Answer:
2ohms
Explanation:
the net resistance is given by
1/R=1/R1 +1/R2,we are supposed to find R
thus by making R the subject ....
R=R1•R2/R1+R2
R=3•6/3+6
R=18/9 =2Ohms
A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 11.5 pC. The inner cylinder has a radius of 0.550 mm, the outer one has a radius of 7.20 mm, and the length of each cylinder is 13.0 cm.
(a) What is the capacitance?
(b) What applied potential difference is necessary to produce these charges on the cylinders?
Answer:
A)2.811 × 10^-12 F
B)4.09V
Explanation:
(a) What is the capacitance?
Capacitance of coaxial cylinder can be determined using below expresion
C= (2π ε0 L)/ Ln[ rb/ra]
Where
ε0= permittivity of free space= 8.85×10^−12 Fm^-1
L= length of each cylinder =13.0 cm= 13×10^-2m
rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m
ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m
If we substitute the values we have,
C= (2π ε0 L)/ Ln[ rb/ra]
C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[
7.20×10^-3/0.550×10^-3]
C=( 7.2288×10^-12 )/2.5729
C=2.811 × 10^-12 F
B) (b) What applied potential difference is necessary to produce these charges on the cylinders?
Vba= Q/C
Where Vba=potential difference
Q= charge on each = 11.5 pC. = 11.5×10^-12
C= capacitance= 2.811 × 10^-12 F
If we substitute the values we have
Vba=(11.5×10^-12)/2.811 × 10^-12
= 4.09V
I need help with science please, ill give brianlist’s :
Question 1 :The size of a plant cell may change depending upon the amount of water it receives.
True
False
________________________________
Question 2: Chloroplasts are a category of organelles found in the cells of green plants.
True
False
_______________________________
Question 3: Photosynthesis in plants produces water and carbon dioxide.
True
False
Answer:
true , true, and I'm not sure about the last one!
Explanation:
The bus lay 40 km at a speed of 72 km / h, and then another 60 km at a speed of 30 m / s. Determine the average speed of the bus along the way.
Answer:
25 m/s
Explanation:
From the question,
Average speed = Total distance /total time.
S' = D/T........................... Equation 1
D = 40+60 = 100 Km = 100000 m.
T = t₁+t₂
t₁ = (40×3600/72) s = 2000 s
t₂ = 60000/30 = 2000 s
T = 2000+2000 = 4000 s.
SUbstitute the values of T and D into equation 1
S' = 100000/4000
S' = 25 m/s
5j-Tj=6j+3 Tj
Determine the value of T from the given vector
A police officer uses a radar gun that emits electromagnetic waves with a frequency of 10.525 GHz (1.0525 1010 Hz). Assume the police officer is at rest, and is aiming the radar gun at vehicles traveling either directly toward, or directly away from, the radar gun. Assume the speed limit is 110 km/h, as it is on many Canadian highways. The police officer observes reflected waves that have a frequency of 2460 Hz below the frequency of the emitted waves.
Required:
a. At what speed is the car moving?
b. Choose the two correct statements about this situation.
1. The car is moving toward the police officer.
2. The car is moving away from the police officer.
3. The police officer should not cite the driver for speeding.
4. The police officer should cite the driver for speeding.
Answer:
Explanation:
For Doppler effect in radar the formula is as follows
Δf = f₀ x 2v /c
Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .
Δf = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .
2460 = 1.0525 x 10¹⁰ x 2 v / 3 x 10⁸
2460 = 105.25 x 2 v / 3
v = 2460 x 3 / (105.25 x 2 )
v = 35 .06 m /s .
(b)
Since the observed frequency is less , the source is moving away from the observer .
option (2) is correct .
What color is a carrot?
Answer:
reddish-orrange
Explanation:
please mark me as brainliest
(WILL MARK BRAINLIAST)( 1 answer question.. look the photo)
As the cars come closer together, the amount of potential energy in the system:
-Increases
-Decreases
-Stays the same
Answer:
increases
Explanation:
due to less speed
As Carlos and Manual both push a 4 kg box to the right across a rough floor, the box speeds up at a rate of 2.0 m/s2.(Hint, this is the acceleration.) If you assume that Manual pushes with a force strength of 8.0 N and the friction force of the floor on the box is 5.0 N, then what is the strength of the force that Carlos pushes on the box
Answer: 5 N
Explanation:
Given
Mass of box [tex]m=4\ kg[/tex]
acceleration of box [tex]a=2\ m/s^2[/tex]
Force applied by Manual [tex]F_m=8\ N[/tex]
Friction force [tex]f=5\ N[/tex]
The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]
Suppose [tex]F_c[/tex] is the force applied by Carlos
[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]
The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
What is force?The force is defined as the external effort applied on any object to move it or to restrict it.
Here following information is given in the question:
Mass of the box m=4 kg
The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]
The force applied by the Manual [tex]F_m=8\ N[/tex]
The frictional force is [tex]F_f=5\ N[/tex]
The net force on the body will be calculated by
[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]
The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:
[tex]F_m+F_c-F_f=F_{net}[/tex]
[tex]8+F_c-5=8[/tex]
[tex]F_c=5\ N[/tex]
Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
To know more about forces follow
https://brainly.com/question/388851
What is double stroking
Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.
Explanation: hope this helps!
Explanation:
it is played as a sequence of alternating strokes
Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (560 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 3.0 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
y = 4.666 10⁻² m
Explanation:
The constructive interference experiment for the double slit
d sin sin θ = m λ
Let's use trigonometry to find a sine relationship.
Tan θ = y / L
tan θ = sin θ/ cos θ
in these experiments the angles are very small
tan θ = sin θ
sin θ = y / L
[tex]d \frac{y}{L}[/tex] = m λ
y = [tex]\frac{ m \lambda \ L}{d}[/tex]
we replace the values
y = 3 560 10⁻⁹ 3.0 / 0.108 10⁻³
y = 4.666 10⁻² m
Define electromagnetism
Answer:
the phenomenon of the interaction of electric currents or fields and magnetic fields.
Why do we use copper wiring?
Explanation:
The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals
please help me with the working too.
Answer:
1 : b 2: d
Explanation:
A baseball is traveling (+30m/s) and is hit by a bat. It leaves the bat traveling (−40m/s). What is the change in its velocity?
Unlike some others, this is any choice, so not just 4 choices!
Answer:
Explanation:
The change must be 30 - - 40 which means it came in a 30 meters / second and went out in the opposite direction at 40 meters / second
The change is 70 m/sec.
You could show it to be - 70 meters per second as well. That's done by making the outgoing direction minus.
Delta v = vf - vi.
Now it depends on which way you define vf and vi.
Expository essay "Climate change in Fiji"
Answer: Climate change poses to the tourism development in Fiji islands. It shows the adverse effects of the changing climate and the dangers pose by the tourism activities and also pose a major hazard for the local people in the region. It also deals with the dangerous carbon emissions and CO2 effect on the landscape, food, water, energy.
The pacific is the world`s largest ocean with a surface area of 175 million sq km and constitutes for 40% of the planet`s waters. Located in the tropical latitudes, it covers more than half the globe`s circumference. Temperature of the surface water in the western tropical regions is always more than 28 ÌŠC over a depth of several hundred meters. This makes up the world`s storage of thermal energy for exchange with atmosphere. Here the interaction between atmosphere and ocean is most extreme and influences the climate not only regionally but planet-wide. The nations of the pacific are obscured human settlements absorbed in this vast fluid universe. The ocean is the most important factor controlling the environment and life.
NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow
Answer:
It is A. Light blue
_____________
Hope this helps!
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┈┃┏┗┛┓┃╭┫o i n k ┃
┈╰┓▋▋┏╯╯╰━━━━╯
╭━┻╮╲┗━━━━╮╭╮┈
┃▎▎┃╲╲╲╲╲╲┣━╯┈
╰━┳┻▅╯╲╲╲╲┃┈┈┈
┈┈╰━┳┓┏┳┓┏╯┈┈┈
┈┈┈┈┗┻┛┗┻┛┈┈┈┈
Direction of Wave Travel
С
Which letter
correctly
identifies the
wavelength of
this wave?
А
B
A. A
B. B
C. C
Answer:
I THINK it's A but I'm not completely sure
C
D
7
The sun is the original source of
energy for many of our energy
resources
Which energy resource does not
originate from the sun? *
(1 Point)
.
A. Geothermal
B. Hydroelectric
C. Waves
D. Win
Answer:
geothermal
Explanation:
geothermal energy is the heat energy obtained from within the Earth. Hence not derived from Sun's energy.
What is Gravity?
PLEASE ANSWER
Answer:
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.
Please mark as brainliest
Have a great day, be safe and healthy
Thank u
XD
Answer:
GRAVITY:
In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.
A baseball is thrown a distance of 20 m what is its speed if it takes 0.5 seconds to cover the distance
Answer:
40m/s
Explanation:
A young parent is dragging a 65 kg (640 N) sled (this includes the mass of two kids) across some snow on flat ground, by means of a rope attached to the sled. The rope is at an angle of 30 degrees with respect to the ground and the tension in the rope is 160 N. The sled is moving at a constant velocity of 1.5 m/s.
(a) Draw and label all forces acting on the kids + sled system. Indicate the relative size of each force by scaling the length of each force arrow appropriately
(b) Calculate the normal force acting on the system
(c) Calculate the force of friction acting on the system.
(d) Calculate the coefficient of friction between the sled and the snow.
Answer:
b) N = 560 N, c) fr = 138.56 N, d) μ = 0.247
Explanation:
a) In the attachment we can see the free body diagram of the system
b) Let's write Newton's second law on the y-axis
N + T_y -W = 0
N = W -T_y
let's use trigonometry for tension
sin θ = T_y / T
cos θ = Tₓ / T
T_y = T sin θ
Tₓ = T cos θ
we substitute
N = W - T sin 30
we calculate
N = 640 - 160 sin 30
N = 560 N
c) as the system goes at constant speed the acceleration is zero
X axis
Tₓ - fr = 0
Tₓ = fr
we substitute and calculate
fr = 160 cos 30
fr = 138.56 N
d) the friction force has the formula
fr = μ N
μ = fr / N
we calculate
μ = 138.56 / 560
μ = 0.247
A frictionless piston-cylinder contains carbon dioxide gas (CO2) initially at 500oC and 2 MPa. The system is o3 cooled in an isobaric process until the final temperature becomes 350 C and the final volume is 1 m . For this process, determine: (a) The reduced pressure and the reduced temperature of the initial state. (b) The initial volume of the piston-cylinder (in m3). (c) The mass of CO2 in the piston-cylinder (in kg). (d) The total boundary work for the process (in kJ). (e) The amount of heat transfer during the cooling process (in kJ).
Answer:
(a) The reduced pressure is 0.2711 MPa
The reduced temperature is 2.54 K
(b) The initial volume of the piston is approximately 0.806 m³
(c) The mass of CO₂ is approximately 16.9884 kg
(d) The work done, W is approximately 388.023 kJ
(e) The heat transfer is approximately -2,650.1904 kJ
Explanation:
The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K
The initial pressure of the gas, P₁ = 2 MPa
The final temperature of the gas, T₂ = 350°C
The final volume of the gas = 1 m³
(a) For an isobaric process, we have;
The reduced pressure,
[tex]P_r = \dfrac{P}{P_c}[/tex]
The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa
[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]
The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa
The critical temperature, [tex]T_c[/tex] = 304.13 K
The reduced temperature, [tex]T_r[/tex], is given by the following formula;
[tex]T_r = \dfrac{T}{T_c}[/tex]
Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K
The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K
(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁
∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³ ≈ 0.806 m³
The initial volume of the piston, V₁ ≈ 0.806 m³
(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;
n = P·V/(T·R)
The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles
The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg
(d) The work done, W = P·([tex]V_f - V_i[/tex])
W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227
The work done, W ≈ 388.023 kJ
(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)
[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)
∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ
Therefore, the heat transfer = dQ = -2,650.1904 kJ
A 1.6 kg ball is attached to the end of a 0.40 m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80 kg block that is at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3 m/s. What is the speed of the ball just after the collision
Answer:
the speed of the ball just after the collision is 1.5 m/s.
Explanation:
Given;
mass of the ball, m₁ = 1.6 kg
initial velocity of the ball, u₁ = 0
mass of the block, m₂ = 0.8 kg
initial velocity of the block, u₂ = 0
final velocity of the block, v₂ = 3 m/s
let the final velocity of the ball after collision = v₁
Apply the principle of conservation of linear momentum for elastic collision;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.6 x 0 + 0.8 x 0 = 1.6 x v₁ + 0.8 x 3
0 = 1.6v₁ + 2.4
-1.6v₁ = 2.4
v₁ = -2.4 / 1.6
v₁ = - 1.5 m/s
v₁ = 1.5 m/s (in opposite direction of the block)
Therefore, the speed of the ball just after the collision is 1.5 m/s.
Which water on earth is the largest,second to the largest,3rd to the largest,fourth to the largest and 5th to the largest?
Answer:
Explanation:
There are a total of 5 differen classification for the types of bodies of water that exist on Earth. These 5 would be the following: Oceans, seas, lakes, rivers, and canals. Oceans are the biggest bodies of water on Earth. If we ranked them by their size the ranking would be the following...
Pacific Ocean - being 155,556,651 sq km. in size
Atlantic Ocean - being 76,761,938 sq km. in size
Indian Ocean - being 68,555,923 sq km. in size
Antarctic / Southern Ocean - being 20,327,001 sq km. in size
Arctic Ocean - being 14,055,930 sq km. in size
Explain why the sound waves always reach the observer after the light waves
Answer:
I think it's because the light waves travel faster than the sound waves.
The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.
What is the speed of light?Light occurs in the electromagnetic spectrum. Recall that light can be transmitted through vaccuum unlike sound.
The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.
Learn more about speed of light:https://brainly.com/question/8832859
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4. If the cooling of magma takes place slowly beneath Earth's surface, the rock is that is formed
is called
a. extrusive igneous rock
b. intrusive igneous rock
c. sedimentary rock
d. metamorphic rock
a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energies (a) a its initial position, (b) at 5 m above the initial position, and (c) at its maximum height
Answer:
a) [tex] E_{p} = 0 [/tex]
[tex] E_{k} = 168.7 J [/tex]
[tex] E_{m} = 168.7 J [/tex]
b) [tex] E_{p} = 73.6 J [/tex]
[tex] E_{k} = 95.8 J [/tex]
[tex] E_{m} = 169.4 J [/tex]
c) [tex] E_{p} = 169.2 J [/tex]
[tex] E_{k} = 0 [/tex]
[tex] E_{m} = 169.2 J [/tex]
Explanation:
We have:
m: is the ball's mass = 1.5 kg
v₀: is the initial speed = 15 m/s
g: is the gravity acceleration = 9.81 m/s²
a) In the initial position we have:
h: is the height = 0
The potential energy is given by:
[tex] E_{p} = mgh = 0 [/tex]
The kinetic energy is:
[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]
And the mechanical energies:
[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]
b) At 5 m above the initial position we have:
h = 5 m
The potential energy is:
[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]
Now, to find the kinetic energy we need to calculate the speed at 5 m:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]
[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]
[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]
And the mechanical energies:
[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]
c) At its maximum height:
[tex] v_{f}[/tex]: is the final speed = 0
[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]
Now, the potential, kinetic and mechanical energies are:
[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]
[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]
[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]
I hope it helps you!
ball A is dropped from a hot air balloon rising at a costant velocity of 14,7 m.s'1 at a height of 19,7 m above the ground.the ball took 1.5s to reach its maximum height and hits the ground after some time in air.ignore the effects of air resistanceUse the ground as zero reference.3.1.1calculate the maximum height reached by the ball above the ground
Answer:
this slow site thinks the answer is a link
Explanation:
this was a week ago so i dont know if u still need help
Which of the following is an example of the transformation of gravitational potential energy into motion energy (kinetic energy)?
Answer:
c
Explanation:
because a drop of water is falling and that is gravitational potential energy into motion energy
Need a little help here, ASAP please. The subject is simple science, not physics.