Answer:
Step-by-step explanation:
Height of the cylinder = 1.4 m
diameter of the cylinder = 1.1 m
Tublu has a full 2 litre tin of paint
Assume that the tank has an open top to allow the capturing of rainwater.
Also, Tublu does not need to paint the base of the tanks.
Tublu needs 250 ml to cover 1 m^2 of the tank body
Only the body of the tank is to be painted, so we find the perimeter of the tank body.
from basic circle mensuration, perimeter of the tank body = [tex]\pi d[/tex]
where d is the diameter of the tank
==> 3.142 x 1.1 = 3.456 m
If we imagine that this perimeter of the tank body is spread out, it will form a rectangle with a height of 1.4 m from the base.
The area of this rectangle that will be formed = (perimeter of the cylinder body) x ( height of the cylinder)
==> 3.456 x 1.4 = 4.838 m^2
this area is the area of the tank that needs to be painted.
Now we convert the 250 ml to litre, we'll have
250 ml = 250 x 10^-3 litres = 0.25 litres
Since 250 ml or rather 0.25 litres of paint is needed to cover 1 m^2 area of the tank's body, then, we will need
==> 4.838 x 0.25 = 1.21 litres of paint
Since Tublu has a full 2 litres tin of paint, and he needs 1.21 litres to cover the body of the tank, then we can say that Tublu has more than enough paint to cover the tank surface in one layer coating.
EXPONENTIAL FUNCTIONS HELP Write the function for each graph described below. the graph of f(x) = 2x reflected across the x-axis. The graph of f(x)= 1/3x translated up 5 units. The graph of f(x) = 3x left 2 units, and down 3. The graph of f(x) = 1/2x translated down 2 units. The graph of f(x) = 4x stretched horizontally by a factor of 3. The graph of f(x) = 2x up 4 units, right 3.
Answer:
-2^x(1/3)^x +53^(x +2) -3(1/2)^x -24^(x/3)2^(x -3) +4Step-by-step explanation:
In general, the transformation ...
g(x) = f(x -h) +k
translates f(x) right h units and up k units.
The transformation ...
g(x) = f(x/a)
stretches the graph horizontally by a factor of "a".
The transformation ...
g(x) = -f(x)
causes the graph to be reflected over the x-axis.
___
Applying the above, we have ...
f(x) = 2^x reflected over x is g(x) = -2^x
f(x) = (1/3)^x translated up 5 is g(x) = (1/3)^x +5
f(x) = 3^x translated by (-2, -3) is g(x) = 3^(x +2) -3
f(x) = (1/2)^x translated down 2 is g(x) = (1/2)^x -2
f(x) = 4^x stretched horizontally by a factor of 3 is g(x) = 4^(x/3)
f(x) = 2^x translated by (3, 4) is g(x) = 2^(x -3) +4
Answer:
-2^x
(1/3)^x +5
3^(x +2) -3
(1/2)^x -2
4^(x/3)
2^(x -3) +4
Step-by-step explanation:
In general, the transformation ...
g(x) = f(x -h) +k
translates f(x) right h units and up k units.
The transformation ...
g(x) = f(x/a)
stretches the graph horizontally by a factor of "a".
The transformation ...
g(x) = -f(x)
causes the graph to be reflected over the x-axis.
___
Applying the above, we have ...
f(x) = 2^x reflected over x is g(x) = -2^x
f(x) = (1/3)^x translated up 5 is g(x) = (1/3)^x +5
f(x) = 3^x translated by (-2, -3) is g(x) = 3^(x +2) -3
f(x) = (1/2)^x translated down 2 is g(x) = (1/2)^x -2
f(x) = 4^x stretched horizontally by a factor of 3 is g(x) = 4^(x/3)
f(x) = 2^x translated by (3, 4) is g(x) = 2^(x -3) +4
Frequency table help
Answer: 1) 21-25
2) III
3) II
4) 8
5) 4
Step-by-step explanation:
Question 1: Which numbers are missing?
The previous interval ends at 20 the following interval starts at 26.
The missing interval is 21 - 25
Question 2: How many tally marks to draw?
The frequency is given as 3, so draw three tally marks: III
Question 3: How many tally marks to draw?
The frequency is given as 2, so draw two tally marks: II
Question 4: What is the frequency?
There are eight tally marks so the frequency is 8.
Question 5: What is the frequency?
There are four tally marks so the frequency is 4.
calculate the force acting on a man of mass 600g running to a tree through a distance of 20m
120N
f= mgh
=o. 6x10x20
= 120N
Step-by-step explanation:
given,
mass ( m)=0.6kg
gravity=9.8 m/s^2
by the formula of force,
f= ma
=0.6×9.8
therefore force is 5.88 n.
if 36a=45/b, then ab=
Answer:
[tex]1.25[/tex]
Step-by-step explanation:
[tex]let \: a = x \: and \: b = y[/tex]
[tex]36x = \frac{45}{y} [/tex]
[tex]36xy = 45[/tex]
[tex]xy = \frac{45}{36} [/tex]
[tex]xy = 1.25[/tex]
[tex]therefore \: ab \: is \: 1.25[/tex]
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of fuel consumed. In an independent random sample of cars driven at high altitudes, of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is less than the proportion of low-altitude vehicles exceeding the standard
Complete question is;
In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices
Answer:
Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).
Step-by-step explanation:
This is a hypothesis test for the difference between the proportions.
The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.
Then, the null and alternative hypothesis are:
H0 ; π1 - π2 = 0
H1 ; π1 - π2 < 0
The significance level would be established in 0.01.
The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;
p1 = x1/n1
p1 = 43/370
p1 = 0.116
The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;
p2 = x2/n2
p2 = 23/80
p2 = 0.288
The difference between proportions is pd = (p1-p2);
pd = p1 - p2 = 0.116 - 0.288
pd = -0.171
The pooled proportion, we need to calculate the standard error, is:
p = (x1 + x2)/(n1 + n2)
p = (43 + 23)/(370 + 80)
p = 66/450
p = 0.147
The estimated standard error of the difference between means is computed using the formula:
S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]
1 - p = 1 - 0.147 = 0.853
Thus;
S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]
S_(p1-p2) = 0.044
Now, we can use the formula for z-statistics as;
z = (pd - (π1 - π2))/S_(p1-p2)
z = (-0.171 - 0)/0.044
z = -3.89
Using z-distribution table, we have the p-value = 0.00005
Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.
We conclude that The null hypothesis is rejected.
Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.
A swimming pool is being drained at a constant rate of 3 inches (depth of the water) per hour. The depth of the water after 5 hours is 32 inches. Write the equation for this function in point slope form
Answer:
The equation in point slope form is [tex]y - 47\,in = \left(-3\,\frac{in}{h}\right)\cdot (t-0\,h)[/tex]
Step-by-step explanation:
Since the swimming pool is being drained at a constant rate, the equation of the process must be a first-order polynomial (linear function), where depth of water decrease as time goes by. The form of the expression is:
[tex]y = m \cdot t + b[/tex]
Where:
[tex]t[/tex] - Time, measured in hours.
[tex]b[/tex] - Initial depth of the water in swimming pool (slope), measured in inches.
[tex]m[/tex] - Draining rate, measured in inches per hour.
[tex]y[/tex] - Current depth of the water in swimming pool (x-Intercept), measured in inches.
If [tex]m = -3\,\frac{in}{h}[/tex] and [tex]y (5\,h) = 32\,in[/tex], the initial depth of the water in swimming pool is:
[tex]b = y - m\cdot t[/tex]
[tex]b = 32\,in -\left(-3\,\frac{in}{h} \right)\cdot (5\,h)[/tex]
[tex]b = 47\,in[/tex]
The equation in point slope form is:
[tex]y-y_{o} = m \cdot (t-t_{o})[/tex]
Where [tex]y_{o}[/tex] and [tex]t_{o}[/tex] are initial depth of the water in swimming pool and initial time, respectively. Then, the equation in point slope form is:
[tex]y - 47\,in = \left(-3\,\frac{in}{h}\right)\cdot (t-0\,h)[/tex]
What are
are the types of algebric
expression?
Answer:
Step-by-step explanation:
monomial, polynomial, binomial, trinomial and multinomial are the different types of algebraic expressions.
plz mark as brainliest!!!!!!!
The following table represents a probability distribution for a random variable, X. What must P(5) be?
Answer:
c) 0.1
P(5) = 0.1
Step-by-step explanation:
Given data
x : 0 1 2 3 4 5
p(x): 0.2 0.1 0.3 0.1 0.2 ?
Given data is discrete distribution
if the numbers [tex]P(x_{i} )[/tex] i = 1,2,3..... satisfies the two conditions
i) [tex]P(x_{i} )\geq 0[/tex] for all values of 'i'
ii) ∑P(x) = 1
Given data
i) [tex]P(x_{i} )\geq 0[/tex] for all values of 'i'
ii) ∑P(x) = 1
P(x=1) + P(x=2) +P(x=3) +P(x=4)+P(x=5) =1
⇒ 0.2 + 0.1 + 0.3 +0.1 +0.2 + p(X=5) = 1
⇒ 0.9 +p(5) =1
⇒ p(5) = 1 -0.9
⇒ P(5) = 0.1
[URGENT] (15 points) F(x) is defined by the equation f(x) = 3x^2 + 3x - 7. What effect will multiplying
f(x) by 0.5 have on the graph?
Answer:
Options (B) and (C).
Step-by-step explanation:
When a quadratic function 'f' is multiplied by k,
1). If k > 0, function 'f' will be vertically stretched Or horizontally compressed.
2). If 0 < k < 1, function will be vertically compressed Or horizontally stretched.
Given quadratic function is,
f(x) = 3x² + 3x - 7
This function is multiplied by 0.5.
Since 0 < 0.5 < 1, therefore, the function will be compressed vertically Or stretched horizontally.
Therefore, Options B and C are the correct options.
John has two jobs. For daytime work at a jewelry store he is paid
$15,000 per month, plus a commission. His monthly commission is
normally distributed with mean $10,000 and standard deviation
$2000. At night he works occasionally as a waiter, for which his
monthly income is normally distributed with mean $1,000 and
standard deviation $300. John's income levels from these two
sources are independent of each other. For a given month, what is
the probability that John's commission from the jewelry store is
between $9,000 and $11,000?
Given Information:
John's mean monthly commission = μ = $10,000
Standard deviation of monthly commission = σ = $2,000
Answer:
[tex]P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%[/tex]
The probability that John's commission from the jewelry store is between $9,000 and $11,000 is 38.3%
Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the probability that John's commission from the jewelry store is between $9,000 and $11,000?
[tex]P(9,000 < X < 11,000) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9,000 < X < 11,000) = P( \frac{9,000 - 10,000}{2,000} < Z < \frac{11,000 - 10,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( \frac{-1,000}{2,000} < Z < \frac{1,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( -0.5 < Z < 0.5 )\\\\P(9,000 < X < 11,000) = P( Z < 0.5 ) - P( Z < -0.5 ) \\\\[/tex]
The z-score corresponding to 0.50 is 0.6915
The z-score corresponding to -0.50 is 0.3085
[tex]P(9,000 < X < 11,000) = 0.6915 - 0.3085 \\\\P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%[/tex]
Therefore, the probability that John's commission from the jewelry store is between $9,000 and $11,000 is 38.3%
How to use z-table?
Step 1:
In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.4, 2.2, 0.5 etc.)
Step 2:
Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.50 then go for 0.00 column)
Step 3:
Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.
If the graph of the function y = f(x) is compressed horizontally by 3, and then reflected across the y -axis , then the resulting graph is the graph of the function :
(a) y = -f(3x) (b) y = f(-3x) (c)y=-f(1/3x)
(d) y = -f(1/3x)
(e) none
Answer:
Please check if the answer is correct or not....
What is the inverse of 520/2 = 260?
260/520 = .5
260 * 2 = 520
2/520 = .004
260 * 520 = 135,200
Answer:
The answer is 260 * 2 = 520
Step-by-step explanation:
520/2 = 260
Multiply both sides by 2
We have
260 × 2 = 560
Hope this helps
Select all the correct equations.
Which equations have no real solution but have two complex solutions? PLZ 20 POINTS
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
This was for 5 points. not 20 my dude. Also the first answer is correct.
Step-by-step explanation:
Find the slope of the line shown on the graph to the right.
Select the correct choice below and fill in any answer boxes within your choice.
#
A. The slope of the line is
(Simplify your answer. Type an integer or a fraction.)
B. The slope is undefined
Answer:
0 (zero)
Step-by-step explanation:
A horizontal line has zero slope.
Find the position function of a particle moving along a coordinate line that satisfies the given conditions. 2sint-cost
Answer:
the position of a particle moving at a coordinate say(y) will satisfy the given conditions t=0 (say) if y=2sint-cost
Step-by-step explanation:
Clearly by the above we can see that if y=2sint-cost at t=0, then y=-1 because at t=0 sint vanishes and leaves us with only cost and at t=0 cos0=1
How many months dose it take to pay off 160,000 paying 677 a month
160,000 / 677 = 293.88 months
Hope this helps.
[tex]\frac{8-i}{3-2i}[/tex] If the expression above is rewritten in the form a+bi, where a and b are real numbers, what is the value of a? (Note: [tex]i=\sqrt{-1}[/tex]
Answer:
a = 2 , b = 1
Step-by-step explanation:
[tex]\frac{8-i}{3-2i}*\frac{3+2i}{3+2i}[/tex]
=> [tex]\frac{(8-i)(3+2i)}{9+4}[/tex]
=> [tex]\frac{24+13i-2i^2}{13}[/tex]
=> [tex]\frac{26+13i}{13}[/tex]
Comparing it with a+bi
a = 26/13 , b = 13/13
a = 2, b = 1
Answer:
a = 2
b = 1
Step-by-step explanation:
[tex]\frac{8-i}{3-2i}[/tex]
Write the fraction in this form:
[tex]\frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}[/tex]
[tex]\frac{\left(8(3)+-1(-2)\right)+\left(-1(3)-8(-2)\right)i}{3^2+-2^2}[/tex]
Evaluate.
[tex]\frac{26+13i}{13}[/tex]
Factor the numerator.
[tex]\frac{13\left(2+i\right)}{13}[/tex]
[tex]2+1i[/tex]
a manufacturer of bicycle parts requires that a bicycle chain have a width of 0.3 inch with an absolute deviation of at most 0.0003 inch. write and solve an absolute value inequality that represents the acceptable widths.
Answer:
[tex] |w-0.3| \leq 0.0003[/tex]
And solving we got:
[tex] -0.0003 \leq w-0.3 \leq 0.0003[/tex]
[tex]0.3-0.0003 \leq w \leq 0.3+0.0003[/tex]
[tex] 0.2997 \leq w \leq 0.3003[/tex]
Step-by-step explanation:
For this case we can define the following notation:
[tex] W[/tex] represent the width
And we want a maximum error of 0.0003 so we can set up the following equation:
[tex] |w-0.3| \leq 0.0003[/tex]
And solving we got:
[tex] -0.0003 \leq w-0.3 \leq 0.0003[/tex]
[tex]0.3-0.0003 \leq w \leq 0.3+0.0003[/tex]
[tex] 0.2997 \leq w \leq 0.3003[/tex]
A triangle and a horizontal line are shown. If the triangle is revolved about the horizontal line, what is the resulting object? a triangle next to a horizontal line solid cylinder hollow cylinder solid cone hollow cone with truncated top
Answer:
d. solid cone
Step-by-step explanation:
Solid revolution is the general method used for revolving a given figure about a reference plane to produce a required solid. This process involves the generation of a 3 dimensional shape from a 2 dimensional figure.
A triangle is a three sided figure which generates a solid or hollow cone when it revolves about a given line. If the given triangle is made to revolve about the line, the resulting object would be a solid cone.
Answer:
the answer would be a solid cone
Step-by-step explanation:
i took the test and got it right.
BRAINLIEST PLS PLS PLS PLS I RLY NEED IT
5. Calculate, in terms of it, the total surface
area of a solid cylinder of radius 3cm and
height 4cm
Answer:
131.88 cm²
Step-by-step explanation:
At = 2×Acircle + Arectangle
= 2×π·r² + w×h
w = 2π·r = 2·3.14·3 = 18.84 cm
At = 2·3.14·9cm² + 18.84cm·4cm
= 56.52cm² + 75.36cm²
= 131.88 cm²
Two cars start moving from the same point. One travels south at 16 mi/h and the other travels west at 12 mi/h. At what rate is the distance between the cars increasing three hours later?
Answer:
20 miles per hour
Step-by-step explanation:
The distances traveled by each car are perpendicular, so we can find the distance between the cars using the Pythagoras' theorem between their distances traveled:
[tex]d^2 = d_1^2 + d_2^2[/tex]
Where d is the distance between the cars, d1 is the distance traveled by the first car and d2 is the distance traveled by the second car.
The distance traveled is calculated by the speed times the time traveled, so we have:
[tex]d^2 = (16t)^2 + (12t)^2[/tex]
[tex]d^2 = 256t^2 + 144t^2[/tex]
[tex]d^2 = 400t^2[/tex]
[tex]d = 20t[/tex]
The rate that the distance is increasing can be found with the derivative of the distance in relation to the time:
[tex]dd/dt = 20\ mph[/tex]
So the rate that the distance increases is always 20 miles per hour, and it's independent of the time.
Find the side of a cube with surface area of 150cm square
Anyone that answers my question I will mark as brilliant
Answer:
5cm for each side
Answer:
5 cmsolution,
Surface area= 150 cm^2
Side of a cube(a)=?
Now,
[tex]surface \: area \: of \: cube = 6 {a}^{2} \\ or \: 150 = 6 {a}^{2} \\ or \: {a}^{2} = \frac{150}{6} \\ or \: {a}^{2} = 25 \\ or \: a = \sqrt{25} \\ or \: a = \sqrt{ {(5)}^{2} } \\ a = 5 \: cm[/tex]
Hope this helps...
Good luck on your assignment..
Find the measure of ∠2.
Answer:
∠[tex]2=131[/tex]°
Step-by-step explanation:
We know that ∠[tex]4[/tex] is ≅ ∠[tex]1[/tex].
This means that ∠ [tex]1=49[/tex]°
Therefore, [tex]49+49=98[/tex]°
We know that a trapezoid is [tex]360[/tex]°.
To find ∠[tex]2[/tex] ,which is congruent to ∠[tex]3\\[/tex], we will have to subtract [tex]360[/tex]° from [tex]98[/tex]°.
[tex]360-98=262[/tex]°.
Because ∠[tex]2[/tex]≅∠[tex]3[/tex], we will have to divide [tex]262[/tex] by [tex]2[/tex] to see their measurement.
So,
[tex]\frac{262}{2}=131[/tex].
Hence, ∠[tex]2=131[/tex]°.
I really hope this helps:D
-Jazz
45 points! Yay An investment may earn interest using a simple interest rate or a compound interest rate. This expression can be used to find the value of an investment that is earning simple interest: P(1+rt) This expression can be used to find the value of an investment that is earning compound interest: P(1+r)t Use the drop-down menus to complete the statements about simple and compound interest. For an investment earning(simple interest,compound interest) , the interest is applied each year to the principal and to any interest that already accrued. For an investment earning(simple interest, compojnd interest) , the interest is applied each year only to the principal. Please help I'm literally the dumbest person i know •,-,•
Answer:
1. Compound Interest
2. Simple Interest
Step-by-step explanation:
Simple Interest multiplies the interest rate on the principal rate by the number of days.
Compound Interest multiplies the interest rate on the principal rate and existing rate by periods.
Answer:
:)
Step-by-step explanation:
Please answer this correctly
Answer:
4
Step-by-step explanation:
help me pls help me pls
Answer:
It should be D if not Than A
Answer:
it should be D
Step-by-step explanation:
the expression7(b+3) is equivalent to which expression? A.7b+3, B.7+b+c, C.7b+10, D.7b+21
Answer:
7b+21
Step-by-step explanation:
7(b+3)
Distribute
7*b + 7*3
7b+21
Can someone help me with this
Answer:
10
Step-by-step explanation:
Since 75 sandwiches have salad this means that 75 - 30 = 45 of them have tuna with salad. Therefore, the amount of sandwiches that have cheese without salad is 100 - (30 + 15 + 45) = 100 - 90 = 10.
Write two point-slope equations for the line passing through the points (6, 5) and (3, 1). Show your work.
Answer:
y=-4/3x-3
Step-by-step explanation:
You look for the slope using the the slope formula (m=y2-y1/x2-x1)
You will end up with (m=1-5/3-6)
Simplify to end up with (-4/3) as your slope.
Then, pick a coordinate point. Your choices are (6,5) and (3,1). You will us it to plug into the equation.
I am picking (3,1) The y-value here is 1 and the x-value is 3.
Your equation to find b, or the y-intercept is going to be (1=-4/3(3)+b)
You will have to simplify.
1=-4/3(3)+b
You will multiply -4/3 and -3 and end up with 4 so it looks like...
1=4+b
You subtract 4 on both sides and then end up with....
-3=b
So, the final answer is: y=-4/3x-3
Which statement is correct regarding g(x) = 35x + 6 - 8 and the parent function f(x) = x ?
O The domains of g(x) and f(x) are the same, but their ranges are not the same.
O The ranges of g(x) and f(x) are the same, but their domains are not the same.
The ranges of g(x) and f(x) are the same, and their domains are also the same.
O The domains of g(x) and f(x) are the not the same, and their ranges are also not the same.
Answer:
The ranges of g(x) and f(x) are the same and their domains are also the same.
Step-by-step explanation:
The function g(x) is the function f(x) multiplied by 35 and later translated twice, first 6 units up and later 8 units down. Since, both expressions are linear functions, both are continuous and both have the same domains and range due to constant slope.
Hence, the ranges of g(x) and f(x) are the same and their domains are also the same.