Answer:
a. 2100
b. 2199
Explanation:
GIven that:
The file size = 1000 MB
The payload size is = 100 bytes
The negotiated window size is = 1000 bytes.
This implies that the sliding window can accommodate maximum number of 10 packets
The sender receives an ACK 1200 from the receiver.
Total byte of the file is :
1000 MB = 1024000000 bytes
a.
Sender receives an ACK 1200 from the receiver but still two packets are still unacknowledged
=1200 + 9 * 100
= 1200 + 900
= 2100
b. What is the last byte number that can be sent without an ACK being sent by the receiver?
b. Usually byte number starts from zero, in the first packet, the last byte will be 99 because it is in 1000th place.
Thus; the last byte number send is :
= 1200 + 10 *100 -1
= 1200 + 1000-1
= 1200 + 999
= 2199
It's not possible to die in an alcohol-related collision if you're not in an automobile.
A. True
B. False
Answer:
B. False
Explanation:
Consumption of alcohol is not a good practice and is generally not allowed at the time of driving an automobile and is considered to be an offense as it may be injurious to health and property. As too much alcohol can create possible chances of collusions and even if the person is not in an automobile can result in a collision if tries to cross the road. Like head injuries or leg injuries can occur.The CPU control unit is responsible for A. obtaining instructions B. interpreting instructions C. all logic functions D. both A and B
Answer:
D. Both A and B
Explanation:
Because it controls the input and output of data, check the signals have been delivered successfully, and make sure that data goes to the correct place at the correct time.
The key schedule results in generating multiple keys from the one secret key. These multiple keys are used:
a. in multiple sessions of communications one after the other. For example, if someone has 12 keys, they can use it for twelve video calls one after the other.
b. such that one of them is picked up at random at a time.
c. some as private keys, some as public keys.
d. for different rounds of encryption for the same plaintext to strengthen the cipher.
Answer:
Option(d) is the correct answer to the given question .
Explanation:
There are various type of algorithm is used for the purpose of the key scheduling such as AES .in the AES algorithm we used same key for encryption and decryption of text .The main objective of the AES algorithm it is used by Various round of the similar plain text encryption to reinforce the cipher text.
The Option (a) is wrong because In the key scheduling the creating keys are not being used one after just another in the various communication cycles.The Option (b) is wrong because In the key scheduling we do not used the the random key for the encryption process .The Option (c) is wrong because we will never arbitrarily subdivided into groups of public and private key.
A variable like userNum can store a value like an integer. Extend the given program to print userNum values as indicated.
(1) Output the user's input. Enter integer: 4 You entered: 4
(2) Extend to output the input squared and cubed. Enter integer: 4 You entered: 4 4 squared is 16 And 4 cubed is 64!!
(3) Extend to get a second user input into userNum2. Output sum and product. Enter integer: 4 You entered: 4 4 squared is 16 And 4 cubed is 64!! Enter another integer: 5 4+5 is 9 4*5 is 20.
Answer:
This program is written using Java programming language.
No comments were used; however, see explanation section for line by line explanation
import java.util.*;
public class Nums {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.println("1.");
int userNum;
System.out.print("Enter Integer: ");
userNum = input.nextInt();
System.out.println("You entered: "+userNum);
System.out.println("2.");
System.out.print("Enter Integer: ");
userNum = input.nextInt();
System.out.println("You entered: "+userNum);
System.out.println(userNum+" squared is "+(userNum * userNum));
System.out.println("And "+userNum+" cubed is "+(userNum * userNum * userNum)+"!!");
System.out.println("3.");
System.out.print("Enter Another integer: ");
int userNum2 = input.nextInt();
System.out.println(userNum+" + "+userNum2+" is "+(userNum + userNum2));
System.out.println(userNum+" * "+userNum2+" is "+(userNum * userNum2));
}
}
Explanation:
This enables the program accept inputs
Scanner input = new Scanner(System.in);
This signifies the beginning of number 1
System.out.println("1.");
Variable userNum is declared as type integer
int userNum;
The line prompts the user for input
System.out.print("Enter Integer: ");
The line accepts the input
userNum = input.nextInt();
This line displays user input
System.out.println("You entered: "+userNum);
This signifies the beginning of number 2
System.out.println("2.");
This line prompts the user for input
System.out.print("Enter Integer: ");
This line accepts input
userNum = input.nextInt();
This line prints user input (as required in number 2)
System.out.println("You entered: "+userNum);
This line calculates and prints the square of user input
System.out.println(userNum+" squared is "+(userNum * userNum));
This line calculates and prints the cube of user input
System.out.println("And "+userNum+" cubed is "+(userNum * userNum * userNum)+"!!");
This signifies the beginning of number 3
System.out.println("3.");
This line prompts the user for another integer value
System.out.print("Enter Another integer: ");
This line accepts the input from the user
int userNum2 = input.nextInt();
This line adds the two inputs by the user and displays the result
System.out.println(userNum+" + "+userNum2+" is "+(userNum + userNum2));
This line multiplies the two inputs by the user and displays the result
System.out.println(userNum+" * "+userNum2+" is "+(userNum * userNum2));
Write a program that inputs a sentence from the user (assume no punctuation), then determines and displays the unique words in alphabetical order. Treat uppercase and lowercase letters the same.
Answer:
Following are the code to this question:
val={} #defining dictionary variable val
def unique_word(i):#defining a method unique_word
if i in val: #defining if condition to add value in dictonary
val[i] += 1#add values
else: #defining else block to update values
val.update({i: 1})#updating dictionary
s =input('Enter string value: ') #defining s variable for input string value
w=s.split()#split string value and sorte in w variable
w.sort() #sorting the value
for i in w: #defining loop for pass value in method unique_word
unique_word(i)#assign value and calling the unique_word method
for j in val:# defining for loop to print dictionary value
if val[j] == 1: #defining if block to check value is unique
print(j) #print value
Output:
Enter string value: my name is dataman
dataman
name
is
my
Explanation:
In the above python code, a dictionary variable "val" is declared, which is used in the method "unique_word" that uses if block to count unique word and in the else block it update its value. In the next step, s variable is declared, that the user input method to store the value and another variable "w" is defined that split and sort the string value. In the last step, two for loop is declared in which the first loop passes the string value and calls the method "unique_word", and in the second loop if block is defined that check unique value and prints its value.For each of these relations on the set {21,22,23,24},decide whether it is re- flexive, whether it is symmetric, whether it is antisymmetric, and whether it is transitive.1. {(22, 22), (22, 23), (22, 24), (23, 22), (23, 23), (23, 24)} 2. {(21,21),(21,22),(22,21),(22,22),(23,23),(24,24)}
Answer:
1. {(22, 22) (22, 23), (22, 24), (23, 22), (23, 23), (23, 24)} : Not reflective, Not symmetric, Not anti-symmetric, Transitive.
2. {(21,21),(21,22),(22,21),(22,22),(23,23),(24,24)}: Reflective, symmetric.
Explanation:
Solution
Reflective: Of every element matched to its own element
Symmetric: For every (a,b) there should be (b,a)
Anti-symmetric: For every (a,b) there should not be (b,a)
Transitive: For every (a,b) ∈R and (b,c)∈ R -then (a,c) ER for all a, b, c ∈ A
Now,
1.{(22, 22) (22, 23), (22, 24), (23, 22), (23, 23), (23, 24)}
Not Reflective: This is because we don't have (21,21) (23,23) and (24,24)
Not symmetric: Because we don't have (23,24) and (24,23)
Not anti symmetric: We have both (22,23) and (23,22)
Transitive: It is either 22 or 23 be (a,b) and 24 (b,a)
2. {(21,21),(21,22),(22,21),(22,22),(23,23),(24,24)}
Reflective: For all we have (a,a)
Symmetric: For every (a,b) we have (b,a)
Not Anti-symmetric
Transitive
When introducing new devices to the network, the organization's security policy requires that devices be monitored to establish normal traffic patterns for the device. Which of the following is generated from initial monitoring?
A. SLA
B. Baseline
C. Forensic log
D. Vulnerability assessment
Answer:
The answer is "Option B".
Explanation:
The Baseline measurement is an essential characteristic of effective coal company monitoring programs to assess the degree of mining effects and keep on improving effect monitoring the system will continue to be modified via periodical analyses, and the wrong choices can be defined as follows:
In choice A, it is wrong because it used in 3D printing technology. In choice C, it is used to analyze the log entities, that's why it is wrong. In choice D, it is used to analyze the security weaknesses, that's why it's wrong.The purpose of validating the results of the program is Group of answer choices To create a model of the program To determine if the program solves the original problem To correct syntax errors To correct runtime errors
Answer:
To determine if the program solves the original problem
Explanation:
Required
Essence of validating a program
From list of given options, only the above option best describes the given illustration.
When a program is validated, it means that the results of the program are tested to meet the requirements of the user;
For a program to be validated, it means it has passed the stage of error checking and correction; whether syntax or run time errors;
However, when modifications are made, the program will need to be re-validated to ensure that it comports with its requirements.
The following code uses a nested if statement.
if (employed == 'Y')
cout << "Employed!" << endl;
else if (employed == 'N')
cout << "Not Employed!" << endl;
else
cout << "Error!" << endl;
a. True
b. False
Answer:
true
Explanation:
else if used so I think it's true
Assume that to_the_power_of is a function that expects two integer parameters and returns the value of the first parameter raised to the power of the second parameter. Write a statement that calls to_the_power_of to compute the value of cube_side raised to the power of 3 and that associates this value with cube_volume.
Answer:
The statement in python is as follows:
to_the_power_of(cube_side,3)
Explanation:
As stated as the requirement of the code segment, the statement takes as parameters a variable cube_side and a constant 3.
It then returns the volume of the cube; i.e. cube raise to power 3
See full program below
def to_the_power_of(val,powe):
result = val**powe
print(result)
cube_side = float(input("Cube side: "))
to_the_power_of(cube_side,3)
#Write a function called 'string_type' which accepts one #string argument and determines what type of string it is. # # - If the string is empty, return "empty". # - If the string is a single character, return "character". # - If the string represents a single word, return "word". # The string is a single word if it has no spaces. # - If the string is a whole sentence, return "sentence". # The string is a sentence if it contains spaces, but # at most one period. # - If the string is a paragraph, return "paragraph". The # string is a paragraph if it contains both spaces and # multiple periods (we won't worry about other # punctuation marks). # - If the string is multiple paragraphs, return "page". # The string is a paragraph if it contains any newline # characters ("\n"). # #Hint: think carefully about what order you should check #these conditions in. # #Hint 2: remember, there exists a count() method that #counts the number of times a string appears in another #string. For example, "blah blah blah".count("blah") #would return 3.
Answer:
I am writing a Python program:
def string_type(string):
if string=="": //if the string is empty
return "empty"
elif string.count(".")>1: #if the period sign occurs more than once in string
if string.count("\n"): #checks if the new line occurs in the string
return "page" #if both the above cases are true then its a page
return "paragraph" # if the period sign condition is true then its a para
elif string.count(" ")>=1: #if no of spaces in string occur more than once
return "sentence" #returns sentence
elif len(string)==1: # if length of the string is 1 this
return "character" #returns character
else: #if none of the above conditions is true then its a word
return "word" #returns word
Explanation:
def string_type(string): this is the definition of method string_type which takes a string as argument and determines whether the type of string is a word, paragraph, page, sentence or empty.
if string=="" this if condition checks if the string is empty. If this condition is true then the method returns "empty"
elif string.count(".")>1 This condition checks if the string type is a paragragh
string.count(".")>1 and if string.count("\n") both statements check if the string type is a page.
Here the count() method is used which is used to return the number of times a specified string or character appears in the given string.
Suppose the string is "Paragraphs need to have multiple sentences. It's true.\n However, two is enough. Yes, two sentences can make a paragraph."
The if condition first checks if count(".")>1 which means it counts the occurrence of period i.e. "." in the string. If the period occurs more than once this means it could be a page. But it could also be a paragraph so in order to determine the correct string type another if statement if string.count("\n") inside elif statement determines if the string is a page or not. This statement checks the number of times a new line appears in the string. So this distinguishes the string type paragraph from string type page.
elif string.count(" ")>=1: statement determines if the string is a sentence. For example if the string is "i love to eat apples." count() method counts the number of times " " space appears in the string. If the space appears more than once this means this cannot be a single word or a character and it has more than one words. So this means its a sentence.
elif len(string)==1: this else if condition checks the length of the string. If the length of the string is 1 this means the string only has a single character. Suppose string is "!" Then the len (string) = 1 as it only contains exclamation mark character. So the method returns "character" . If none of the above if and elif conditions evaluates to true then this means the string type is a word.
Answer:
def string_type(string):
if string=="": //if the string is empty
return "empty"
elif string.count(".")>1: #if the period sign occurs more than once in string
if string.count("\n"): #checks if the new line occurs in the string
return "page" #if both the above cases are true then its a page
return "paragraph" # if the period sign condition is true then its a para
elif string.count(" ")>=1: #if no of spaces in string occur more than once
return "sentence" #returns sentence
Explanation:
Although the term podcasting has caught on, a more accurate term when it applies to video content is ________. a. tubecasting b. webcasting c. vcasting d. viewcasting
Answer:
The answer is option (c) vcasting
Explanation:
Solution
Vcasting for video content are more exact terms to use in place of podcast and podcasting.
Video content or vcasting: It refers any content format that attribute or contains video. common forms of video content are vlogs, animated GIFs, customer testimonials, live videos, recorded presentations and webinar.
A network technician is designing a network for a small company. The network technician needs to implement an email server and web server that will be accessed by both internal employees and external customers. Which of the following would best secure the internal network and allow access to the needed servers?
A. Implementing a site-to-site VPN for server access.B. Implementing a DMZ segment for the server.C. Implementing NAT addressing for the servers.D. Implementing a sandbox to contain the servers.
Answer:
Option A (Implementing a site-to-site VPN for server access) seems to be the correct choice.
Explanation:
A site-to-site configuration is something that a single Open VPN network links several more separate networks linked. Technologies through one network will access machines in all the other computer systems in that connection model, including conversely. Implementing this would be extremely straightforward, for as much further even though Access Server was indeed implicated.The much more challenging aspect happens when interacting regarding firewalls including privacy filtering methods, as well as modifying the forwarding table in internet gateways, as several of them from different manufacturers but instead prototypes which they may not be able to log many of these.This rather gateway device uses an Open VPN with a Linux VPN client, to create a connection between various channels. If someone's server hardware is also measured accurately then perhaps a site-to-site configuration could be accomplished which works straightforwardly throughout all systems in both cable systems.Other choices are not related to the given instance. So that Option A would be the right one.
any element that has a starting tag and does not have a closing tag is called a ?
pls be quick guys
Answer:
Any element that has a starting tag and doesn't have a closing tag is called a empty element.
:)
"The correct syntax for passing an array as an argument to a method when a method is called and an array is passed to it is: "
Question:
"The correct syntax for passing an array as an argument to a method when a method is called and an array is passed to it is: "
A) a[0]..a[a.length]
B) a()
C) a
D) a[]
Answer:
The correct answer is A.
An example is given in the attachment.
Cheers!
A vowel word is a word that contains every vowel. Some examples of vowel words are sequoia, facetious, and dialogue. Determine if a word input by the user is a vowel word.
Answer:
vowels = ("a", "e", "i", "o", "u")
word = input("Enter a word: ")
is_all = True
for c in vowels:
if c not in word:
is_all = False
if is_all == True:
print(word + " is a vowel word.")
else:
print(word + " is not a vowel word.")
Explanation:
Initialize a tuple, vowels, containing every vowel
Ask the user to enter a word
Initially, set the is_all as True. This will be used to check, if every vowel is in word or not.
Create a for loop that iterates through the vowels. Inside the loop, check if each vowel is in the word or not. If one of the vowel is not in the vowels, set the is_all as False.
When the loop is done, check the is_all. If it is True, the word is a vowel word. Otherwise, it is not a vowel word.
what kind of company would hire an information support and service employee?
-software development
-computer repair
-website development
-network administration
Answer:
it's a
Explanation:
Explain what a honeypot is. In your explanation, give at least one advantage and one disadvantage of deploying a honeypot on a corporate network.
Answer:
A honeypot is a computer network set up to act as a decoy to track, deflect, or research trying to obtain unwanted access to the information system.
Explanation:
A honeypot is a device or device network designed to imitate possible cyber-attack targets. It can be utilized to detect or deflect assaults from a legitimate military target. It may also be used to collect knowledge on how cybercrime works.
Advantage:-
Data Value:- One of the challenges faced by the research community is to obtain meaning from big data. Companies hold large quantities of data daily including firewall logs, device logs, and warnings for vulnerability scanning. Resources:- The problem facing most protection systems is resource shortages or even the depletion of resources. Power saturation is when a protection asset can no longer work since it is overloaded by its assets. Simplicity :- I find simplicity to be the biggest single strength of honeypots. No flashy techniques are to be created, no stamp computer systems to be managed, no rule units to be misconfigured.Disadvantage:-
That honeypot doesn't replace any safety mechanisms; they just operate with your overall security infrastructure and improve it.
TLS does not require mutual authentication. Only server must authenticate its public key to the client. Client is authenticated by the application via a password. The most common way for public key authentication would be a. a photo ID. b. a password. c. a certificate. d. biometrics.
Answer:
c. a certificate.
Explanation:
Public key infrastructure authentication is intended to make transactions occurring through the internet as secure as possible. Public keys are usually assigned to entities like business firms or individuals, and digital certificates are given to them as proof that they have been authenticated.
A certificate authority has the role of signing, storing, and issuing digital certificates. A software or humans could be charged with the responsibility of actually ensuring a key to user binding if all conditions are satisfied.
Patrick Stafford's article argues that the growth of mobile phone usage "has given developers the ability to great robust and engaged communities" that help a game's chance of success.
a. true
b. false
Answer:
The statement is False.
Explanation:
In his article published on the 31st Aug 2010, Patrick suggests that a 100% penetration rate for any market is now possible due to the growth of the use of mobile phones.
The strategy of accessing the market using mobile ads, according to Patrick, is called Mobile Marketing.
In his article, Patrick provides statistics which help buttress his position that a good number of mobile phone users are ready to respond positively to mobile ads.
While it is implied that this concept has increased the chances of mobile games as a product being successful, nowhere in the article did Patric mention "games".
Cheers!
How does computer mouse impact the world, society and health?
Explanation:
Without it, we may have endured convoluted keyboard commands for years, greatly hindering the process of bringing the PC into homes everywhere. The mouse revolutionized computer interfaces, simplified an otherwise scary machine, and helped connect the world.
the typing area is bordered on the right side by bars in ms word
Answer:
Explanation:
PTA NHI
)You have been asked to do voice-overs and ""wild lines"" for a film. What is your position on the film crew? Boom operator Sound board operator Production sound mixer Sound designer
Answer:
Sound designer.
Explanation:
A boom operator is responsible for positioning of the microphone.
A sound board operator is responsible for playing pre-recorded sound effects.
A production sound mixer records all sounds on the set.
A sound designer creates and edits new sounds.
In conclusion, it must be a sound designer as this best fits the role.
Define stubs for the functions get_user_num) and compute_avg). Each stub should print "FIXME: Finish function_name" followed by a newline, and should return -1. Each stub must also contain the function's parameters Sample output with two calls to get_user_num) and one call to compute_avg): FIXME: Finish get_user_num() FIXME: Finish get_user_num() FIXME: Finish compute_avg() Avg: -1 1 ' Your solution goes here '' 2 4 user_num1 = 0 5 user_num2 = 0 6 avg_result = 0 7 8 user_num1 = get_user_num 9 user_num2 = get_user_num ) 10 avg_result = compute_avg(user_num1, user_num2) 11 12 print'Avg:', avg_result)|
Answer:
Here are the stub functions get_user_num() and compute_avg()
def get_user_num():
print('FIXME: Finish get_user_num()')
return -1
def compute_avg(user_num1, user_num2):
print('FIXME: Finish compute_avg()')
return -1
Explanation:
A stub is a small function or a piece of code which is sometimes used in program to test a function before its fully implemented. It can also be used for a longer program that is to be loaded later. It is also used for a long function or program that is remotely located. It is used to test or simulate the functionality of the program.
The first stub for the function get_user_num() displays FIXME: Finish get_user_num() and then it returns -1.
The seconds stub for the function compute_avg() displays the FIXME: Finish compute_avg() and then it returns -1.
Here with each print statement, there is function name after this FIXME: Finish line. The first function name is get_user_num and the second is compute_avg().
Next the function get_user_num() is called twice and function compute_avg() followed by a print statement: print('Avg:', avg_result) which prints the result. So the program as a whole is given below:
def get_user_num():
print('FIXME: Finish get_user_num()')
return -1
def compute_avg(user_num1, user_num2):
print('FIXME: Finish compute_avg()')
return -1
user_num1 = 0 # the variables are initialized to 0
user_num2 = 0
avg_result = 0
user_num1 = get_user_num() #calls get_user_num method
user_num2 = get_user_num()
avg_result = compute_avg(user_num1, user_num2)
print('Avg:', avg_result)
The method get_user_num() is called twice so the line FIXME: Finish get_user_num() is printed twice on the output screen. The method compute_avg() is called once in this statement avg_result = compute_avg(user_num1, user_num2) so the line FIXME: Finish compute_avg() is printed once on the output screen. Next the statement print('Avg:', avg_result) displays Avg: -1. You can see in the above program that avg_result = compute_avg(user_num1, user_num2) and compute_avg function returns -1 so Avg= -1. The program along with the produced outcome is attached.
6. A distribution consists of three components with frequencies 200, 250 and 300 having means
25,10, and 15 and standard deviations 3, 4, and 5 respectively.
Calculate
The mean?
The standard deviation?
Answer:
The mean = 16
The standard deviation = 7.19
Explanation:
N1 = 200 X1 = 25 σ1 = 3
N2= 250 X2 = 10 σ2 = 4
N3 = 300 X3= 15 σ3 = 5
The mean of a combined distribution is given by:
[tex]X = \frac{X_1N_1+X_2N_2+X_3N_3}{N_1+N_2+N_3}\\X = \frac{25*200+10*250+15*300}{200+250+300}\\X=16[/tex]
The differences from the mean for each component are:
[tex]D_1 = 25-16=9\\D_2=10-16=-6\\D_3=15-16=-1[/tex]
The standard deviation of a combined distribution is given by:
[tex]\sigma=\sqrt{\frac{N_1(\sigma_1^2+D_1^2)+N_2(\sigma_2^2+D_2^2)+N_3(\sigma_3^2+D_3^2)}{N_1+N_2+N_3}}\\\sigma=\sqrt{\frac{200(3^2+9^2)+250(4^2+(-6)^2)+300(5^2+(-1)^2)}{200+250+300}}\\\sigma=\sqrt{\frac{18000+13000+7800}{750} }\\\sigma=7.19[/tex]
The mean = 16
The standard deviation = 7.19
Which operating system problem might cause the desktop background to change
unexpectedly? Choose the answer.
A boot failure
B startup loop
C malware D incompatibility
It should be noted that the operating system problem that might cause the desktop background to change is D incompatibility.
What is operating system problem?The operating system problem serves as those error that can affect the operation of the operating system in computer.
This System errors are caused by malfunctioning hardware components as well as corrupted operating system modules and one of this is compatibility.
Learn more about operating system problem at;
https://brainly.com/question/17506968
Identify and write the errors given in the flowchart (with steps and flowchart) : Start ↓ Input A,B ↓ Average = (A + B + C) / 3 ↓ Print Average ↓ Stop
Answer:
i will send you the answers in the next 10minute
More than one component in a particular automotive electric circuit is not working. Technician A starts testing the circuit at the power source. Technician B starts testing the circuit at its load. Who is right?
Hi there! Hopefully this helps!
--------------------------------------------------------------------------------------------------
The answer is A, testing the circuit at the power source.
On a system with paging, a process cannot access memory that it does not own. Why? How could the operating system allow access to other memory?
Answer:
Because the page is not in its page tableThe operating system could allow access to other memory by allowing entries for non-process memory to be added to the process page tableExplanation:
On a system with paging, a process cannot access memory that it does not own because the page is not in its page table also the operating system controls the contents of the table,therefore it limits a process of accessing to only the physical pages allocated to the process.
The operating system could allow access to other memory by allowing entries for non-process memory to be added to the process page table.that way two processes that needs to exchange data can efficiently do that . i.e creating a very efficient inter-process communication
Write a program that asks the user to input a positive integer and then calculates and displays the factorial of the number. The program should call a function named getN
Answer:
The program is written in python and it doesn't make use of any comment;
(See explanation section for line by line explanation)
def getN(num):
fact = 1
for i in range(1, 1 + num):
fact = fact * i
print("Factorial: ",fact)
num = int(input("Number: "))
if num < 0:
print("Invalid")
else:
getN(num)
Explanation:
The function getNum is defined here
def getN(num):
Initialize the result of the factorial to 1
fact = 1
Get an iteration from 1 to the user input number
for i in range(1, 1 + num):
Multiply each number that makes the iteration
fact = fact * i
Print result
print("Factorial: ",fact)
Ths line prompts user to input number
num = int(input("Number: "))
This line checks if user input is less than 0; If yes, the program prints "Invalid"
if num < 0:
print("Invalid")
If otherwise, the program calls the getN function
else:
getN(num)