turns into _____ energy (when plants convert into food)

Answers

Answer 1

Answer:

the answer is PHOTOSYNTHESIS..

Explanation:

photosynthesis is the process when plants make their food from taking energy from the sun creating sugar.


Related Questions

What is the velocity of the boat if the passenger shoots at an angle 60 with horizontal ? The mass of boat with the passenger is 100 kg ,mass of the bullet is 35g and its velocity is 400 m/s. <3

Answers

Answer:

400cos(60) = 200m/s

100(v) = 0.035(200)

v= 0.07m/s

Hydropower is alternative source of energy​

Answers

Answer:

Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.

Answer:

because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.

Explanation:

please mark as brainlest

Suppose an astronaut floating in space throws a rock. What will happen to the rock?

Answers

Answer:

C

Explanation:

2. What do pitch and loudness have in common?
Both are measured in decibels, or dB.
Both depend on a wave's frequency.
Both are subject to a person's interpretation.

Answers

Answer:

Both are subject to a persons interpretation

Explanation:

We hear people describe this when somebody is making an irresistible sound. usually people say the baby has a pitch scream.

How do gamma rays use electromagnetic waves to function....PLS HELP

Answers

Answer:

Gamma-rays have the smallest wavelengths and the most energy of any other wave in the electromagnetic spectrum. These waves are generated by radioactive atoms and in nuclear explosions.

Explanation:

Gamma-rays can kill living cells, a fact which medicine uses to its advantage, using gamma-rays to kill cancerous cells.

Hope this helps!

Brain-LIst?

A newly discovered particle, the SPARTYON, has a mass 455 times that of an electron. If a SPARTYON at rest absorbs an anti-SPARTYON, what is the frequency of each of the emitted photons (in 1020 Hz)? The mass of an electron is 9.11×10-31 kg.

Answers

Answer:

υ = 5.62 x 10¹⁴ Hz

Explanation:

The process of of formation of photons takes place due to interaction of a particle with its anti-particle is called Annihilation of Matter. Here SPARTYON absorbs anti-SPARYTON to form 2 photons. Applying conservation of energy to the to this scenario, we get:

2(Energy of Each Photon) = Rest Mass Energy of SPARTYON + Rest Mass Energy of anti-SPARTYON

[tex]2hv = m_{0}c^2 + m_{0}c^2\\\\2hv = 2m_{0}c^2\\\\hv = m_{0}c^2\\\\v = \frac{m_{0}c^2}{h}[/tex]

where,

υ = frequency of each photon = ?

m₀ = rest mass of SPARTYON = mass of anti-SPARTYON = 455*Mass of electron

m₀ = 455(9.1 x 10⁻³¹ kg) = 4.14 x 10⁻²⁸ kg

c = speed of light = 3 x 10⁸ m/s

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

Therefore, using these values in the equation, we get:

[tex]v = \frac{(4.14 x 10^{-28} kg)(3 x 10^8 m/s)^2}{6.625 x 10^{-34}J.s}\\\\[/tex]

υ = 5.62 x 10¹⁴ Hz

If the equal tensions T in the pulley cable are 300 N, express in vector notation the force R exerted on the pulley by the two tensions. Determine the magnitude of R.

Answers

Answer:

[tex]R=519.61N[/tex]

Explanation:

From the question we are told that

Tension T on a cable are T=300N

Generally the tensions on a pulley is

       [tex]\sum f_x=T+T*cos(\theta)[/tex]

Therefore

      [tex]\sum f_x=300+300*cos(60)[/tex]

      [tex]\sum f_x=300 *1.5[/tex]

      [tex]\sum f_x=450N[/tex]

Hence

      [tex]T*sin(60) = 259.81N[/tex]

     [tex]R= 450\=i +259.81\=i[/tex]

     [tex]R=\sqrt{450^2+259.8^2}[/tex]

     [tex]R=519.61N[/tex]

If a wave is traveling at 200 m/s and it’s wavelength is 0.5 meters , what is the frequency of the wave

Answers

Answer:

400 Hz

Explanation:

The frequency of a sound wave is found by the velocity/wavelength.  Therefore, f = v/wavelength = (200 m/s)/(0.5 m) = 400 Hz

I hope this helps! :)

What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor

Answers

Complete Question

A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?

Answer:

The magnetic field is  [tex]B = 6.4*10^{-4} \ T[/tex]

Explanation:

From the question we are told that

    The current is  [tex]I = 8.0 \ A[/tex]

    The diameter is  [tex]d = \ cm = \frac{1}{100} = 0.01 m[/tex]

      The position considered is  [tex]d = 2.5 \ mm = 0.0025 \ m[/tex]

 Generally the magnetic field is mathematically represented as

           [tex]B = \frac{\mu_o * I }{ 2 \pi d}[/tex]

Here [tex]\mu_o[/tex] is permeability of free space with value  

[tex]\mu_o = 4\pi * 10^{-7} \ N/A^2[/tex]

      So

                 [tex]B = \frac{ 4\pi * 10^{-7} * 8 }{ 2 \pi * 0.0025 }[/tex]

=>               [tex]B = \frac{ 2 * 10^{-7} * 8 }{ * 0.0025 }[/tex]

=>               [tex]B = 6.4*10^{-4} \ T[/tex]

A person pushes a 10 kg box from rest and accelerates it to a speed of 4 m/s with a constant force. If the box is pushed for a time of 2.5 s, what is the force exerted by the person?

Answers

The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration a is such that

4 m/s = a (2.5 s)   →   a = (4 m/s) / (2.5 s) = 1.6 m/s²

Then the force applied to the box has a magnitude F such that

F = (10 kg) (1.6 m/s²) = 16 N

A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy potential store

Answers

hhhhuuuxuuuudddddddddddd

Fire trucks have the word FIRE written two ways, as seen here, on the front of the truck. Why is that?

Answers

Answer:

b.

Explanation:

If you had to choose one device to use with the battery, what would it be? Do you think such a battery could be invented
someday? Explain

Answers

Answer:

I would choose refrigerator.

Explanation:

In my opinion, such a battery could be invented by changing the device as a low power mode. Plus, it is a must in order to decrease the CFC gas spreading through the atmosphere. That's all, thank you.

Fix this problem, please.

Answers

Answer:

The correct option is (a).

Explanation:

Given that,

Radius of a horizontal circle, r = 80 cm = 0.8 m

Angular velocity, ω = 5 rev/minute = 0.523 rad/s

We need to find the magnitude of its centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

[tex]a=\omega^2 r\\\\a=(0.523)^2\times 0.8\\\\a=0.218\ m/s^2[/tex]

or

[tex]a=0.22\ m/s^2[/tex]

So, the magnitude of its acceleration is [tex]0.22\ m/s^2[/tex].

You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic friction is .4, how far will it move in 3 seconds?

Answers

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

The crate will move at a distance of 1.215 m in 3 seconds.

How do you calculate the distance of motion?

Given that the mass m of the crate is 70 kg and the angle above the horizontal is 30°. External force F on the crate is 600 N and the coefficient of friction is 0.4.

The friction force applied to the crate is calculated as given below.

Friction force = [tex]\mu mgcos \theta[/tex]

Where [tex]\mu[/tex] is the friction constant, g is the gravitational acceleration and [tex]\theta[/tex] is the angle above the horizontal.

Friction Force = [tex]0.4\times 70\times 9.8\times cos30^\circ[/tex]

Friction force = 237.63 N.

There is a force applied on the crate due to its weight is calculated as given below.

Force (weight component) = [tex]mgsin\theta[/tex]

Force (weight component) = [tex]70\times 9.8\times sin 30^\circ[/tex]

Force (weight component) = 343 N.

The net force applied to the crate is given below.

Net force = External force - friction force - force (weight component)

Net force F' = [tex]600 - 237.63 - 343[/tex]

Net force F' = 19.37 N.

The acceleration of the crate can be calculated as given below.

[tex]a = \dfrac {F'}{m}[/tex]

[tex]a =\dfrac {19.37}{70}[/tex]

[tex]a = 0.27 \;\rm m/s^2[/tex]

Hence the distance traveled by the crate in 3 seconds is calculated by the formula given below.

[tex]s = ut + \dfrac {1}{2} at^2[/tex]

Where, s is the distance, u is the initial velocity, a is the acceleration and t is the time of motion of the crate.

[tex]s = 0\times 3 + \dfrac {1}{2} \times 0.27 \times 3^2[/tex]

[tex]s = 1.215[/tex]

Hence we can conclude that the crate will move a distance of 1.215 m in 3 seconds.

To know more about the force, follow the link given below.

https://brainly.com/question/26115859.

Which of the following is not a factor used to find climate?

pressure on a given day
wind and ocean currents
latitude and altitude

Answers

Answer:

pressure on a given day

Explanation:

because you can't find pressure in a day

Hooke's law describes a certain light spring of unstretched length 32.1 cm. When one end is attached to the top of a doorframe and a 7.94 kg object is hung from the other end, the length of the spring is 42.4 cm. (a) Find its spring constant. .7554 Correct: Your answer is correct. kN/m (b) The load and the spring are taken down. Two people pull in opposite directions on the ends of the spring, each with a force of 178 N. Find the length of the spring in this situation. .7923 Incorrect: Your answer is incorrect.

Answers

Answer:

[tex]0.75623\ \text{kN/m}[/tex]

[tex]55.6\ \text{cm}[/tex]

Explanation:

m = Mass of object = 7.94 kg

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

x = Change in length of the spring = [tex](42.4-32.1)\ \text{cm}[/tex]

F = Force on the spring

Force of gravity on the object and the force on the spring will be equal

[tex]mg=kx\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{7.94\times 9.81}{0.424-0.321}\\\Rightarrow k=756.23\ \text{N/m}[/tex]

The spring constant is [tex]756.23\ \text{N/m}=0.75623\ \text{kN/m}[/tex]

F = 178 N

Force on spring is given by

[tex]F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{178}{756.23}\\\Rightarrow x=0.235\ \text{m}=23.5\ \text{cm}[/tex]

The length of the spring will be [tex]32.1+23.5=55.6\ \text{cm}[/tex].

Describe any major landmarks (buildings, bridges, historical sites, etc.) that were destroyed during the valdivia earthquake.

Answers

Answer:

Homes, Workplaces, Statues, Meuseums

Explanation:

if you did look into it you would know after the earthquake there was a tsunami which flooded alot of places, this made many homeless, jobless, and many lossing vaklueable things

It takes 10 lb of force to stretch a spring 2 in. What is the stiffness (spring constant) of the spring

Answers

Answer:

875.59 N/m

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 lb

Extention (e) = 2 in

Spring constant (K) =?

Next, we shall convert 10 lb to Newton (N). This can be obtained as follow:

1 lb = 4.448 N

Therefore,

10 lb = 10 lb × 4.448 N / 1 lb

10 lb = 44.48 N

Thus, 10 lb is equivalent to 44.48 N

Next, we shall convert 2 in to metre (m). This can be obtained as follow:

1 in = 0.0254 m

Therefore,

2 in = 2 in × 0.0254 m / 1 in

2 in = 0.0508 m

Thus, 2 in is equivalent to 0.0508 m.

Finally, we shall determine the spring constant i.e the stiffness of the spring as follow:

Force (F) = 44.48 N

Extention (e) = 0.0508 m.

Spring constant (K) =?

F = Ke

44.48 = K × 0.0508

Divide both side by 0.0508

K = 44.48 / 0.0508

K = 875.59 N/m

Therefore the spring constant i.e the stiffness of the spring is 875.59 N/m

16. Explain the following observations:
i. Water wets glass surface but does not wet the waxed glass surface.

Answers

Answer:

because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.

Answer:

the adhesive forces between the drops are stronger than cohesive force between the liquid

A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at the rate of 1 foot per second. Calculate the true distance between the top of the ladder and the ground when the base of the ladder is 9 feet from the wall.

Answers

Answer:

[tex]y = 4.36[/tex]

Explanation:

Let the height of the ladder be L

[tex]L = 10[/tex]

Also:

Let [tex]x = distance\ from\ the\ base\ of\ the\ ladder[/tex]Let [tex]y = height\ of\ the\ base\ of\ the\ ladder[/tex]

When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.

So, we have:

[tex]L^2 = x^2 + y^2[/tex] --- Pythagoras Theorem

When the base is 9ft from the wall, this means that:

[tex]x = 9[/tex]

Substitute 9 for x and 10 for L in [tex]L^2 = x^2 + y^2[/tex]

[tex]10^2 = 9^2 + y^2[/tex]

[tex]100 = 81 + y^2[/tex]

Make [tex]y^2[/tex] the subject

[tex]y^2 = 100 - 81[/tex]

[tex]y^2 = 19[/tex]

Make y the subject

[tex]y = \sqrt{19[/tex]

[tex]y = 4.36[/tex]

Hence, the true distance at that point is approximately 4.36ft

The true statement about the true distance between the top of the ladder and the ground when the base is 9 feets from the wall is - 9/√19

Let :

x = distance from base of ladder y = Length of ladder

Ladder forms a right angle triangle as it leans against the wall :

Hence, we have :

Opposite² + Adjacent² = hypotenus²

x² + y² = 100

Taking the implicit derivative of both sides:

2xdx/dt + 2ydy/dt = 0

xdx/dt + ydy/dt = 0

ydy/dt = - xdx/dt

dy/dt = (-xdx/dt) / y

When the ladder is 9 ft from the wall;

x = 9

81 + y² = 100

y² = 100 - 81 = 19

y = √19

Substituting into the equation :

dy/dt = -9(1)/√19

Hence, dy/dt = - 9/√19

Learn more : https://brainly.com/question/13511183

What type of energy transfer occurs
when two objects touch?
O conduction
O induction
O convection

Answers

Answer:

conduction

Explanation:

Suppose that you wanted to use either conservation of momentum or conservation of kinetic energy to predict the outcome when a large car collides with a smaller car in a demolition derby. Which of the two quantities would be more appropriate for your calculation? Explain please.

Answers

Answer:

Conservation of momentum

Explanation:

Out of the two options given, the more appropriate one is the law of conservation of momentum. This is particularly so because momentum deals with the velocity or speed of the car while considering its mass. So, if a large car is to collide with another car, small one, then the momentum is what is considered. Energy on the other hand is talking about the work that is done, while the momentum considers the mass of the car while it is moving and considering its speed also

Given A = (0.210 + 0.41) (1.10 x 102). Show the result for A in correct number of
significant figures.

Answers

Answer:

69

Explanation:

Perform addition first as;

(0.210 + 0.41) = 0.62 -------{2 significant figures}

Perform product

(1.10 x 102) = 112 -------------- {3 significant figures}

The combined product

0.62 x 112 =69.44

                 = 69 ----------2 significant figures

Rule

The least number of significant figures in the numbers performing the operation determines the number of significant figures in the answer.

A car is being driven down a level track with no net force on it. This motion is best described as
A)Linear motion
B)circular motion
C) periodic motion
D) projectile motion​

Answers

A)Linear motion

If there is not net force on the car, then by the Newton Second Law, the acceleration is zero, and the only valid option for zero acceleration is A).

Which example is most likely made from both metals and gemstones?

Answers

Answer:

A Necklace is most likely made from both metals and gemstones

Explanation:

Brainliest?

the answer is necklace on ed2020 correct A is the correct answer

What is the launch speed of a projectile that rises vertically above the Earth to an altitude equal to 14 REarth before coming to rest momentarily

Answers

Answer:

 v = 1.078 10⁴ m / s

Explanation:

To solve this exercise we can use conservation of mechanical energy

Starting point. Just clearing

          Em₀ = K + U = ½ m v² - G m M / [tex]R_{e}[/tex]

Final point. At r = 14R_{e}

        Em_{f} = U = -G m M / 14R_{e}

how energy is conserved

         Em₀ = [tex]Em_{f}[/tex]

         ½ m v² - G m M /R_{e} = -G m M / 14R_{e}

        ½ v² = G M / R_{e} (-1/14 + 1)

        v² = 2 G M / R_{e} 13/14

we calculate

       v² = 2 6.67 10⁻¹¹ 5.98 10²⁴ / 6.37 10⁶ 13/14

       v = √ (1,16 10⁸)

       v = 1.078 10⁴ m / s

The launch speed of a projectile that rises above the earth will be

v = 1.078 10⁴ m / s

What is speed?

Speed is defned as the movement of any object with respect to the time the formula of speed is given as the ratio of the distance with time.

To solve this exercise we can use conservation of mechanical energy

Starting point. Just clearing

[tex]E_{mo} = K + U = \dfrac{1}{2}m v^2 - \dfrac{G m M} { r}[/tex]

Final point. At[tex]r = 14R_{e}[/tex]

 [tex]Em_{f} = U = \dfrac{-G m M }{14R_{e}}[/tex]

how energy is conserved

 [tex]E_{mo }= \dfrac{1}{2} m v^2 -\dfrac{-G m M }{R_{e}} = \dfrac{-G m M }{ 14R_{e}}[/tex]

  [tex]\dfrac{1}{2} v^2 = \dfrac{G M }{ R_{e} (\dfrac{-1}{14} + 1)}[/tex]

 

    [tex]v^2 = \dfrac{2 G M} { R_{e} \dfrac{13}{14}}[/tex]

we calculate

[tex]v^2 = \dfrac{2 6.67 \times10^{-11}\times 5.98 \times 10^{24}} { 6.37 \times 10^{6} \times \dfrac{13}{14}}[/tex]

  [tex]v = \sqrt{ (1,16\times 10^8)}[/tex]

  v = 1.078 10⁴ m / s

Hence the launch speed of a projectile that rises above the earth will be

v = 1.078 10⁴ m / s

To know more about speed follow

https://brainly.com/question/4931057

The highest surface temperature on any of the solar system’s planets is found on Venus. Partly because of its nearness to the sun and partly because of the extreme pressure of its atmosphere, the average daytime temperature on Venus is 453°C. What is this temperature in degrees Fahrenheit and in kelvins?

Answers

Answer:

Fahrenheit ⇒ 847.4 °FKelvin ⇒ 726.15K

Explanation:

To convert Celsius to Fahrenheit, use the following formula;

= (°C * 9/5) + 32

= (453 * 9/5) + 32

= 847.4 °F

To convert Celsius to Kelvin, use the following;

= °C + 273.15

= 453 + 273.15

= 726.15K

Can you find two ways that carbon can get from the ocean to the lithosphere?

Answers

Answer:    

Two ways carbon can get from the ocean to the lithosphere is through the marine plants + animals (in the ocean) , sediments, petroleum then to the lithosphere.

Hope that helps!

If you drop a rock from 700 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)

Answers

Answer:

it would be 11.95 seconds

Explanation:

sorry for saying i did not know

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