Two speakers that are 15.0 mproduce in-phase sound waves of frequency 250.Hz in a roomwhere the speed of sound is 340. m/s. A woman starts out at the midpoint between the two speakers.a.What does she hear at the midpoint, constructive or destructive interference?b.She now walks slowly towards one of the speakers. How far from the center must she walk before she first hears the sound reach a minimum intensity?c.How far from the center must she walk before she first hears the sound at a maximum intensity?d.How far from the center must she walk before the second time she hears the sound at the minimum intensity?

Answers

Answer 1

Answer:

a. Constructive interference.

b. [tex]0.34\; \rm m[/tex].

c. [tex]0.68\; \rm m[/tex].

d. [tex]1.02\; \rm m[/tex].

Explanation:

Frequency of this sound wave: [tex]f = 250\; \rm Hz = 250\; \rm s^{-1}[/tex].

Speed of this sound wave: [tex]v = 340\; \rm m \cdot s^{-1}[/tex].

Calculate the wavelength of this sound wave:

[tex]\begin{aligned} \lambda &= \frac{v}{f} \\ &= \fraac{340\; \rm m \cdot s^{-1}}{250\; \rms^{-1}} \approx 1.36\; \rm m\end{aligned}[/tex].

Path difference refers to the absolute value of the difference between:

the distance between the first source (the first speaker) and the observer, andthe distance between the second source (the second speaker) and the observer.

When the observer in this question is on the line between the two speakers at [tex]d[/tex] meters from the midpoint, the corresponding path difference would be [tex]2\; d[/tex] meters. (Add [tex]d\![/tex] to the distance from the closer source, and subtract [tex]d\!\![/tex] from the distance from the other source.)

The question states that sound from the two speakers are in-phase. In other words, at every instant, the sound wave from the two speakers are at the same phase at the position of each speaker.

Because wave from the two sources are in-phase at the source:

Constructive interference happens when the path difference is an integer multiple of wavelength ([tex]k\, \lambda[/tex], where [tex]k[/tex] is an integer.) That includes: [tex]0[/tex], [tex]\lambda[/tex], [tex]2\, \lambda[/tex], etc.Destructive interference happens when the path difference is an one-half plus some integer multiple of wavelength ([tex](k + 1/2) \, \lambda[/tex], where [tex]k[/tex] is an integer.) That includes: [tex]\lambda / 2[/tex], [tex]3\, \lambda / 2[/tex], [tex]5\, \lambda / 2[/tex], etc.

Path difference is [tex]0[/tex] when the observer is at the midpoint. That would correspond to constructive interference.

The first destructive interference (minimum intensity) corresponds to a path difference of [tex]\lambda / 2[/tex]. Along the line, that would be observed at [tex](1/2) \cdot (\lambda / 2) = 0.34\; \rm m[/tex] from the midpoint.

The next constructive interference (maximum intensity) would be observed when path difference is [tex]\lambda[/tex]. Along the line, that would be observed at [tex](1/2)\cdot \lambda = 0.68\; \rm m[/tex] from the midpoint.

The second destructive interference (minimum intensity) would be observed when path difference is [tex](1 + (1/2))\, \lambda[/tex]. Along the line, that would be observed at [tex](1/2) \cdot ((3/2)\cdot \lambda) = 1.02\; \rm m[/tex] from the midpoint.


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EDGE 2021

Mr. LaCosta is making a circular garden for our outdoor green space. The garden has a diameter of 11m. He has to buy plastic fencing to put around the edge. The fencing costs $5.75/m. What would be the total cost before taxes?

Answers

Answer:

The total cost before taxes to fence the garden is approximately $198.71

Explanation:

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A roller coaster is released from the top of a track that is 125 m high. Find the rollar coaster speed when it reaches ground level.​

Answers

Explanation:

A roller coaster is released from the top of a track that is 125 m high. Find the roller coaster speed when it reaches ground level. 75. A 1500 kg car, moving at a speed of 20 m/s comes to a halt. How much work was done .

HOPE IT HELPS

mark me in brainliest answers please please please

The roller coaster speed when it reaches to ground level is 15.65 m/sec

Given-

Roller coaster is released at a height of 125 meters.

It is known that, square of the final velocity [tex]v[/tex] of the body is equal to the sum of the square of initial velocity [tex]v_{10}[/tex] and the product of the twice of acceleration [tex]a[/tex] and displacement [tex]d[/tex]. It can be written as,

[tex]v^{2} =v_{0}^2+2ad[/tex]

Roller coaster released from rest therefore initial velocity is zero.

[tex]v^{2} =0+2ad[/tex]

[tex]v^{2} =2ad[/tex]

Roller coaster will fall towards the ground with an acceleration equal to gravity g and height of 125 m. therefore,

[tex]v^{2} =2\times g\times 125[/tex]

[tex]v^{2} =2\times 9.8\times 125[/tex]

[tex]v^{2} =2450[/tex]

[tex]v=15.65[/tex]

Hence, the roller coaster speed when it reaches to ground level is 15.65 m/sec.

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Have a good day



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Answer:

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Answers

Answer:

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Answer:

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[tex]m_{s}[/tex] - Mass of the sled, measured in kilograms.

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[tex]v_{s,o}[/tex] - Initial velocity of the sled, measured in meters per second.

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The combined velocity of Sally and the sled is 1.688 meters per second.

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Answer:

see below

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hope this helps,

please mark it

The correct answer to this question is  (120 waves)

Given:

Frequency= 2Hz

Number of waves = ?

The number of waves that is been formed per seconds = frequency

Then since frequency= 2Hz then there are 2 complete waves that is formed  in 1 seconds

1 seconds= 2 waves

But 60 seconds = 1 minutes

Number of  waves produced in 1 minutes ( 60 seconds) = ( 2×60)

= 120 waves

Therefore, the number of waves that will be formed in one minute is 120 waves

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