15. A manufacturer of electronic calculators is interested in estimating the fraction of defective units produced. A random sample of 800 calculators contains 10 defectives. a. Formulate and test the hypothesis to determine if the fraction defective exceeds 0.01. Use 0.05 significance level. b. Calculate a 95% CI for this problem. Does the CI agreed with your result on (a) explain.

Answers

Answer 1

Answer:

a

   The Null hypothesis is  [tex]H_o : p = 0.01[/tex]

   The defect did not exceed 0.01

b

   The  95%  confidence interval is   [tex]0.004801 < p < 0.020199[/tex]

   Yes the CI agrees with the result in a  because the value 0.01 fall within the CI

Step-by-step explanation:

From the question we are told that

     The sample size is  n = 800

      The number of defective calculators is  k =  10

       The population is  [tex]p = 0.01[/tex]

The Null hypothesis is  [tex]H_o : p = 0.01[/tex]

The Alternative hypothesis is  [tex]H_a : P> 0.01[/tex]

Generally the proportion of defective calculators is mathematically represented as

         [tex]\r p = \frac{k}{n}[/tex]

substituting values

          [tex]\r p = \frac{10}{800}[/tex]

          [tex]\r p = 0.0125[/tex]

Next is to obtain the critical value of  [tex]\alpha[/tex] from the z-table.The  value is  

          [tex]Z_{\alpha } = 1.645[/tex]

Now the test statistics is mathematically evaluated as

        [tex]t = \frac{\r p - p }{ \sqrt{ \frac{p (1- p )}{n} } }[/tex]

substituting values

          [tex]t = \frac{ 0.0125 - 0.01 }{ \sqrt{ \frac{0.01 (1- 0.01 )}{800} } }[/tex]

           [tex]t = 0.71067[/tex]

Now comparing the values of  t to the value of [tex]Z_{\alpha }[/tex] we see that [tex]t < Z_{\alpha }[/tex] hence we fail to reject the null hypothesis

Generally the margin of error is mathematically represented as  

       [tex]E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1-\r p )}{n} }[/tex]

where  [tex]Z_{\frac{\alpha }{2} }[/tex] is the critical value of  [tex]\frac{\alpha }{2}[/tex] which is obtained from the z-table.The  value is

              [tex]Z_{\frac{\alpha }{2} } = Z_{\frac{0.05 }{2} } = 1.96[/tex]

The reason we are obtaining critical value of    [tex]\frac{\alpha }{2}[/tex]  instead of    [tex]\alpha[/tex] is because    [tex]\alpha[/tex]

represents the area under the normal curve where the confidence level interval (   [tex]1- \alpha[/tex] ) did not cover which include both the left and right tail while  

 [tex]\frac{\alpha }{2}[/tex]  is just the area of one tail which what we required to calculate the margin of error .

NOTE: We can also obtain the value using critical value calculator (math dot armstrong dot edu)

So

      [tex]E = 1.96 * \sqrt{\frac{ 0.0125 (1-0.0125 )}{800} }[/tex]

     [tex]E = 0.007699[/tex]

The  95%  confidence interval is mathematically represented as

       [tex]\r p - E < p < \r p - E[/tex]

substituting values

      [tex]0.0125 - 0.007699 < p < 0.0125 + 0.007699[/tex]

      [tex]0.004801 < p < 0.020199[/tex]

Now given the p = 0.01 is within this interval then the CI  agrees with answer gotten in a


Related Questions

An object is moving at a speed of 7300 inches every 3 seconds. Express this speed in miles per day.

Answers

Answer:

≈3318 miles per day....

Step-by-step explanation:

Which equations are equivalent to Three-fourths + m = negative StartFraction 7 over 4 EndFraction? Select three options. m = StartFraction 10 over 4 EndFraction m = negative StartFraction 10 over 4 EndFraction m = negative five-halves StartFraction 11 over 4 EndFraction + m = negative one-fourth Negative five-fourths + m = negative StartFraction 15 over 4 EndFraction

Answers

Answer:

1)  m = negative StartFraction 10 over 4 EndFraction

2) m = negative five-halves

3) m = [tex]-\frac{7}{4} - \frac{3}{4}[/tex]

Step-by-step explanation:

The given equation is:

=> [tex]\frac{3}{4} +m = -\frac{7}{4}[/tex]

Subtracting 3/4 to both sides

=> m = [tex]-\frac{7}{4} - \frac{3}{4}[/tex]

=> m = [tex]\frac{-10}{4}[/tex]

=> m = [tex]-\frac{5}{2}[/tex]

Answer:

-5/2 ye

cause ya do the math

Step-by-step explanation:

Need answers!!!!! ASAPPP

Answers

Answer:

t

Step-by-step explanation:

What is the square root of nine?

Answers

Answer:

3 or -3

Step-by-step explanation:

sqrt(9)

What number multiplied by itself will give you 9

3*3 =9

-3 * -3 =9

The square root of 9 is 3 or -3

In the last year, the population of Japan had a decay rate of 0.17% and decreased to 127,484,450. If this rate continues, what will be the population in 7 more years? Round your answer to the nearest whole number.

Answers

Answer:

125975100 the population in 7 years

Step-by-step explanation:

the population in 7 more years : 127,484450(1-0.0017)^7=125975100.1919 close to 125975100

Answer: 125,976,376 IN 7 YEARS

Step-by-step explanation:

A=127,484,450

R=-0.0017/YEAR

T=7/YEARS

[tex]A=127,484,450E ^{-0.0017.7}[/tex]a=125,976,375.88a=125,976,376 in 7years

Questions:

1. What do you notice about how the angles fit together around a point?

2. What is the measure of a straight angle?

3. Describe the relationship amoung the measure of the angles of ∆ABC

4. The triangle sum theorem states that forma ∆ ABC, m<A + m<A = 180°. Is this true? Explain

Answers

1. The angles form a straight angle

2. A straight angle is defined to be 180 degrees

3. The three angles of any triangle always add to 180, as the diagram shows.

4. This is false. We need to add the three different angles A,B,C to get 180. Adding angle A to itself may not lead to 180. A+A = 180 only happens when angle A is a right angle (90 degree angle).

What is the distance to the earth’s horizon from point P? Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

Answers

Answer:

156.7 miles

Step-by-step explanation:

Since [tex]x[/tex] is tangent to the circle, then it is also a right angle with the radius, from here, just do Pythagorean theorem ([tex]a^{2}+b^{2}=c^{2}[/tex]) to solve for [tex]x[/tex].

Since 1 leg and the hypotenuse is given to you, you want to solve for the other leg, which is [tex]x[/tex] (either [tex]a[/tex] or [tex]b[/tex]). Lets use [tex]b[/tex] for [tex]x[/tex] and set up the equation.

[tex]b^{2}=c^2-a^2[/tex]

[tex]b^2=(3959+3.1)^2-3959^2[/tex]

[tex]b^2 = 3962.1^2 - 3959^2[/tex]

[tex]b^2 = 15,698,236.41 - 15,673,681[/tex]

[tex]b^2 = 24,555.41[/tex]

[tex]\sqrt{b^2}=\sqrt{24,555.41}[/tex]

[tex]b=156.7016592[/tex]

[tex]b=156.7[/tex] (round to nearest tenth)

The distance to the earth’s horizon from point P is 281.6 miles

What is distance?

The distance between two points is the length of the line joining the two points. Distance is a numerical or occasionally qualitative measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.

here, we have,

to determine the distance to the earth’s horizon from point P:

The tangent line from P meets the radius of the earth at a right angle.

This means that the triangle is a right triangle.

The length of x is then calculated as:

(3959 + 10)^2= 3959^2 + x^2

Rewrite as:

x^2 = (3959 + 10)^2- 3959^2

Evaluate

x^2 = 79280

Take the square root of both sides

x = 281.6

Hence, the distance to the earth’s horizon from point P is 281.6 miles

Read more about distance at:

brainly.com/question/3503424

#SPJ3

College Calculus - hyperbolic functions (see attachment)

Answers

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx [tex]\int\limits^x_4 {g(t)} \, dt = g(x)[/tex]

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation of 16,500 miles, what should be the guarantee period if the company wants less than 2% of the engines to fail while under warranty g

Answers

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

[tex]z = \dfrac{x - \mu }{\sigma}[/tex]

[tex]z = \dfrac{x - 170000 }{16500}[/tex]

Now;

[tex]P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})[/tex]

[tex]P( Z < \dfrac{T- 170000}{16500})< 0.02[/tex]

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

[tex]\dfrac{T- 170000}{16500}<- 2.06[/tex]

[tex]{T- 170000}<- 2.06({16500})[/tex]

[tex]{T- 170000}< - 33990[/tex]

[tex]{T}< - 33990+ 170000[/tex]

[tex]{T}<136010[/tex]

Thus; the guarantee period should be less than 136010 miles

3/4 (1/2x - 12) + 4/5 HELP

Answers

Answer:

3/8x - 9 4/5

Step-by-step explanation:

Well we need to simplify the following expression,

[tex]\frac{3}{4} (\frac{1}{2}x - 12) + \frac{4}{5}[/tex]

So we need to distribute 3/4 to (1/2x - 12)

3/8x - 9 + 4/5

3/8x - 9 4/5

Thus,

the answer is 3/8x - 9 4/5.

Hope this helps :)

Adam is going to cook a turkey for 14 people

Answers

Answer:

they divied the turkey into 14 pices

Step-by-step explanation:

magazine provided results from a poll of adults who were asked to identify their favorite pie. Among the ​respondents, ​% chose chocolate​ pie, and the margin of error was given as percentage points. What values do ​, ​, ​n, E, and p​ represent? If the confidence level is ​%, what is the value of ​?

Answers

Complete Question

A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 ​respondents, 12 ​% chose chocolate​ pie, and the margin of error was given as plus or minus 5 percentage points.What values do ​ [tex]\r p , \ \r q[/tex], ​n, E, and p​ represent? If the confidence level is 90​%, what is the value of [tex]\alpha[/tex] ​?

Answer:

a

   [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

   [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

   [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e                        [tex]\r q = 1- \r p[/tex]

b

   [tex]\alpha = 10\%[/tex]

Step-by-step explanation:

Here

    [tex]\r p[/tex] is the sample proportion   [tex]\r p = 0.12[/tex]

   [tex]n[/tex] is the  sample size is  [tex]n = 500[/tex]

    [tex]\r q[/tex] represents the proportion of those that did not chose chocolate​ pie i.e  

      [tex]\r q = 1- \r p[/tex]

      [tex]\r q = 1- 0.12[/tex]

      [tex]\r q = 0.88[/tex]

     [tex]E[/tex] is the  margin of error is [tex]E = 0.05[/tex]

Generally [tex]\alpha[/tex] is the level of significance and it value is mathematically evaluated as

     [tex]\alpha = ( 100 - C )\%[/tex]

Where  [tex]C[/tex] is the confidence level which is given in this question as  [tex]C = 90 \%[/tex]

So  

    [tex]\alpha = ( 100 - 90 )\%[/tex]

    [tex]\alpha = 10\%[/tex]

PLEASEEEEE HELPPOO
For Individual or Group Explorations
Maximizing the Total Profit
Payles at The Christmas Store very periodically with a high ef 550.000 in December
the Christmas Stove also comes the Powe, where profits reach a high of $80,000
in Aurust and a few of $20,000 in February Assume that the profit function for
Crm Store
Save
40
20
10
1 2 3 4 5 6 7 8 9 10 11 12
Month
a) Write the profit function for The Christmas Store as a function of the month
and sketch its graph
b)
Write the profit function for The Pool Store as a function of the month and
sketch its graph.
are are length
Write the total profit as a function of the month and sketch its graph. What is
the period?
are inside the
est enth of a
Use the maximum feature of a graphing calculator to find the owner's maxi-
mum total profit and the month in which it occurs.
Find the owner's minimum total profit and the month in which it occurs.
We know that y -a sin x + bcos x is a sine function. However, the sum of
two arbitrary sine or cosine functions is not necessarily a sine function. Find an
example in which the graph of the sum of two sine functions does not look like
a sine curve.
Explain.
is tangent to one

Answers

Answer:

what

Step-by-step explanation:

Nakashima Gallery had the following petty cash transactions in February of the current year. Nakashima uses the perpetual system to account for merchandise inventory. Feb 2 Write a $400 check to establish a petty cash fund. Feb 5 Purchased paper for the copier for $14.15 that is immediately used. Feb 9 Paid $32.50 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These costs are added to merchandise inventory. Feb 12 Paid $7.95 postage to deliver a contract to a client Feb 14 Reimbursed Adina Sharon, the manager, $68 for mileage on her car. Feb 20 Purchased office paper for $67.77 that is immediately used. Feb 23 Paid a courier $20 to deliver merchandise sold to a customer, terms FOB destination. Feb 25 Paid $13.10 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These cost are added to merchandise inventory. Feb 27 Paid $54 for postage expenses Feb 28 The fund had $120.42 remaining in the petty cashbox. Sorted the petty cash receipts by accounts affected and exchanged them for a check to reimburse the fund for expenditures. Feb 28 The petty cash fund amount is increased by $100 to a total of $500

Answers

Answer:

1. Debit Petty cash for $400; and Credit Cash for $400.

2. Total petty cash payment = $270.57

3(a) Cash reimbursement is $279.58; and Cash over and short is $9.01.

3(b) Debit Petty cash for $100; and Credit Cash for $100.

Step-by-step explanation:

Note: This question is not complete. The full complete question is therefore provided before answering the question. See the attached pdf file for the full question.

The explanations to the answers are now given as follows:

1. Prepare the journal entry to establish the petty cash fund.

Note: See the journal entry in the attached excel file

2. Prepare a petty cash payments report for February with these categories: delivery expense, mileage expense, postage expense, merchandise inventory (for transportation-in), and office supplies expense. Sort the payments into the appropriate categories and total the expenditures in each category.

Note: See the petty cash payments report in the attached excel file.

3. Prepare the journal entries for required 2 to both (a) reimburse and (b) increase the fund amount.

Note: See the journal entries (a) and (b) in the attached excel file

3(a) Reimburse Workings:

w.1: Calculation of Cash reimbursement

Cash reimbursement = Petty cash fund - Petty cash fund balance = $400 - $120.42 = $279.58

w.2: Calculation of the Cash over and short

Cash over and short = Cash reimbursement – Total expenses = $279.58 - $270.57 - $120.42 = $9.01

What is the missing term that makes these ratios equivalent? 1.5:3, 31.5:____

Answers

Answer:  63

=========================================

Work Shown:

1.5/3 = 31.5/x

1.5x = 3*31.5  cross multiply

1.5x = 94.5

x = 94.5/1.5  dividing both sides by 1.5

x = 63

-----------

An alternative equation to solve is

1.5/31.5 = 3/x

1.5x = 31.5*3

1.5x = 94.5

The remainder of the steps are the same as in the previous section above.

Fake question: Should Wishing be a moderator? (If you could answer I'd appreciate it haha.)
Real question: Simplify [tex](z^3*z^2)-(y^4*y)[/tex]

Answers

Step-by-step explanation:

(z³*z²)-(y^4 *y) z^5 - y^5

Answer:

[tex]z^5-y^5[/tex]

Step-by-step explanation:

=> [tex](z^3*z^2)-(y^4*y)[/tex]

When bases are same, powers are to be added

=> [tex](z^{3+2})-(y^{4+1})[/tex]

=> [tex]z^5-y^5[/tex]

P.s. Yessss, Wishing should be a moderator so that he can delete all the absurd or plagiarized answer!!!!!!!!

Determine whether the function below is an even function, an odd function, both, or neither.
f(x)=x^6 + 10x^4-11x^2+19
ОА.
neither even nor odd
OB.
odd function
Ос.
both even and odd
OD.
even function
Reset
Next

Answers

Even function because the highest exponent of the variable is a 6, and 6 is an even number.

Answer:

Step-by-step explanation:

even function are symmetrical about the y axis or f(-x)=f(x)

odd function are symmetrical about the origin -f(-x)=f(x)

f(x)=x^6 + 10x^4-11x^2+19

f(-x)=(-x)^6+10(-x)^4+11(-x)^2+19=x^6 + 10x^4-11x^2+19

the function is even

What is a3 if an=64(12)n−1

Answers

Answer:

[tex]\huge\boxed{a_3=9,216}[/tex]

Step-by-step explanation:

[tex]a_n=64(12)^{n-1}\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^{3-1}=64(12)^2=64(144)=9,216[/tex]

What is the value of x in the equation 5 (4 x minus 10) + 10 x = 4 (2 x minus 3) + 2 (x minus 4)?

Answers

Answer:

x = 1.5

Step-by-step explanation:

5(4x-10)+10x=4(2x-3)+2(x-4)

Distribute(5)

20x-50+10x=4(2x-3)+2(x-4)

Distribute(4)

20x-50+10x=8x-12+2(x-4)

Distribute(2)

20x-50+10x=8x-12+2x-8

Combine like terms

30x-50=10x-20

Subtract(10x)

20x-50=-20

Add(50)

20x=30

Divide(20)

x = 1.5

Hope it helps <3

Answer:

x = 3/2

Step-by-step explanation:

5 ( 4x - 10) + 10x = 4(2x - 3) + 2(x - 4)

Expand the terms

That's

20x - 50 + 10x = 8x - 12 + 2x - 8

Simplify

30x - 50 = 10x - 20

Group the constants at the right side of the equation

That's

30x - 10x = - 20 + 50

20x = 30

Divide both sides by 20

x = 3/2

Hope this helps you

what are the coordinates of point b on ac such that ab=2/5ac

Answers

Answer:

[tex](-\frac{36}{7},\frac{40}{7})[/tex]

Step-by-step explanation:

Coordinates of points A and C are (-8, 6) and (2, 5).

If a point B intersects the segment AB in the ratio of 2 : 5

Then coordinates of the point B will be,

x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]

and y = [tex]\frac{my_2+ny_1}{m+n}[/tex]

where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the extreme end of the segment and a point divides the segment in the ratio of m : n.

For the coordinates of point B,

x = [tex]\frac{2\times 2+(-8)\times 5}{2+5}[/tex]

  = [tex]-\frac{36}{7}[/tex]

y = [tex]\frac{2\times 5+5\times 6}{2+5}[/tex]

  = [tex]\frac{40}{7}[/tex]

Therefore, coordinates of pint B will be,

[tex](-\frac{36}{7},\frac{40}{7})[/tex]

Help ASAP!!!

A recursive sequence is a sequence where each term is found by adding a common difference

True or false

Answers

Answer:

True

Step-by-step explanation:

Classify the polynomial 2x^3+6x^2-4 by the number of terms. binomial. trinomial. cubic. quadratic.

Answers

Answer:

monomial

Step-by-step explanation:

WHY CAN'T ANYONE HELP ME :( Solve the formula for the specified variable. tex]D=\frac{1}{4}fk for f.

Answers

Answer:

4d/k or [tex]\frac{4d}{k}[/tex]

Step-by-step explanation:

first multiply both sides by four

you will have 4d=fk

then divide by k

4d/k=f

x/3 ≥−33 solve for x answer must be simplified

Answers

Answer:

[tex]\boxed{x\geq -99}[/tex]

Step-by-step explanation:

[tex]\frac{x}{3} \geq -33[/tex]

[tex]\sf Multiply \ both \ sides \ by \ 3.[/tex]

[tex]\frac{x}{3} (3) \geq -33(3)[/tex]

[tex]x\geq -99[/tex]

Answer:

[tex]\boxed{\red{x \geqslant - 99}}[/tex]

Step-by-step explanation:

[tex] \frac{x}{3} \geqslant - 33 \\ x \geqslant - 33 \times 3 \\ x \geqslant - 99[/tex]

hope this helps you!

The equations x + 5 y = 10, 3 x minus y = 1, x minus 5 y = 10, and 3 x + y = 1 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (0, negative 1) and (1, 2). Blue line goes through (0, 1) and (1, negative 2). Pink line goes through (0, 2), and (2, 1.5). Orange line goes through (negative 2, negative 2.5) and (2, negative 1.5). Which is the approximate solution for the system of equations x + 5 y = 10 and 3 x + y = 1? (–0.3, 2.1) (–0.3, –2.1) (0.9, –1.8) (0.9, 1.8)

Answers

Answer:

A: (–0.3, 2.1)

Answer:a

Step-by-step explanation:

The second drop down menu on each question includes options: decimal place(s) or significant figure(s)

Answers

Answers:

A. 1 Decimal Place 92.2B. 4 Decimal Places 1.8164

Step-by-step explanation:

I solved the problem.

I'm always happy to help :)

Taylor and Jeff have been selling frozen pizzas for a class fundraiser. Taylor has sold half as many
pizzas as Jeff. Together they have sold a total of 126 pizzas. How many pizzas did Taylor sell?

Answers

Answer:

Taylor sold 42 pizzas

Step-by-step explanation:

Make a system of equations where t represents the number of pizzas Taylor sold and j represents the number that Jeff sold:

t + j = 126

j = 2t

We can solve this system by substitution, since we can substitute 2t as j.

t + j = 126

t + 2t = 126

3t = 126

t = 42

Taylor sold 42 pizzas.

Answer:

Step-by-step explanation:

Let x represent the number of pizzas that Tailor sold.

Let y represent the number of pizzas that Jeff sold.

Together they have sold a total of 126 pizzas. This means that

x + y = 126- - - - - - - - -1

Taylor has sold half as many

pizzas as Jeff. This means that

x = 1/2 × y = y/2

Substituting x = y/2 into equation 1, it becomes

y/2 + y = 126

Multiplying both sides of the equation by 2, it becomes

y + 2y = 252

3y = 252

y = 252/3

y = 84

x = y/2 = 84/2

x = 42

Taylor sold 42 pizzas

Which two points are on the graph of y=-x+ 3?
(-1,-2), (1,4)
(1, 2), (0, -3)
(0, 3), (4, -1)
(4, -1), (1, 3)

Answers

Answer:

(0, 3), (4, -1)

(1, 2)

Step-by-step explanation:

If the answers that have been provided to you are only in pairs then it'd just be the first answer I wrote. The points (1, 2) also are on the graph of y=x+3 but if the answers aren't individual than I'd just stick with the (0, 3), (4, -1). Does that make sense? I used a graphing calculator online called Desmos, it's very good. I highly recommend it for problems like these.

I hope this helps:) Select as brainliest because I actually put work into this and tried.

A bag of 20 tulip bulbs purchased from a nursery contains 10 red tulip bulbs, 7 yellow tulip bulbs, and 3 purple tulip bulbs. What is the probability of randomly selecting a purple tulip bulb from the bag

Answers

Answer:

3/20

Step-by-step explanation:

since there is a total of 20 tulips that would be your denominator then your numerator would be the number of purple tulips which would be 3 so you probability of randomly selecting a purple tulip would be 3/20

Write 3 expressions containing exponents so that each expression equals 81

Answers

Answer:

9x9= 81

3x3x3x3=81

81 to the first power.

Step-by-step explanation:

I hope this helps in any way:)

Other Questions
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