uses of generator
pls in points
if you answer correct i will mark you as brainliest​

Answers

Answer 1

Answer:

Electric generator, also called dynamo, any machine that converts mechanical energy to electricity for transmission and distribution over power lines to domestic, commercial, and industrial customers. Generators also produce the electrical power required for automobiles, aircraft, ships, and trains.

Answer 2

Answer:

Electric motors are used in a broad range of industrial, commercial, and residential, applications, such as fans, pumps, compressors, elevators, and refrigerators. ... DC motors are used for variable speed control applications such as industrial machinery and motor vehicles.

In electricity generation, a generator is a device that converts mechanical energy to electrical energy for use in an external circuit. Generators provide nearly all of the power for electric power grids.

Hope it helps


Related Questions

There are three 20.0 Ω resistors connected in series across a 120 V generator

Answers

Answer:

That is equal to R1 + R2. If three or more unequal (or equal) resistors are connected in series then the equivalent resistance is: R1 + R2 + R3 +…, etc. One important point to remember about resistors in series networks to check that your maths is correct.

What is meant by electricity and magnetism

Answers

Electricity is just the flow of electrons or charges from a point of production through a conductor, to another point where it can be utilized or converted to another form of energy.

Magnetism is the force exerted by magnets when they attract or repel each other. Magnetism is caused by the motion of electric charges from two or more magnetic substances.

Answer:

By Electricity.. We mean the Flow of electrical power or Charge.

While Magnetism is a phenomenon that occurs from or by the Motion of Charges

Atoms are composed of protons, ______, and electrons.​

Answers

Atoms are composed of protons, [tex]\sf\purple{neutrons}[/tex]and electrons. ✅

The [tex]\sf\blue{protons}[/tex] (positively charged) and the [tex]\sf\pink{neutrons}[/tex] (no charge) are in the centre of the atom, making up the nucleus.[tex]\sf\red{Electrons}[/tex] (negatively charged) are present in the outermost shell of the atom.

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

A. Obtain the following: microwave, ruler, something meltable (e.g. candy bar, marshmallows) B. A microwave works by setting up a standing electromagnetic wave inside of a box made of conducting materials. What is the value of an electric field inside a conductor

Answers

Answer:

E = 124.7 N / C

Explanation:

Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.

The electric field of the standing wave is

            I = E²

            E =√I

where I is the intensity of the radiation.

What is it

             I = P / A

where P is the effective emission power, almost all the power of the microwave and A is the area of ​​the cavity, in the most used microwaves

P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²

             I = 700 / 0.045

             I = 15555.56 W/m²

let's calculate the electric field

            E = √15555.56

            E = 124.7 N / C

Which of the following. Chemical represent the law of conservation of Matter?

Answers

Answer:

The answer is first one 1...

A closed loop conductor that forms a circle with a radius of 2.0 m is located in a uniform but changing magnetic field. If the maximum emf Induced in the loop is 5.0 V what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies

Answers

Answer:

The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.

Explanation:

Given;

radius of the circular loop, r = 2.0 m

maximum induced emf, E = 5.0 V

The emf induced in a magnetic field is given as;

[tex]emf = \frac{d\phi}{dt} \\\\\phi = AB\\\\emf = A\frac{dB}{dt} \\\\\frac{dB}{dt} = \frac{emf}{A} \\\\where;\\A \ is \ the \ area \ circular \ l00p = \pi r^2 = \pi (2)^2 = 4\pi \ m^2\\\\\frac{dB}{dt} = \frac{5}{4\pi} \\\\\frac{dB}{dt} = 0.398 \ T/s[/tex]

Therefore, the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies 0.398 T/s.

paano matutugunan o matutulungan ng pamahalaan at ng mga guro yubg mga estudyanteng nakararanas nag stress at anxiety.

Answers

Answer: how the government and teachers can address or help students experiencing stress and anxiety.

Explanation:

A copper wire has a diameter of 4.00 x 10-2 inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit

Answers

Complete question is;

A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.

Answer:

F_max = 28.9 lbf

Explanation:

Elastic limit is simply the maximum amount of stress that can be applied to the wire before it permanently deform.

Thus;

Elastic limit = Max stress

Formula for max stress is;

Max stress = F_max/A

Thus;

Elastic limit = F_max/A

F_max is maximum load

A is area = πr²

We have diameter; d = 4 × 10^(-2) inches = 0.04 in

Radius; r = d/2 = 0.04/2 = 0.02

Plugging in the relevant values into the elastic limit equation, we have;

2.30 × 10⁴ = F_max/(π × 0.02²)

F_max = 2.30 × 10⁴ × (π × 0.02²)

F_max = 28.9 lbf

4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?​

Answers

Force = area * pressure
F = 0.0025 m * 200000 pa
F = 500 N

A bullet with a mass of 12 g moving horizontally strikes a fixed block of wood and penetrates a distance of 5.2 cm. The speed of the bullet just before the collision is 640 m/s. What is the average force that the wood exerted on the bullet

Answers

Answer:

F = 47261.5 N = 47.26 KN

Explanation:

First, we will calculate the deceleration of the bullet by using the third equation of motion:

[tex]2as = v_f^2-v_i^2[/tex]

where,

a = deceleration = ?

s = distace covered = 5.2 cm = 0.052 m

vf = final speed = 0 m/s

vi = initial speed = 640 m/s

Therefore,

[tex]2(a)(0.052\ m) = (0\ m/s)^2-(640\ m/s)^2\\\\a = -\frac{409600\ m^2/s^2}{0.104\ m}\\\\a=-3938461.5\ m/s^2[/tex]

negative sign shows deceleration.

Now for the force, we will use Newton's Second Law of Motion:

F = ma

where,

F = Force = ?

m = mass of bullet = 12 g = 0.012 kg

Therefore,

F = (0.012 kg)(3938461.5 m/s²)

F = 47261.5 N = 47.26 KN

An old fashioned string of 80 Christmas lights is wired in series. Each bulb has a resistance of 2 Ohms and the entire string is plugged into a 120V outlet. What is the current passing through each of the bulbs?

Answers

The sum of the resistance = 2 ohms x 80 lights = 160 ohms.

Current = Total voltage / total resistance:

Current = 120V / 160 ohms

Current = 0.75 Amps

ADHD is triggered ________ by genetic and neurological factors and ________ by social or environmental ones.
A. less; more
B. somewhat; somewhat
C. little; mostly
D. more; less

Answers

Answer:

D More: Less

Explanation:

ADHD is triggered more by genetic and neurological factors and less by social or environmental ones.

What is ADHD?

ADHD is one of the most common neurodevelopmental disorders of childhood. It is usually first diagnosed in childhood and often lasts into adulthood. Children with ADHD may have trouble paying attention, controlling impulsive behaviors (may act without thinking about what the result will be), or be overly active.

Moreover, ADHD tends to run in families and, in most cases, it's thought the genes you inherit from your parents are a significant factor in developing the condition. Research shows that parents and siblings of someone with ADHD are more likely to have ADHD themselves.

Therefore, adults with attention deficit hyperactivity disorder (ADHD or ADD) lead anxious lives. The nature of ADHD often makes day-to-day life stressful, creating situations and environments fraught with uncertainty – anxiety's primary fuel.

Learn more about ADHD:

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A thermionic tube with only a cathode and anode is called​

Answers

Answer:

the simplest vacuum tube, the diode


5. Stopping a fast-moving object is harder than stopping a slow-moving
one.
True
False

Answers

true because well it’s moving fast lol sometimes ur eyes have a hard time following its speed
True because it’s fast

An electron that has an instantaneous velocity of is moving through the uniform magnetic field (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity

Answers

Answer:

Explanation:

From the given information:

The missing value are as follows:

The velocity  [tex]v ^{\to} = (2.0 \times 10^6 \ m/s) \hat i + (3.0 \times 10^6 \ m.s) \hat j[/tex]

The uniform magnetic field [tex]B^{\to} = (0.030 T)\hat i -(0.15 T) \hat j[/tex]

The force on electron as a result of the Magnetic field is:

[tex]F^\to = q(v^\to \times B^\to)[/tex]

here;

Change of electron [tex]q = -1.6 \times 10^{-19} C[/tex]

Then,

[tex]v^{\to} \times B^{\to} = \left|\begin{array}{ccc}2\times10^6&3\times 10^6&0\\0.03&-0.15&0\end{array}\right|[/tex]

[tex]= \hat i(0-0) -\hat j ( 0-0) +\hat k (-3\times 10^5 -0.9\times 10^5) \\ \\ =-3.9 \times 10^5 \ k[/tex]

[tex]F^\to = q(v^\to \times B^\to)[/tex]

[tex]F^{\to} = -1.6 \times 10^{-19} \times -3.9 \times 10^5 \\ \\ F^{\to} = 6.24 \times 10^{-14 } \ N[/tex]

For the proton with the same velocity:

[tex]q = 1.6 \times 10^{-19 } \ C \\ \\ F = q (v^\to * B^\to) \ \\ \\ F^\to = q(-3.9 \times 10^5) \\ \\ F = (1.6 \times 10^{-19}) (-3.9 \times 10^5) \\ \\ \mathbf{F ^{\to} = -6.24 \times 10^{-14} \ N}[/tex]

WILL GIVE BRAINLIEST

Answers

Answer:

[tex]2\:\mathrm{m/s^2}[/tex]

From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. Substituting given values, we have:

[tex]40=20a,\\a=\frac{40}{20}=\boxed{2\:\mathrm{m/s^2}}[/tex]

What is the speed of a wave if it has a wavelength of
42 m and a frequency of 7 hertz?

Answers

Answer:

♕ [tex]\large{ \red{ \tt{Step - By - Step \: Explanation}}}[/tex]

☃ [tex] \underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} : [/tex]

Frequency ( f ) = 7 HertzWavelength ( λ ) = 42m

♨ [tex] \underline {\underline{ \orange{ \large{ \tt{T \: O \: \: F \: I \: N\: D}}}} }: [/tex]

Wave velocity ( v )

☄ [tex]\underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}: [/tex]

✧ [tex] \red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}[/tex]

~Plug the known values and then multiply!

↦ [tex] \large{ \tt{7 \times 42}}[/tex]

↦ [tex] \boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}[/tex]

☥ [tex] \large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}} [/tex]

---------------------------------------------------------------

❁ [tex] \underline{ \large{ \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \: \: I\: N \: F \: O}}}} : [/tex]

Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

# KILL : Excuses

KISS : Opportunities

MARRY : Goals

♪ Hope I helped! ♡

☂ Have a wonderful day / night ! ツ

✎ [tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✔

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In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt/pi including the background correction.

Answers

Answer:

The answer is "[tex]15.38\%[/tex]"

Explanation:

Background[tex]= 13 \ mv\\\\[/tex]

corrected signal[tex]= 91 \ mv-13\ mv= 78\ mv\\\\[/tex]

with attenuator[tex]=25\ mv-13\ mv= 12\ mv\\\\[/tex]

[tex]\to \frac{p_t}{p_i}=\frac{12}{78}\times 100= 15.38\%[/tex]

A sound wave with a frequency of 700 Hz and a wavelength of 5 m travels through a liquid. How fast does sound travel through the liquid?

A.
140 m/s
B.
0.007 m/s
C.
3500 mHz
D.
3500 m/s

Answers

Answer:

It’s D, 3500 m/s
It’s D 3500 m/s in most cases

An irrigation canal has a rectangular cross section. At one point where the canal is 18.2 m wide and the water is 3.55 m deep, the water flows at 2.55 cm/s . At a second point downstream, but on the same level, the canal is 16.3 m wide, but the water flows at 11.6 cm/s . How deep is the water at this point

Answers

Answer:

Explanation:

Rate of volume flow at two points will be same at two points .

A₁ V₁ = A₂V₂

A₁ and A₂ are area of cross section at two points and V₁ and V₂ are velocities .

A₁ = 18.2 x 3.55 = 64.61 m²

V₁ = 2 .55 x 10⁻² m/s

A₂ = 16.3 x d = 16.3 d  m²

d is depth at second point .

V₂ = 11.6 x 10⁻² m/s

64.61 m² x 2 .55 x 10⁻² m/s = 16.3 d  m² x 11.6 x 10⁻² m/s

d = .87 m

so canal is .87 m deep.

what is the transfer of heat energy by direct contact. A . convection b. radiation c. thermal or heat and d. conduction ​

Answers

Answer:

d. conduction ​

Explanation:

Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.

In conclusion, conduction typically involves the transfer of heat energy by direct contact between two or more conductors such as a pot and electric cooker.

Answer:

d. conduction ​

Explanation:

Conduction is the transfer of energy from one molecule to another by direct contact.

Copper zinc and magnesium do not contain any iron. What word is used to describe these types of
metals?

Answers

Answer:

Metals that do not contain traces or large proportions of iron in them are called Non-Ferrous metals.

Non-Ferrous metals because they do not contain iron while those that contain iron are called ferrous metals

You have two flashlights that have 0.500-A currents flowing through them. One flashlight has a single 1.50-V battery in its circuit, and the second flashlight has three 1.50-V batteries connected in a chain that provides 4.50 V. How much power is the battery in the first flashlight providing

Answers

Answer: 0.75 W

Explanation:

Given

Current flowing [tex]I=0.5\ A[/tex]

The first flashlight has a single 1.5 V battery

The second flashlight has three 1.5 V batteries connected to provide 4.5 V

Power is the product of voltage and current.

For the first flashlight

[tex]\Rightarrow P=1.5\times 0.5\\\Rightarrow P=0.75\ W[/tex]

Thus, the first flashlight providing 0.75 W of power.

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What is the longest wavelength that forms an intensity maximum in the fifth order

Answers

Answer:

377 nm

Explanation:

Number of lines per meter is, [tex]N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}[/tex]

Grating element is, [tex]d=\frac{1}{N}[/tex]

[tex]=1.8868 \times 10^{-6} \mathrm{~m}[tex]

Order is, n=5

Condition for maximum intensity is, [tex]d \sin \theta=n \lambda[/tex]

 [tex]\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\ &=0.377 \times 10^{-6} \mathrm{~m} \\ &=377 \mathrm{~nm}[/tex]

Which of the following is form of energy:
a) Power
b) Light
C) pressure
d) None​

Answers

Answer:

Explanation:

b) light

which statement describes the molecules and a reaction once it reaches equilibrium
A. They maintain stable concentrations
B. They stop moving
C. They consist mainly of reactant molecules
D. They react only if they are disturbed

Answers

Answer:

They maintain stable concentrations

Explanation:

Just took the test.

The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is option A as the When a chemical reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.

What is equilibrium?

Equilibrium is a dynamic state, meaning that the reaction is still ongoing but the rates of the forward and reverse reactions are equal. This means that molecules are still reacting with each other, but at a constant rate, so that the concentrations of the reactants and products remain stable. When a reaction is not at equilibrium, the concentrations of the reactants and products change as the reaction progresses. However, once equilibrium is reached, the concentrations of the reactants and products no longer change, but the individual molecules are still moving and reacting with each other.

Hence, The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is an option. A 

Learn more about equilibrium here.

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Please helpppppppppp!!!!!!!!!!!

Answers

37N is the answer.

Also pls mark me brianliest!!

A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30-kg ball is dropped from rest. It collides with and sticks to the spring, which is compressed by 2.5 cm in bringing the block to a momentary halt. Assuming air resistance is negligible, from what height (in cm) above the uncompressed spring was the block dropped

Answers

Answer:

h = 1.91 m

Explanation:

From the law of conservation of energy, we know that:

[tex]Potential\ Energy\ of\ Ball = Elastic\ Petential\ Energy\ of\ Spring\\mgh = \frac{1}{2}kx^2[/tex]

where,

m = mass of ball = 0.3 kg

g = acceleration due to gravity = 9.81 m/s²

h = height of ball = ?

k = spring constant = 450 N/m

x = compressed length = 2.5 cm = 0.025 m

Therefore,

[tex](0.3\ kg)(9.81\ m/s^2)h = \frac{1}{2} (450\ N/m)(0.025\ m)^2\\\\h = \frac{(450\ N/m)(0.025\ m)^}{(2)(0.3\ kg)(9.81\ m/s^2)}[/tex]

h = 1.91 m

When was the most gravitational potential energy stored between the model and Earth? Assume that the model's mass did not change.​

Answers

Answer:

As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy

Explanation:

Answer:As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy

Explanation:

Explain gravitational implicit energy in terms of work done against graveness.Show how knowledge of the implicit energy as a function of position can be used to simplify computations and explain physical marvels. Show that the gravitational potential energy of an object of mass  m at height  h on Earth is given by  PEg=mgh.

Two blocks are connected by a massless rope that passes over a 1 kg pulley with a radius of 12 cm. The rope moves over the pulley without slipping. The mass of block A is 2.1 kg and the mass of block B is 4.1 kg. Block A is also connected to a horizontally-mounted spring with a spring constant of 358 J/m2. What is the angular frequency (in rad/s) of oscillations of this system

Answers

Answer:

[tex]F=1.159[/tex]

Explanation:

From the question we are told that:

Mass of pulley [tex]M=1kg[/tex]

Radius [tex]r=12cm[/tex]

Mass of block A [tex]M_a=2.1kg[/tex]

Mass of block B [tex]m_b=4.1kg[/tex]

Spring constant[tex]\mu= 358 J/m2[/tex]

Generally the equation for Torque is mathematically given by

Since [tex]\sumF=ma[/tex]

At mass A

 [tex]T_2-f_3=2.1a[/tex]

At mass B

 [tex]4.8-T_1=4.1a[/tex]

At  Pulley

 [tex]R(T_1-T_2)=\frac{1*1*R^2}{2}\frac{a}{R}[/tex]

 [tex]R(T_1-T_2)=0.55a[/tex]

Therefore the equation for total force F

At mass A+At mass B+At  Pulley

 [tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.1a+4.1a+0.55a[/tex]

 [tex](T_2-f_3+4.8-T_1+R(T_1-T_2)=2.7a+4.8a+0.55a[/tex]

 [tex]-f_3+4.1=6.75a[/tex]

 [tex]-f_3=6.75a+4.8[/tex]

Since From above equation

[tex]M_{eff}=6.7kg[/tex]

Therefore

[tex]T=2\pi \sqrt{{\frac{M_{eff}}{k}}[/tex]

[tex]T=2\pi \sqrt{{\frac{6.75}{\mu}}[/tex]

[tex]T=0.862s[/tex]

Generally the equation for frequency is mathematically given by

[tex]F=\frac{1}{T} \\F=\frac{1}{0.862}[/tex]

[tex]F=1.159[/tex]

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