A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
coaster? (Formula: PE = mgh)
O 800 kg
O 7,840 kg
O 8,000 kg
O 78,400 kg

Answers

Answer 1

Answer:

800 kg

Explanation:

I just did it :)


Related Questions

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

Answers

Question:

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

A. sinks slightly  

B. rises slightly  

C. floats at the same height  

D. bobs up and down about its old position

Answer:

The correct answer is C)  floats at the same height  

Explanation:

The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.

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What are the Laws of conservation of atoms?​

Answers

Answer:

Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.

Explanation:

Answer:

The law of conservation of atoms is simple but it has a great affect. An atom cannot be destroyed by such a force. Matter/atoms can't be created by any means. An atom exits only by nature and not by force.

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Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Answers

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

[tex]v_y = v \times sin(\theta)[/tex]

Substituting the values from the question gives;

[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]

The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.

How do you solving kinematic equations for horizontal projectiles?

Answers

See projectiles are very simple unless you understand its core concepts....projectile is nothing just mixture of upward motion and horizontal motion....
THE KEY IS FORGET THE NAME PROJECTILE...ITS JUST HORIZONTAL MOTION + VERTICAL MOTION

PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!

Answers

Answer:

d

Explanation:

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