we need to add 64 on both sides and required equation is x=-8±2√5-8
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The given equation is x²+16x=-44
Now we need to make the coefficient of x variable half and to square it.
(16/2)²=8²=64
Now add 64 on both the sides
x²+16x+64=-44+64
x²+16x+64=20
(x+8)²=20
x+8=±√20
x+8=±2√5
Now subtract 8 on both sides
x=-8±2√5-8
Hence, we need to add 64 on both sides and required equation is x=-8±2√5-8
To learn more on Equation:
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What is the quotient? StartFraction 7 Superscript negative 4 Over 7 Superscript negative 9 EndFraction
Answer:
19
Step-by-step explanation:
7 supersricpt 8
A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measure his/her reading ability. You are interested in calculating a 95% confidence interval for the population mean score. In the sample, the mean score is 64 points, and the standard deviation is 12 points. What is the margin of error associated with the confidence interval
Answer:
Margin of Error = ME =± 5.2592
Step-by-step explanation:
In the given question n= 20 < 30
Then according to the central limit theorem z test will be applied in which the standard error will be σ/√n.
Sample Mean = μ = 64
Standard Deviation= S= σ = 12
Confidence Interval = 95 %
α= 0.05
Critical Value for two tailed test for ∝= 0.05 = ±1.96
Margin of Error = ME = Standard Error *Critical Value
ME = 12/√20( ±1.96)=
ME = 2.6833*( ±1.96)= ± 5.2592
The standard error for this test is σ/√n
=12/√20
=2.6833
A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age?
Hey there! I'm happy to help!
We see that the father is 60 years old, and the son is half of that age, so this means that the son is 30 years old.
We want to see the age the son was at when the father was four times his age. We know that the father is thirty years older than him, so we can write this equation with s representing the age of the son.
s+30=4s (30 years older than the son is equal to to four times the son's age at the time)
We subtract 30 from both sides.
s=4s-30
We subtract 4s from both sides.
-3s=-30
We divide both sides by -3.
s=10
Therefore, the boy was 10 when his father was four times his age. This is because his father would have been 40 because that is 30 more years than 10, and it is four times ten!
Have a wonderful day! :D
A hospital found that a lower outside temperature indicates a higher number of patient visits. What can we determine from this
Information?
Answer:
Second Answer
Step-by-step explanation:
For the functions f(x)=4x−3 and g(x)=3x2+4x, find (f∘g)(x) and (g∘f)(x).
Answer:
(16x + 21) and (16x - 6)
Step-by-step explanation:
f(g(x)) = f(6 + 4x)
Applying the f(x) function on (6 + 4x) gives
4(6 + 4x) - 3
Which equals 16x + 24 - 3
= 16x + 21
g(f(x)) = g(4x - 3)
Applying the g(x) function on (4x - 3) gives
6 + 4(4x - 3)
Which equals 6 + 16x - 12
= 16x - 6
Answer:
(g∘f)(x)=48x2+48x+10
(g∘f)(x)=12x^2-6
Step-by-step explanation:
To find (f∘g)(x), use the definition of (f∘g)(x),
(f∘g)(x)=f(g(x))
Substituting 3x2−2 for g(x) gives
(f∘g)(x)=f(3x2−2)
Find f(3x2−2), where f(x)=4x+2, and simplify to get
(f∘g)(x)(f∘g)(x)(f∘g)(x)=4(3x2−2)+2=12x2−8+2=12x2−6
To find (g∘f)(x), use the definition of (g∘f)(x),
(g∘f)(x)=g(f(x))
Substituting 4x+2 for f(x) gives
(g∘f)(x)=g(4x+2)
Find g(4x+2), where g(x)=3x2−2, and simplify to get
(g∘f)(x)=3(4x+2)^2−2
(g∘f)(x)=48x2+48x+12−2
(g∘f)(x)=48x2+48x+10
Whal value of x is in the solution set of 9(2x + 1) < 9x - 18?
A: -4
B: -3
C: -2
D: -1
Answer:
A:-4
Step-by-step explanation:
If you simplify 9(2x+1)<9x-18 you will get 9x<-27. That will mean x<-3 and the only answer for something less than -3 is -4.
If the answer was right, please put 5 stars.
Answer:
The answer would be-4
Step-by-step explanation:
Here,
9(2x+1) < 9x-18
or, 18x+9 < 9x-18
or, 18x-9x<-18-9
or, 9x<-27
or, x= -27/9
Therefore, the value of x is -4.
Hope it helps...
determining the probability of events. please help :)
Answer:
C. 1/8
Step-by-step explanation:
Probability of shooting a goal on a throw is 2/4 = 1/2.
Probability of 3 in a row is (1/2)³ = 1/8.
What will happen to the median height of the outlier is removed?
{75, 63, 58, 59, 63, 62, 56, 59)
Answer:
The meadian decreases by 1.5 when the outlier is removed.
Step-by-step explanation:
Well first we need to find the median of the following data set,
(75, 63, 58, 59, 63, 62, 56, 59)
So we order the set from least to greatest,
56, 58, 59, 59, 62, 63, 63, 75
Then we cross all the side numbers,
Which gets us 59 and 62.
59 + 62 = 121.
121 / 2 = 60.5
So 65 is the median before the outlier is removed.
Now when we remove the outlier which is 75.
Then we order it again,
56, 58, 59, 59, 62, 63, 63
Which gets us 59 as the median.
Thus,
the median height decreases by 1.5 units when the outlier is removed.
Hope this helps :)
Over the last three evenings, Melissa received a total of 126 phone calls at the call center. The first evening, she received 6 more calls than the third evening. The second evening, she received 4 times as many calls as the third evening. How many phone calls did she receive each evening? Number of phone calls the first evening: Number of phone calls the second evening: Number of phone calls the third evening:
Answer:
calls first evening = 26
calls second evening = 80
calls third evening = 20
Step-by-step explanation:
Let x = calls third evening
x+6 = calls first evening
4x = calls second evening
x+6 + 4x + x = total calls = 126
Combine like terms
6x+6 = 126
Subtract 6 from each side
6x =120
Divide by 6
6x/6 =120/6
x = 20
x+6 = calls first evening = 20+6 = 26
4x = calls second evening = 4*20 = 80
Let x = calls third evening = 20
A tool rental store charges a flat fee of $10.00 to rent a chain saw, and $4.25 for each day, including the first. Write an equation that expresses the cost y of renting this saw if it is rented for x days.
Answer:
y= 4.25x + $10
Step-by-step explanation:
A tool rental shop charges a flat fee of $10.00 to rent out their chain saw
An amount of $4.25 is charged for each of the days
Let x represent the amount that is charged for each day
Let y represent the total cost of the chain saw
Since the rental fee for each day is given as $4.25 and the flat fee is given as $10 then, the equation can be expressed as
y= $4.25x + $10
Hence the equation that expresses the cost y of renting this saw if it is rented for x days is y= $4.25x + $10
7.
The area of this parallelogram is 120 ft. Find the value of h.
1
20 ft
12 ft
3 ft
15 ft
6 ft
Answer:
h = 6 ft.Step-by-step explanation:
area = base x height
where base = 20 ft.
height = ?
area = 120 ft²
plugin values into the formula
120 = 20 x height
height = 120
20
height = 6 ft.
For what value of k are the roots of the quadratic equation kx (x-2)+6=0 equal?
Answer:
[tex]\boxed{\sf k=6}[/tex]
Step-by-step explanation:
[tex]\sf kx (x-2)+6=0[/tex]
Expand brackets.
[tex]\sf kx^2 -2kx+6=0[/tex]
This is in quadratic form.
[tex]\sf ax^2 +bx+c=0[/tex]
Since this is for equal roots:
[tex]\sf b^2 -4ac=0[/tex]
[tex]\sf a=k\\b=-2k\\c=6[/tex]
[tex]\sf (-2k)^2 -4(k)(6)=0[/tex]
[tex]\sf 4k^2-24k=0[/tex]
[tex]\sf 4k(k-6)=0[/tex]
[tex]\sf 4k=0\\k=0[/tex]
[tex]\sf k-6=0\\k=6[/tex]
Plug k as 0 to check.
[tex]\sf \sf 0x^2 -2(0)x+6=0\\6=0[/tex]
False.
So that means k must equal 6.
Find the value of n such that 540n is perfect cube.
Answer:
1.35
Step-by-step explanation:
next cube above 540 is 729
to get to 729: 729 / 540 = 1.35
n = 1.35
A 24-centimeter by 119-centimeter piece of cardboard is used to make an open-top box by removing a square from each corner of the cardboard and folding up the flaps on each side. What size square should be cut from each corner to get a box with the maximum volume
Answer:
The size square removed from each corner = 32.15 cm²
Step-by-step explanation:
The volume of the box = Length * Breadth * Height
Let r be the size removed from each corner
Note that at maximum volume, [tex]\frac{dV}{dr} = 0[/tex]
The original length of the cardboard is 119 cm, if you remove a size of r (This typically will be the height of the box) from the corner, since there are two corners corresponding to the length of the box, the length of the box will be:
Length, L = 119 - 2r
Similarly for the breadth, B = 24 - 2r
And the height as stated earlier, H = r
Volume, V = L*B*H
V = (119-2r)(24-2r)r
V = r(2856 - 238r - 48r + 4r²)
V = 4r³ - 286r² + 2856r
At maximum volume dV/dr = 0
dV/dr = 12r² - 572r + 2856
12r² - 572r + 2856 = 0
By solving the quadratic equation above for the value of r:
r = 5.67 or 42
r cannot be 42 because the size removed from the corner of the cardboard cannot be more than the width of the cardboard.
Note that the area of a square is r²
Therefore, the size square removed from each corner = 5.67² = 32.15 cm²
A= 63°
C = 7.75 inch
B = 47°
Oblique Triangle
4. Refer to the oblique triangle shown. What's the size of angle C?
O A. 60°
B. 125°
O C. 45°
O D. 70°
Answer:
Option D is correct.
Angle C = 70°
Step-by-step explanation:
The sum of angles in a triangle = 180°
So,
(Angle A) + (Angle B) + (Angle C) = 180°
(Angle A) = 67°
(Angle B) = 43°
(Angle C) = ?
67° + 43° + (Angle C) = 180°
Angle C = 180 - 67 - 43 = 70°
Angle C = 70°
Hope this Helps!!!
The price of a boat that Arthur wants is $29,450. Arthur finances this by paying $6000 down and monthly payment of $792.22 for 36 months.
a. Determine the amount to be financed.15a. _______________
b. Determine the installment price.b. _________________
c. Determine the finance charge.c. _________________
Answer:
see details below
Step-by-step explanation:
The price of a boat that Arthur wants is $29,450. Arthur finances this by paying $6000 down and monthly payment of $792.22 for 36 months.
a. Determine the amount to be financed.15a. ___$23450____________
29450 - 6000 = 23450
b. Determine the installment price.b. ___$792,22______________
"monthly payment of $792.22"
c. Determine the finance charge.c. __$5069.92_______________
A = 792.22
n = 36
finance charge = total paid - amount to be financed
= 36*792.22 - 23450
= 5069.92
Need answers ASAP!!!!! (due today)
Answer:
15) 2.08m
Step-by-step explanation:
We kow tanA= p/b
Here, A=33°
b=3.2m
Then,
tan33°=p/3.2
0.65=p/3.2
p=0.65*3.2
p=2.08
So, The height of tree is 2.08m
14) 59.58ft
tan50°=p/b
1.19=p/50
p=59.58ft
So, The height of signpost is 59.58ft
In both of these problems, we will be using trigonometry! Remember, SOH-CAH-TOA.
14. x = 13.5950 ft
Visualization of the problem is attached below.
We want to find out the opposite side to the angle, and we know the adjacent side. Therefore, we should use the tangent function.
tan(50) = x / 50
x = tan(50) * 50
x = 13.5950 ft (round off wherever you need)
15. x = 241.0016 m
The visualization of the problem is already given. We know the same information as we need in the previous problems, an angle and an adjacent side, and we want to find the opposite side. Therefore, we should use the tangent function.
tan(33) = x / 3.2
x = tan(33) * 3.2
x = 241.0016 (round off wherever you need)
Hope this helps!! :)
Families USA, a monthly magazine that discusses issues related to health and health costs, survey 19 of its subscribers. It found that the annual health insurance premiums for a family with coverage through an employer averaged $10,800. The standard deviation of the sample was $1095.
A. Based on the sample information, develop a 99% confidence interval for the population mean yearly premium
B. How large a sample is needed to find the population mean within $225 at 90% confidence? (Round up your answer to the next whole number.)
Answer:
a
$10,151 [tex]< \mu <[/tex] $11448.12
b
[tex]n = 158[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 19
The sample mean is [tex]\= x =[/tex]$10,800
The standard deviation is [tex]\sigma =[/tex]$1095
The population mean is [tex]\mu =[/tex]$225
Given that the confidence level is 99% the level of significance is mathematically represented as
[tex]\alpha = 100 -99[/tex]
[tex]\alpha = 1[/tex]%
=> [tex]\alpha = 0.01[/tex]
Now the critical values of [tex]\alpha = Z_{\frac{\alpha }{2} }[/tex] is obtained from the normal distribution table as
[tex]Z_{\frac{0.01}{2} } = 2.58[/tex]
The reason we are obtaining values for [tex]\frac{\alpha }{2}[/tex] is because [tex]\alpha[/tex] is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while [tex]\frac{\alpha }{2}[/tex] is the area under the normal distribution curve for just one tail and we need the value for one tail in order to calculate the confidence interval
Now the margin of error is obtained as
[tex]MOE = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]MOE = 2.58* \frac{1095 }{\sqrt{19} }[/tex]
[tex]MOE = 648.12[/tex]
The 99% confidence interval for the population mean yearly premium is mathematically represented as
[tex]\= x -MOE < \mu < \= x +MOE[/tex]
substituting values
[tex]10800 -648.12 < \mu < 10800 + 648.12[/tex]
[tex]10800 -648.12 < \mu < 10800 + 648.12[/tex]
$10,151 [tex]< \mu <[/tex] $11448.12
The largest sample needed is mathematically evaluated as
[tex]n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{\mu} ][/tex]
substituting values
[tex]n = [ \frac{ 2.58 * 1095}{225} ]^2[/tex]
[tex]n = 158[/tex]
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts.
Diet Regular
μ μ1 μ2
n 20 20
x 0.78062lb 0.81645 lb
s 0.00444 lb 0.00745 lb
A. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.
What are the null and alternative and hypotheses?
B. What is the test statistic? (Round to two decimal places as needed.)
C. What is the P-value? (Round to three decimal places as needed.)
State the conclusion for the test.
A. Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
D. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
b. Construct a confidence interval appropriate for the hypothesis test in part (a).
___lb < u1 - u2 < ___lb (Round to three decimal places as needed.)
Does the confidence interval support the conclusion found with the hypothesis test?
(No/Yes) because the confidence interval contains (zero/only positives values/ only negative values)
Answer:
(A) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex]
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex]
(B) The value of t-test statistics is -18.48.
(C) The P-value is Less than 0.005%.
(D) Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.
Step-by-step explanation:
We are given that the Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right;
Diet Regular
μ μ1 μ2
n 20 20
x 0.78062lb 0.81645 lb
s 0.00444 lb 0.00745 lb
Let [tex]\mu_1[/tex] = mean weight of contents of cans of diet soda.
[tex]\mu_2[/tex] = mean weight of contents of cans of regular soda.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \geq \mu_2[/tex] {means that the contents of cans of diet soda have weights with a mean that is more than or equal to the mean for the regular soda}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1<\mu_2[/tex] {means that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda}
The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;
T.S. = [tex]\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ~ [tex]t__n_1_+_n_2_-_2[/tex]
where, [tex]\bar X_1[/tex] = sample mean weight of cans of diet soda = 0.78062 lb
[tex]\bar X_2[/tex] = sample mean weight of cans of regular soda = 0.81645 lb
[tex]s_1[/tex] = sample standard deviation of cans of diet soda = 0.00444 lb
[tex]s_2[/tex] = sample standard deviation of cans of regular soda = 0.00745 lb
[tex]n_1[/tex] = sample of cans of diet soda = 20
[tex]n_2[/tex] = sample of cans of diet soda = 20
Also, [tex]s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(20-1)\times 0.00444^{2}+ (20-1)\times 0.00745^{2}}{20+20-2} }[/tex] = 0.00613
So, the test statistics = [tex]\frac{(0.78062-0.81645)-(0)}{0.00613 \times \sqrt{\frac{1}{20}+\frac{1}{20} } }[/tex] ~ [tex]t_3_8[/tex]
= -18.48
The value of t-test statistics is -18.48.
Also, the P-value of the test statistics is given by;
P-value = P( [tex]t_3_8[/tex] < -18.48) = Less than 0.005%
Now, at a 0.01 level of significance, the t table gives a critical value of -2.429 at 38 degrees of freedom for the left-tailed test.
Since the value of our test statistics is less than the critical value of t as -18.48 < -2.429, so we have sufficient evidence to reject our null hypothesis as it will not fall in the rejection region.
Therefore, we conclude that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda.
HELPPPPPP !!!!!!!!!!!!
! 25 ~! points
Which graph best models the inequality y<_ -2/5x+2
Answer:
Step-by-step explanation:
Simplify each term.
y ≤ −2x/5 + 2
Find the slope and the y-intercept for the boundary line.
Slope: -2/5
Y-intercept: 2
Graph a solid line, then shade the area below the boundary line since
y is less than -2x/5 + 2
y ≤ −2x/5 + 2
Hope this can help
What is 3/4 improper or proper or mixed
Answer:
proper because the numerator is lower than the denominator
What is the measure of JOK, given that GH=JK ?
A.
288
B.
108
C.
72
D.
18
Answer:
72 degrees.
Step-by-step explanation:
The angle marked as 72 degrees and the angle of JOK are considered vertically opposite angles in relation to each other. This relationship means that the angles are equal.
Answer:
[tex]\boxed{Option \ C}[/tex]
Step-by-step explanation:
Congruent arcs subtend congruent central angles.
So,
∠GOH ≅ ∠JOK
∠JOK = 72 degrees
A toy falls from a window 70 feet above the ground. How long does it take the toy to hit the ground?
Answer:
2.09 seconds.
Step-by-step explanation:
We are given...
y = 70 feet
v0 = 0 feet/second
a = 32 feet/second^2
We need to find t using the following equation...
y = v0 * t + (1/2) * a * t^2
70 = 0 * t + (1/2) * 32 * t^2
70 = (1/2) * 32 * t^2
70 = 16t^2
16t^2 = 70
t^2 = 4.375
t = sqrt(4.375)
t = 2.091650066
So, it will take the toy about 2.09 seconds to hit the ground.
Hope this helps!
What is the degree of the polynomial?
Answer:
2
Step-by-step explanation:
The degree of this polynomial is 2, since a parabola is drawn. A parabola is a graph of a quadratic equation which has the highest degree of 2.
what is 1.8÷0.004? using long division
Answer:
Hi! Answer will be below.
Step-by-step explanation:
The answer is 450.
If you divide 1.8 and 0.004 the answer you should get is 450.
Below I attached a picture of how to do long division...the picture is an example.
Hope this helps!:)
⭐️Have a wonderful day!⭐️
by what number 7whole 2/3be divided to get 4whole1/3
Answer: 1 30/39
Step-by-step explanation:
Because y/x=z and y/z=x are true with the same values, simply do 7 2/3 divided by 4 1/3 to get 69/39.
Hope it helps <3
M angle D=? What is the degree of the angle?
Answer:
80°Step-by-step explanation:
In ACB and ECD
AC =~ CE [ Given ]
BC =~ CD [ Given ]
<ACD =~ <ECD [ Vertical angles ]
Hence, ∆ ACB =~ ECD by SAS congruency of triangles.
Then, <B = <D
In ∆ABC , sum of all three angles must be 180°
<A + <B + <C = 180°
plug the values
[tex] 30 + < d \: + 70 = 180[/tex]
Add the numbers
[tex]100 + < d = 180[/tex]
Move constant to R.H.S and change it's sign
[tex] < d = 180 - 110[/tex]
Subtract the numbers
[tex] < d = 80[/tex] °
Hope this helps..
Best regards!!
Various studies indicate that approximately 11% of the world's population is left handed. You think this number is actually higher. You take an SRS of 225 people and find that 31 of them are left handed. Test your claim at the 5% significance level.
A. State your null and alternative hypotheses.
B. Sketch the rejection region.
C. Calculate the test statistic.
D. Determine the P-value for your test.
Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
What is the inequality
Answer:
x ≥ 4
Step-by-step explanation:
Well to find the inequality we need to single out x,
4x - 1 ≥ 15
+1 to both sides
4x ≥ 16
Divide 4 by both sides
x ≥ 4
Thus,
x is greater than or equal to 4.
Hope this helps :)