URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (33pts)

Answer:

Odel has sold 84 Pizzas and Sam has sold 42

Step-by-step explanation:

:p

Answer:

B x

C 20

E 100

Step-by-step explanation:

Answer:

You turn it into a fraction or decimal.

Step-by-step explanation:

Answer:

The answer is 91.

Step-by-step explanation:

If p = -3, then your equation is 64 + (-9 × -3).

-9 times -3 is 27.

27 + 64 = 91

The scale factor of triangle M to N is 4/3

In the above similar triangles, the corresponding sides are:

M = 27 ft

N = 36 ft

So, the scale factor of M to N is:

Scale factor = N/M

This gives

Scale factor = 36/27

Evaluate

Scale factor = 4/3

Hence, the scale factor of triangle M to N is 4/3

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Answer:

£510

Step-by-step explanation:

Simple interest = (principal × rate × time) / 100

Principal = £1700

Rate = 10%

Time = 3 years

Simple interest = (principal × rate × time) / 100

= (1700 × 10 × 3) / 100

= 51,000/100

= 510

Simple interest = £510

Answer:

9

Step-by-step explanation:

here you go!

Answer:

5/6

4/5

6/7

Step-by-step explanation:

Answer:

6 and 7; 1 and 4; 4 and 5

Step-by-step explanation:

a supplementary angle is when two angles added together equal 180 degrees. In other words, if two angles make a straight line when put together, they are supplementary.

dude the answer is 36828337

Answer:

25 is one third of 75 and 30 is 2/5 of 75 is 30 so 5 more people voted for the cat in the hat

Step-by-step explanation:

Answer: it will be subtract try all things possible

Step-by-step explanation:

Answer:

y = 25x – 300

Step-by-step explanation:hope I helped

Answer:

388

Step-by-step explanation:

i looked it up

Answer:8

8/2− 2/5≈ 6.841572544

Step-by-step explanation:i hoep ite helps u

Answer:

code lazar

Step-by-step explanation:

Answer:

m∠A = 45⁰

m∠B = 75⁰

Step-by-step explanation:

Given question 4;

m∠A = x + 51

m∠B = 81 + x

m∠C = 60⁰

The value of the missing angles can be determined by the finding the value of x first;

m∠A  +  m∠B  + m∠C = 180⁰ (sum of angles in a triangle)

(x + 51)  +  (81 + x)  +  60⁰ = 180

(x + x) + (51 + 81 + 60) = 180

2x + 192 = 180

2x = 180 - 192

2x = -12

x = -12/2

x = -6

Thus, the values of the angles are calculated as follows;

m∠A = x + 51

         = -6 + 51  

          = 45⁰

m∠B = 81 + x

        = 81 - 6

         = 75⁰

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

Answer:

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Step-by-step explanation:

PS and RS are tangents to the circle with center T at points P and R. (given)

TP and TR are radii of the given circle.

[tex] \therefore PS\perp TP\: \&\: RS\perp TR[/tex]

(radius is perpendicular to the tangent)

[tex] \therefore m\angle TPQ= m\angle TRS =90\degree [/tex]

In quadrilateral SPTR

[tex] m\angle TPQ+ m\angle TRS+m\angle PSR +m\angle PTR=360\degree [/tex]

[tex] 90\degree+ 90\degree+44\degree +m\angle PTR=360\degree [/tex]

[tex] 224\degree +m\angle PTR=360\degree [/tex]

[tex] m\angle PTR=360\degree - 224\degree[/tex]

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

By inscribed angle theorem:

[tex] m\angle PQR=\frac{1}{2} \times m\angle PTR[/tex]

[tex] m\angle PQR=\frac{1}{2} \times 136\degree[/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Answer:

[tex] \sf8 \: \frac{newspapers}{plie}\: or\: \text{8 newspapers per pile} [/tex]

Step-by-step explanation:

according to the question

Answer:

Solution given:

48 newspaper in 6 pile=48news paper per 6 piles

=48/6=8 news paper per pile

the unit rate of 48 newspapers in 6 piles is 8 news paper per pile

Answer:

i think 18 since 11+7=18

i think this it is not corect 100%100

Answer:12/5

Step-by-step explanation:

Answer: 75 students

Step-by-step explanation:

we know that 1/5 of the students wear glasses and 4/5 do not. In this equation we know 4/5=60 so we divide 60 by 4 and the multiply that (15) by 5.

Answer:

[tex]-14[/tex]

Step-by-step explanation:

Given: Trey's test score average decreased by 14 points this semester.

To find: a signed number to represent this change in average.

Solution:

The decrease can be denoted by minus [tex](-)[/tex] sign and increase can be denoted by plus [tex](+)[/tex] sign.

So, a signed number to represent the change in test score average is [tex]-14[/tex]

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

[tex]\Rightarrow h(t)=-8t^2+16+2[/tex]

Height will be zero once the rocket lands on the ground

So, we can write

[tex]\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s[/tex]

The rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

The given equation is  [tex]\rm h(t)=-8t^2+16t+2\\[/tex], where h(t) is the rocket's height in meters t seconds after launch.

In algebra, a quadratic equation is an equation that can be written in standard form as

[tex]\rm ax^{2}+bx+c=0}[/tex]

where x represents variable, and a, b, and c represent coefficient.

The given equation is

h(t) = 0

[tex]\rm h(t)=-8t^2+16t+2\\h(t)=-8t^2+16t+2 = 0\\[/tex][tex]\rm h(t)=-8t^2+16t+2\\[/tex]

The roots will be

[tex]\rm {\displaystyle t={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}[/tex]

[tex]\rm {\displaystyle t={\frac {16\pm {\sqrt {(-16)^{2}-4\times 8\times 2}}}{16}}.}\\\rm {\displaystyle t={\frac {16\pm {\sqrt{320} }}{16}}}\\\rm {\displaystyle t={\frac{16+17.88}{16}\\[/tex]

Here, we have neglected the negative value of t

t = 2.1 seconds

So, the rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

Here learn more about quadratic equations here:

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