Use the following table to calculate the train's average velocity during part B of the train ride.​

Use The Following Table To Calculate The Train's Average Velocity During Part B Of The Train Ride.

Answers

Answer 1

Answer:

60km/hr due east

Explanation:

Given parameters:

Displacement = 60km East

Start time  = 10am

End time  = 11am

Unknown:

Average velocity  = ?

Solution:

The average velocity is the displacement divided by the time taken.

 For this journey, the time taken is;

              11am  -  10am  = 1hr

 So;  

 Average velocity  = [tex]\frac{60km}{1hr}[/tex] = 60km/hr due east


Related Questions

If each of the charges is increased by two times and the distance between them is also increased by two times, the electromagnetic force between them Group of answer choices

Answers

Answer: The force does not change.

Explanation:

The force between two charges q₁ and q₂ is:

F = k*(q₁*q₂)/r^2

where:

k is a constant.

r is the distance between the charges.

Now, if we increase the charge of each particle two times, then the new charges will be: 2*q₁ and 2*q₂.

If we also increase the distance between the charges two times, the new distance will be 2*r

Then the new force between them is:

F = k*(2*q₁*2*q₂)/(2*r)^2 = k*(4*q₁*q₂)/(4*r^2) = (4/4)*k*(q₁*q₂)/r^2 = k*(q₁*q₂)/r^2

This is exactly the same as we had at the beginning, then we can conclude that if we increase each of the charges two times and the distance between the charges two times, the force between the charges does not change.

A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.

Answers

Answer:

1500000 Pa

Explanation:

The formula for pressure is force per unit area.

P=F/A where  F is force and A is area

Given that ;

F= mass * acceleration due to gravity

F= 60 * 9.81 = 588.6 = 589 N

A= area = 4cm² = 0.0004 m²

P= F/A = 589 / 0.0004

P= 1471500

P=1500000 Pa

A jumbo egg (80 grams) is dropped from a height of 15 meters onto a 1 inch of foam. Using kinematics, determine the velocity of the egg the instant before impact.

Answers

Answer:

the velocity of the egg the instant before impact is 17.15 m/s.

Explanation:

Given;

mass of the egg, m = 80 g = 0.08 kg

height through which the egg was dropped, h = 15 m

The velocity of the egg before impact will be maximum, and the final velocity is given by the following kinematic equation;

v² = u² + 2gh

where;

u is the initial velocity of the egg = 0

v is the final velocity of the egg before impact

v² = 0 + 2 x 9.8 x 15

v² = 294

v = √294

v = 17.15 m/s

Therefore, the velocity of the egg the instant before impact is 17.15 m/s.

Paul and Ivan are riding a tandem bike together they're moving at a speed of 5 meters per second Paul and Ivan each have a mass of 50 kg what can I do to increase the bikes kinetic energy.

a: he can let Ivan off at the next stop

b: he can pedal harder to increase the speed to 10 meters per second

c: he could reduce the speed to 3 meters per second

d: he can pick up a third Rider ​

Answers

Recall the equation for Kinetic Energy: = m

Knowing this, we know that there are only two factors that can alter Kinetic Energy: mass and velocity. Looking at the equation, we can deduce that an increase in either mass or velocity would increase the overall Kinetic Energy as long as everything else stays constant.

a) He can let Ivan off at the next stop - Wrong. By letting Ivan off, mass decreases. Assuming Paul maintains the same speed as before, Kinetic Energy decreases.

b) He can pedal harder to increase the speed to 10 meters per second - Correct. By speeding up, "v" increases and the overall Kinetic Energy increases.

c) He could reduce the speed to 3 meters per second - Wrong. Looking at the equation, we know reducing speed would reduce Kinetic Energy

d) He can pick up a third rider - Correct, assuming they keep the same speed after picking up the third rider: if mass increases and velocity stays the same, then Kinetic Energy will increase.

Answers - B, D

If there's anything you don't understand here, just let me know :)

Old-fashioned heating systems sent steam into radiators in each room of a house. In the radiators, the steam condense

back to water. Analyze this process and explain how it heated a room.

Need help

Answers

Answer:

The steam gives what is known as the LATENT HEAT OF VAPORIZATION TO THE ROOM

Explanation:

The term known as " latent heat if vaporization" deals with changes in a specific phase of matter to another one, that is from liquid to vapor. It can be defined as the quantity or the amount of heat required to change the liquid into vapor.

Therefore, when the system send the steam into radiators in each room of the house the steam gives what is known as the LATENT HEAT OF VAPORIZATION TO THE ROOM.

The steam which Is first of all condensed In order to produce the latent heat of vaporization is then sent back into the system and then comes out again to repeat the process in the paragraph above.


Which gas in Earth's atmosphere has increased over time due to burning fossil fuels?
BER
oxygen
O nitrogen
water vapor
O carbon dioxide

Answers

Answer:

The carbon dioxide levels have increased due to burning fossil fuels

Explanation:

Correct on edge 2021 hope this helps!✌️

The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.

What is meant by global warming ?

Global warming is defined as the phenomenon of heating up of the earth's surface in a long term due to the increased amount of emission of green house gases in the earth's atmosphere.

Here,

When more fossil fuels and the materials like coal are burned for the purpose of energy production, it will result to the production of an increased amount of carbon dioxide. This leads to the emission of huge amount of carbon dioxide in the earth's atmosphere. Since, carbon dioxide is a green house gas, the release of higher amount of carbon dioxide will lead to an increased concentration of green house gases. This causes an increase in the temperature of the atmosphere, resulting in the increased heating of the surface of earth. This uneven heating up of  earth's surface is called global warming. This is the result of higher release of carbon dioxide in the earth's atmosphere.

Hence,

The gas in Earth's atmosphere that has increased over time due to burning fossil fuels is carbon dioxide.

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A car accelerates uniformly from rest and reaches a speed of 9.9 m/s in 11.4 s. The diameter of a tire is 86.9 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev.

Answers

Answer:

Number of revolutions = 20.71 rev.

Explanation:

Given the following data;

Initial speed, u = 0m/s

Final speed, v = 9.9m/s

Time, t = 11.4secs

Diameter = 86.9cm to meters = 86.9/100 = 0.869m

To find the acceleration;

Acceleration, a = (v - u)/t

Acceleration, a = (9.9 - 0)/11.4

Acceleration, a = 9.9/11.4

Acceleration, a = 0.87m/s²

Now we would find the distance covered by the tire using the second equation of motion.

S = ut + ½at²

S = 0(11.4) + ½*0.87*11.4²

S = 0 + 0.435*129.96

S = 56.53m

The circumference of the tire is calculated using the formula;

Circumference = 3.142 * diameter

Circumference = 3.142 * 0.869

Circumference = 2.73m

Number of revolutions = distance/circumference

Number of revolutions = 56.53/2.73

Number of revolutions = 20.71 rev.

Therefore, the number of revolutions the tire makes during this motion is 20.71 revolutions.

For which medical procedure would Doppler ultrasound be most useful?

A.
Finding a lung tumor
B.
Fixing a pulled muscle
C.
Locating a broken bone in a finger
D.
Detecting a blockage in a heart artery

Answers

The answer is d.

Thank me by clicking the ❤️. Thanks!

Doppler ultrasound would be most useful in detecting a blockage in a heart artery.

What are the clinical uses of Doppler ultrasound?

By monitoring the rate of change in pitch, a Doppler ultrasound may calculate how quickly blood flows (frequency). A sonographer with training in ultrasound imaging applies pressure to your skin with a tiny, hand-held instrument (transducer) roughly the size of a bar of soap across the area of your body being scanned, moving from one place to another as required.

As an alternative to more invasive treatments like angiography, which involves injecting dye into the blood arteries to make them visible on X-ray images, this test may be performed.

Your doctor may use a Doppler ultrasound to assess for artery damage or to keep track of specific vein and artery therapies.

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A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.

Answers

Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

[tex]P=F/A[/tex]

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

[tex]A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }[/tex]

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

[tex]w = m*g[/tex]

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]w = 60*9.81\\w = 588.6[N][/tex]

And the pressure:

[tex]P=588.6/0.0004\\P=1471500 [Pa][/tex]

Because 1 [Pa] = 1 [N/m²]

What is the wavelength of a wave that has a speed of 350 meters second and a frequency of 140 hert??

Answers

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).

Hope this helped

The momentum of a car traveling at 20m/s is 24,500 kgm/s. What is the car's mass?

Answers

Answer:

1225kg

Explanation:

Given parameters:

Velocity of the car  = 20m/s

Momentum = 24500kgm/s

Unknown:

Mass of the car  = ?

Solution:

To solve this problem, we must understand that the momentum of a body is the quantity of motion that it possess.

So;

  Momentum  = mass x velocity

 

    Mass of the car  = [tex]\frac{Momentum }{velocity}[/tex]   = [tex]\frac{24500}{20}[/tex]   = 1225kg

Two force vectors are oriented such that the angle between their directions is 46 degrees and they have the same magnitude. If their magnitudes are 2.81 newtons, then what is the magnitude of their sum

Answers

Answer:

F = 5.17 N

Explanation:

If we know the magnitudes of both vectors, and the angle between them, we can find the magnitude of their sum, applying the cosine theorem, as follows:

       [tex]F =\sqrt{F_{1} ^{2} +F_{2} ^{2} + 2*F_{1} * F_{2} * cos \theta} (1)[/tex]

Replacing by the givens, F₁ = F₂ = 2.81 N, θ = 46º, we get:

       [tex]F =\sqrt{2.81 N ^{2} +2.81 N ^{2} + 2*2.81N* 2.81N* cos 46} = 5.17 N (2)[/tex]


You carry a 50 N backpack for 10000 meters in 500 secs. How much power did
you use?

Answers

for cara a 50+10000=9768m in for 500×9768=586858metres

R:1.0000000000.

The work done by the force of 50 N for a displacement of 10000 m is 500000 J. Then the power is 250 × 10⁷ W.

What is work done?

Work done in physics is the product of force and displacement of an object. If a force applied on an object results in a displacement the force is said to be done some work on the object.

Work done W = F.ds

Given F = 50 N

displacement = 10000 m

Then w = 50 N × 10000 m = 500000 J

Power is the rate of energy or work needed to bring a displacement in an object. It is the product of work done and time.

w = 500000 J

time = 500 s

then power = w. t

p = 500000 J × 500 s = 250 × 10⁷ W

Therefore, the power of the action is 250 × 10⁷ W.

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A 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m. A constant frictional force, introduced at point A, brings the block to rest at point B, 19 m to the right of point A. What is the speed of the box just before it reaches point A

Answers

I'm going to assume that, judging by the fact that the coefficient of friction and angle of the incline seem to be intentionally left out, the point A refers to a point at the bottom of the incline, and the point B is located 19 m away from A on a horizontal surface. If this is not the case, please be sure to correct me!

Let v denote the speed of the box at point A, x the distance the box slides (without friction) down the incline, and θ the angle of the incline.

Recall that

v ² - v₀² = 2 ax

where

v = final speed

v₀ = initial speed

a = acceleration

x = displacement

While on the incline, the box starts at rest (v₀ = 0) and slides a distance x from the starting point to point A with acceleration a to attain some speed v.

Use the free body diagram to determine the acceleration. By Newton's second law, the net force on the object acting parallel to the incline

F = m g sin(θ) = m a   →   a = g sin(θ)

where m = 9.0 kg and g = 9.8 m/s².

Write the distance x in terms of θ with some trigonometry:

sin(θ) = (5.0 m) / x   →   x = (5.0 m) / sin(θ)

Now plug a and x into the formula above to solve for v :

v ² = 2 g sin(θ) ((5.0 m) / sin(θ))

v ² = (10.0 m) g

v9.9 m/s

A person lying on an air mattress in the ocean rises and falls through one complete cycle every five seconds. The crests of the wave causing the motion are 20.0 mapart. Determine (a) the frequency and (b) the speed of the wave. (Cutnell 16.6)

Answers

Answer:

a) the frequency of the wave is 0.2 Hz

b) the speed of the wave 4 m/s

Explanation:

Given that;

time period = to complete one cycle t = 5 sec

frequency f = 1/t

frequency f = 1 / 5sec

f = 0.2 Hz

Therefore the frequency of the wave is 0.2 Hz

b)

speed of wave V = λf

given that our wavelength is 20.0 m

we substitute

speed of wave V = 20.0 × 0.2

speed of wave V = 4 m/s

Therefore, the speed of the wave 4 m/s

Which statements correctly describe the formula or name of a compound? Select all that apply.
OA. The formula of nitrogen trifluoride is NF 3
B. The formula of ammonia is NH3.
C. The name of AlF, is trialuminum fluoride.
D. The formula of calcium chloride is CaCl2
E. The name of Li, Se is lithium selenate.
OF. The formula of dinitrogen monoxide is NO
2
Results
G. The formula of sulfur trioxide is 30.
Cho
Аа
H. The formula of magnesium hydroxide is Mg(OH)2
G.

Answers

Answer:

A, B, D, and H

Explanation:

Statements A, B, D and H are all correct except the following:

Statement C is incorrect. The name of [tex] AlF_3 [/tex] is aluminium fluoride NOT "trialuminium fluoride".

Statement E is incorrect. The name of [tex] Li_2Se [/tex] is lithium selenide NOT "lithium selenate".

Statement F is incorrect. Dinitrigen monoxide, also known as nitrous oxide has a formula of [tex] N_2O [/tex] NOT [tex] NO_2 [/tex].

Statement G is incorrect. Sulfur trioxide formula is [tex] SO_3 [/tex].

If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the ideal speed to take a 100 m radius curve banked at 15.0o. (b) What is the minimum coefficient of friction needed for a frightened dri

Answers

Answer:

a) The ideal speed = 16.21 m/s

b) Minimum co-efficient of friction = 0.216

Explanation:

From the given information:

The ideal speed can be determined by considering the centrifugal force component and the gravity component.

[tex]\dfrac{mv^2}{r}cos \theta = mg sin \theta[/tex]

[tex]v = \sqrt {gr \ tan \theta}[/tex]

[tex]= \sqrt{(9.8 \ m/s^2) (100) \ tan 15^0}[/tex]

= 16.21 m/s

(b)

Let assume that it requires 25 km/h to take the same curve.

Then, using the equilibrium conditions;

[tex]mg \ sin \theta = \dfrac{mv^2}{r} cos \theta + \mu ((\dfrac{mv^2}{r}) sin \theta + mg cos \theta)[/tex]

[tex]\mu = \dfrac{mg sin \theta - \dfrac{mv^2}{r} cos \theta }{((\dfrac{mv^2}{r}) sin \theta + mg cos \theta) }[/tex]

[tex]\mu = \dfrac{g sin \theta - \dfrac{ v^2}{r} cos \theta }{((\dfrac{v^2}{r}) sin \theta + g cos \theta) }[/tex]

[tex]\mu = \dfrac{(9.8 \ m/s^2 ) sin (15^0) - \dfrac{ \dfrac{(25 \times 10^3}{3600} \ m/s)^2 }{100 \ m } cos (15^0) }{((\dfrac{(\dfrac{25 \times 10^3}{3600} )^2}{100}) sin 15^0 + (9.8 \ m/s^2) cos 15^0 ) }[/tex]

[tex]\mathbf{\mu = 0.216}[/tex]

A 56-kg woman contestant on a reality television show is at rest at the south end of a horizontal 149-kg raft that is floating in crocodile-infested waters. She and the raft are initially at rest. She needs to jump from the raft to a platform that is several meters off the north end of the raft. She takes a running start. When she reaches the north end of the raft she is running at 4.2 m/s relative to the raft. At that instant, what is her velocity relative to the water

Answers

Answer:

3.04 m/s

Explanation:

As the woman moves north, the raft moves south.

We then make the following assumptions for easier calculations

Let the motion of the woman = x

Let the motion of the raft = 4.2 - x

Using law of momentum, we see that

m*v = m1*v1, where

m = 56 kg

v = x

m1 = 149 kg

v1 = (4.2 -x)

Substituting the values into the equation, we have

56 * x = 149 (4.2 - x), opening the bracket

56x = 623 - 149x collecting like terms

205x = 623 Divide by 205

x = 623/205

x = 3.04 m/s

This then means that our answer is 3.04 m/s

A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fast!!!)

Answers

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

An athlete runs on track at a constant speed of 75 meters/min for 15 s. What is the total distance he covered during that time?

Answers

Answer:

45

Explanation:

A 10 kg box initially at rest moves along a frictionless horizontal surface. A horizontal force to the right is applied to the box.A student calculates the impulse applied by force during the 2 seconds is 4 N.s. and that the impulse applied during the following 3 seconds is 6 Nâs.

Required:
a. What, if anything, is wrong with these calculations? If something is wrong, identify it and explain how to correct it. If these calculations are correct, explain why?
b. What is the difference between a perfectly elastic and an inelastic collision?

Answers

Answer:

The answer is below

Explanation:

a) Impulse is the total effect of force which has been acting on a body over a period of time. Impulse is the product of the force and the period of time applied. It is given by:

Impulse = force × time

Given that during 2 seconds, the impulse is 4 Ns, we can calculate the force applied.

Impulse = force × change in time

4 = force * 2

force = 4 / 2 = 2 N.

Hence the impulse applied during the following 3 seconds is:

Impulse = force × change in time = 2 * (2 + 3) = 2 * 5 = 10 Ns

The impulse applied during the following 3 seconds is 10 Ns not 6 Ns

b) In perfectly elastic collision, there is no loss in kinetic energy while in an inelastic collision there is loss in kinetic energy due to energy conversion or transfer.

In perfectly elastic collision the object does not stick together while in an inelastic collision the object stick together.

Determine the gravitational field of Earth at a height 2.88 x 10^8 m above its surface (the height of the moon above Earth). Earth's mass is 6.0 x 10^24 kg and its radius is 6.4 x 10^6 m.

Answers

Answer:

12

Explanation:

A toy car, mass of 0.025 kg, is traveling on a horizontal track with a velocity of 5 m/s. If
the track then starts to climb upwards, how high up the track can the car reach?

Answers

Answer:

1.25 m

Explanation:

This is the vertical height not the distance along the slope.

[tex]K=U\\\frac{1}{2}mv^{2} = mgh\\h = \frac{v^{2}}{2g}=\frac{25}{20}=1.25 m[/tex]

The height the car can reach if the the track starts to climb upwards is 1.2742 meters up.

What is kinetic and potential energy?

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or its relation with its surrounding systems.

P.E. = mass × g × height

K.E. = 0.5 × mass × (velocity)²

Given that the toy car has a mass of 0.025 kg and is traveling on a horizontal track with a velocity of 5 m/s. Now, the car starts to climb up vertically, therefore, the kinetic energy will be converted to potential energy.

Kinetic Energy = Potential Energy

0.5 × mass × (velocity)² = mass × g × height

Cancel mass from both the sides,

0.5 × (velocity)² = g × height

0.5 × (5 m/s)² = 9.81 m/sec² × height

height = 1.2742 meters

Hence, the car will travel 1.2742 meters up.

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Suppose the posted designated speed for a highway ramp is to be 30 mph and the radius of the curve is 700 ft. At what angle must the curve be banked? No Friction

Answers

Answer:

4.92°

Explanation:

The banking angle θ = tan⁻¹(v²/rg) where v = designated speed of ramp = 30 mph = 30 × 1609 m/3600 s = 13.41 m/s, r = radius of curve = 700 ft = 700 × 0.3048 m = 213.36 m and g = acceleration due to gravity = 9.8 m/s²

Substituting the variables into the equation, we have

θ = tan⁻¹(v²/rg)

= tan⁻¹((13.41 m/s)²/[213.36 m × 9.8 m/s²])

= tan⁻¹((179.8281 m²/s)²/[2090.928 m²/s²])

= tan⁻¹(0.086)

= 4.92°

fired, the ball moves 15.9 cm through the horizontal barrel of the cannon, and the barrel exerts a constant friction force of 0.032 8 N on the ball. (a) With what speed does the projectile leave the barrel of the cannon

Answers

Answer:

Explanation:

Where is the remaining part of the question? This is a very easy one

100 POINTS. PLEASE EXPLAIN

Answers

Answer:

Explanation:

Note the charge balls on the top and bottom row are identical. So those charges cancel each other out. The only charges in the net electric field are the two in the middle row.

Electric field strength = k*Q/r^2

= (8.99 *10^9) * (3-(-3)) * 5*10^(-6) / (2*0.5)^2

= 269700 N/C

Answer:

Explanation:

(b) cuz the 1st n 3nd row cancel out, net electric field will go from +3Q to -3Q. the direction is right.

1. Amy uses 30N of force to push a lawn mower 10 meters. How much work does she do?

Answers

Work=300J (basically multiplying)

A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have the same uniform mass density. The orbit of each planet is circular.

In the observed planetary system, Planet A orbits the central star at the distance of 2R and takes T hours to complete one revolution around the star. Planet B orbits the central star at the distance of R. Which of the following expressions is correct for the number of hours it takes Planet B to complete one revolution around the star?

a. 1/â8T
b. 1/2T
c. 1/3â4T
d. 2T
e. â8T

Answers

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

The correct expression for the number of hours it takes Planet B to complete one revolution around the star is [tex]\frac{T}{\sqrt{8} }[/tex].

The given parameters;

position of planet A from central star, = 2Rtime taken for Planet A = Tnumber of revolutions at the given time = 1 revposition of planet B from central star, = R

From Kepler's law, the period of planet is related to radius as follows;

[tex]\frac{T_1^2}{R_1^3} = \frac{T_2^2}{R_2^3} \\\\T_2 ^2 = \frac{T_1^2 \times R_2^3}{R_1^3} \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} } \\\\T_2 = \sqrt{\frac{T_1^2 \times R_2^3}{R_1^3} }\\\\T_2 = T_1 \sqrt{\frac{ R_2^3}{(2R_2)^3} }\\\\T_2 = T_1 \sqrt{\frac{R_2^3}{8R_2^3} } \\\\T_2 = T_1 \sqrt{\frac{1}{8} } \\\\T_2 = \frac{T_1}{\sqrt{8} }\\\\T_B = \frac{T_A}{\sqrt{8} } = \frac{T}{\sqrt{8} }[/tex]

Thus, the correct expression for the number of hours it takes Planet B to complete one revolution around the star is [tex]\frac{T}{\sqrt{8} }[/tex].

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A 2.0 kg block of ice with a speed of 8.0 m/s makes an elastic collision with another block of ice that is at rest. The first block of ice proceeds in the same direction as it did initially, but with a speed of 2.0 m/s. What is the mass of the second block? (Hint: Use the conservation of kinetic energy to solve for the second unknown variable.)

Answers

Answer:

6kg

Explanation:

According to conservation of kinetic energy

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses of the bodies

u1 and u2 are the initial velocities

v is the final velocity

Given

m1 =2kg

u1 = 8.0m/s

m2 = ?

u2 = 0m/s (second ice at rest)

v = 2.0m/s

Substitute into the formula

2(8)+m2(0) = (2+m2)(2)

16+0 = 4+2m2

16-4= 2m2

12 = 2m2

m2 =12/2

m2 = 6kg

Hence the mass of the second block is 6kg

3.
A person drives north 6 blocks, then drives west 6 blocks.
The displacement is a straight line from the starting point to the finish in a
direction
O A northwesterly
O B southwesterly
O c northeasterly
OD southeasterly

Answers

The answer is c northeasterly because it goes through the middle of those two
Other Questions
plllllllllzzzzzzzzzzzzzzzzz helpppp meeeeeeeeeeeeeeeeeee There are 10 different verbs and 16 total in the song. Listen to the following song: the second time that you listen to it, identify the imperfect tense on the lyrics and make a list with all the verbs in the imperfect tense.go to u tube and search ADALBERTO ALVAREZ. "LA FALTA DE ORTOGRAFIA". ALBUM "EL SON DE ALTURA" 2010. and click the first one1. 6.2. 7.3. 8.4. 9.5. 10. You know, sometimes having the ability to look into the future isn't all that great.QuestionAn author using this sentence to begin a story is using what literary device?Answer options with 4 options1. flashback2. imagery3. symbolism4. foreshadowing Jim is making frozen juice treats that are in the shape of a cone. The molds he bought are each 3 inches (in.) deep with a diameter of 3 in. What is the approximate volume of juice needed for Jim to make 6 juice treats? At Mario's restaurant, 59% of his plates are dirty. If there are 118 dirty plates, how many plates are there total? Below are the rates of travel of 4 shipping trucks. Which truck drove the fastest rate? Truck A: 300 miles in 4 hours Truck B: 240 miles in 3 hours Truck C: 325 miles in 5 hours Truck D: 170 miles in 2 hours a Truck A b Truck B c Truck C d Truck D The narrator is best characterizedas...Tell-take heart and Marianne designs an experiment involving electrically charged objects. She wants to know which objects will be attracted to a negatively charged balloon. Identify the test variable, the outcome variable, and the control variable for this experiment.WILL GIVE BRAINIST A projectile is launched with an initial velocity of200 meters per second at an angle of 30 above thehorizontal. What is the magnitude of the verticalcomponent of the projectile's initial velocity by?(1) 200 m/s x cos 30(2) 200 m/s X sin 30(3) (200 m/s)/(cos 30 )(4) (200 m/s)/(sin 30 ) Graph AB with endpoints A(-2,5) and B( 4, 2) and its image after the composition. Answer: d Explanation: Hope this helps pzzzz marke brainliest Cross a person who does not have freckles and is heterozygous for dimples with a person who hasfreckles (but her mom does not) but no dimples.1. What is the probability that these parents will have a child with dimples?2. What is the probability that these parents will have a child with freckles?3. What is the probability that these parents will have a child with dimples and freckles? Help for Spanish please True or False Resources like fossil fuels, water, and minerals are evenly distributedthroughout the Earth.pls show your work thx :) What is the volume of a sphere with a radius of 34.2 m, rounded to the nearest tenthof a cubic meter? help plz will give brainliest also it either A or D and show your work if u can Read this passage from The Jungle Book. There was very little talking at the Rock. The cubs tumbled over one another in the center of the circle where their mothers and fathers sat, and now and again a senior wolf would go quietly up to a cub, look at him carefully, and return to his place on noiseless feet. Sometimes a mother would push her cub far out into the moonlight, to be sure that he had not been overlooked. Akela from his rock would cry: "Ye know the Lawye know the Law! Look well, O Wolves!" And the anxious mothers would take up the call: "Looklook well, O Wolves!" How are the mother wolves affected by the Law of the Jungle? They ignore their cubs at the top of Council Rock. They sometimes push their cubs away if they are naughty. They tumble over the cubs in the circles center. They are careful to show their cubs to Pack leaders. which expression is equivalent to -15x + 39a. -3(5x-13)b. -3(5x+13)c. 3(5x-13)d. 3(5x+13) Help please!! What is the distance between these points? (-7, 6) and (3, 6)Y'all get 12 points if you help! :) Are 2z2 and 4z like terms? Why or whynot?A: Yes, they both have exponents.B: Yes, they both have a Z.C: No, one has an exponent and the other does not.