Two possible floor plans for a new bathroom are shown.
Is there a value for x for which the perimeters are equal?
What is the linear equations?

Answer:

4:36

24 x 4:36

96:36

8:4

1day = 24 hours

Step-by-step explanation:

Answer:

no rocky

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

I think it's C and I am always right so it is C! You're welcome!

Answer:

[tex]DM=12[/tex]

Step-by-step explanation:

(Let the point where the altitude from [tex]D[/tex] intersects [tex]AB[/tex] be called as point [tex]E[/tex].) First, let's find the area of parallelogram [tex]ABCD[/tex]. The area of a parallelogram is simply [tex]b*h=bh[/tex], where [tex]b[/tex] is the parallelogram's base and [tex]h[/tex] is the parallelogram's height. If we let [tex]AB[/tex] and [tex]DE[/tex] be the base and height respectively, since we are already given their lengths, we know that the area of parallelogram [tex]ABCD[/tex] will be [tex]AB*DE=15*8=120[/tex].

Now, how does this information matter, you might ask? Well, we can take either [tex]AB[/tex] or [tex]CB[/tex] to be the base and either [tex]DE[/tex] or [tex]DM[/tex] to be the height. In this case, let's take the latter two options, as we are looking to find the length of [tex]DM[/tex].

Therefore, we know that the area of parallelogram [tex]ABCD[/tex] can also be found by calculating [tex]CB*DM[/tex]. Since we know the values of the area and [tex]CB[/tex], we can write the following equation to solve for [tex]DM[/tex]:

[tex]Area = CB*DM[/tex]

[tex]120=10*DM[/tex] (Substitute [tex]Area=120[/tex] and [tex]CB=10[/tex] into the equation)

[tex]\frac{120}{10}=\frac{10*DM}{10}[/tex] (Divide both sides of the equation by [tex]10[/tex] to get rid of [tex]DM[/tex]'s coefficient)

[tex]12=DM[/tex] (Simplify)

[tex]DM=12[/tex] (Symmetric Property of Equality)

Hope this helps!

Answer:

the answer is D.

Step-by-step explanation:

Since the square: (3√15) is common in both of them, you only focus on 21 and 9. if you subtract 9 from 21, it will give you 12. so, just add (3√15) to 12, which will give you: 12^3sqrt15

Answer:

5852.86 = 5000 (1+ .032)^5

1170572956 = 1,000,000,000(1+ .032)^5

Step-by-step explanation:

Answer:

60

Step-by-step explanation:

9/15=0.6

0.6x100=60

Answer:

Step-by-step explanation:

exponential decay

rate of change: 20%

Answer:

21 I think, might be wrong.

Answer: $11.25

Step-by-step explanation:

Answer:

$11.25

Step-by-step explanation:

I assume that x = the 5 videos streamed

5*1.25=6.25

6.25+5 =11.25

y=$11.25

Answer:

0.254

Step-by-step explanation:

Given that:

Percentage of those having health insurance = 71%

p = 71 / 100 = 0.71

Number of adults selected at random, n = 4

Probability that 4 selected have health insurance :

p^n = 0.71^4 = 0.25411681

= 0.254

Answer:

Please check the attached graph.

Step-by-step explanation:

The slope-intercept form of the line equation

[tex]y = mx+b[/tex]

where

Given the system of equations

2x - 5y = -5    --- [Equation 1]

y = -3x + 1​      --- [Equation 2]

converting the equation 1 in the slope-intercept form

2x - 5y = -5

5y = 2x+5

divide both sides by 5

y = 2/5x + 1

Thus, the y-intercept  = 1

Now, please check the attached graph below.

The red line represents the equation  2x - 5y = -5

From the graph, it is clear that the red line has the y-intercept y = 1.

Now, considerng the equation 2

y = -3x + 1​  

comparing with the slope-intercept form of line equation

The y-intercept b = 1

Hence, the y-intercept of the line y = -3x + 1​ is y = 1

The green line represents the equation  y = -3x + 1​  

From the graph, it is clear that the green line has the y-intercept y = 1.

Point of Intersection:

It is clear from the graph:

As both lines meet or intersect at the point (0, 1).

Therefore, the point of intersection of both the lines is:

(x, y) = (0, 1)

As we know that the point of intersection of both the lines represents the solution to the system of equations.

Therefore, (0, 1) on the graph represents the solution to the system of equations.

The graph is attached below.

Answer:

The answer is below

Step-by-step explanation:

For a normal distributed population with a mean (μ), and a standard deviation (σ), if a sample size of n is selected from the population, the mean of the sample ([tex]\mu_x[/tex]) =  μ and the standard deviation of the sample ([tex]\sigma_x[/tex]) = [tex]\frac{\sigma }{\sqrt{n} }[/tex]

Let the normal distribution population have a standard deviation of σ. If the standard deviation is to be decreased by half, the sample size (n) needed is:

[tex]Using:\\\\\sigma_x=\frac{\sigma}{\sqrt{n} } \\\\but\ \sigma_x=\frac{\sigma}{2}\\\\Hence:\\\\ \frac{\sigma}{2}=\frac{\sigma}{\sqrt{n} }\\\\Divide\ through\ by \ \sigma\ to\ get:\\\\ \frac{1}{2}=\frac{1}{\sqrt{n} }\\\\\sqrt{n}=2\\\\square\ both\ sides:\\\\(\sqrt{n} )^2=2^2\\\\n=4\\\\[/tex]

To decrease the standard deviation of the sampling distribution by half we need a sample size of 4

Answer:

a) % age of samples containing none of these defects = 93.9%

b)% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect = 98.9%

Step-by-step explanation:

Data Given:

Number of Samples = 1000

Type X defect = 2.1% = 21 samples

Type Y defect = 2.4% = 24 samples

Type Z defect = 2.8% = 28 samples

Both Type X and Y defect = 0.3% = 3 samples

Both Type X and Z defect = 0.4% = 4 samples

Both Type Y and Z defect = 0.6% = 6 samples

Type X and Y and Z defect = 0.1%  = 1 sample

Venn Diagram is attached in the attachment below. Please refer to attachment for the Venn Diagram.

a) % age of samples containing none of these defects.

Solution:

Number of samples containing none of these defects = Total - Samples with defects

Number of samples containing none of these defects = 1000 - { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

 Number of samples containing none of these defects = 1000 - { (21) + (24) +(28) - (3) -(4) - (6) + (1) }

Number of samples containing none of these defects = 1000 - 61

Number of samples containing none of these defects = 939

% age of samples containing none of these defects = 939/1000 x 100

% age of samples containing none of these defects = 93.9%

b) % age of samples containing at least one of these defects:

We have already calculated this above, number of samples containing at least on of these defects:

number of samples containing at least on of these defects = { (Type X) + (Type Y) + (Type Z) - (Both X and Y) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

number of samples containing at least on of these defects = { (21) + (24) +(28) - (3) -(4) - (6) + (1) }  

number of samples containing at least on of these defects = 61

% age of samples containing at least one of these defects = 61/1000 x 100

% age of samples containing at least one of these defects = 6.1%

c) % age of samples free of type X and/or type Y defects.

For this find, we need to find the samples with only Z Type defect.

Number of Samples with Only Z type defects = { (Type Z) - (Both X and Z) - (Both Y and Z) + (All defects X and Y and Z) }

Number of Samples with Only Z type defects = { (28)  -(4) - (6) + (1) }

Number of Samples with Only Z type defects = 19

Now, we also know the number of samples without any defects = 939

Now,

The number of samples free of type X and/or type Y defect = Sum of Number of Samples with Only Z type defects and number of samples without any defects

The number of samples free of type X and/or type Y defect = 19+939

The number of samples free of type X and/or type Y defect = 958

% age of samples free of type X and/or type Y defects = 958/1000 x 100

% age of samples free of type X and/or type Y defects = 95.8%

d) %age of samples with not more than 1 defect:

For this find, we need to find number of samples with only X type and with only type Y and with only type Z.

We have already found the number of samples with only Z type defect = 19

Now,

number of samples with only X type defect = { (Type X) - (Both X and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only X type defect =  { (21)  -(4) - (3) + (1) }

number of samples with only X type defect =  15

Similarly,

number of samples with only Y type defect =  { (Type Y) - (Both Y and Z) - (Both X and Y) + (All defects X and Y and Z) }

number of samples with only Y type defect =  { (24)  -(6) - (3) + (1) }

number of samples with only Y type defect =  16

For,

samples with not more than 1 defect = number of samples with only Y type defect + number of samples with only X type defect + number of samples with only z type defect + number of samples without any defects

samples with not more than 1 defect = 939 + 16 + 15 + 19

samples with not more than 1 defect = 989

%age of samples with not more than 1 defect = 989/1000 x 100

%age of samples with not more than 1 defect = 98.9%

Answer:

We get [tex]\mathbf{n>-10\:\:and\:\:n<8}[/tex]

Or we can write as:  [tex]\mathbf{-10<n<8}[/tex]

The graph is shown is figure attached below:

Step-by-step explanation:

We need to solve the inequality [tex]-1<9+n<17[/tex] and graph the answer.

Solving the inequality

[tex]-1<9+n<17[/tex]

We know that if a<u<b then we can write a<u and u<b

So, we can write

[tex]-1<9+n \:and\: 9+n<17[/tex]

Solving these equations and finding values of n

[tex]-1<9+n \:and\: 9+n<17\\9+n>-1\:and\:9+n<17\\n>-1-9\:and\:n<17-9\\n>-10\:and\:n<8[/tex]

So, we get [tex]\mathbf{n>-10\:\:and\:\:n<8}[/tex]

We can write it as: -10< n and n<8

Overlapping we get: [tex]\mathbf{-10<n<8}[/tex]

The graph is shown is figure attached below: