Two planes travel toward each other from cities that are about 1725 km apart at rates of 360 km/hr and 330 kr/hr. They started at the same time. In how many hours
will they meet?
hours.
The two planes will meet after
(Simplify your answer.)​

Let's raise i to various powers starting with 0,1,2,3...

i^0 = 1

i^1 = i

i^2 = ( sqrt(-1) )^2 = -1

i^3 = i^2*i = -1*i = -i

i^4 = (i^2)^2 = (-1)^2 = 1

i^5 = i^4*i = 1*i = i

i^6 = i^5*i = i*i = i^2 = -1

We see that the pattern repeats itself after 4 iterations. The four items to memorize are

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

It bounces back and forth between 1 and i, alternating in sign as well. This could be one way to memorize the pattern.

To figure out something like i^25, we simply divide the exponent 25 over 4 to get the remainder. In this case, the remainder of 25/4 is 1 since 24/4 = 6, and 25 is one higher than 24.

This means i^25 = i^1 = i

Likewise,

i^5689 = i^1 = i

because 5689/4 = 1422 remainder 1. The quotient doesn't play a role at all so you can ignore it entirely

Answer:

z-Axis. The axis in three-dimensional Cartesian coordinates which is usually oriented vertically. Cylindrical coordinates are defined such that the -axis is the axis about which the azimuth coordinate. is measured.

Step-by-step explanation:

Answer:

4320 minutes

Step-by-step explanation:

Recall,

1 day --->  24 hours

but each hour has 60 minutes, hence 1 day can also be expressed:

1 day -----> 24 x 60 = 1440 minutes

3 days -----> 1440 min/day  x 3 days = 4320 minutes

Answer: 4,320 minutes

Step-by-step explanation: 1 day = 1440 days. 1440 * 3 = 4,320 minutes

Answer:

81

Step-by-step explanation:

Let's do this systematically:

Four numbers: a, b, c, d

Whose mean is 85: [tex]\frac{a + b + c + d}{4} = 85[/tex]

Whose largest number is 97: [tex]\frac{a + b + c + 97}{4} = 85[/tex]

Lets solve for the other numbers:

a+b+c+97 = 85*4 = 340

340 - 97 = 243

a+b+c = 243

at this point it doesn't matter what the numbers are, they just need to add up to 243.

We can do 243÷3=81, which is our answer

Answer:

1) [tex]h(x) = \frac{f(x)}{g(x)}[/tex], 2) [tex]h(x) = \frac{g(x)}{f(x)}[/tex], 3) [tex]h(x) = f(x) + g(x)[/tex], 4) [tex]h (x) = f [g (x)][/tex], 5) [tex]h(x) = f(x) - g(x)[/tex]

Step-by-step explanation:

1) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h (x) = \frac{x+4}{2\cdot x + 1}[/tex], then:

[tex]h(x) = \frac{f(x)}{g(x)}[/tex]

2) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = \frac{2\cdot x + 1}{x+4}[/tex], then:

[tex]h(x) = \frac{g(x)}{f(x)}[/tex]

3) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = 3\cdot x + 5[/tex], then:

[tex]h(x) = 3\cdot x + 5[/tex]

[tex]h (x) = (1 + 2)\cdot x + (4+1)[/tex]

[tex]h(x) = x + 2\cdot x + 4 +1[/tex]

[tex]h(x) = (x+4) + (2\cdot x + 1)[/tex]

[tex]h(x) = f(x) + g(x)[/tex]

4) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = 2\cdot x + 5[/tex], then:

[tex]h(x) = 2\cdot x + 5[/tex]

[tex]h(x) = 2\cdot x + 1 + 4[/tex]

[tex]h(x) = (2\cdot x +1)+4[/tex]

[tex]h (x) = f [g (x)][/tex]

5) Let be [tex]f(x) = x + 4[/tex] and [tex]g(x) = 2\cdot x + 1[/tex], if [tex]h(x) = -x + 3[/tex], then:

[tex]h(x) = -x + 3[/tex]

[tex]h(x) = (1 - 2)\cdot x + 4 - 1[/tex]

[tex]h(x) = x - 2\cdot x + 4 - 1[/tex]

[tex]h(x) = x + 4 - (2\cdot x + 1)[/tex]

[tex]h(x) = f(x) - g(x)[/tex]

Answer:

ln e = 1

ln e 2x = 2x

ln 1 = 0

Step-by-step explanation:

ln e

ln(2.718282) = 1

In e 2x

ln(2.718282)(2)x = 2x

ln 1 = 0

Answer:

56% shaded

Step-by-step explanation:

if there are 100 boxes, then every box it 1%

5 rows (50%) + 6 extra boxes (6%) = 56%

Answer:

Step-by-step explanation:

A) u = 4      v = 4/(sqrt)3

B) b = 5      c = 10

C) b = 2(sqrt)2     a = 4

D) m and n are both 7(sqrt)2/2

The missing side lengths for the three triangles are 10√3, 12, and 8. The first triangle is a 30-60-90 triangle, the second triangle is a 45-45-90 triangle, and the third triangle is a right triangle. The missing side lengths were found using the properties of special triangles and the Pythagorean Theorem.

Here are the missing side lengths for the following triangles:

Triangle 1:

The missing side length is 15.

The triangle is a 30-60-90 triangle, so the ratio of the side lengths is 1:√3:2. The hypotenuse of the triangle is 20, so the shorter leg is 10 and the longer leg is 10√3. The missing side length is the longer leg, so it is 10√3.

Triangle 2:

The missing side length is 12.

The triangle is a 45-45-90 triangle, so the ratio of the side lengths is 1:1:√2. The hypotenuse of the triangle is 12√2, so each of the legs is 12. The missing side length is one of the legs, so it is 12.

Triangle 3:

The missing side length is 8.

We can use the Pythagorean Theorem to find the missing side length. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, the hypotenuse is 10 and one of the other sides is 6. Let x be the missing side length.

[tex]10^{2}[/tex] = [tex]6^{2}[/tex] + [tex]x^{2}[/tex]

100 = 36 +[tex]x^{2}[/tex]

[tex]x^{2}[/tex] = 64

x = 8

Therefore, the missing side length is 8.

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Answer:

3.15 dollars

Step-by-step explanation:

The sales tax rate is 7% = 0.07

So, we need to multiply the listed price and the sales tax rate.

= 45 * 0.07 = 3.150 (3.15)

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Answer:

Yes, it contradict this prior belief as there is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes.

Test statistic t=2.238>tc=1.708.

The null hypothesis is rejected.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the true average escape time is significantly higher than 6 minutes (360 seconds).

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=360\\\\H_a:\mu> 360[/tex]

The significance level is 0.05.

The sample has a size n=26.

The sample mean is M=370.69.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=24.36.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{24.36}{\sqrt{26}}=4.777[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{370.69-360}{4.777}=\dfrac{10.69}{4.777}=2.238[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=26-1=25[/tex]

The critical value for a  right-tailed test with a significance level of 0.05 and 25 degrees of freedom is tc=1.708. If the test statistic is bigger than 1.708, it falls in the rejection region and the null hypothesis is rejected.

As the test statistic t=2.238 is bigger than the critical value t=1.708, the effect is significant.  The null hypothesis is rejected.

There is enough evidence to support the claim that the true average escape time is significantly higher than 6 minutes (360 seconds).

Answer: 484m²

Step-by-step explanation: This is a question on solid shape.

The surface area of a cone is the same thing as the perimeter of the cone ie, the materials required to construct the cone.

Formula for the surface area of the cone = πrl + πr², ( the circular base )

From.the diagram,

r = 7.1m , l = 14.6m, π = 3.142

Now substitute for those values in.the formula above

SA = πrl + πr²

= 3.142 × 7.1 × 14.6 + 3.142 × 7.1²

= 325.6997 + 158.388

= 484.09

Now to the nearest tenth meter,

SA = 484m²

Answer:

about 10

Step-by-step explanation:

62.8 = 2 pi r/2

62.8/2 = pi r

31.4/pi = pi r/pi

about 10 = r

Answer:

y = [tex]\frac{1}{2}[/tex] x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] x + 7 ← is in slope- intercept form

with slope m = [tex]\frac{1}{2}[/tex]

Parallel lines have equal slopes

line M crosses the y- axis at (0, 3) ⇒ c = 3

y = [tex]\frac{1}{2}[/tex] x + 3 ← equation of line M

Answer:

50°

Step-by-step explanation:

ABCD is a kite.

Therefore, AB = BC

[tex]\therefore m\angle BCA= m\angle BAC = 40\degree \\

\because BD \perp AC.. (Diagonals \: of\: kite) \\

\therefore y + 90\degree + m\angle BCA = 180\degree \\

\therefore y + 90\degree + 40\degree = 180\degree \\

\therefore y = 180\degree - 130\degree \\

\huge\red {\boxed {y = 50\degree}} [/tex]

Answer:

7+c or 6

Step-by-step explanation:

Answer:

-89+c

Step-by-step explanation:

I'm assuming

"(7-6)(-1)

-7 +0

-7-

7-6

7+ c"

Is the whole equation.

(7-6)(-1) -7+0 -7- 7-6 7+c=

(1)(-1)-7+0-7-7-67+c=

-1-7+0-7-7-67+c=

-8+0-7-7-67+c=

-8-7-7-67+c=

-15-7-67+c=

-22-67+c=

-89+c

Answer:

Step-by-step explanation:

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 60, \sigma = 16[/tex]

P(X < 80)

This is the pvalue of Z when X = 80. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{80 - 60}{16}[/tex]

[tex]Z = 1.25[/tex]

[tex]Z = 1.25[/tex] has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

Answer:

a) Test statistic

    Z = 1.265 < 1.96 at 0.05 level of significance

The battery life is not exceeds 40 hours

b)

p- value = 0.8962

Step-by-step explanation:

Step(i):-

Given sample size 'n' =10

Mean of the sample x⁻ = 40.5 hours

Mean of  of the Population μ = 40 hours

Standard deviation of the Population = 1.25 hours

Step(ii):-

Null Hypothesis:H₀: μ = 40 hours

Alternative Hypothesis :H₁ : μ < 40 hours

step(ii):-

Test statistic

               [tex]Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }[/tex]

              [tex]Z = \frac{40.5 -40}{\frac{1.25}{\sqrt{10} } }[/tex]

             Z = 1.265

Level of significance = 0.05

Z₀.₀₅ = 1.96

Z = 1.265 < 1.96 at 0.05 level of significance

The battery life is not exceeds 40 hours

Step(iii):-

P - value        

P( Z < 1.265) = 0.5 + A( 1.265)

                     = 0.5 + 0.3962  

                    = 0.8962

P( Z < 1.265) = 0.8962

i ) p- value = 0.8962 > 0.05

Accept H₀

There is no significant

The battery life is not exceeds 40 hours

Answer:

a. In the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. The correct option is zero.

c. See the attached excel file for the new supply schedule.

d. The monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Step-by-step explanation:

Note: This question is not complete. A complete question is therefore provided in the attached Microsoft word file.

a. In the butter market, the monthly equilibrium quantity is million pounds and the equilibrium price is $ per pound.

At equilibrium, quantity demanded must be equal with the quantity supplied.

In this question, equilibrium occurs at the price of $1.20 per pound and quantity of 95 million pounds.

Therefore, in the butter market, the monthly equilibrium quantity is 95 million pounds and the equilibrium price is $1.2 per pound.

b. What is the monthly surplus created in the wholesale butter market due to the price support (price floor) program?

Price floor refers to a government price control on the lowest price that can be charged for a commodity.

It should be noted that for a price floor to be binding, it has to be fixed above the equilibrium price.

Since the price floor of $1 per pound is lower than the equilibrium price of $1.2 per pound, the price floor will therefore not be binding. As a result, the market will still be at the equilibrium point and the monthly surplus created in the wholesale butter market due to the price support (price floor) program will be zero.

Therefore, the correct option is zero.

c. Fill in the new supply schedule given the change in the cost of feeding cows.

Since a decrease in the cost of feeding cows shifts the supply schedule to the right by 40 million pounds at every price, this implies that there will be an increase in supply by 40 million at each price.

Note: Find attached the excel file for the new supply schedule.

d. Given the new supply of butter, what is the monthly surplus of butter created by the price support program?

Since the price floor has been fixed at $1 per pound by the price support program, we can observe that the quantity demanded is 101 million pounds and quantity supplied is 119 million pounds at this price floor of $1. The surplus created is then the difference between the quantity demanded and quantity supplied as follows:

Surplus created = Quantity supplied - Quantity demanded = 119 - 101 = 18 million pounds

Therefore, the monthly surplus created by the price support program is 18 million pounds given the new supply of butter.

Answer:

(4b)•(0.5a) = (4•0.5)(a)(b) = 2ab

Step-by-step explanation:

Answer:

b median

Step-by-step explanation:

Answer:

  orthocenter

Step-by-step explanation:

The red segment is an altitude of the triangle, as are the two legs. The intersection point of the altitudes is the orthocenter.

__

This is basically a vocabulary question.

Answer:

1. Test statistic t=1.581.

2. The null hypothesis H0 failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

NOTE: if the null hypothesis is µ = 40, there is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40 (test statistic t=3.161).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 41.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=41\\\\H_a:\mu> 41[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-41}{0.633}=\dfrac{1}{0.633}=1.581[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=1.581, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>1.581)=0.061[/tex]

As the P-value (0.061) is bigger than the significance level (0.025), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 41.

For µ = 40:

This is a hypothesis test for the population mean.

The claim is that the mean number of calls per salesperson per week is significantly more than 40.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=40\\\\H_a:\mu> 40[/tex]

The significance level is 0.025.

The sample has a size n=38.

The sample mean is M=42.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=3.9.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{3.9}{\sqrt{38}}=0.633[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{42-40}{0.633}=\dfrac{2}{0.633}=3.161[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=38-1=37[/tex]

This test is a right-tailed test, with 37 degrees of freedom and t=3.161, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=P(t>3.161)=0.002[/tex]

As the P-value (0.002) is smaller than the significance level (0.025), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean number of calls per salesperson per week is significantly more than 40.  

Area of one side of a U.S. dime is approximately 254  square millimeters.

A circle is a shape consisting of all points in a plane that are at a given distance from a given point, the centre.

Given that  U.S. dime has a diameter of about 18 millimeters.

We need to find the area of one side of a dime to the nearest square millimeter.

Diameter=18 millimeters

Diameter is two times of radius

D=2R

18=2R

Divide both sides by 2

Radius is 9 millimeters.

Area of dime=πr²

=3.14×(9)²

=3.14×81

=254 square millimeters.

Hence, area of one side of a U.S. dime is approximately 254  square millimeters.

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Answer: k = 4, k = -4 and k = 0.

Step-by-step explanation:

If we have y = sin(kt)

then:

y' = k*cos(kt)

y'' = -k^2*son(x).

then, if we have the relation:

y'' - y = 0

we can replace it by the things we derivated previously and get:

-k^2*sin(kt) + 16*sin(kt) = 0

we can divide by sin in both sides (for t ≠0 and k ≠0 because we can not divide by zero)

-k^2 + 16 = 0

the solutions are k = 4 and k = -4.

Now, we have another solution, but it is a trivial one that actually does not give any information, but for the diff equation:

-k^2*sin(kt) + 16*sin(kt) = 0

if we take k = 0, we have:

-0 + 0 = 0.

So the solutions are k = 4, k = -4 and k = 0.

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

   1     2        3 4   5     6

1 (1, 1)   (1, 2)   (1, 3)   (1, 4)  (1, 5)   (1, 6)

2 (2, 1)   (2, 2)  (2, 3)  (2, 4) (2, 5)  (2, 6)

3 (3, 1)   (3, 2)  (3, 3)  (3, 4)  (3, 5)  (3, 6)

4 (4, 1)   (4, 2)  (4, 3)  (4, 4)  (4, 5)  (4, 6)

5 (5, 1)   (5, 2)  (5, 3)  (5, 4)  (5, 5)  (5, 6)

6 (6, 1)   (6, 2)  (6, 3)  (6, 4)  (6, 5)  (6, 6)

Answer:

Correct option: C.

Step-by-step explanation:

(Assuming the correct function is R(x) = 2x^2 + 3x + 5)

To find the input value that gives the value of R(x) = 19, we just need to use this output value (R(x) = 19) in the equation and then find the value of x:

[tex]R(x) = 2x^2 + 3x + 5[/tex]

[tex]19 = 2x^2 + 3x + 5[/tex]

[tex]2x^2 + 3x -14 = 0[/tex]

Solving this quadratic function using the Bhaskara's formula (a = 2, b = 3 and c = -14), we have:

[tex]\Delta = b^2 - 4ac = 9 + 112 = 121[/tex]

[tex]x_1 = (-b + \sqrt{\Delta})/2a = (-3 + 11)/4 = 2[/tex]

[tex]x_2 = (-b - \sqrt{\Delta})/2a = (-3 - 11)/4 = -3.5[/tex]

So looking at the options, the input to the function is x = 2

Correct option: C.

Answer:

the answer is A

Step-by-step explanation:

Answer:

a = ±4√5

Step-by-step explanation:

Solve for c.

3√c = 9

√c = 9/3

√c = 3

c = 3²

c = 9

Put b=2√2 and c=9, solve for a.

a² + (2√2)² + 9² = 169

a² + 8 + 81 = 169

a² = 169 - 81 - 8

a² = 80

a = ±√80

a = ±4√5

Answer:

-4x -11

Step-by-step explanation:

-(x + 5) - 3(x + 2)

Distribute

-x -5  -3x -6

Combine like terms

-x-3x   -5-6

-4x -11

Answer:

[tex] = - (4x + 11)[/tex]

Step-by-step explanation:

[tex]-(x + 5) - 3(x + 2) \\ -x - 5 - 3x - 6 \\ -x - 3x -5 - 6 \\ - 4x - 11 \\ = -(4x + 11)[/tex]