Usami Bolt has a mass of 85kg and is running at a steady speed of 10m/s how much kinetic energy does he have

Answers

Answer 1

Answer:

Ek = 4250 J

Explanation:

Data:

m = 85 kgv = 10 m/sEk = ?

Formula:

[tex]\boxed{\bold{Ek=\frac{m*(v)^{2}}{2}}}[/tex]

Replace and solve:

[tex]\boxed{\bold{Ek=\frac{85\ kg*(10\frac{m}{s})^{2}}{2}}}[/tex][tex]\boxed{\bold{Ek=\frac{85\ kg*100\frac{m^{2}}{s^{2}}}{2}}}[/tex][tex]\boxed{\bold{Ek=\frac{8500\ J}{2}}}[/tex][tex]\boxed{\boxed{\bold{Ek=4250\ J}}}[/tex]

It has 4250 Joules of Kinetic Energy.

Greetings.


Related Questions

large amounts of energy are converted to small amounts of mass. small amounts of energy are converted to large amounts of mass. small amounts of mass are converted to large amounts of energy. large amounts of mass are converted to small amounts of energy. mass is destroyed and energy is created. energy is destroyed and mass is created.

Answers

Answer:

small amounts of mass are converted to large amounts of energy

Explanation:

According to the mass-energy equivalence, which Albert Einstein initially proposed as a general principle. It was revealed that mass and energy are connected and that a "small amount of mass can be converted into enormous amounts of energy."

Using the formula E=mc^2. This means Energy equals mass times the speed of light squared.

Hence, it is true that "small amounts of mass are converted to large amounts of energy."

An aluminum-alloy rod has a length of 10.0 cm at 20°C and a length of 10.015 cm at the boiling point of water (1000C). (a) What is the length of the rod at the freezing point of water (0 0C)? (b) What is the temperature if the length of the rod is 10.009 cm? /4mks

Answers

Answer:

a.  9.99625 cm b. 68 °C

Explanation:

(a) What is the length of the rod at the freezing point of water (0 0C)?

Before we find the length of the rod, we need to find the coefficient of linear expansion, α = (L - L₀)/[L₀(T - T₀)] where L₀ = length of rod at temperature T₀ = 10.0 cm, T₀ = 20 °C, L = length of rod at temperature T = 10.015 cm and T = 100 °C

Substituting the values of the variables into the equation, we have

α = (L - L₀)/[L₀(T - T₀)]

α = (10.015 cm - 10.0 cm)/[10.0 cm(100 °C - 20 °C)]

α = 0.015 cm/[10.0 cm × 80 °C]

α = 0.015 cm/[800.0 cm °C]

α = 0.00001875 /°C

We now find the length L₁ at T₁ = 0 °C from

L₁ = L₀(1 + α(T₁ - T₀))

So, substituting the values of the variables into the equation, we have

L₁ = L₀(1 + α(T₁ - T₀))

L₁ = 10.0 cm[1 +  0.00001875 /°C(0° C - 20 °C)]

L₁ = 10.0 cm[1 +  0.00001875 /°C × -20° C]

L₁ = 10.0 cm[1 - 0.000375]

L₁ = 10.0 cm[0.999625]

L₁ = 9.99625 cm

(b) What is the temperature if the length of the rod is 10.009 cm?

With length L₃ = 10.009 cm at temperature T₃, using

L₃ = L₀(1 + α(T₃ - T₀))

making T₃ subject of the formula, we have

L₃/L₀ = 1 + α(T₃ - T₀)

L₃/L₀ - 1 = α(T₃ - T₀)

T₃ - T₀ = (L₃/L₀ - 1)/α

T₃ = T₀ + (L₃/L₀ - 1)/α

substituting the values of the variables into the equation, we have

T₃ = 20 °C + (10.009 cm/10.0 cm - 1)/0.00001875 /°C

T₃ = 20 °C + (1.0009 - 1)/0.00001875 /°C

T₃ = 20 °C + 0.0009/0.00001875 /°C

T₃ = 20 °C + 48 °C

T₃ = 68 °C

what is fire proof plastic​

Answers

Explanation:

.Flame retar,dant plastic additi,ves are compounds added to plastics and other materials to inhibit, suppress or de,lay combustion. These compounds are useful in impending burning in the ign,ition phase of fire. They do not prevent char,ring or melting nor do they increase the heat resistance of a material

what is a product made from no renewable resources

Answers

Answer:

a nail

Explanation:

Answer:

crude oil, natural gas, coal, and uranium. These are all resources that are processed into products that can be used commercially.

Explanation:

the degree of hotness and coldness of th body is.......​

Answers

Answer:

Explanation:

The degree of hotness and coldness of the body is called temperature.

A 4kg and 5kg bodies moving on a frictionless horizontal surface at a velocity of ( -6i )m/s and ( +3 )m/s respectively. Collide a head on elastic collision. What is the velocity ( magnitude and direction) of the each body after collision?

Answers

Answer:

4 kg → +4 m/s

5 kg → -5 m/s

Explanation:

The law of conservation of momentum states that:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'left side → velocities before collisionright side → velocities after collision

You'll notice that we have two missing variables: v₁' & v₂'. Assuming this is a perfectly elastic collision, we can use the conservation of kinetic energy to set the initial and final velocities of the individual bodies equal to each other.

v₁ + v₁' = v₂ + v₂'  

Let's substitute all known variables into the first equation.

(4)(-6) + (5)(3) = (4)v₁' + (5)v₂' -24 + 15 = 4v₁' + 5v₂' -9 = 4v₁' + 5v₂'  

Let's substitute the known variables into the second equation.

(-6) + v₁' = (3) + v₂' -9 = -v₁' + v₂' 9 = v₁' - v₂'  

Now we have a system of equations where we can solve for v₁ and v₂.

-9 = 4v₁' + 5v₂' 9 = v₁' - v₂'  

Use the elimination method and multiply the bottom equation by -4.

-9 = 4v₁' + 5v₂' -36 = -4v₁' + 4v₂'

Add the equations together.

-45 = 9v₂'-5 = v₂'

The final velocity of the second body (5 kg) is -5 m/s. Substitute this value into one of the equations in the system to find v₁.  

9 = v₁' - v₂'9 = v₁' - (-5) 9 = v₁' + 5 4 = v₁'

The final velocity of the first body (4 kg) is 4 m/s.

We can verify our answer by making sure that the law of conservation of momentum is followed.

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' (4)(-6) + (5)(3) = (4)(4) + (5)(-5)-24 + 15 = 16 - 25 -9 = -9

The combined momentum of the bodies before the collision is equal to the combined momentum of the bodies after the collision. [✓]

A parallel combination of 3ohms and 4ohms resistor is connected in series with a resistor of 4ohms and a battery of negligible resistance. Calculate the effective resistance in the circuit

Answers

Answer:

Explanation:

Equivalent resistance of parallel combination of two resistors of 3 ohms and 4 ohms .

R₁ = 3 x 4 / ( 3 + 4 )

= 12 / 7 = 1.7 ohms .

This equivalent resistance is connected with 4 ohms in series

Total resistance = 1.7 ohms + 4 ohms

= 5.7 ohms.

Hence effective resistance of the circuit = 5.7 ohms .

ik its a lot but can u help​

Answers

Answer:

your correct ans is D.

object float in liquid when its density is less than liquid and sinks when its density is more than liquid..

stay safe healthy and happy.

Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The length of each rod is 1.1 m, while the mass of each is 0.10 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 11 mm. Determine the current in the rods.

Answers

Answer:

220 A

Explanation:

The magnetic force on the floating rod due to the rod held close to the ground is F = BI₁L where B = magnetic field due to rod held close the ground = μ₀I₂/2πd where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, I₂ = current in rod close to ground and d = distance between both rods = 11 mm = 0.011 m. Also, I₁ = current in floating rod and L = length of rod = 1.1 m.

So, F = BI₁L

F = (μ₀I₂/2πd)I₁L

F = μ₀I₁I₂L/2πd

Given that the current in the rods are the same, I₁ = I₂ = I

So,

F = μ₀I²L/2πd

Now, the magnetic force on the floating rod equals its weight , W = mg where m = mass of rod = 0.10kg and g = acceleration due to gravity = 9.8 m/s²

So, F = W

μ₀I²L/2πd = mg

making I subject of the formula, we have

I² = 2πdmg/μ₀L

I = √(2πdmg/μ₀L)

substituting the values of the variables into the equation, we have

I = √(2π × 0.011 m × 0.1 kg × 9.8 m/s²/[4π × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2 × 10⁻⁷ H/m × 1.1 m])

I = √(0.01078 kgm²/s²/[2.2 × 10⁻⁷ H])

I = √(0.0049 × 10⁷kgm²/s²H)

I = √(0.049 × 10⁶kgm²/s²H)

I = 0.22 × 10³ A

I = 220 A

Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?

wavelength get longer

wavelength remains constant

the wavelengths get shorter

wavelength eventually disappear altogether

Answers

Explanation:

the wavelengths get shorter

3. How do energy transformations, energy transfers, and conservation of energy allows you to track how energy moves through in a system? ​

Answers

Answer:

The law of conservation of energy states that when one form of energy is transformed to another, no energy is destroyed in the process. According to the law of conservation of energy, energy cannot be created or destroyed. So the total amount of energy is the same before and after any transformation

Explanation:

The energy in a system always transforms from one form to another without any significant loss or addition. It simply changes from one form to another with the effect of numerous external influences.

What is Energy transformation?

Energy transformation may be defined as the process through which energy can convert from one form to another. It also illustrates the migration of energy from one place to another due to physical factors.

According to the law of conservation of energy, in a closed system energy can neither be created nor destroyed. The total amount of energy remains the same before and after the process of transformation.

Therefore, the energy in a system always transforms from one form to another without any significant loss or addition.

To learn more about Energy transformations, refer to the link:

https://brainly.com/question/16917873

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Does a feather fall as fast as a rock in a vacuum? If so why?

Answers

Answer:

No.

Explanation:

A feather is less dense and thus less force exerted while a rock is very dense thus exerting more force .

Which object will take the most force
to accelerate? *
4 kg
6 kg
8 kg
02 kg

Answers

Answer:

I think it might be 8kg grams because it is bigger

Find the temperature of a mixture obtained by mixing 32 grams of water at a temperature of 22 degrees Celsius with 88 grams of water at a temperature of 75 degrees Celsius.

Answers

Answer:

60.87 °C

Explanation:

Applying,

Heat lost = heat gain

cm'(t₂-t₃) = cm(t₃-t₁).............. Equation 1

Equation 1 can futher be simplified to

m'(t₂-t₃) = m(t₃-t₁)................Equation 2

Where m' = mass of the hot water, m = mass of the cold water, t₁ = initial temperature of the cold water, t₂ = initial temperature of the hot water, t₃ = temperature of the mixture.

From the question,

Given: m' = 88 g, m = 32 g, t₁ = 22°C, t₂ = 75°C

Substitute these values into equation 2

88(75-t₃) = 32(t₃-22)

6600-88t₃ = 32t₃-704

32t₃+88t₃ = 6600+704

120t₃ = 7304

t₃ = 60.87 °C

A positive charge is moving across a room from south to north. A magnetic field runs from east to west. In what direction is the magnetic force on the moving positive charge?

Answers

Answer:

the force is on the z axis, coming out of the blade

Explanation:

The direction of the magnetic force is given by the right hand rule,

For a positive charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm points in the direction of force.

In this case.

Thumb points North

The fingers extended is in the east - west direction parallel to the blade

The palm is sticking out of the leaf, in the z direction

the answer is the force is on the z axis, coming out of the blade

Charges of +3 µC and –5 µC are 2 mm from each other. The –5 µC charge is replaced with a +5 µC charge.

How will the electrical force between the charges compare with the original force?

same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction

Answers

Answer: same force in opposite direction.

Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.

Answer:

A) same force, but in the opposite direction

Explanation:

he's right

Juan's mother drives 12.5 miles southwest to her favorite shopping mall. What is the velocity of her
automobile if she arrives at the mall in 7.25 minutes?

Answers

Answer:

v1= 12.5miles, t= -7.25m, a= 0

v= 1/2at^2

v= 1/2×

A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of
motion to calculate the amount of acceleration the object will experience. Then explain how the
amount of acceleration will change if the net force or the mass of the object increases.

Answers

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

After being assaulted by flying cannonballs, the knights on the castle walls (12.0 m above the ground) respond by propelling flaming pitch balls at their assailants. One ball lands on the ground at a distance of 81.1 m from the castle walls. If it was launched at an angle of 53.0° above the horizontal, what was its initial speed?

Answers

Answer:

28.6 m/s

Explanation:

Using the equation for the range of a projectile,

R = U²sin2θ/g where U = initial speed of flaming pitch balls, θ = launch angle = 53° and g = acceleration due to gravity = 9.8 m/s²

Making U subject of the formula, we have

U = √(gR/sin2θ)

substituting the values of the variables into the equation given that R = 81.1 m, we have

U = √(9.8 m/s² × 81.1 m/sin2(53°))

U = √(794.78 m²/s²/sin106°)

U = √(794.78 m²/s²/0.9613)

U = √(826.78 m²/s²)

U = 28.75 m/s

U ≅ 28.6 m/s

Jorge tightens a bolt on his bicycle with a wrench that is 0.20 m long. If he pulls perpendicularly on the end of the wrench with a force of 140 N, how much torque does he apply ?

Answers

Answer:

28Nm

Explanation:

Torque is expressed as the prduct of force and radius

Given

Force = 140N

radius  = 0.20m

Torque = 140 * 0.2

Torque = 140 * 1/5

Torque = 28Nm

Hence the amouunt of torque applied is 28Nm

The point A on the above graph is an example of
extrapolation
variation
interpolation
average method

Answers

Answer:

Interpolation

Explanation:

The graph shows that it falls between 2 values and interpolation means that you estimate the unknown values that fall between the 2 values. Hope this helps!

The data point A is between two given data points and it lies within the line connecting the data points, thus we can conclude that point A is an example of interpolation.

Extrapolation is the process of extending a line connecting the data points beyond the given data points to make inferences based on the previous trend of the data set. This helps us to understand what will happen in the future if the trend continues in the same manner.

Interpolation is the process of determining an unknown variable between two known variables. In this process the data point is located within the line connecting the data points.

In this given graph, the data point A is between two given data points and it lies within the line connecting the data points, thus we can conclude that point A is an example of interpolation.

Learn more here: https://brainly.com/question/11958294


What are some core features of waves in physics?

Answers

Answer:

Waves are disorders that travel through a fluid medium. Several simple wave features include frequency, period, wavelength, and amplitude.

Explanation:

HELP ASAP need it soon

Answers

Answer:

The answer to your question is given below.

Explanation:

The energy and frequency of a wave are related by the following equation:

E = hf

Where

E => is the energy.

h => is the Planck's constant.

f => is the frequency

From the formula i.e

E = hf

The energy is directly proportional to the frequency. Thus, an increase in the frequency of the wave will lead to an increase in the energy and a decrease in the frequency of the wave will lead to a decrease in the energy.

Considering the question given above, if the frequency of the wave is decreased, then the energy of the wave will also decrease.

ACELLUS PHYSICS HELP!!

A 6.93*10-4 C charge has a potential energy U = -3.09 J at a point in space. What is the electric potential V at that point? Include the sign, + or - . (Unit = V)​

Answers

Answer:

Potential difference, V = -0.000224 Volts

Explanation:

Given the following data;

Quantity of charge = 6.93*10-4 C

Energy = -3.09 J

To find the electric potential V at that point?

Mathematically, the energy transferred per unit of charge is given by the formula;

E = QV

Where:

E is the energy

Q is the quantity of charge

V is the potential difference.

Substituting into the formula, we have;

[tex] -3.09 = 6.93*10^{-4} * V [/tex]

[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]

Potential difference, V = -0.000224 Volts

What if the World turned to Gold?

Answers

Answer:

We would all freeze at close to absolute zero and gold will not be worth anything

Explanation:

In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger, what happens to the magnitude of difference between the incident and scattered wavelengths

Answers

Answer:

Increases

Explanation:

In the Compton scattering experiment with x-rays,

The change in operation

[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]

Now rest being constant, as \theta increases, cos\theta decreases

Hence, The change in wavelength will increase with the increase in \theta.

Hence, wavelength increases with an increase in the angle of scatttering.

If 150 Joules of work is needed to move a box 1000 cm, calculate the force that was used?

Answers

Answer:

[tex] \large{ \tt{☄ EXPLANATION}} : [/tex]

We're provided : Work ( W ) = 150 J & Displacement ( D ) = 1000 cm & We're asked to find out the force that was used. Firstly, Notice that we're provided the unit of Displacement as centimetre so we have to convert 1000 cm into m. Displacement ( D ) = [tex] \frac{1000}{ 100} = 10[/tex] m

[tex] \large{ \tt{♡ \: LET'S \: GET \: STARTED}} : [/tex]

Work is defined as the product of force and Displacement. By definition ,

[tex] \large{ \boxed{ \tt{❃ \: WORK ( \: W \: ) = FORCE\: ( \: F) \times DISPLACEMENT \: ( \: D \: )}}}[/tex]

- Plug the values and then simplify !

[tex] \large{ \bf{↦ \: 150 = F \times 10}}[/tex]

[tex] \large{ \bf{↦F\times 10 = 150}}[/tex]

[tex] \large{ \bf{↦ \: F = \frac{150}{10}}} [/tex]

[tex] \large {\bf{↦F = \boxed{ \bf{15} \: N}}}[/tex]

[tex] \boxed{ \boxed{ \large{ \tt{✤ \: OUR \: FINAL \: ANSWER : \boxed{ \bf{15 \: n}}}}}}[/tex]

KEEP READING , KEEP STUDYING , KEEP WORKING , KEEP PUSHING , KEEP TAKING CARE OF YOURSELF. YOUR HARD WORK WILL PAY OFF ! ♪

ツ Hope I helped ! ۵

☪ Have a wonderful day / evening ! ☼

# StayInAndExplore ! ☂

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Why does the needle of a compass point north?
a. Because the southern pole of the Earth's magnet repels it.
b. Because the southern pole of the Earth's magnet is in the north.
Because the northern pole of the Earth's magnet is in the north
d. Because the Earth's core is made of steel.
C.

Answers

Answer:

b. Because the southern pole of the Earth's magnet is in the north.

Explanation:

This is very weird to think about but Earth's southern magnetic pole is in Earth's geographic north. So when compass points north, it is actually getting attracted to the southern magnetic pole (that is actually located in the north direction- geographic location- in earth).

After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg bowling pin initially at rest. Find the final velocity of the second pin in the following situations: a) The first pin moves to the right after the collision at 0.8 m/s. Answer in units of m/s. 010 (part 2 of 2) 10.0 points b) The first pin stops moving when it hits the second pin. Answer in units of m/s

Answers

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s[/tex]

v₂ = 4.2 m/s

b)

We will use the law of conservation of momentum here:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)[/tex]

v₂ = 5 m/s

Two light waves of equal wavelength, lambda, are emitted in phase from separate sources and propagate to a common point P. Light wave 1 must travel a longer distance (d1) than light wave 2 (d2) to reach point P, where d1 – d2 is equal to the path difference between the two light waves. If the two waves interfere constructively at point P, what must be true about the path difference between the two light waves?

Answers

Answer:

The path difference must be equal to an integral (1 * lambda, 2 * lambda, -------n * lambda) number of wavelengths for constructive interference to occur.

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