Answer:
The angle from vertical of the axis of the second polarizing filter is 50.57⁰.
Explanation:
Given;
intensity of the unpolarized light, I₀ = 300 W/m²
intensity of emergent polarized light, I = 121 W/m²
let the angle from vertical of the axis of the second polarizing filter = θ
Apply Malus's law, intensity of emergent polarized light is given as;
I = I₀Cos²θ
[tex]Cos^2 \theta = \frac{I}{I_o} \\\\Cos^2 \theta =\frac{121}{300} \\\\Cos^2 \theta =0.4033\\\\Cos \theta = \sqrt{0.4033} \\\\Cos \theta = 0.6351\\\\\theta = Cos^{-1} (0.6351)\\\\\theta = 50.57 ^0[/tex]
Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.
What is the velocity of a wave that traveled 36 meters south in 6 seconds?
O 6 meters per second
O 30 meters per second
O 42 meters per second
O 216 meters per second
Answer:
A
Explanation:
I need help
Pls for me
Can you find two ways that carbon can get from the ocean to the lithosphere?
Answer:
Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.
Hope that helps!
A newly discovered particle, the SPARTYON, has a mass 455 times that of an electron. If a SPARTYON at rest absorbs an anti-SPARTYON, what is the frequency of each of the emitted photons (in 1020 Hz)? The mass of an electron is 9.11×10-31 kg.
Answer:
υ = 5.62 x 10¹⁴ Hz
Explanation:
The process of of formation of photons takes place due to interaction of a particle with its anti-particle is called Annihilation of Matter. Here SPARTYON absorbs anti-SPARYTON to form 2 photons. Applying conservation of energy to the to this scenario, we get:
2(Energy of Each Photon) = Rest Mass Energy of SPARTYON + Rest Mass Energy of anti-SPARTYON
[tex]2hv = m_{0}c^2 + m_{0}c^2\\\\2hv = 2m_{0}c^2\\\\hv = m_{0}c^2\\\\v = \frac{m_{0}c^2}{h}[/tex]
where,
υ = frequency of each photon = ?
m₀ = rest mass of SPARTYON = mass of anti-SPARTYON = 455*Mass of electron
m₀ = 455(9.1 x 10⁻³¹ kg) = 4.14 x 10⁻²⁸ kg
c = speed of light = 3 x 10⁸ m/s
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
Therefore, using these values in the equation, we get:
[tex]v = \frac{(4.14 x 10^{-28} kg)(3 x 10^8 m/s)^2}{6.625 x 10^{-34}J.s}\\\\[/tex]
υ = 5.62 x 10¹⁴ Hz
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to 2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 3 ft/s. (Use g
Answer:
[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]
Explanation:
From the given information concerning the spring-mass system:
Let us apply Hooke law.
Then, we have:
mg = ks
8 = k4
k = 8/4
k = 2
Provided that the mass weighing 8 lbs is attached to a spring.
Then, we can divide it by gravity 32 ft/s².
∴
m = 8/32
m = 1/4 slugs
The medium that offers the damping force [tex]\beta = \sqrt{2}[/tex]
Now, let us set up a differential equation that explains the motion of the spring-mass system.
The general equation is:
[tex]mx '' + \beta x' + kx = 0[/tex]
where;
[tex]m = \dfrac{1}{4}[/tex]
k = 2, and
[tex]\beta = \sqrt{2}[/tex]
Then;
[tex]\dfrac{1}{4}x'' + \sqrt{2} x' + 2x = 0[/tex]
By solving the above equation, the auxiliary equation is:
[tex]m^2 + 4 \sqrt{2} m + 8n = 0[/tex]
Using quadratic formula:
[tex]\dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{(4 \sqrt{2})^2 -4(1)(8) }}{2}[/tex]
[tex]m = \dfrac{-4 \sqrt{2} \pm \sqrt{32 -32 }}{2}[/tex]
[tex]m = -2 \sqrt{2}[/tex]
Since this is a repeated root, the solution to their differential equation took the form.
[tex]x_c = c_1 e^{mt} + c_2 t e^{mt}[/tex]
[tex]x_c = c_1 e^{-2\sqrt{2} t} + c_2 t e^{-2\sqrt{2} t}[/tex]
From the initial condition.
At equilibrium position where the mass is being from:
x(0) = 0
Also, at the downward velocity of 3 ft/s
x'(0) = 3
Then, at the first initial condition:
[tex]x_c (0) = c_1 e^{-2\sqrt{2} *0} + c_2 (0) e^{-2\sqrt{2} *0}[/tex]
[tex]0= c_1 e^{0} + 0[/tex]
[tex]0= c_1[/tex]
At the second initial condition;
[tex]x' = -2 \sqrt{2} c_1 e^{-2 \sqrt{2} t } -2 \sqrt{2} c_2 t e^{-2 \sqrt{2} t } + c_2 e^{-2 \sqrt{2} t}[/tex]
where;
x'(0) = 3
[tex]x' (0) = -2 \sqrt{2} c_1 e^{-2 \sqrt{2}* 0 } -2 \sqrt{2} c_2 (0) e^{-2 \sqrt{2} *0 } + c_2 e^{-2 \sqrt{2} *0}[/tex]
[tex]3 = -2 \sqrt{2} * 0 *e^0 - 0 + c_2 e^0[/tex]
[tex]3 = 0 + c_2[/tex]
[tex]3 = c_2[/tex]
Replacing in the constraints, the equation of the motion is:
[tex]\mathbf{x = 3te ^{-2 \sqrt{2t}}}[/tex]
What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor
Complete Question
A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?
Answer:
The magnetic field is [tex]B = 6.4*10^{-4} \ T[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 8.0 \ A[/tex]
The diameter is [tex]d = \ cm = \frac{1}{100} = 0.01 m[/tex]
The position considered is [tex]d = 2.5 \ mm = 0.0025 \ m[/tex]
Generally the magnetic field is mathematically represented as
[tex]B = \frac{\mu_o * I }{ 2 \pi d}[/tex]
Here [tex]\mu_o[/tex] is permeability of free space with value
[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]
So
[tex]B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }[/tex]
=> [tex]B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }[/tex]
=> [tex]B = 6.4*10^{-4} \ T[/tex]
If the equal tensions T in the pulley cable are 300 N, express in vector notation the force R exerted on the pulley by the two tensions. Determine the magnitude of R.
Answer:
[tex]R=519.61N[/tex]
Explanation:
From the question we are told that
Tension T on a cable are T=300N
Generally the tensions on a pulley is
[tex]\sum f_x=T+T*cos(\theta)[/tex]
Therefore
[tex]\sum f_x=300+300*cos(60)[/tex]
[tex]\sum f_x=300 *1.5[/tex]
[tex]\sum f_x=450N[/tex]
Hence
[tex]T*sin(60) = 259.81N[/tex]
[tex]R= 450\=i +259.81\=i[/tex]
[tex]R=\sqrt{450^2+259.8^2}[/tex]
[tex]R=519.61N[/tex]
If you push against the wall the wall will push back what is the name of the force that pushes back?
tension force
Оа
Ob
Ос
normal force
applied force
friction force
Od
Answer:
applied force
Explanation:
I think that's right
A mouse is running across a room with a speed of 2.2 m/s. The mass of the mouse is 1.4 kg. What is the Kinetic Energy of the mouse?
Answer:
3.39 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 1.4 \times {2.2}^{2} \\ = 0.7 \times 4.84 \\ = 3.388 \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
3.39 JHope this helps you
Answer:
im not sure
Explanation:
If you drop a rock from 700 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)
Answer:
it would be 11.95 seconds
Explanation:
sorry for saying i did not know
Centripetal forces are always directed toward the (center, outside) of a circle.
Answer:
Centripetal forces are directed toward the center of a circle.
Hope this helps.
Explanation:
The force needed to move a body in a curved way is understood as centripetal force. Centripetal forces are always directed toward the center of a circle.
What is centripetal force?The force needed to move a body in a curved way is understood as centripetal force. This is a force that can be sensed from both the fixed frame and the spinning body's frame of concern.
The direction of centripetal force is always in the path of the center of the course.
Hence center is the right option. Centripetal forces are always directed toward the center of a circle.
To learn more about the centripetal force refer to the link;
https://brainly.com/question/10596517
What type of energy transfer occurs
when two objects touch?
O conduction
O induction
O convection
Answer:
conduction
Explanation:
Which two options describe physical properties of matter?
Answer:
A and E.
Explanation:
Physical properties have to do with things that are not done chemically.
A has to do with light that you can see.
B has to do with Ph (If not A this is your next answer)
C mentions a Patina which is a chemical reaction known as oxidation
D has to do with chemical reactions
E is always correct. One of the fundamental laws about matter is that it must always have mass.
I am 99% confident in A and E as your answer, but if it is wrong go with B and E.
Hope this helps!
What single resistor could replace 20 Ω, 30 Ω and 50 Ω resistors which have been joined in series ?
Answer:
sine the resistors are connected in series, we could add the sum and that single value replaces the individual resistors in series. therefore, 100ohm resistor can do.
Which of the following is not a factor used to find climate?
pressure on a given day
wind and ocean currents
latitude and altitude
Answer:
pressure on a given day
Explanation:
because you can't find pressure in a day
Describe any major landmarks (buildings, bridges, historical sites, etc.) that were destroyed during the valdivia earthquake.
Answer:
Homes, Workplaces, Statues, Meuseums
Explanation:
if you did look into it you would know after the earthquake there was a tsunami which flooded alot of places, this made many homeless, jobless, and many lossing vaklueable things
Acceleration and force are proportional
Answer:
whats the question tho
A material that reflects or absorbs all the light that strikes it is
A. opaque.
B. transparent.
C. translucent.
D. primary.
Answer:
b. transparent
Explanation:
Photons interact with an object by some combination of reflection, absorption and transmission. Some materials, such as plate glass and clean water, transmit much of the light that falls on them and reflect little of it; such materials are called optically transparent.
An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of 2.70 x 10^-3 V/m and is parallel to the x axis. What are the frequency and the magnetic-field amplitude of this wave? In calculating the amplitude of the magnetic field, you divide the electric-field amplitude by the speed of light, which requires you to convert some units. Which of the following is equivalent to 1 T?
a. 1 (N/A.m)
b. 1 (N/c.m)
c. 1 (N.s/C.m)
d. 1 (V.s/m^2)
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
From the question, we know that
435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m
a)
To find the frequency of the wave, we would be applying this formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b) again, to find the amplitude of the magnetic field, we would use this relation
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c) and lastly,
1T = 1 (V.s/m^2)
Which example is most likely made from both metals and gemstones?
Answer:
A Necklace is most likely made from both metals and gemstones
Explanation:
Brainliest?
what is simple machine? write any four advantages if it
Answer: See explanation
Explanation:
Simple machine is a machine that has few moving parts or may also have no moving parts and they are usually used to make ones work easier. Examples include wheel and axle, wedge, pulley, lever, screw or an inclined plane.
Their advantages include:
• Less energy is required to perform a particular work.
• It makes work easier.
• It makes work faster.
• Simple machine enable one to do things that might have been difficult to achieve or do.
HEre now can somebody help!!
Pic is what i need help with
Answer:
which of the cars are speeding up: c
which of the cars or slowing down: a
which of the cars are maintaning a constant speed: b
Explanation:
Answer:
Explanation:
I gave a good enough explanation in your other posting. I'm sorry that I'm eating up your points.
The orange line is speeding up
The blue line is neither speeding up nor slowing down. It's speed is constant.
The green line is starting from 4 m/s and is slowing down to 0.
The diagram helps a lot. Thank you for that.
4. A massless spring hangs from the ceiling, and a mass is hung from the bottom of it. The mass is supported
so that initially the tension in the spring is zero. The mass is then suddenly released. At the bottom of
its trajectory, the mass is 5 centimeters from its original position. Find its oscillation period.
(A) 0.05 s
(B) 0.07 s
(C) 0.31 s
(D) 0.44 s
(E) Not enough information is given.
Answer:
The correct option is C: 0.31 s.
Explanation:
When the mass is then suddenly released we have:
[tex] F = k\Delta y [/tex]
Where:
F is the force
k: is the spring constant
Δy: is the spring displacement
Since the tension in the spring is zero, the force is the weight:
[tex] F = mg [/tex]
Where:
m is the mass of the object
g is the gravity
[tex] mg = k\Delta y [/tex] (1)
The oscillation period of the spring is given by:
[tex] T = 2\pi \sqrt{\frac{m}{k}} [/tex] (2)
By solving equation (1) for "k" and entering into equation (2) we have:
[tex] T = 2\pi \sqrt{\frac{m}{\frac{mg}{\Delta y}}} [/tex]
[tex]T = 2\pi \sqrt{\frac{\Delta y}{g}}[/tex]
Since the spring will osclliates in a position between the initial position (when it is at rest) and the final position (when the mass is released and reaches the bottom), we have Δy = 2.5 cm = 0.025 m:
[tex] T = 2\pi \sqrt{\frac{0.025 m}{10 m/s^{2}}} = 0.31 s [/tex]
Hence, the oscillation period is 0.31 s.
The correct option is C: 0.31s.
I hope it helps you!
How do gamma rays use electromagnetic waves to function....PLS HELP
Answer:
Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions.
Explanation:
Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.
Hope this helps!
Brain-LIst?
Given A = (0.210 + 0.41) (1.10 x 102). Show the result for A in correct number of
significant figures.
Answer:
69
Explanation:
Perform addition first as;
(0.210 + 0.41) = 0.62 -------{2 significant figures}
Perform product
(1.10 x 102) = 112 -------------- {3 significant figures}
The combined product
0.62 x 112 =69.44
= 69 ----------2 significant figures
Rule
The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.
a ship sonar sends message and recives the eschoes from the ocean bottom 0.6 second after the sound is sent down the ship how deep is the water beneath the ship
Answer: 600 feet
Explanation:
Which of these quantities is constant in uniform circular motion?
A.speed
B.Velocity
C.acceleration
D.displacement
who win tug of war with what net force
Answer:
The force on rope is equal for both of them at any time.
For winning the game the force on ground is responsible.
Explanation:
Fix this problem, please.
Answer:
The correct option is (a).
Explanation:
Given that,
Radius of a horizontal circle, r = 80 cm = 0.8 m
Angular velocity, ω = 5 rev/minute = 0.523 rad/s
We need to find the magnitude of its centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :
[tex]a=\omega^2 r\\\\a=(0.523)^2\times 0.8\\\\a=0.218\ m/s^2[/tex]
or
[tex]a=0.22\ m/s^2[/tex]
So, the magnitude of its acceleration is [tex]0.22\ m/s^2[/tex].
Suppose an astronaut floating in space throws a rock. What will happen to the rock?
Answer:
C
Explanation: