Una carga de 50 N unida a un resorte que cuelga verticalmente estira el resorte 5cm. El resorte se coloca ahora horizontalmente sobre una masa y se estira 11cm.

Answers

Answer 1

Answer:

-110 N

Explanation:

Una carga de 50 N unida a un resorte que cuelga verticalmente estira el resorte 5cm. El resorte se coloca ahora horizontalmente sobre una masa y se estira 11cm. ¿Qué fuerza se requiere para estirar ese resorte en esa cantidad?

Solution:

La constante de resorte (k) es la relación entre la fuerza (F) y la extensión (d) como resultado de la fuerza aplicada, por lo tanto:

k = F / d

Dado que F = 50 N, d = 5 cm = 0.05 m. Por eso:

k = F / d = 50 N / 0.05 = 1000 N / m

La fuerza (F) requerida para provocar un estiramiento de 11 cm se da como:

F = -kx

x = 11 cm = 0,11 m. Por eso:

F = -kx = -1000 * 0,11 = -110 N

El signo negativo significa que el objeto se tira hacia el resorte.


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Answer:

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Answers

Answer:

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Explanation:

I just took a test.

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Answer:

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Answers

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