Two cylindrical resistors are made from the same material. The shorter one has a length LL and diameter DD . The longer one has a length 16L16L and diameter 4D4D . How do their resistances compare? The resistance of the longer resistor is four times the resistance of the shorter resistor. The resistance of the longer resistor is twice the resistance of the shorter resistor. The resistance of the longer resistor is the same as the resistance of the shorter resistor. The resistance of the longer resistor is half the resistance of the shorter resistor. The resistance of the longer resistor is a quarter of the resistance of the shorter resistor.

Answers

Answer 1

Answer:

The resistance of the longer resistor is a quarter of the resistance of the shorter resistor.

Explanation:

If Two cylindrical resistors are made from the same material, then their resistivity will be the same.  Formula for calculating resistivity of a material is expressed as;

[tex]\rho = \frac{RA}{L} \ where \ A = \frac{\pi d^2}{4}[/tex] where;

R is the resistance

A is the cross sectional area of the material

L is the length of the material

For the shorter cylinder:

Length = L

diameter = D

[tex]\rho = \dfrac{R_s(\frac{\pi D^2}{4})}{L} \\\\\rho = \dfrac{R_s{\pi D^2}}{4L}[/tex]

For the longer cylinder:

Length = 16L

diameter = 4D

[tex]\rho = \dfrac{R_l(\frac{\pi (4D)^2}{4})}{16L} \\\\\\\rho = \dfrac{R_l(\frac{\pi (16D^2)}{4})}{16L} \\\\\rho = \dfrac{R_l{16\pi D^2}}{16L}\\\\\rho = \dfrac{R_l{\pi D^2}}{L}[/tex]

Since their resistivity are the same then;

[tex]\dfrac{R_s{\pi D^2}}{4L} = \dfrac{R_l{\pi D^2}}{L} \\\\ \dfrac{R_s}{4} = {R_l} \\\\R_s = 4R_l\\\\R_l = \frac{R_s}{4}[/tex]

Hence the resistance of the longer resistor is a quarter of the shorter resistor.


Related Questions

If horizontal velocity is 5 m/s, and vertical velocity is 8 m/s, what is the magnitude of the resultant velocity?

Answers

Answer:

40 m/s

Explanation:

a torch battery produces electricity from – energy​

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Answer:

First, the batteries contain chemical energy, which is energy that is released during a chemical change. When chemical bonds are formed or broken, electrons are rearranged, and this movement of electrons produces chemical energy. Batteries can convert stored chemical energy into electrical energy.

chemical energy

which is an example of a vector quantity
A.time
B.speed
C. acceleration
D. distance

Answers

Answer:

The answer to your question is C

Explanation:

acceleration is a vector quantity because it has both magnitude and direction

what is alpha decay?

Answers

Answer:Alpha decay, type of radioactive disintegration in which some unstable atomic nuclei dissipate excess energy by spontaneously ejecting an alpha particle.

Explanation:

Newtons Second Law of motion states that for acceleration to stay the same...​

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Answer:

newton force is the state of gravity force they abstract when they came closer

A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.
What is the time interval of marble?

Answers

Answer:

t = 6.09 seconds

Explanation:

Given that,

Speed, v = 44.1 cm/s

Distance, d = 269 cm

We need to find the time interval of the marble. Speed is distance per unit time.

[tex]v=\dfrac{d}{t}\\\\\implies t=\dfrac{d}{v}\\\\t=\dfrac{269\ \text{cm}}{44.1\ \text{cm/s}}\\\\t=6.09\ s[/tex]

Hence, the time interval of the marble is 6.09 seconds.

How many elements in oxygen gas? PLEASE ANSWER!

Answers

Answer:

8

Explanation:

Answer:

Chemical Properties of Oxygen

At standard temperature and pressure (STP), two atoms of the element bind to form dioxygen, a colorless, odorless, tasteless diatomic gas with the formula O2. Oxygen is a member of the chalcogen group on the periodic table and is a highly reactive nonmetallic element.

Explanation:

does potential thermal energy affect the temperature of an object?

Answers

Answer:

Yes, it does

Explanation:

There are not many explanations, but when thermal energy is shined on an object it usually starts to heat up.

A marble rolls 269cm across the floor with a constant speed of in 44.1cm/s.

Answers

Answer:

what's the question ,so I can answer it right ?

A statement about what happens in nature that seems to be true all the time ES​

Answers

Answer:

their is always a animal or bug in nature

Explanation:

What do the elements in group 17 of the periodic table have in common

Answers

They are toxic and all non metals

Explain How can you
use a distance-time graph
to calculate average
speed?

Answers

Explanation:

Average speed = change in distance / change in time

In other words, the average speed is the slope of the line connecting two points on the graph.

if AN OBJECT HAS ZERO NET FORCE ON IT THEN THE OBJECT MUST BE AT REST true or false

Answers

Answer:

False

Explanation:

constant velocity is also 0 net force

Answer:

FALSE

Explanation:

The object can be at rest or also could be in uniform motion (moving with constant velocity)

A squirrel is running a race where she is on track for her average velocity to be 6.0 m/s. She is distracted by a dummy of an attractive male squirrel and pauses for 3.0 s. As a result her average velocity ends up being 5.0 m/s instead. What is the length of the race? [HINT: construct two equations with the same two unknowns in them and you can solve the system of equations]

Answers

Answer:

90 m

Explanation:

There are two unknowns: the amount of time the squirrel spent running, and the length of the race.  Let's call these t and x, respectively.

The average velocity is the total distance divided by the total time.

5.0 m/s = x / (t + 3.0)

The total distance is the time she spent running times the speed she ran at.

x = (6.0 m/s) t

Substitute and solve:

5 = 6t / (t + 3)

5 (t + 3) = 6t

5t + 15 = 6t

t = 15

She ran for 15 seconds (not including the 3 seconds she stopped).  So the length of the race is:

x = (6.0 m/s) (15 s)

x = 90 m

a barge is pulled down the canal by a horse walking beside it, if the rope angle is 60.0 degrees, the force exterted is 400N and the barge being pulled is 100N how much work did the horse do

Answers

Answer:

The horse does 20,000 Nm of work.

Explanation:

Using = ∶ (400 ∗ 60°)(100) → The horse does 20,000 Nm of work.

The horse does 20,000 Nm of work.

What is work?

Work is the energy transferred to or from an object via the application of force along a displacement.

In its simplest form, it is often represented as the product of force and displacement.

The work W is equal to the force f times the distance d, or W = fd.

If the force is being exerted at an angle θ to the displacement, the work done is W = f d cos θ.

From the given values,

W = f d cos θ.

W = 400*100 cos60°

W= 20,000 Nm

The horse does 20,000 Nm of work.

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When a wave goes through a substance, _______________ has occurred.
When a wave gets trapped or stuck in a substance, ______________ has occurred.
When a wave bounces off of a surface, ______________ has occurred.

The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.

Answers

Answer:

A) When a wave goes through a substance, _______________ has occurred.

This is refraction or transmission.

Refraction refers to the changes in the wave that occur when it enters a new medium, in this case, the substance.

Transmission refers to the transfer of energy that is now in the medium.

Usually, we have both of those together.

B) When a wave gets trapped or stuck in a substance, ______________ has occurred.

This is total internal reflection. This happens when, by the Snel Law, the angle of the transmited wave is 90° (or larger) which is traduced in no transmitted wave, this is why the wave is "trapped" in the substance.

C) When a wave bounces off of a surface, ______________ has occurred.

This is reflection.

D) The ____________________ states that the angle of an incoming wave is equal to the angle of the reflected wave.

This is the Law of Reflection, that says "when light is reflected from a surface, the angle of reflection is the same as the angle of incidence"

A trumpet player on a moving railroad flatcar moves toward a second trumpet player standing alongside the track both play a 490 Hz note. The sound waves heard by a stationary observer between the two players have a beat frequency of 2.0 beats/s. What is the flatcar's speed? Take the speed of sound to be 343 m/s.

Answers

Answer:

The value is [tex]v_s = 1.394 \ m/s[/tex]

Explanation:

From the question we are told that

The frequency of the second player is [tex]f_2 = 490 \ Hz[/tex]

The beat frequency is [tex]f_b = 2.0 \ Hz[/tex]

The speed of sound is [tex]v_s = 343 \ m/s [/tex]

Generally the frequency of the note played by the first player is mathematically represented as

[tex]f_1 = f_2 + f_b[/tex]

=> [tex]f_1 = 490 + 2.0 [/tex]

=> [tex]f_1 = 492 Hz[/tex]

From the relation of Doppler Shift we have that

[tex]f_1 = \frac{ f_2 (v+ v_o )}{v-v_s }[/tex]

Here [tex] v_o\ is\ the\ velocity\ of\ the\ observer\ with\ value\ 0 \ m/s [/tex]

So

[tex]492 = \frac{ 490 (343+0 )}{343 -v_s }[/tex]

=> [tex]v_s = 1.394 \ m/s[/tex]

sort the properties of metalloids into the correct categories

Answers

Boron

Sillicon

Germanium

Arsenic

Antimony

Tellurium

Pelorium

Metallic characteristics: lustrous, solid at room temperature

In-between characteristics: semiconducting, amphoteric

Nonmetallic: brittle

Two forces P and Q act on an object of mass 7.00 kg with Q being the larger of the two forces. When both forces are directed to the left, the magnitude of the acceleration of the object is 1.30 m/s2. However, when the force P is directed to the left and the force Q is directed to the right, the object has an acceleration of 0.600 m/s2 to the right. Find the magnitudes of the two forces P and Q in newtons.

Answers

Answer:

P = 2.45 N

Q = 6.65 N

Explanation:

According to Newton's 2nd Law:

Unbalanced Force = ma

where,

m = mass = 7 kg

a = acceleration

In the first case when both forces P and Q act on left side:

Unbalanced Force = P + Q

a = 1.3 m/s²

Therefore,

P + Q = (7 kg)(1.3 m/s²)

P + Q = 9.1 N   ------------------------- equation 1

Now, in second case when both forces have different directions:

Unbalanced Force = Greater Force - Smaller Force

Unbalanced Force = Q - P

a = 0.6 m/s²

Therefore,

Q - P = (7 kg)(0.6 m/s²)

Q - P = 4.2 N   ------------------- equation 2

Adding equation 1 and equation 2, we get:

(Q + P) + (Q - P) = 9.1 N + 4.2 N

2 Q = 13.3 N

Q = 6.65 N

Using this value in equation 2, we get:

6.65 N - P = 4.2 N

P = 2.45 N

Personal behavior is the only factor that determines if a person becomes ill.
Please select the best answer from the choices provided.
ОТ
OF

Answers

Answer:

FALSE

Explanation:

Which law applies to the picture?
Newtons 1st Law of Motion
Newtons 2nd Law of Motion
Newtons 3rd Law of Motion​

Answers

Answer:

Newton's first law

Explanation:

Newton's first law of motion says, that an object will stay in its current motion, unless if a force acts upon it.

So an object already at rest, will stay at rest. And the ball rolling will keep rolling, if no other force such as friction slows it down.

express forty meters with four significant figures

Answers

40.00 meters

add a decimal place so that trailing zeroes are counted as significant figures.

When a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 N .m2 /C. When the paper is turned 25° with respect to the field the flux through it is:_____.1. 02. 12 N .m2 /C3. 21 N .m2 /C4. 23 N .m2 /C5. 25 N .m2 /CB. A charged point particle is placed at the center of a spherical Gaussian surface. The electric flux is changed if:______.1. the sphere is replaced by a cube of the same volume2. the sphere is replaced by a cube of one-tenth the volume3. the point charge is moved off center (but still inside the original sphere)4. the point charge is moved to just outside the sphere5. a second point charge is placed just outside the sphereC. A charge of 0.8 × 10−9 C is placed at the center of a cube that measures 5 m along each edge. What is the electric flux through any 2 faces of the cube?

Answers

Answer:

1) 23 N.m²/C

2) The point charge is moved just outside the sphere

3) 30 N.m²/C

Explanation:

1) The flux through the field can be gotten by finding the dot product of the angle the later is turned, and the given uniform electric field.

25 * cos 25 =

25 * 0.9063 =

22.66 or approximately, 23 N.m²/C

2) The point charge is moved just outside the sphere

3) Using Gauss' Law, the electric flux through one face of the cube is given as Φ = Q / 6ε₀, thus,

Φ = 0.8*10^-9 / 6 * 8.85*10^-12

Φ = 0.8*10^-9 / 5.311*10^-11

Φ = 15 N.m²/C

And therefore, the flux through any 2 faces of the cube is 2 * 15 = 30 N.m²/C

Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temperature), and measured terminal speed of 2.64X10^-5 m/s and weight-neutralizing voltage of 35.0 V. How many electrons have been attached to, or detached from the initially neutral plastic sphere

Answers

Following are the calculation to the given question:

Given:

Please find the given question.

To find:

value=?

Solution:

With terminal voltage, no force equals zero.

So,

[tex]\to mg = 6\times \pi \times \eta \times r\times \vartheta \\\\[/tex]

As [tex]35\ V[/tex] is weight neutralizing voltage

[tex]\to mg= q\times v \times r\\\\[/tex]

So,

[tex]\to q\times v \times r= 6 \times \pi \times \eta \times r \times \vartheta \\\\\to q\times v = 6 \times \pi \times \eta \times \vartheta \\\\\to q =\frac{6 \times \pi \times \eta \times \vartheta}{v} \\\\[/tex]

      [tex]=\frac{6 \times 3.14 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 18.84 \times \eta \times 2.64 \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\=\frac{ 49.7376 \times \eta \times 10^{-5}\ \frac{m}{s}}{35} \\\\ =3.2 \times 10^{-10}\ coulombs[/tex]

Therefore

[tex]\to q= n \times e\\\\[/tex]

Hence n comes to be [tex]2\times 10^9\[/tex] electrons.

Learn more:

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A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a with negative charge −e distributed uniformly around the ring (representing the electron in orbit around the proton). Find the magnitude of the total electric field due to this charge distribution at a point a distance a from the proton and perpendicular to the plane of the ring.

Answers

Answer:

Now e is due to the ring at a

So

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

So

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

The bonds between molecules store ____ Energy?

Answers

Answer:

chemical energy

Explanation:

Answer:

chemical energy

Explanation:

Energy is also stored in the covalent bonds holding atoms together in molecules. ... the difference in the amount of free energy given off as the original, reacting molecules fly apart, and the amount of free energy absorbed as the new covalent bonds form is left in the environment, often as light and/or heat.

A 3.7-mm-diameter wire carries a 20 A current when the electric field is 8.2×10−2 V/m .
What is the wire's resistivity? (in Ωm)

Answers

Answer:

   ρ = 4.4 10⁻⁸ Ω m

Explanation:

For this exercise let's start by finding the value of the resistance using Ohm's law

          V = I R

           R = V / I

   

The voltage is related to the electric field

          V = E L

           

let's substitute

          R = E L / I

          R = 8.2 10⁻² / 20  

          R = 4.1 10⁻³ L

now we can use the resistance relation

          R = ρ L / A

the area of ​​a circular wire is

          A = π r² = π d² / 4

         ρ = R π d² / (4 L)

let's calculate

        ρ = (4.1 10⁻³ L) π 0.0037² / (4 L) = (4.1 10⁻³) π 0.0037² / (4)

        ρ = 4.4 10⁻⁸ Ω m

The resistivity of the wire is 4.4 10⁻⁸ Ω m.

We know that;

V = I R

R = V / I

The voltage  the electric field can be connected using the formula;

V = E L

Hence;

R = E L /I

R = 8.2 10⁻² / 20  

R = 4.1 10⁻³ L

For resistivity;

R = ρ L / A

the area can be obtained from;

A = π r² = π d² / 4

ρ = R π d² / (4 L)

ρ = (4.1 10⁻³ L) π 0.0037² / (4 L) = (4.1 10⁻³) π 0.0037² / (4)

ρ = 4.4 10⁻⁸ Ω m

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The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?

Answers

I think c but I’m not sure so don’t use mine

Which phenomenon related to light allows scientists to measure the distance between a star and Earth? A. Dark patches appear in the electromagnetic spectrum emitted by stars. B. Light waves spread out as they move farther from their source. C. Stars have different colors based on their temperature. D. Stars have unique elements that make up their atmospheres.

Answers

Answer:

The Answer Is B not C

Explanation:

Answer:b

Explanation:

(1.736+9.6435)÷3.22=

Answers

The answer is 3.53400621

Reduce the expression, if possible, by cancelling common factors.

Answer: 3.53400621

Explanation: Hope this helped! :)

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