b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
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How do you solving kinematic equations for horizontal projectiles?
Calculate Vector component in Y if the hypotenuse is 32 and angle is 45
Answer:
The correct option is;
c. 22.6
Explanation:
The given parameters are;
The hypotenuse of the vector = 32
The angle of the vector = 45°
Therefore, the vector component in the y-axis is given as follows;
[tex]v_y = v \times sin(\theta)[/tex]
Substituting the values from the question gives;
[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]
The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.
A complex arrangement of pulleys forms what is called the block in a block and tackle. The rope used to lift the pulleys and the load is the tackle. A block and tackle is used to lift a truck engine, which has a weight and output force of nearly 8000 N. The input force required to lift this weight using the block and tackle is 400N. What is the mechanical advantage of the block and tackle?
Answer:
Mechanical advantage = 20
Explanation:
Given:
Output force = 8,000 N
Input force = 400 N
Find:
Mechanical advantage
Computation:
Mechanical advantage = Output force / Input force
Mechanical advantage = 8,000 / 400
Mechanical advantage = 20
A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
coaster? (Formula: PE = mgh)
O 800 kg
O 7,840 kg
O 8,000 kg
O 78,400 kg
Answer:
800 kg
Explanation:
I just did it :)
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Answer:
d
Explanation:
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:
Question:
A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:
A. sinks slightly
B. rises slightly
C. floats at the same height
D. bobs up and down about its old position
Answer:
The correct answer is C) floats at the same height
Explanation:
The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.
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You place a drop of blue food coloring in a cup of cold water and another drop of food coloring in a cup of hot water. Which observation is correct and why? A The food coloring in the hot water will spread more slowly than in the cold water because water molecules move more slowly when hot. B The food coloring in the hot water will spread more quickly than in the cold water because water molecules move more quickly when hot. C The food coloring in the cold water will spread more quickly than in the hot water because water molecules move more quickly when cold. D The food coloring in the cold water will spread at the same rate at the food coloring in the hot water because water molecules at any temperature move at the same rate.
Answer:
B food coloring will move quicker in hot water because the molecules move faster when they are hot
Explanation:
SCIENCE! aaaaand my physics text book
Option B is correct: The food coloring in the hot water will spread more quickly than in the cold water because water molecules move more quickly when hot since they have more kinetic energy.
Kinetic energy of the molecules:According to the question, we place a drop of blue food coloring in a cup of cold water and another drop of food coloring in a cup of hot water and then observe the spreading of the blue color in both the cups.
Option B will be correct because the kinetic energy of the molecules of a gas or a liquid is directly proportional to the absolute temperature of the gas or the liquid.
High kinetic energy means that the molecules will have higher velocity, which will make it easier for any solvent to dissolve in water since it will spread faster.
So the cup which has water at a higher temperature will have a faster spread of the food coloring.
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What are the Laws of conservation of atoms?
Answer:
Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.
Explanation:
Answer:
The law of conservation of atoms is simple but it has a great affect. An atom cannot be destroyed by such a force. Matter/atoms can't be created by any means. An atom exits only by nature and not by force.
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Melissa my pet cow from childhood that i could ride like a horse had a weight of 0.65 tons. Philip my pet rabbit had a weight of 192 ounces. How many philips would it take to weigh as much as one melissa
Answer:
11 times the weight of Philip.
Explanation:
From the question given above, the following data were obtained:
Weight of Melissa (i.e cow) = 0.65 tons
Weight of Philip (i.e rabbit) = 192 ounces
Next, we shall express the weight of Philip (i.e the rabbit) in tons. This can be obtained as follow:
1 ounce = 3.125×10¯⁵ ton
Therefore,
192 ounce = 192 ounce × 3.125×10¯⁵ ton / 1 ounce
192 ounce = 0.06 ton
Thus, the weight of Philip (i.e the rabbit) in ton is 0.06 ton.
Next, we shall determine the ratio of the weight of Melissa (i.e the cow) to the weight of Philip (i.e the rabbit). This can be obtained as follow:
Weight of Melissa (i.e cow) = 0.65 ton
Weight of Philip (i.e rabbit) = 0.06 ton
Melissa /Philip = 0.65/0.06
Melissa /Philip = 11
Melissa = 11 × Phillip
Thus, it will take 11 times the weight of Philip to weigh as much as Melissa.
A cow standing atop a building in Times Square recalled a funny joke and began to laugh. The uncontrollable laughter caused the cow to fall over the side of the building. He fell for a time period of 3.5 s and landed in a bed of bushes. How fast was the cow moo-ving when he reached the bushes?
Which equation should be used to solve the problem?
Answer:
Vf = 34.3 m/s
1st equation of motion was used to solve.
Explanation:
In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity of Cow = ?
Vi = Initial Velocity of Cow = 0 m/s
g = acceleration due to gravity = 9.8 m/s²
t = time taken = 3.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3.5 s)
Vf = 34.3 m/s
1st equation of motion was used to solve.
State one way to decrease the moment of a given force about a given axis of rotation.
Answer:
The moment of a given force about a given axis of rotation can be decreased by decreasing the perpendicular distance of force from the axis of rotation.
Answer:
hope it helps...
Explanation:
The moment of a given force about a given axis of rotation can be decreased by decreasing the perpendicular distance of force from the axis of rotation.