Answer:
F₁ = 499.61 N , this is the force that Bubba support
Explanation:
The trunk is in equilibrium with the two forces applied by man, let's use the equilibrium relation
let's set a reference frame at the extreme left and assume that the counterclockwise rotations are positive
Let's write the expression for the translational equilibrium
subscript 1 is for Bubba's mass and subscript 2 for his partner
F₁ + F₂ -W = 0
F₁ + F₂ = W
the expression for rotational equilibrium
∑ τ = 0
F₁ 2.2 + F₂ (6.2-0.9) - W 6.2/2 = 0
2.2 F1 + 5.3 F2 = 3.1 W
let's write our system of equations
F₁ + F₂ = W
2.2 F₁ + 5.3 F₂ = 3.1 W
we solve for F₁ in the first equation and substitute in the second
F₁ = W-F₂
2.2 (W- F₂) + 5.3 F₂ = 3.1 W
F₂ ( -2.2 +5.3) = W (3.1 - 2.2)
F₂ = 704 0.9 / 3.1
F₂ = 204.39 N
This is the force that the partner supports
we look for F1
F₁ = W-F₂
F₁ = 704 - 204.39
F₁ = 499.61 N
This is the force that Bubba support
You throw a ball straight up. Compare the sign of the work done by gravity while the ball goes up with the sign of the work done by gravity while it goes down.
a. Work is + on the way up and + on the way down
b. Work is + on the way up and - on the way down
c. Work is - on the way up and + on the way down
d. Work is - on the way up and - on the way down
Answer:
c. Work is - on the way up and + on the way down
Explanation:
Work done is given as the product of the applied force and the displacement of the object.
Work done = F x d
Work done = mg x d
where;
g is acceleration due to gravity = 9.8 m/s²
When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.
Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.
The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a period of 28 seconds about its axis. Astronauts walk on the inside surface of the space station, and they experience an Earth-like gravitational acceleration of 9.8 m/s2. What is the diameter of the space station?
510m
145m
660m
390m
Answer:
P = 2 pi R / v period of space station
F / m = v^2 / R centripetal force per unit of mass
So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2
Also, F / m = 9.8 m/s^2 earth's gravitational attraction
So 9.8 = 4 pi^2 R / P^2 or R = 9.8 P^2 / 4 * pi^2) = 195 m
Or D = 2 R = 390 m the diameter required
write the formula of mechanical advantage
Answer:
the formula of mechanical advantage is
MA = load / effort
VR = effort distance / load distance
hope it is helpful to you
An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in the figure below. O is the origin. Suppose you take measurements and find that AB is 31 cm , BC is 12 cm , and AO is 7 cm .(Figure 1)
A. What is the ant’s position at point A?
B. What is the ant’s position at point B?
C. What is the ant’s position at point C?
D. What is the ant’s position at point D?
Answer:
Ants position at point A = -7 cm
Ants position at point B = 38 cm
Ants position at point C = 26 cm
Ants position at point D = -7 cm
Explanation:
In this question, we are dealing with displacement which is the change in position of an object.
Now, we are told the journey began from A to B and then from C to D.
Now, AB = 31 cm and AO = 7cm
But along AB, we have the origin O.
Since A is on the left hand side of the origin, it means it is negative. Thus, position A = -7cm
Then position B = 31 - (-7) = 31 + 7 = 38 cm
Since BC = 12cm, then position C = 38 - 12 = 26 cm
Position D is same as position A = -7cm
A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?
Answer:
A) E / B = 2.99 10⁸ V/ mT, B) B = 2.50 10⁻⁶ T
Explanation:
A) the expressions for the energy densities are:
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
indicate that the two densities are equal
½ ε₀ E² = ½ B² /μ₀
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o }[/tex]
we calculate
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹9
E / B = 2.99 10⁸ V/ mT
B) for this case E = 750 V / m, ask the magnetic field
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
B = E [tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
we calculate
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
Energy densities can be expressed as
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
When the two densities are equal we use the formula
½ ε₀ E² = ½ B² /μ₀
E / B = 1 / μ₀
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹
E / B = 2.99 10⁸ V/ mT
If the magnetic field and electric-field energy densities are equal and E = 750 V / m, we can deduce thatE / B = 1 / √ ξ₀ μ₀
B = E √ ξ₀ μ₀
We substitute the values into the equation
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
Read more on https://brainly.com/question/23360987
Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.
Answer:
v = 4.233 m/s
Explanation:
By applying the rate of boiling from [tex]Q= mL_v[/tex];
the rate of the boiling can be described as:
[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]
The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:
[tex]P_oV_o = nRT[/tex] --- (1)
where;
n = number of moles;
[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]
Then; equation (1) can be rewritten as:
[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]
∴
[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]
Then:
[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]
making (v) the subject of the formula:
[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]
Given that:
[tex]\mathcal{P}[/tex] = 0.90 kW = 900 W
R(rate constant) = 8.314 J/mol.K
Temperature at 100° C = 373K
For water vapor:molar mass= 18.015 g/mol ≅ 0.0180 kg/mol
Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg
Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]
Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²
[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]
v = 4.233 m/s
Convert 0.00553s to cs
Answer: 0.553
Explanation:
Convert 0.0334 to scientific notation
Answer:
[tex]3.34 * 10^{-2}[/tex]
Explanation:
Scientific notation is writing a number between 1 and 10, and multiplying the number by a power of 10.
Our number is 0.0334
Let's move the decimal point of the number to make it so that the number is at least 1 and less than 10.
We get: 3.34
We moved the decimal point 2 places to the right, so the power of 10 would be -2
Putting what we got together, the scientific notation for the number is:
[tex]3.34 * 10^{-2}[/tex]
Does the law of attraction actually have a basis in physics?
Answer:
Scientific theories are cited by proponents of the Law of Attraction as evidence in its favor. It, on the other hand, has no theoretical basis. A variety of scientists have questioned the promoters' abuse of scientific principles.
A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep encounters an unbanked curve of radius 50 m. The Jeep follows the road from B to C traveling at a constant speed of 10 m/s while the direction of the Jeep changes from east to south. What is the magnitude of the acceleration of the Jeep as it travels from A to B
Answer:
a = 0 m/s²
Explanation:
From A to B the jeep travels in a straight line with a constant speed of 10 m/s. Acceleration is defined as the rate of change in velocity. In the current scenario, the velocity of the jeep remains constant. The direction of the jeep does not change as it travels in the straight path. Also, the magnitude of the velocity is constant at 10 m/s.
Therefore, there is no change in the velocity of the jeep from A to B. Hence, the will be no acceleration from A to B.
a = 0 m/s²
If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
a-60kgm/s
b-120kgm/s
c-90kgm/s
D-30kgm/s
Typical novae occur when (a) a red-giant star ejects a planetary nebula; (b) two neutron stars merge, forming a more massive neutron star; (c) an extremely massive star collapses, and also ejects its outer atmosphere; (d) matter accreted from a companion star unstably ignites on the surface of a white dwarf; or (e) a neutron star’s magnetic field becomes strong enough to produce two oppositely directed jets of rapidly moving particles.
Answer:
I think its d matter accreted from a companion star unstable ignites on the surface of a white dwarf.
A metal spherical shell with inner radius 14 cm and outer radius 24 cm has a net charge of 1= -3 nC. At the center of the shell is a small particle with charge Q2= -7 nC. What is the charge density in (C/m2) on the outer surface of the spherical shell?
Answer:
I don't no the answer sorry
The instrument measuring the temperature change between inspired cool air and expired warm air is called?
Answer:
It's called a Spirometer
Convert 13.7g to mg
URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.
Answer:
A
Explanation:
because the speed divide by the frequency is equal to the wavelength(in meters)
5×10² m
Please help with all three questions
Answer:
The correct answer is D C A
A person is 88 J of work lifting a grocery bag straight off the ground to a height of 1.7 m what is a grocery bags mass
Answer:
5.277 kg
Explanation:
Since the formula for work is W = F * d and we are given distance and work, the force on the grocery bag is 88 = F * 1.7 F = 88 / 1.7 = 51.765 N.
We also know that force follows the equation F = m * a. Since the constant gravitational acceleration on earth is 9.81 m / s^2, we can find the mass through 51.765 = m * 9.81 m = 51.765/9.81 = 5.277 kg
In the diagram shown below, the distance from the dotted line to Point A, or the distance from the dotted line to Point D is known as the
Answer:
The dotted line connecting two points is known as the distance traveled.
Explanation:
The distance traveled is a physical quantity that refers to the total displacement of a body. This distance is usually shown as a dotted line that connects two points in an image. In general, we can say that the distance traveled is calculated by adding all the distances that an element makes when leaving one point and reaching another point, which is its final position.
An example of this can be seen in the image shown below, where the red line represents the displacement of a body that left point A and arrived at point B. The blue dotted line represents the distance traveled and refers to the total displacement of that body, showing all the distances it covered while walking from point A to point B.
Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?
Answer:
The difference between the positions of the two events as measured in = 3.53 *10^8 m/s
Explanation:
As we know -
[tex]\Delta x = -\gamma \mu\Delta t[/tex]
Here,
[tex]\Delta x[/tex] is the difference between the positions of the two events as measured in S^
[tex]\gamma[/tex] [tex]= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }[/tex]
And
[tex]\mu[/tex] = 0.547 c
Substituting the given values in above equation, we get -
[tex]\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8[/tex]meter per second
What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.
Answer:
10 GHz
Explanation:
Applying,
v = λf.................... Equation 1
Where v = speed of microwave, λ = wavelength, f = frequency.
make f the subject of the equation
f = v/λ................ Equation 2
Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s
From the question,
Given: λ = 3 cm = 0.03 m
Constant; v = 3×10⁸ m/s
Substitute these values into equation 2
f = 3×10⁸/(0.03)
f = 10¹⁰ Hz
f = (10¹⁰/10⁹) GHz
f = 10 GHz
A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]
Answer:
Explanation:
Force on a current carrying wire in a magnetic field
= B i L where B is magnetic field , i is current and L is length of the wire .
Putting in the given values in the question
force on a current carrying wire in a magnetic field = .001 T x i x .5 m
5 x 10⁻⁴ i N .
weight of the wire = .050 kg x 9.8 m/s²
= .49 N .
For equilibrium
5 x 10⁻⁴ i = .49
i = 980 A .
Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.
Answer:
8 meters/second
Explanation:
Rate x Time = Distance
R x T = D
R x 50sec = 400meters
R x 50sec/50sec = 400meters/50sec
R = 8meters/sec
Explain the mode of operation of x-ray
Answer:
If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.
Answer:
Explanation:
Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.
PLS HELPP MEEE
Fiber-optic cables rely on total internal reflection.
Please select the best answer from the choices provided
T
F
A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane
Answer:
[tex]w^2=5.5rads/s[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=2.0kg[/tex]
Radius [tex]r=1.8m[/tex]
Height [tex]h=7.5m[/tex]
Generally the equation for Potential energy is mathematically given by
Potential energy=Kinetic energy+Rotational energy
[tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]
Since there is no slipping
[tex]v=rw[/tex]
Therefore
[tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]
Where
[tex]I=\frac{1}{2}mr^2[/tex]
[tex]l=3.24m[/tex]
[tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]
[tex]147.15=3.24w^2+1.62w^2[/tex]
[tex]w^2=\frac{147.15}{4.86}[/tex]
[tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]
[tex]w^2=5.5rads/s[/tex]
Any is 160 cm tall and stands 50 cm in front of a plane mirror. The image of Amy is ?
Answer:
Option A. 160 cm tall and 100 cm in front of Amy
Explanation:
To know the the correct answer to the question, we must recognise that the image formed by plane mirror is:
I. Same size as the object.
II. Same distance as the object from the mirror.
III. Laterally inverted.
IV. Virtual
With the above information, we obtained the answer to the question as follow:
Object height = 160 m
Thus,
Image height = 160 m
Distance of object from mirror = 50 cm
Therefore,
Distance of image from the mirror = 50 cm
Distance between the object and image = 50 + 50 = 100 cm
Thus, option A gives the correct answer to the question because the image of Amy is 160 cm tall and 100 cm in front of her.
which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer in your own words.
NO LINKS.
Answer:
b (i think)
Explanation:
what determines the strength of a base?
The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.