Two 0.55-kg basketballs, each with a radius of 19 cm , are just touching. You may want to review (Pages 399 - 401) . Part A How much energy is required to change the separation between the centers of the basketballs to 1.4 m ? (Ignore any other gravitational interactions.)

Answers

Answer 1

Answer:

      ΔU = - 9,179 10-11 J

Explanation:

For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy

               U = - G m₁m₂ / R

In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m

               U₁ = - G m² / r₁

let's calculate

              U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19

              U₁ = - 10,619 10⁻¹¹ J

when its centers are separated it is at r₂ = 1.4 m

              U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4

              U₂ = - 1.44 10-11 J

the energy between these two points is

          ΔU = U₂ - U₁

          ΔU = (-1.44 +10.619) 10-11

          ΔU = - 9,179 10-11 J


Related Questions

What are matter, particle and atom? How can you explain matter using the terms particle and atom?

Answers

Answer:

Matter is matter. Particles are particles. Atoms are atoms. You can explain matter using particles and atoms.

JK!

Real Answer:

The term matter refers to anything that occupies space and has mass—in other words, the “stuff” that the universe is made of. An atom is the smallest unit of matter that retains all of the chemical properties of an element. Most atoms contain all three of these types of subatomic particles—protons, electrons, and neutrons.

Hope this helps!

1. Light from a laser shines through two narrow slits 0.300 mm apart and produces an interference pattern on a screen 4.35 m away consisting of 9 bright fringes over a distance of 6.4 cm. a) Draw a labeled diagram of this scenario and briefly explain how the interference pattern is created b) Calculate the wavelength of the laser. What color is it?

Answers

Answer:

Explanation:

slit separation d = .3 x 10⁻³ m

screen distance D = 4.35 m

fringe width = 6.4 x 10⁻² / 9

= .711 x 10⁻² m

a ) Interference pattern on the screen is created due to interference of two light waves coming from two slits and falling in screen . When they fall on different points on the screen they travel different distance . This is called path difference . When their path difference is equal to their wave length or its integral multiple , they reinforce each other and at that point the brightness increases . On the other hand when at a point the path difference is equal to odd multiple of half wavelength , they kill or destroy each other and darkness is found at that point . In this way dark band and bright band appear on the screen . This is called interference pattern .

b )

Fringe width  = λ D / d

Putting the values

.711 x 10⁻² = λ x 4.35 /  0.3 x 10⁻³

λ = .049 x 10⁻⁵

= 490 x  10⁻⁹

= 490 nm

The colour of this wavelength will be blue .

A runner starts at point A, runs around a 1-mile track and finishes the run back at point A. Which of the following statements is true?

Answers

This question is incomplete because the options are missing; here is the complete question:

A runner starts at point A, runs around a 1-mile track, and finishes the run back at point A. Which of the following statements is true?

A. The runner's displacement is 1 mile.

B. The runner's displacement is zero.

C. The distance the runner covered is zero.

D. The runner's speed was zero.

The answer to this question is B. The runner's displacement is zero

Explanation:

Displacement always implies a change of position; this means an object or individual moves from point A to point B, and therefore the original position is different from the final position. Additionally, in displacement, other related factors such as the total distance the body moved and the direction of movement. In the case presented, it can be concluded there was no displacement or the displacement is zero because even when the runner moved and ran two miles, he returned to the initial position, and without a change in the position, there is no displacement.

Explain what the purpose of projectile motion is, and the different equations used. Explain what each equation does.

Answers

Answer:

MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...

Explanation:

TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....

TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..

MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g

Range =Search Results

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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

A skater with an initial speed of 7.30 m/s stops propelling himself and begins to coast across the ice, eventually coming to rest. Air resistance is negligible. (a) The coefficient of kinetic friction between the ice and the skate blades is 0.105. Find the deceleration caused by kinetic friction. (b) How far will the skater travel before coming to rest?

Answers

Answer:

a. a= 1.029 ms⁻²

b. S=25.89 m

Explanation:

given

initial speed is u = 7.30 m/sec

final speed is v = 0 m/sec

mu_k = 0.105

kinetic frictional force is Fk = mu_k×m×g

mu_k×m×g = m×a

m cancels

mu_k×g = a

deccelaration a = mu_k×g = 0.105×9.8 =1.029 ms⁻²

b) using v²-u² = 2aS

0²-7.3² = -2×1.029×S

53.29=2.058×S

S = 53.29/2.058

S=25.89 m

An alternating-current (AC) source supplies a sinusoidally varying voltage that can be described with the function v of t is equal to V times cosine of begin quantity omega times t end quantity, where V is the maximum voltage, omega is the angular frequency, and t is the time. If the frequency of this source is 60 Hz, what is omega equal to

Answers

Answer:

ω, the angular frequency of the source equals 377 rad/s

Explanation:

From the question, V(t) = V cosωt.

Now, ω = the angular frequency of the sinusoidal wave is given by

ω = 2πf where f = the frequency of the source = 60 Hz

So, the angular frequency of the source ,ω = 2π × the frequency of the source.

So, ω = 2πf

ω = 2π × 60 Hz

ω = 120π rad/s

ω = 376.99 rad/s

ω ≅ 377 rad/s

So, ω, the angular frequency of the source equals 377 rad/s

which statement best describes metallic bonding

Answers

Answer:

It's a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal bars. It can also be described as the sharing of free electrons among a structure of positively charged ions

Your question is incomplete. Please read below to find the missing content.

Metallic bonds end result because of electrostatic forces of enchantment which results while the definitely charged atoms and negatively charged atoms interaction to form an everyday electron sea version.

What is true approximately steel bonding?

Metallic bonds occur among metallic atoms. Whereas ionic bonds are part of metals to non-metals, metal bonding joins a bulk of metallic atoms. A sheet of aluminum foil and a copper cord are both places where you could see metallic bonding in action.

Learn more about electrostatic forces here: https://brainly.com/question/17692887

#SPJ2

As part of previous adventures, formerly conjoined identical twin, Sue, is now 13.4 years younger than her identical twin Lou. (The anniversaries of their birth are no longer the same day.) It is Lou's turn to travel, and he goes away and back at 0.96c. During his round trip, Lou ages 1 year. What is the the difference in the twin's ages when he returns.

Answers

Answer:

Difference in Twin's Ages = 12.68 years

Explanation:

Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.

t = t₀/[√(1 - v²/c²)]

where,

t = time measured by the person in relative motion = 1 year

t₀ = time measured by the person at rest = ?

v = speed of relative motion = 0.96 c

c = speed of light  

Therefore,

1 year = t₀/[√(1 - 0.96² c²/c²)]

1 year = t₀/[√(1 - 0.9216)]

(1 year)(0.28 year) = t₀

t₀ = 0.28 year

Let,

y = Sue's age

x = Lou's age

so,

x - y = 13.4 years

but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,

x = x + 1

y = y + 0.28

Therefore,

(x + 1 year) - (y + 0.28 year) = 13.4 years

x - y = 13.4 years - 0.72 year

x - y = 12.68 years

Difference in Twin's Ages = 12.68 years

The world’s fastest elevator is in Taipei, Taiwan. It can lift passengers 1,010 m in 39 s. What is the speed of this elevator?

Answers

Answer: 25.90 m/sec

Explanation:

Speed = Distance / Time

Speed = 1010 / 39

Speed = 25.90 m/s

An anti-aircraft gun fires at an elevation of 60° at an enemy aircraft at 10000m above the ground At what speed must the cannon be shot to hit the plane at that height?(g=10m/s^2)​

Answers

Answer:

516m/s^2

Explanation:

Given the following :

Height of aircraft = 10000m

Acceleration due to gravity (g) = 10m/s^2

Angle of projection (θ) = 60°

Height of aircraft = maximum height

Maximum height of a projectile:

H = (u^2sin^2θ) / 2g

Where H = height

u = initial velocity

10000 = [(usinθ)^2] / 2g

10000 = [(u * sin60°) ^2] / 2*10

10000 = (0.866 * u)^2 / 20

20 * 10000 = 0.749956 * u^2

200000 = 0.749956u^2

u^2 = (200000/0.749956)

u^2 = 266,682.31

u = √266,682.31

u = 516.41292

Initial velocity (u) = 516m/s^2

pls help guys this is my 7th time posting XD​

Answers

Answer:

Explanation:

initial velocity u = 54 km/h = 15 m/s

final velocity v = 18 km/h = 5 m/s

distance s = 10 m

1. v^2 = u^2 + 2as

5^2 = 15^2 + 2a × 10

25 = 225 + 20a

25 - 225 = 20a

20 a = -200

a = -200/2

a = -100m/s^2

∴Deacceleration = -100m/s^2

2. v = u + at

5 = 15 -100t

5-15 = -100t

-10 = -100t

t = 100 / 10

∴t = 10 sec

Total distance covered by the car 10 m

To me, the hardest part of this whole thing is keeping the units straight.  We're starting out with information given to us in kilometers, hours, and meters, and we have to come up with answers in m/s² , seconds, and meters.

When I worked this problem, I jumped right in without thinking, and I immediately got bogged down when I had to go off to the side and convert some units.

Now I know better.  THIS time, before we get all tangled up trying to solve anything, let's get clever and change everything to m/s right now !

(54 km/hour) · (1,000m/km) · (1 hour/3600 sec)  =  15 meters/second

(18 km/hour) · (1,000 m/km) · (1 hour/3600 sec) = 5 meters/second

NOW I'll betcha it's gonna be about 70% faster and easier !

i). Acceleration = (change in speed / time for the change)

We know the distance, but not the time.  I know there's a formula for it, but I've learned so many formulas during my lifetime that I can't remember ALL of them.  So I just memorize some of them, and I work things out from the formulas that I know.  Here's how I do time:)

Average speed during the given slow-down = (1/2)·(15+5) = 10 m/s

Distance covered during the given slow-down = 10 m.

Time = (distance) / (average speed) = (10m) / (10 m/s) = 1 second

Acceleration = (change in speed) / (time for the change)

Acceleration = (5 m/s - 15 m/s) / (1 second)

Acceleration = (-10 m/s) / (1 second)

Acceleration = -10 m/s²   (or 'Deceleration' = 10 m/s² )

_____________________________________________

For parts ii). and iii)., there's a big shift in the question.

It only gave you the slow-down from 54 to 18 km/hr for the purpose of calculating the deceleration.  NOW, for the rest of the answers, it's talking about a complete stop ... 0 m/s .

____________________________________________

ii). Time required to stop = (initial speed) / (deceleration)

Time to stop from 54 km/hr = (15 m/s) / (10 m/s²)

Time to stop = 1.5 seconds

iii).  Distance covered = (average speed) · (time to stop)

Distance covered = (7.5 m/s) · (1.5 sec)

Distance covered = 11.25 meters

OR ... use the official formula:

Distance = (1/2) · (acceleration) · (time² )

Distance = (1/2) · (10 m/s²) · (1.5 sec)²

Distance = 11.25 meters           yay !

The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state. After the change, the atoms are close together but are able to slide past one another.


A diagram has a triangle at center with gas on top, liquid on bottom right, solid on bottom left. An arrow from gas to liquid is labeled O, and an arrow from liquid to gas is labeled N. An arrow from solid to liquid is labeled P, and an arrow from liquid to solid is labeled Q. An arrow from solid to gas is labeled L, and an arrow from gas to solid is labeled M.

Which arrow represents the change of state described above?


L

N

O

P


will mark brainiest

Answers

Answer:

O

Explanation:

Matters exist majorly either as solids, liquids or gases. These are called states of matter. A change of state occurs when a substance either absorb or release energy.

Since the atoms of the substance lost energy and become close together with the ability to slide past one another, the change of state is from gaseous to liquid. And the process is called condensation (O). Thus the process is that of O, called condensation.

Answer:

O

Explanation:

your welcome have a great day.

Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of the larger disks rigidly connected to each other with a common axis of rotation. System B consists of one of the larger disks and a number of the smaller disks rigidly connected with a common axis of rotation. If the moment of inertia for system A equals the moment of inertia for system B, how many of the smaller disks are in system B?

Answers

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

A body of volume 100cc immersed completely in water contained in a jar. The weight of water and jar before immersion of the body was 700gm. After immersion, what will be the weight of water and jar?

Answers

Answer:

800gm

Explanation:

Archimedes principle states that when an object is immersed in a liquid there is an apparent loss of weight of the object. This apparent loss of weight is also the upthrust experienced by the liquid. The upthrust is equal to the weight of the liquid displaced.

Following from the above statement, when the body of volume 100c.c is immersed in the water contained in the jar, the upthrust experienced is equal to the weight of the water displaced.

Note: In the question, weight is measured just using the mass.

Mass (m) is the product of density (ρ) of liquid (which is water in this case) and volume (v) of body immersed. i.e

m = ρ x v

Where;

ρ = 1 gm/cm³

v = 100c.c = 100cm³

=> m = 1 gm/cm³ x 100cm³

=> m = 100gm

Therefore the weight of water displaced is 100gm

Now, the weight of the water and jar after immersion is the sum of the weight of water and jar before immersion, and the weight of the water displaced. i.e

Weight of water and jar after immersion = 700gm + 100gm = 800gm

A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V household electricity, decreasing the resistance of the filament will _____ the current through the bulb and _____ the power dissipated by the bulb. A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V household electricity, decreasing the resistance of the filament will _____ the current through the bulb and _____ the power dissipated by the bulb. Decrease, decrease Decrease, increase Increase, increase Increase, decrease

Answers

Answer:

Increases, increases

Explanation:

The current is directly proportional to the voltage and inversely proportional to the resistance. The implication of this is that, whenever the voltage is increased, the current increases simultaneously. On the other hand, if the resistance is increased, the current will decrease accordingly and vice versa.

Recall that power is given by P= V^2/R where;

P= power, V= voltage and R= resistance

We can see that power and resistance are inversely related hence decreasing the resistance increases the power output of the lightbulb.

Answer:

Increase, increase

Explanation:

Ohm's law states that R=V/I .

This can be rearranged as I = V/R , showing that current is inversely proportional to resistance. When resistance decreases, current increases (with constant voltage).

Power dissipated by a resistor is given by the equation P = RI^2 . Showing that as R decreases and increases I, the increase to I is exponential while the decrease in resistance is not, which leads to increased power dissipation.

Evelyn walked to the store a distance of 1.6 km in 30 min. What is her average speed in m/s?

Answers

Average speed = (distance covered) / (time to cover the distance)

Average speed = (1.6 km) / (30 min)

Average speed = 0.0533 km/min

This is the true average speed, but it's not in the units that the question asked for.  So we have to massage it and convert it to ' meters/sec '.

Speed = (1.6 km) / (30 min)

Speed = (1.6 km / 30 min) x (1,000 m / 1 km) x (1 min / 60 sec)

Speed = (1.6 x 1,000 x 1) / (30 x 1 x 60) (km-m-min / min-km-sec)

Speed = (1,600 / 1,800) (m / sec)

Speed = 0.89 m/s    

2/​A mains electricity hairdryer has a resistance of 46 Ω and a current of 5 A flows through it when in use. What is the voltage across the hairdryer? (This is the mains voltage in the UK)




3/ What is the voltage across a lamp of resistance 4 Ω if a current of 2.5 A flows through it?

Please help :)

Answers

Answer:

I hope this answer will help you

A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5m/s^2 . After the wind stops, the sailboat is traveling to the left with a velocity of 3.0m/s. Assuming the acceleration from the wind is constant, what was the initial velocity of the sailboat before the gust of wind? Answer using a coordinate system where rightward is positive.

Answers

Answer:

+7.0 m/s

Explanation:

Let's take rightward as a positive direction.

So in this problem we have:

a = -2.5 m/s^2 acceleration due to the wind (negative because it is leftward)

t = 4 s time interval

v = -3.0 m/s is the final velocity (negative because it is leftward)

We can use the following equation:

v = u + at

Where u is the initial velocity

We want to find u, so if we rearrange the equation we find:

u = v - at = (-3m/s) - (-2.5m/s^2) (4s) = +7.0m/s

and the positive sign means the initial direction was rightward.

Find the velocity. 10 points. Will give brainliest!

Answers

Answer:

6.060606...

Explanation:

To figure out velocity, you divide the distance by the time it takes to travel that same distance, then you add your direction to it. So the distance would be 1000m and the time would be 2 minutes and 45 seconds and if you convert the minutes into fractions you would get 165 seconds than you would divide 1000m by 165 seconds and you would get 6.060606... seconds as her average velocity

You notice the flagpole at school vibrating in the breeze. You count the vibrations and find that
the flagpole makes 20 complete vibrations in 10 seconds. You read somewhere that this
lagpole vibrates at a speed of 25 m/s when the wind is blowing Find the wavelength of these
vibrations

Answers

Answer: 12.5m

Explanation:

Given the following :

Flagpole makes 20 complete vibrations in 10 seconds

Velocity (V) of vibration = 25m/s

Find the wavelength of vibration (λ) =?

Frequency is number of complete oscillation per Second

Therefore ;

Frequency (F) = number of oscillations / time taken

F = 20 / 10 = 2Hz

Wavelength = Velocity / frequency

Wavelength = 25 / 2

Wavelength = 12.5m


A balloon and a mass are attached to a rod that is pivoted at P.

The balloon is filled with helium, a gas less dense than air, so that it applies an upward force on
the rod.

The rod is horizontal and stationary.
Which action causes the rod to rotate clockwise?

A Move both the balloon and mass 10 cm to the left.
B Move both the balloon and mass 10 cm to the right.
C Move both the balloon and mass to the 25 cm mark.
D Move the balloon to the 20 cm mark and the mass to the 30 cm mark.

Answers

Answer:

The correct option is;

B Move both the balloon and mass 10 cm to the right

Explanation:

Given that the system is in equilibrium, we have;

Force of balloon = [tex]F_b[/tex]↑

Force of mass = [tex]F_m[/tex] ↓

The direction of the balloon is having an upward motion which gives a clockwise moment or motion to the rod while the direction of the force of the mass weight is downwards, giving the rod an anticlockwise moment

for the rod to rotate clockwise, the moment of the balloon should be larger than that of the rod

At the present equilibrium we have;

[tex]F_b[/tex] × 30 =  [tex]F_m[/tex] × 20

Therefore;

[tex]F_m[/tex] = 1.5×[tex]F_b[/tex]

Moving both balloon and mass 10 cm to the right gives;

The moment of the balloon = [tex]F_b[/tex] × (30 - 10)  = [tex]F_b[/tex] × 20 = 20×[tex]F_b[/tex],

The moment of the mass =  [tex]F_m[/tex] × (20 - 10) =  [tex]F_m[/tex] × 10

When we substitute  [tex]F_m[/tex] = 1.5×[tex]F_b[/tex] in the moment equation for the mass, we have;

The moment of the mass = [tex]F_m[/tex] × 10 = 1.5×[tex]F_b[/tex] ×10 = 15×[tex]F_b[/tex]

Therefore, the balloon now has a larger momentum than that of the mass and the rod will rotate clockwise.

Answer:

the answer is

Explanation:

the ballon's force is clockwise will the mass's force is anticlockwise

the mass will have a smaller moment due to less distance, while the balloon will have a greater distance, therefore more moment

the blank waves in the electromagnetic spectrum are gamma rays

Answers

Answer:

Gamma-rays. Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions. Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Explanation:

mark me brainliest if my answer is helpful.....

Find the enthalpy change per mole of sodium when sodium reacts with water. 8 grams of sodium reacts with 227 cm3 of water, producing a temperature change from 298 K to 308.4 K. The specific heat capacity of water is 4.18 J/K g. A. -28.36 kJ B. 9868.1 J C. 62.75 kJ D. -28356.7 kJ

Answers

Answer:

The correct answer to the following question will be Option A (-28.36 KJ). The further explanation is given below.

Explanation:

The given values are:

Sodium's mass = 8 grams

Water's volume = 227 cm³

Molar mass = 23 g/mol

Density of water = 1 g/cm³

Specific heat capacity ([tex]C_{w}[/tex]) = 4.18 J/Kg

As we know,

⇒  [tex]Moles \ of \ Na =\frac{mass \ of \ Na}{Molar \ mass \ of \ Na}[/tex]

On putting the estimated values, we get

⇒                        [tex]=\frac{8}{23}[/tex]

⇒                        [tex]=0.348 \ mol[/tex]

Now, Water's mass will be:

⇒  [tex]M_{w} = density\times volume[/tex]

           [tex]=1\times 227[/tex]

           [tex]=227 \ g[/tex]

Change in temperature will be:

⇒  [tex]\Delta T=(308.4-298)K[/tex]

           [tex]=10.4 \ K[/tex]

Heat released will be:

⇒  [tex]q=M_{w}\times C_{w}\times \Delta T[/tex]

On substituting the estimated values, we get

       [tex]=227\times 4.18\times 10.4[/tex]

       [tex]=9.87\times 10^3[/tex]

       [tex]=9.87 \ KJ[/tex]

So that the change in the solution of Na will be:

⇒  [tex]\Delta H=\frac{-q}{Moles \ of \ Na}[/tex]

            [tex]=\frac{-9.87}{0.348}[/tex]

            [tex]=-28.36 \ KJ/mol[/tex]

Can someone please help me out with this question? It's due pretty soon and I dont really understand it

One idea of how the universe formed is based on a huge explosion that sent matter and energy speeding throughout space. Stars, planets, and other space objects formed when the matter clumped together slowly.

What is the name of the idea that matches this description of how the universe formed?
Select one:
a. Convection Particle theory
b. Clumping Matter theory
c. Swirling Cloud theory
d. Big Bang theory

Answers

Answer: The Big Bang Theory

Explanation:

An object has a mass of 23.40 kg. If its acceleration is 28.10 m/s? what is the amount of force causing the acceleration?
A. 657.5 N
B. 0.8327 N
C. 51.50 N
D. 1.201 N​

Answers

Answer:

[tex] \boxed{\huge {\sf A. \ 657.5 \ N}} [/tex]

Given:

Mass = 23.40 kg

Acceleration = 28.10 m/s

To Find:

Amount of force causing acceleration

Explanation:

[tex] \sf Force = Mass \times Acceleration \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 23.40 \times 28.10 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 657.54 \ N \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \approx 657.5 \ N [/tex]

give four example each for newton's first,second,and thirdlaw of motion​

Answers

1st: [An airplane midflight] will maintain its direction unless maneuvered by a pilot
Kicking a ball. Driving a car, any stationary object.
2nd: [Pushing a box] the more force you put into moving the box the faster the box will move.
Ball rolling down a hill, riding a bike, batting a ball
3rd: [Jumping] your feet push against the ground
Moving car, running into a wall, paddling

State Archimedes' principle.​

Answers

Answer:

Archimedes Principle states that "any body completely or partially submerged in water is acted upon by an upthrust force which is equal to the magnitude of Weight of the body."

Answer:

We know that due to upthrust ,objects tend to lose weight when immersed in liquid.

Archimedes principle states that " If an object is partially or completely immersed in the liquid, the weight of liquid displaced by the object is its upthrust.

This law is applicable for the gaseous medium too.The weight of the displaced liquid =pgv where p is density of liquid ,g is acceleration due to gravity and v is volume of displaced liquid.

Hope this helps...

Good luck on your assignment..

A student of mass 40kg takes 10s to run up a flight of 50steps. If each step is 15cm high, calculate the Potential Energy of the student at the maximum height.​

Answers

Answer:

2943 J

Explanation:

Potential energy = mass x acceleration due to gravity x height in meters

(P.E. = mgh)

Substitute the given numbers: (I take acceleration due to gravity as 9.81 m s^-2)

PE = 40 x 9.81 x (0.15x50)

PE = 2943 J

The centres of a ring of mass m and a sphere
of mass Mof equal radius R, are at a distance
V8 Rapart as shown. The force of attraction
between the ring and the sphere is.
Plz help me out !!!

Answers

Given that,

Mass of ring = m

Mass of sphere = M

Radius = R

Distance = √8R

We need to calculate the intensity of gravitational field

Using formula of intensity

[tex]E_{g}=\dfrac{Gmx}{\sqrt{(r^2+x^2)^\frac{3}{2}}}[/tex]

Put the value into the formula

[tex]E_{g}=\dfrac{Gm\sqrt{8}R}{(R^2+8R^2)^{\frac{3}{2}}}[/tex]

[tex]E_{g}=\dfrac{2\sqrt{2}Gm}{(9R^2)^{\frac{3}{2}}}[/tex]

[tex]E_{g}=\dfrac{2\sqrt{2}Gm}{27R^2}[/tex]

We need to calculate the force of attraction  between the ring and the sphere

Using formula of attraction force

[tex]F=M\times E_{g}[/tex]

Where, M = mass of sphere

E = intensity of gravitational field

Put the value into the formula

[tex]F=\dfrac{2\sqrt{2}GmM}{27R^2}[/tex]

Hence, The force of attraction  between the ring and the sphere is [tex]\dfrac{2\sqrt{2}GmM}{27R^2}[/tex]

What climate conditions occur during La Niña?
A.stronger prevailing winds and more hurricane activity
B.warmer Pacific waters and warmer winters
C.more hurricane activity and warmer Pacific waters
D.warmer winters and stronger prevailing winds

Answers

Answer:

A. stronger prevailing winds and more hurricane activity

Explanation:

edg2020

Answer:A

Explanation:

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