Determine the change in energy when an electron transitions from n= to n=5?

Answers

Answer 1

Answer:

ΔE  = 13.056 ev

Explanation:

Energy associated with nth state is,

En =  -13.6/n²

For n = 1

E₁ = -13.6 / 1²

E₁ = -13.6/1

E₁ = -13.6 ev

Kinetic energy of electron = -E₁ = 13.6 ev

For n = 5

E₅ = -13.6 / 5²

E₅ = -13.6/25

E₅ = -0.544 ev

Kinetic energy of electron = -E₅ = 0.544 ev

Wavelength of radiation emitted:

ΔE = hc/λ = E₅ - E₁

by putting values,

ΔE  = -0.544ev  - (-13.6 ev  )

ΔE  = 13.056 ev


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