Two cars approach each other from opposite directions each
with a velocity of 54 km/h. One of the cars emits a note of frequency 480 Hz. What will be the approximate frequency
heard in the other car before they cross each other?

Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

[tex]f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1[/tex]

Here, [tex]V_s[/tex] is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

[tex]\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s[/tex]

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

[tex]f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz[/tex]

The approximate frequency heard in the other car before they cross each other is 524 Hz.

Learn more about the frequency here;

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