 2.66\ Hz}[/tex]

the time required for one revolution can be calculated as

[tex]\bold {T =\dfrac 1f}\\\\\bold {T = \dfrac 1{2.66}\ Hz}\\\\\bold {T = 0.38\ s}[/tex]

Therefore, the time required for one revolution to simulate the desired gravity is 0.38 s.

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Answer:

d. may be either greater, smaller, or equal to that observed inside the bus.

Explanation:

Answer:

The excess charge is [tex]Q = 3.5 *10^{-7} \ C[/tex]

Explanation:

From the question we are told that

      The diameter is [tex]d = 45 \ cm = 0.45 \ m[/tex]

       The potential of the surface is [tex]V = 14 \ kV = 14 *10^{3} \ V[/tex]

The radius of the sphere is  

           [tex]r = \frac{d}{2}[/tex]

substituting values

          [tex]r = \frac{0.45}{2}[/tex]

         [tex]r = 0.225 \ m[/tex]

The potential on the surface is mathematically represented as  

          [tex]V = \frac{k * Q }{r }[/tex]

Where k is coulomb's constant with value  [tex]k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

  given from the question that there is no other charge the Q is the excess charge  

Thus  

        [tex]Q = \frac{V* r}{ k}[/tex]

substituting values

        [tex]Q = \frac{14 *10^{3} 0.225}{ 9*10^9}[/tex]

        [tex]Q = 3.5 *10^{-7} \ C[/tex]

Answer:

The force is  [tex]F = 784 \ N[/tex]

Explanation:

From the question we are told that

      The mass of the man is  [tex]m = 70 \ kg[/tex]

      The mass of the beam is [tex]m_b = 10 \ kg[/tex]

Now from the question we can deduce that when this beam start to tip that both the force exerted by the weight of the man and that of the beam is been supported by the  right support so

 The force exerted on the right support is mathematically evaluated as

           [tex]F = (m + m_b) * g[/tex]

substituting values

         [tex]F = (70 + 10 ) * 9.8[/tex]

         [tex]F = 784 \ N[/tex]

The force exerted on the beam by the right support is 784 Newton.

Given the data in the question;

Force exerted on the beam by the right support; [tex]F = W = \ ?[/tex]

When the beam just starts to tip, the right support holds up the combined mass of the man and the beam.

Hence;

[tex]M_{net} = m_m + m_b\\\\M_{net} = 70kg + 10kg\\\\M_{net} = 80kg[/tex]

Now, To determine the force exerted on the beam by the right support, we use the general formula for weight or equation of force of gravity which is expressed as:

[tex]F = W = m * g[/tex]

Where m is mass and g represents the acceleration due to gravity( [tex]9.8m/s^2[/tex] )

We substitute our values into the equation

[tex]F = 80kg * 9.8m/s^2\\\\F = 784kg.m/s^2\\\\F = 784N[/tex]

Therefore, the force exerted on the beam by the right support is 784 Newton.

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Explanation:

It is given that,

The distance between the radio and the radio station is 174 m

We need to find how many wavelengths of the radio waves are there between the transmitter and radio receiver if the woman is listening to an AM radio station broadcasting at 1540 kHz.

f = 1540 kHz

Wavelength,

[tex]\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1540\times 10^3}\\\\\lambda=194.8\ m[/tex]

Let there are n wavelengths of the radio waves. So,

[tex]n=\dfrac{d}{\lambda}\\\\n=\dfrac{174}{194.8}\\\\n=0.89\ \text{wavelengths}[/tex]

There are 0.89 wavelengths.

Answer:

v = 9.07 m/s

the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s

Explanation:

Given;

An eagle is flying horizontally at a speed of 4.6 m/s

Initial horizontal velocity uh = 4.6 m/s

Initial vertical velocity uy = 0

Height to fall d = 4.2 m

Acceleration due to gravity g = 9.8 m/s^2

The final vertical velocity of the fish when it hits the water can be calculated using the equation of motion;

v^2 = u^2 + 2as

v^2 = uy^2 + 2gd

uy = 0

v^2 = 2gd

v = √(2gd)

Substituting the given values;

v = √(2×9.8×4.2)

v = 9.073036977771 m/s

v = 9.07 m/s

the vertical component of the velocity of the fish relative to the water when it hits the water is 9.07 m/s

Answer:

Therefore, the answer is E. They strike the plane at the same time.

Explanation:

Here, it is seen that the time depends only on acceleration due to gravity (which is a constant) and vertical displacement, and not on velocity of the bullets or mass of the bullets.

Hence, the bullets that are fired simultaneously parallel to the horizontal plane will strike the plane at the same time.

using equation of motion for displacement

s= ut + ¹/₂gt²

here, g is the acceleration due to gravity along y- direction

U along y is 0

s = (0)t + ¹/₂gt²

s=¹/₂gt²

make t the subject of formula =  [tex]\sqrt{\frac{2s}{g} }[/tex]

Answer:

D

Explanation:

W = P∆V

Use the above equation and substitute, thanks

Answer:

If x = A sin w t    where w is the angular frequency

then v = w A cos w t

Since KE = 1/2 m Vmax^2 and Vmax = w A     maximum KE

the total energy is proportional to A^2

Also, since the maximum potential energy is

PEmax = 1/2 K A^2    where the KE is zero (maximum amplitude)

one can again see that the total energy is proportional to A^2

Answer:

Their frequency is 111.22 Hz

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration and is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The propagation speed of a wave is the quantity that measures the speed at which the wave's disturbance propagates throughout its displacement. The speed at which the wave propagates depends on both the type of wave and the medium through which it propagates. Relate wavelength (λ) and frequency (f) inversely proportional using the following equation:

v = f * λ.

Then the frequency can be calculated as: f=v÷λ

In this case:

Replacing:

[tex]f=\frac{3.37 \frac{m}{s} }{0.0303 m}[/tex]

Solving:

f=111.22 Hz

Their frequency is 111.22 Hz

Answer:

Explanation:

Radius of wheel = 1.2 m

A )

To know angular speed after t sec , we use the formula

ω = ω₀ + α t  , where ω₀ is initial velocity , α is angular acceleration

ω = 0 + 4.4 x 2

= 8.8 rad / s

v= ωR , v is tangential speed , ω is angular speed , R is radius of wheel .

= 8.8 x 1.2 = 10.56 m /s

B )

radial acceleration

Ar = v² / R

= 10.56² / 1.2

= 92.93 m /s²

Tangential acceleration

At = angular acceleration x radius

= 4.4 x 1.2 = 5.28 m /s²

Total acceleration

=  √ ( At² + Ar² )

=√ (5.28² +92.93²)

= 93 m /s²

C )

θ = ωt + 1/2 α t²     where θ is angular position after time t .

= 0 + .5 x 4.4 x 2²

= 8.8 rad

= 180x 8.8/ 3.14  = 504.45 degree

initial position = 57.3°

final position = 504 .45 + 57.3

= 561.75 °

= 561.75 - 360

= 201.75 ° .

Position of radius vector of point P will be at angle of 201.75 from horizontal axis .

Answer:

432 J

Explanation:

When moving linearly:

Kinetic Energy = (1/2)mV^2

So here you have:

KE=(1/2)(6)(12^2)=(1/2)(6)(144)=432

The unit for energy is Joules (J), so your answer would be 432 J.

Answer:

Explanation:

From,

1cm = [tex]10^{-2}m[/tex]

1mm = [tex]10^{-3}m[/tex]

1nanometer = [tex]10^{-9[/tex]

1micrometer = [tex]10^{-6[/tex]

Therefore,

A) [tex]10^0[/tex] meters = 1meter

B) [tex]10^2[/tex] cm = [tex]10^2 * 10^{-2} = 1meter[/tex]

C) [tex]10^4[/tex] mm = [tex]10^4 * 10^{-3} = 10meter[/tex]

D) [tex]10^5[/tex] micrometer = [tex]10^5 * 10^{-6} = 0.1meter[/tex]

E) [tex]10[/tex] nanometer = [tex]10 * 10^-9 = 1*10^{-8}[/tex]

Therefore 10nanometers is the shortest length

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Answer:

The air-water interface is an example of boundary. The transmitted portion of the initial wave energy is way smaller than the reflected portion. This makes the boundary  wave hard to hear.

When both the source of the sound and your ears are located underwater, the sound is louder because the sound waves can travel directly to your ear.

Explanation:

The air-to-water sound wave transmission is inhibited because more of reflection than transmission of the wave occurs at the boundary. In the end, only about 30% of the sound wave eventually reaches underwater. For sound generated underwater, all the wave energy is transmitted directly to the observer. Sound wave travel faster in water than in air because, the molecules of water are more densely packed together, and hence can easily transmit their vibration to their neighboring molecules, when compared to air.

Answer: The air-water interface is an example of boundary. The (transmitted) portion of the initial wave is way smaller than the (reflected) portion. This makes the (transmitted) wave hard to hear.

When both the source of the sound and your ears are located underwater, the sound is louder because the sound waves can (travel directly to your ears.)

Explanation:

The part of the sound wave that is transmitted across the boundary between air and water is much smaller than the part of the wave that is reflected. This is what makes it hard to hear your friend knocking two rocks together above the surface.

When you and the rocks are underwater, the sound that comes from knocking the rocks together can travel directly to your ears rather than having to be transmitted across mediums.

Answer:

m = 0.0125 kg

Explanation:

Let us apply the formula for the speed of a wave on a string that is under tension:

[tex]v = \sqrt{\frac{F}{\mu} }[/tex]

where F = tension force

μ = mass per unit length

Mass per unit length is given as:

μ  = m / l

where m = mass of the string

l = length of the string

This implies that:

[tex]v = \sqrt{\frac{F}{m/l} }\\ \\v = \sqrt{\frac{F * l}{m} }[/tex]

Let us make mass, m, the subject of the formula:

[tex]v^2 = \frac{F * l}{m}\\\\m = \frac{F * l}{v^2}[/tex]

From the question:

F = 20 N

l = 4.50 m

v = 85 m/s

Therefore:

[tex]m = \frac{20 * 4.5}{85^2}\\\\m = \frac{90}{7225}\\ \\m = 0.0125 kg[/tex]

Answer:

The magnitude of the magnetic field is  [tex]B = 0.0890 \ T[/tex]

Explanation:

From the question we are told that

   The mass of the rod is  [tex]m =0.300 \ kg[/tex]

    The distance of separation is  [tex]d = 0.440 \ m[/tex]

     The current is  [tex]I = 15.0 \ A[/tex]

     The coefficient of friction is   [tex]\mu = 0.300[/tex]

Generally for the rod the rod to continue moving at a constant speed

   The frictional force must equal to the magnetic field force so

    [tex]F_m = F_f[/tex]

Where  [tex]F_m = B* I * d[/tex]

and     [tex]F_f = \mu * m * g[/tex]

   [tex]B*I *d = \mu * m * g[/tex]

=>    [tex]B = \frac{\mu * m * g }{I * d }[/tex]

substituting values

       [tex]B = \frac{0.2 * 0.300 * 9.8 }{ 15 * 0.440 }[/tex]

       [tex]B = 0.0890 \ T[/tex]

Answer:

E = (-3.61^i+1.02^j) N/C

magnitude E = 3.75N/C

Explanation:

In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:

[tex]\vec{E}=-k\frac{q}{r^2}cos\theta\ \hat{i}+k\frac{q}{r^2}sin\theta\ \hat{j}\\\\\vec{E}=k\frac{q^2}{r}[-cos\theta\ \hat{i}+sin\theta\ \hat{j}][/tex]              (1)

Where the minus sign means that the electric field point to the charge.

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q = -4.28 pC = -4.28*10^-12C

r: distance to the charge from the point P

The point P is at the point (0,9.83mm)

θ: angle between the electric field vector and the x-axis

The angle is calculated as follow:

[tex]\theta=tan^{-1}(\frac{2.79mm}{9.83mm})=74.15\°[/tex]

The distance r is:

[tex]r=\sqrt{(2.79mm)^2+(9.83mm)^2}=10.21mm=10.21*10^{-3}m[/tex]

You replace the values of all parameters in the equation (1):

[tex]\vec{E}=(8.98*10^9Nm^2/C^2)\frac{4.28*10^{-12}C}{(10.21*10^{-3}m)}[-cos(15.84\°)\hat{i}+sin(15.84\°)\hat{j}]\\\\\vec{E}=(-3.61\hat{i}+1.02\hat{j})\frac{N}{C}\\\\|\vec{E}|=\sqrt{(3.61)^2+(1.02)^2}\frac{N}{C}=3.75\frac{N}{C}[/tex]

The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C

Answer:

[tex]$ \phi_{21} = \frac{\phi_{12}}{2} $[/tex]

Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.

Explanation:

The flux through each loop of the first coil due to current in the second coil is,

[tex]\phi_{12} = \phi[/tex]

The number of loops in the first coil is

no. of loops = 2N

Total flux passing through the first coil is

[tex]\phi_{12} = 2N\phi[/tex]

The flux through each loop of the second coil due to current in the first coil is,

[tex]\phi_{21} = \phi[/tex]

The number of loops in the second coil is

no. of loops = N

Total flux passing through the second coil is

[tex]\phi_{21} = N\phi[/tex]

Comparing both

[tex]\phi_{12} = \phi_{21} \\\\ 2N\phi = N\phi\\\\\phi_{21} = \frac{\phi_{12}}{2}[/tex]

Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.

Answer:

the other force= (16.3i + 14.6j)N

EXPLANATION:

Given:

Mass=2.80-kg

t= 1.2s

Since the object started from rest, the origin is (0,0) which symbolize the the object's initial position.

We will need to calculate the magnitude of the displacement using the below formula;

d = (1/2)at2 + v0t + d0

But note that

d0 = 0,( initial position)

v0 = 0( initial position)

a is the net acceleration

d = √[4.202 + (-3.30)2] m = 5.34 m

Hence, the magnitude of the displacement is 5.34 m, then we can make 'a' the subject of formula in the above expression in order to calculate the value for acceleration, note that d0 = 0,( initial position) and v0 = 0( initial position)

d = (1/2)at2

a = 2d/t2 = 2(5.34)/(1.20)2 m/s2 = 7.42 m/s2

the net acceleration is 7.42 m/s2

Acceleration in terms of the vector can be calculated as

a=2(ri - r0)/t^2

Where t =1.2s which is the time

a= 2(4.2i - 3.30j)/ 1.2^2

a=( 5.83i - 4.58j)m/s

now the net force can now be calculated since we have known the value of acceleration, using the formula below;

F(x) = ma - mg

Where a = 5.83i - 4.58j)m/s and g= 9.8m/s

2.8(5.83i - 4.58j)m/s - (2.80 × 9.8)m/s^2

Therefore, the other force= (16.3i + 14.6j)N

Answer:

Impossible to know without more information about the fields.

Explanation:

Changing the magnetic field induces the external magnetic field, but the information regarding magnetic field variation is not provided. We need to required more information for this

Therefore according to the above explanation the correct option is Impossible to know without more information about the fields.

Hence, the b option is correct

Answer:

"Upwards and towards the left" is the right answer.

Explanation:

The magnitude of the field will be:

⇒  [tex]E=\frac{kq}{r^2}[/tex]

And direction -> for negative charges, to positive charges, except charges.  

Thus the net field is upwards as well as to the left.

Centripetal acceleration = (speed squared) / (radius)

Centripetal acceleration = (10 m/s)² / (1.0 m)

Centripetal acceleration = (100 m²/s²) / (1.0 m)

Centripetal acceleration = 100 m/s²

Answer:

e. Doubles.

Explanation:

Resolving power is given by the formula as follows :

[tex]\dfrac{1}{d\theta}=\dfrac{D}{1.22\lambda}[/tex]

Here, [tex]d\theta[/tex] is the angle subtended by two distant objects

D is diameter of the telescope

Here, the diameter of a radar dish is doubled, assuming all other factors remain unchanged, then the resolving power gets doubled. Hence, the correct option is (e).

Answer:

less than

Explanation:

The force of kinetic friction for a particular pair of interacting objects is always less than the force of static friction.

The force of static friction between two surfaces is always higher than the force of kinetic friction.

Answer:

The potential enwrgy associated with charge decreases.

The ele ric field does negative work on the charge.

Explanation:

Answer:

The potential energy associated with the charge decreases

The electric field does positive work on the charge.

Answer:

large

Explanation:

Cumulus clouds is a term in metrology that defines the type of clouds which are characterized by its low altitude, puffy appearance, and fair-weather nature. They are generally considered as low-level clouds, with less than than 2,000m in altitude except they are the more vertical cumulus congestus form.

Thus, it can be noted that, the difference between the surface dew point temperature and the surface temperature is related to relative humidity. Hence, in a situation when there is a LARGE difference between the surface temperature and the surface dewpoint temperature, then the relative humidity is very low (e.g., 10%).

Therefore, the bases of developing convective cumulus clouds will be relatively higher at a location with a relatively LARGE difference between the surface temperature and surface dew point temperature.

Answer:

397.51 kJ

Explanation:

Since the change in velocity is done on a level road, there is no change in the potential energy. The workdone is the workdone on reducing the kinetic energy.

Workdone W = change in kinetic energy ∆K.E

W = ∆K.E

K.E = 0.5mv^2

∆K.E = 0.5m(m1^2 - m2^2)

Given;

Mass m = 2065 kg

Initial velocity v1 = 23.0 m/s

Final velocity v2 = 12.0 m/s

W = ∆K.E = 0.5m(m1^2 - m2^2)

Substituting the given values;

W = ∆K.E = 0.5×2065(23^2 - 12^2)

W = 397512.5J

W = 397.51 kJ

Answer:

The work done in moving the chain is 4116 J

Explanation:

Given;

mass of the chain, m = 70 kg

length of the chain, l = 10 m

vertical height through which one end of the chain was raised, h = 6 m

Work done in raising this chain to this height is equal to potential energy due to this vertical height

W = PE

W = mgh

where;

m is mass of the chain

g is acceleration due to gravity

h is the vertical height through which the chain was raised

W = 70 x 9.8 x 6

W = 4116 J

Therefore, the work done in moving the chain is 4116 J

Answer:

30.67m

Explanation:

Using one of the equations of motion as follows, we can describe the path of the projectile in its horizontal or vertical displacement;

s = ut ± [tex]\frac{1}{2} at^2[/tex]               ------------(i)

Where;

s = horizontal/vertical displacement

u = initial horizontal/vertical component of the velocity

a = acceleration of the projectile

t = time taken for the projectile to reach a certain horizontal or vertical position.

Since the question requires that we find the vertical distance from where the projectile was launched to where it hit the target, equation (i) can be made more specific as follows;

h = vt ± [tex]\frac{1}{2} at^2[/tex]               ------------(ii)

Where;

h = vertical displacement

v = initial vertical component of the velocity = usinθ

a = acceleration due to gravity (since vertical motion is considered)

t = time taken for the projectile to hit the target

From the question;

u = 47m/s, θ = 0.6rads

=> usinθ = 47 sin 0.6

=> usinθ = 47 x 0.5646 = 26.54m/s

t = 1.7s

Take a = -g = -10.0m/s   (since motion is upwards against gravity)

Substitute these values into equation (ii) as follows;

h = vt - [tex]\frac{1}{2} at^2[/tex]

h = 26.54(1.7) - [tex]\frac{1}{2} (10)(1.7)^2[/tex]

h = 45.118 - 14.45

h = 30.67m

Therefore, the vertical distance is 30.67m        

Answer:

a) 1.95 V

b) 1.87 mA

c) 0.115 A

Explanation:

Given that

Number of primary turns, N(p) = 480

Number of secondary turns, N(s) = 7.8

Velocity of primary turns, V(p) = 120 V

Velocity of secondary turns, V(s) = ?

Current in the primary, I(p) = ?

Current in the secondary, I(s) ?

To solve this question, we would be using the formula

V(s)/V(p) = N(s)/N(s), now substituting the values, we have

V(s) / 120 = 7.8 / 480

V(s) = (7.8 * 120) / 480

V(s) = 936 / 480

V(s) = 1.95 V

To find the current in the primary, remember ohms law?

I = V/R

I(s) = V(s) / R(s)

I(s) = 1.95 / 17

I(s) = 0.115 A

Now, remember the relationship between current and voltage

I(p)/I(s) = V(s)/V(p)

I(p) / 0.115 = 1.95 / 120

I(p) = (1.95 * 0.115) / 120

I(p) = 0.22425 / 120

I(p) = 0.00187 A

I(p) = 1.87 mA